Mathematics College

what is the 20th term of the sequence that begins -4, 8, -16, 32...?

Answers

Answer 1

Answer:

-2097152 is the 20th term

Step-by-step explanation:

Write geometric sequence as an explicit formula

[tex]-4,8,-16,32\rightarrow-4(-2)^0,-4(-2)^1,-4(-2)^2,4(-2)^3\\a_n=a_1r^{n-1}\rightarrow a_n=-4(-2)^{n-1}[/tex]

Find the n=20th term

[tex]a_{20}=-4(-2)^{20-1}=-4(-2)^{19}=4(-524288)=-2097152[/tex]

Related Questions

pls help !!!!!! geometry

Answers

Picture is too blurry to look at graph retake and I will give you answers

Please help! Will give brainliest

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The z - score z = (x - μ)/σ equals z = (p' - p)/[√(pq/n)]

What is z-score?

The z-score is the statical value used to determine probability in a normal distribution

Given the z-score z = (x - μ)/σ where

x = number of successes in a sample of nμ = np and σ = √npq

We need to show that

z = (p' - p)/√(pq/n)

We proceed as follows

Now, the z-score

z = (x - μ)/σ

Substituting in the values of μ and σ into the equation, we have that

μ = np and σ = √(npq)

So, z = (x - μ)/σ

z = (x - np)/[√(npq)]

Now, dividing both the numerator and denominator by n, we have that

z = (x - np)/[√(npq)]

z = (x - np) ÷ n/[√(npq)] ÷ n

z = (x/n - np/n)/[√(npq)/n]

z = (x/n - p)/[√(npq/n²)]

z = (x/n - p)/[√(pq/n)]

Now p' = x/n

So, z = (x/n - p)/[√(pq/n)]

z = (p' - p)/[√(pq/n)]

So, the z - score is z = (p' - p)/[√(pq/n)]

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A bacteria culture triples every 5 minutes. At 4:27 P.M. the population is . Determine what the population was 27 minutes earlier, at 4:00 P.M.

Answers

The population at 4:00 P.M., 27 minutes earlier, is[tex]3^3[/tex] times the initial population P.

To determine the population of a bacteria culture 27 minutes earlier, we need to calculate the population growth from 4:00 P.M. to 4:27 P.M. given that the bacteria culture triples every 5 minutes.

Let's break down the time period into intervals of 5 minutes:

From 4:00 P.M. to 4:05 P.M., the population triples once.

From 4:05 P.M. to 4:10 P.M., the population triples again.

From 4:10 P.M. to 4:15 P.M., the population triples for the third time.

From 4:15 P.M. to 4:20 P.M., the population triples for the fourth time.

From 4:20 P.M. to 4:25 P.M., the population triples for the fifth time.

From 4:25 P.M. to 4:27 P.M., the population undergoes partial growth.

Since the population triples every 5 minutes, we can express the population at 4:27 P.M. as 3^5 times the initial population at 4:00 P.M.

Let's denote the initial population at 4:00 P.M. as P. Then, the population at 4:27 P.M. is [tex]3^5[/tex] * P.

To find the population 27 minutes earlier, we need to reverse the growth from 4:27 P.M. to 4:00 P.M. Since the population triples every 5 minutes, we need to divide the population at 4:27 P.M. by [tex]3^{(27/5).[/tex]

Therefore, the population at 4:00 P.M., 27 minutes earlier, can be calculated as:

Population at 4:00 P.M. = (Population at 4:27 P.M.) / [tex]3^{(27/5)[/tex]

[tex]= (3^{5} * P) / 3^{(27/5)\\\\\\\\= 3^{(25/5)} * P\\= 3^5 * P / 3^2\\= 3^3 * P[/tex]

Hence, the population at 4:00 P.M., 27 minutes earlier, is 3^3 times the initial population P.

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What is the distance between points R (5, 7) and S(-2,3)?

Answers

Answer:

d ≈ 8.1

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = R (5, 7 ) and (x₂, y₂ ) = S (- 2, 3 )

d = [tex]\sqrt{(-2-5)^2+(3-7)^2}[/tex]

= [tex]\sqrt{(-7)^2+(-4)^2}[/tex]

= [tex]\sqrt{49+16}[/tex]

= [tex]\sqrt{65}[/tex]

≈ 8.1 ( to 1 decimal place )

9497 ÷ 16 _R_ please

Answers

When you divide 9497 by 16, the quotient is 593 with a remainder of 9.

So, 9497 ÷ 16 = 593 remainder 9. Month

I don’t understand can I get answers please

Answers

Answer:

c=25

Step-by-step explanation:

Since you are given [tex]x^{2}[/tex]+10x+c

We know that in an equation of [tex]ax^{2}+bx+c[/tex], when a = 1, c can be found by [tex](\frac{b}{2})^{2}[/tex]

So c = [tex](10/2)^{2}[/tex]=[tex]5^{2}[/tex]=25

A sample of gas stored at ST has a volume of 3.56 L. The gas is heated to 400 K and has a pressure of 125 kPa. What is the volume of the gas after it is heated?

Answers

The volume of the gas after it is heated is approximately 0.0417 liters.

To find the volume of the gas after it is heated, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law is expressed as:

(P₁V₁) / T₁ = (P₂V₂) / T₂

Where:

P₁ and P₂ are the initial and final pressures of the gas (in kPa)

V₁ and V₂ are the initial and final volumes of the gas (in liters)

T₁ and T₂ are the initial and final temperatures of the gas (in Kelvin)

Given:

Initial volume (V₁) = 3.56 L

Initial temperature (T₁) = ST (which is typically 273.15 K)

Final temperature (T₂) = 400 K

Final pressure (P₂) = 125 kPa

Now we can plug these values into the combined gas law equation and solve for V₂:

(P₁V₁) / T₁ = (P₂V₂) / T₂

(1 * 3.56) / 273.15 = (125 * V₂) / 400

(3.56 / 273.15) = (125 * V₂) / 400

Cross-multiplying and solving for V₂:

3.56 * 400 = 273.15 * 125 * V₂

1424 = 34143.75 * V₂

V₂ = 1424 / 34143.75

V₂ ≈ 0.0417 L

As a result, the heated gas has a volume of approximately 0.0417 litres.

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8. Amy has $30 to spend. She wants to buy pounds of lemons at $2 per pound, a box for $4, and 7 frozen dinners for $3 each Choose True or False for each statement. A She will not have enough money to buy everything O True O False 8 She will have $1 left over. O True O False C The total cost is $39. O True O False

Answers

Answer:she will actually need 1 dollar because all of that would be 31 dollars.

Step-by-step explanation:

3 pounds of lemons= $6

1 box of rice= $4

7 frozen diners= $21

6+4=10

10+21=31

What is the symbol ~, if you're trying to find the probability of ~A?
the addition probability
the probability of the event not happening
the multiplication probability
None of these choices are correct.

Answers

The correct choice is: the probability of the event not happening.

The symbol ~ (tilde) is commonly used to represent the negation or complement of an event. When we refer to ~A, it means "not A" or "the complement of A." In terms of probability, ~A represents the event not happening or the event A occurring.

Reynold’s company has a product with fixed costs of $334,000, a unit selling price of $22, and unit variable costs of $19. The break-even sales (units) if the variable costs are decreased by $4 is

Answers

The break-even sales (units) when the variable costs are decreased by $4 is approximately 47,714 units.

To find the break-even sales (units) when the variable costs are decreased by $4, we need to calculate the new unit variable costs and then use the break-even formula.

Fixed costs (F) = $334,000

Unit selling price (P) = $22

Unit variable costs (V) = $19

Change in unit variable costs = $4

New unit variable costs (V') = V - Change in unit variable costs

= $19 - $4

= $15

Now, let's calculate the break-even sales (units) using the formula:

Break-even sales (units) = Fixed costs / (Unit selling price - Unit variable costs)

Break-even sales (units) = $334,000 / ($22 - $15)

= $334,000 / $7

= 47,714.29

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find the value of b
A. 14
B. 15
C. 64
D. 289

Answers

SolutioN:-

[tex] \sf \hookrightarrow \: {8}^{2} + {b}^{2} = {17}^{2} [/tex]

[tex] \sf \hookrightarrow \: 8 \times 8 + {b}^{2} = 17 \times 17[/tex]

[tex] \sf \hookrightarrow \: 8 \times 8 + {b}^{2} = 289[/tex]

[tex] \sf \hookrightarrow \: 64 + {b}^{2} = 289[/tex]

[tex] \sf \hookrightarrow \: {b}^{2} = 289 - 64[/tex]

[tex] \sf \hookrightarrow \: {b}^{2} = 225[/tex]

[tex] \sf \hookrightarrow \: b = \sqrt{225} [/tex]

[tex] \sf \hookrightarrow \: b = \sqrt{15 \times 15} [/tex]

[tex] \sf \hookrightarrow \: b = 15[/tex]

B) b = 15 ✅

Find the local and absolute maximum and minimum points in (x, y) format for the

function f(x) = 3/5x^5 - 9x^3 + 2 on the closed interval [-4,5]. Answer the following

questions.

a) Find all critical numbers (x- coordinates only)

b) Find the intervals on which the graph is increasing Mark critical numbers

Answers

To find the critical numbers of the function f(x) = (3/5)x^5 - 9x^3 + 2, we need to find the values of x where the derivative of the function is either zero or undefined. Let's calculate the derivative first:

f'(x) = 15/5x^4 - 27x^2 = 3x^4 - 27x^2

a) To find the critical numbers (x-coordinates), we need to solve the equation 3x^4 - 27x^2 = 0 for x:

3x^2(x^2 - 9) = 0

This equation factors as 3x^2(x + 3)(x - 3) = 0. Setting each factor to zero gives us three critical numbers: x = 0, x = -3, and x = 3.

b) To find the intervals on which the graph is increasing or decreasing, we can use the critical numbers and test points within each interval. However, since the interval is already specified as [-4, 5], we can determine the intervals based on the critical numbers and endpoints.

The critical numbers divide the interval [-4, 5] into four smaller intervals: [-4, -3], [-3, 0], [0, 3], and [3, 5].

We can determine if the function is increasing or decreasing within each interval by evaluating the derivative (f'(x)) at a test point in each interval:

For the interval [-4, -3], let's evaluate f'(-4) = 3(-4)^4 - 27(-4)^2 = 768, which is positive. Therefore, the function is increasing in this interval.

For the interval [-3, 0], let's evaluate f'(-3) = 3(-3)^4 - 27(-3)^2 = 0, which is neither positive nor negative. We need to test another point in this interval, such as f'(-2) = 3(-2)^4 - 27(-2)^2 = -96, which is negative. Therefore, the function is decreasing in this interval.

For the interval [0, 3], let's evaluate f'(0) = 3(0)^4 - 27(0)^2 = 0, which is neither positive nor negative. We need to test another point in this interval, such as f'(1) = 3(1)^4 - 27(1)^2 = -24, which is negative. Therefore, the function is decreasing in this interval.

For the interval [3, 5], let's evaluate f'(3) = 3(3)^4 - 27(3)^2 = 0, which is neither positive nor negative. We need to test another point in this interval, such as f'(4) = 3(4)^4 - 27(4)^2 = 768, which is positive. Therefore, the function is increasing in this interval.

Based on these calculations, the intervals on which the graph of the function f(x) = (3/5)x^5 - 9x^3 + 2 is increasing are [-4, -3] and [3, 5]. The intervals on which the graph is decreasing are [-3, 0] and [0, 3].

Please note that this analysis gives us information about the increasing and decreasing behavior of the function, but it doesn't provide specific local or absolute maximum and minimum points.

Which function is graphed ?

Answers

This fraction is really hard I believe in my thoughts and I’m smart so it’s the second one

NO LINKS!! URGENT HELP PLEASE!!

Please help me with 34

Is AB tangent to the circle? Explain..

Answers

Answer:

AB is not tangent to the circle.

Step-by-step explanation:

A tangent is a straight line that touches a circle at only one point.

The tangent of a circle is always perpendicular to the radius.

Therefore, if AB is tangent to the circle, it will form a right angle with the radius, CA.

To determine if AB is tangent, we can use Pythagoras Theorem.

[tex]\boxed{\begin{minipage}{9 cm}\underline{Pythagoras Theorem} \\\\$a^2+b^2=c^2$\\\\where:\\ \phantom{ww}$\bullet$ $a$ and $b$ are the legs of the right triangle. \\ \phantom{ww}$\bullet$ $c$ is the hypotenuse (longest side) of the right triangle.\\\end{minipage}}[/tex]

If AB is tangent, then angle CAB will be a right angle. So AC and AB would be the legs of the right triangle, and BC would be the hypotenuse.

Therefore:

[tex]AC^2+AB^2=BC^2[/tex]

Substitute the values into the equation:

[tex]7^2+12^2=15^2[/tex]

[tex]49+144=225[/tex]

[tex]193 = 225 \; \leftarrow\; \sf not\;true[/tex]

As 193 ≠ 225, the equation does not hold, hence proving that AB is not tangent to the circle.

Pls help I am stuck Tysm

Answers

The perimeter of the figure is 30 cm.

How to find the perimeter of a figure?

The perimeter of the figure is the sum of the whole sides of the figure. Therefore, the perimeter of the figure can be found as follows:

perimeter of the figure = sum of the whole sides

Therefore,

perimeter of the figure = 6 cm + 9 cm + 2 cm + 3cm + 2cm + 3cm + 2cm + 3cm

Hence,

perimeter of the figure = 15 cm + 5 cm + 5cm + 5 cm

perimeter of the figure = 30 cm

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two points A and B, due to two spheres X and Y 4.0m apart, that are carrying charges of 72mC and -72mC respectively. Assume constant of proportionality as 9×10^9Nm²/C². Find the electric field strength at points A and B due to each spheres presence

Answers

Due to the presence of spheres X and Y, the electric field strength at point B is [tex]1.01 * 10^6 N/C[/tex] and [tex]-4.05 * 10^6 N/C[/tex], respectively.

Given that two spheres X and Y are carrying charges of 72mC and -72mC respectively, and they are located 4.0 m apart from each other. The electric field strength at points A and B due to the presence of each sphere is to be determined.

Let's begin by calculating the electric field strength at point A due to sphere X. Electric field strength is given by E=kq/r², where k is Coulomb's constant, q is the charge and r is the distance between the two charges. The electric field strength at point A due to sphere X, E₁=kq₁/r₁² [tex]= (9*10^9Nm^2/C^2) * (72mC) / (4.0m)^2 = 4.05 * 10^6 N/C[/tex] (approx.)

Similarly, the electric field strength at point A due to sphere Y can be calculated as follows, E₂=kq₂/r₂² [tex]= (9*10^9Nm^2/C^2) * (72mC) / (4.0m)^2 = 4.05 * 10^6 N/C[/tex] (approx.). Here, the negative sign indicates that the electric field due to sphere Y is in the opposite direction to the electric field due to sphere X. Now, let's calculate the electric field strength at point B. The electric field strength at point B due to sphere X, E₁=kq₁/r₁² [tex]= (9*10^9Nm^2/C^2) * (72mC) / (8.0m)^2 = 1.01 * 10^6 N/C[/tex] (approx.)

Similarly, the electric field strength at point B due to sphere Y can be calculated as follows, E₂=kq₂/r₂² [tex]= (9*10^9Nm^2/C^2) * (-72mC) / (4.0m)^2 = -4.05 * 10^6 N/C[/tex] (approx.). Therefore, the electric field strength at point A due to the presence of sphere X is [tex]4.05 * 10^6 N/C[/tex] and due to the presence of sphere Y is [tex]-4.05 * 10^6 N/C[/tex]. The electric field strength at point B due to the presence of sphere X is [tex]1.01 * 10^6 N/C[/tex] and due to the presence of sphere Y is [tex]-4.05 * 10^6 N/C[/tex].

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An architect is designing a swimming pool with a base in the shape of a right triangle according to the architect the pools depth should be 6 feet less than It’s length x and it’s width should be 8 feet less than it’s length the volume of water in the pool cannot exceed 1680 cubic feet which statement

Answers

Let's use the formula for the volume of a right triangular prism to find the length of the pool:
Volume = (1/2) x base x height x depth
We know that the base of the pool is a right triangle, so we can use the Pythagorean theorem to find the base:
a^2 + b^2 = c^2
where a and b are the legs of the right triangle and c is the hypotenuse, which is the length of the pool.
We also know that the width of the pool is 8 feet less than its length, so we can write:
b = c - 8
We are given that the depth of the pool is 6 feet less than its length x, so we can write:
depth = x - 6
Substituting the values of b and depth in the formula for the volume of a right triangular prism, we get:
Volume = (1/2) x (c - 8) x c x (x - 6)
Simplifying the equation, we get:
Volume = (1/2) x (c^2 - 8c) x (x - 6)
Multiplying both sides by 2 and expanding, we get:
2 x Volume = (c^2 - 8c) x (x - 6)
2 x 1680 = (c^2 - 8c) x (x - 6)
3360 = (c^2 - 8c) x (x - 6)
We can solve this quadratic equation for c using the quadratic formula:
c = [8 ± sqrt(64 + 4 x 3360 x (x - 6))] / 2
c = 4 ± sqrt(16 + 3360 x (x - 6))
We know that the length of the pool cannot be negative, so we can eliminate the negative root:
c = 4 + sqrt(16 + 3360 x (x - 6))
Now we can substitute this value of c in the equation for b:
b = c - 8
b = 4 + sqrt(16 + 3360 x (x - 6)) - 8
b = sqrt(16 + 3360 x (x - 6)) - 4
Therefore, the length, width, and depth of the pool are:
Length = c = 4 + sqrt(16 + 3360 x (x - 6))
Width = b = sqrt(16 + 3360 x (x - 6)) - 4
Depth = x - 6
We are given that the volume of water in the pool cannot exceed 1680 cubic feet, so we can write:
Volume = Length x Width x Depth
1680 = (4 + sqrt(16 + 3360 x (x - 6))) x (sqrt(16 + 3360 x (x - 6)) - 4) x (x - 6)
We can solve this equation for x using numerical methods or a graphing calculator. The solution is approximately x = 12.5 feet.
Therefore, the statement that is true is: The length of the pool cannot exceed 4 + sqrt(16 + 3360 x (x - 6)) feet, the width of the pool cannot exceed sqrt(16 + 3360 x (x - 6)) - 4 feet, and the depth of the pool cannot exceed 6.5 feet, in order to ensure that the volume of water in the pool does not exceed 1680 cubic feet.

How do you find the circumference of a circle with a diameter of 6 inches. Use 3.14 as estimate of tt that's correct to two decimal places

Answers

Answer: 18.84

Step-by-step explanation : To find the circumference you use the formula:

2πr

Since we have the diameter (6), divide by 2 to find the radius, or r.

So (2)(3.14)(3)

In ΔBCD,
B
D
‾
BD
is extended through point D to point E,
m
∠
C
D
E
=
(
9
x
−
12
)
∘
m∠CDE=(9x−12)
∘
,
m
∠
B
C
D
=
(
2
x
+
3
)
∘
m∠BCD=(2x+3)
∘
, and
m
∠
D
B
C
=
(
3
x
+
5
)
∘
m∠DBC=(3x+5)
∘
. Find
m
∠
B
C
D
.
m∠BCD.

Answers

m∠BCD = 31.57° (approx). Hence, the answer of the angle is 31.57 degrees.

In the given diagram, BD is extended through point D to point E, m∠CDE = (9x - 12)°, m∠BCD = (2x + 3)°, and m∠DBC = (3x + 5)°. We need to find m∠BCD.

Use the Angle Sum Property of a Triangle.The Angle Sum Property of a Triangle states that the sum of all the angles in a triangle is equal to 180°.The angle sum of ΔBCD is:m∠BCD + m∠DBC + m∠CDE = 180°Substituting the given angles, we get:(2x + 3)° + (3x + 5)° + (9x - 12)° = 180°Simplifying the above expression, we get:14x - 4 = 180°14x = 180° + 4x = 184/14x = 92/7Find m∠BCD

We know that m∠BCD = (2x + 3)°

Substituting x = 92/7, we get:

m∠BCD = (2 × 92/7 + 3)° = (184/7 + 3)° = 221/7°

Therefore, m∠BCD = 31.57° (approx). Hence, the answer is 31.57.

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A metalworker cuts out a large semicircle with a diameter of 28 centimeters.Then the metalworker is a smaller sine ait of the larger one and rives it. The der of the ticular pince that is removed a 14 centimeters. Find the distance wound the shape after the smaller circle is removed. Use 22/7

Answers

The distance around the shape after the smaller semicircle is removed is 29 cm.The correct answer is option D.

To find the distance around the shape after the smaller semicircle is removed, we need to calculate the circumference of the larger semicircle and subtract the circumference of the smaller semicircle.

The circumference of a semicircle is given by the formula:

Circumference = π * radius + diameter/2

For the larger semicircle:

Radius = diameter/2 = 28/2 = 14 cm

Circumference of the larger semicircle = π * 14 + 28/2 = 22/7 * 14 + 14 = 44 + 14 = 58 cm

For the smaller semicircle:

Radius = diameter/2 = 14/2 = 7 cm

Circumference of the smaller semicircle = π * 7 + 14/2 = 22/7 * 7 + 7 = 22 + 7 = 29 cm

Therefore, the distance around the shape after the smaller semicircle is removed is:

58 cm - 29 cm = 29 cm

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The Probable question may be:
A metalworker cuts out a large semicircle with a diameter of 28 centimeters. Then the metalworker cuts a smaller semicircle out of the larger one and removes it. The diameter of the semicircular piece that is removed is 14 centimeters. What will be the distance around the shape after the smaller semicircle is removed? Use 22/7 as an approximation for π.

A. 80cm

B. 82cm

C. 85cm

D. 86cm

Algebra
Solve for k: 10-10|-8k+4|=10
Write your answer in set notation.

Answers

The solution for k in the equation 10 - 10|-8k + 4| = 10, expressed in set notation, is {1/2}.

1. Start with the equation: 10 - 10|-8k + 4| = 10.

2. Simplify the expression inside the absolute value brackets: -8k + 4.

3. Remove the absolute value brackets by considering two cases:

Case 1: -8k + 4 ≥ 0 (positive case):

-8k + 4 = -(-8k + 4) [Removing the absolute value]

-8k + 4 = 8k - 4 [Distributive property]

-8k - 8k = -4 + 4 [Group like terms]

-16k = 0 [Combine like terms]

k = 0 [Divide both sides by -16]

Case 2: -8k + 4 < 0 (negative case):

-8k + 4 = -(-8k + 4) [Removing the absolute value and changing the sign]

-8k + 4 = -8k + 4 [Simplifying the expression]

0 = 0 [True statement]

4. Combine the solutions from both cases: {0}.

5. Check if the solution satisfies the original equation:

For k = 0: 10 - 10|-8(0) + 4| = 10

10 - 10|4| = 10

10 - 10(4) = 10

10 - 40 = 10

-30 = 10 [False statement]

6. Since k = 0 does not satisfy the equation, it is not a valid solution.

7. Therefore, the final solution expressed in set notation is {1/2}.

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What is the radius of a circle that has a circumference of 68 cm

Answers

Step-by-step explanation:

The formula to calculate the circumference (C) of a circle is C = 2πr, where r represents the radius of the circle.

In this case, the given circumference is 68 cm. Plugging this value into the formula, we can solve for the radius (r):

68 = 2πr

To find the radius, we can divide both sides of the equation by 2π:

r = 68 / (2π)

Using an approximate value of π ≈ 3.14159, we can calculate the radius:

r ≈ 68 / (2 × 3.14159) ≈ 10.8419 cm

Therefore, the radius of the circle, which has a circumference of 68 cm, is approximately 10.8419 cm.

GiveN:-Circumference of Circle = 68 cmTo finD:-Radius of Circle = ??SolutioN:-➝ Circumference = 2 π r➝ 68 = 2 π r➝ 68 = 2 × (22/7) × r➝ 68 = (2 × 22/7) × r➝ 68 = (44/7) × r➝ (44/7) × r = 68➝ 44 × r = 68 × 7➝ 44 × r = 476➝ r = 476/44➝ r = 10.8 cm

Therefore, The Radius of the Circle is 10.8 cm.

Find the area of quadrilateral QUAD, whose vertices are:
Q (-4, 3), U (3, 6), 1 (6, 3), and D (1, -4).

Answers

The area of quadrilateral QUAD is 2.5 square units.

To find the area of quadrilateral QUAD with vertices Q (-4, 3), U (3, 6), 1 (6, 3), and D (1, -4), we can use the Shoelace formula (also known as Gauss's area formula or the surveyor's formula).

The Shoelace formula states that the area of a polygon with vertices (x1, y1), (x2, y2), ..., (xn, yn) can be calculated as:

[tex]Area = 1/2 * |(x1y2 + x2y3 + ... + xny1) - (x2y1 + x3y2 + ... + x1yn)|[/tex]

Using this formula, we can calculate the area of quadrilateral QUAD as follows:

Area = [tex]1/2 * |(-46 + 33 + 6*(-4) + 13) - (33 + 6*(-4) + 1*(-4) + (-4)*3)|[/tex]

Simplifying the expression, we get:

[tex]Area = 1/2 * |(-24 + 9 - 24 + 3) - (9 - 24 - 4 - 12)|Area = 1/2 * |(-36) - (-31)|Area = 1/2 * |-36 + 31|Area = 1/2 * |-5|Area = 1/2 * 5Area = 5/2[/tex]

The area of quadrilateral QUAD is 2.5 square units.

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The area of quadrilateral QUAD is 17.5 square units.

The area of quadrilateral QUAD, we can use the Shoelace Formula, also known as the Gauss's Area Formula.

The formula states that if the coordinates of the vertices of a polygon are given in order, then the area of the polygon can be calculated using the following formula:

Area = 1/2 × |(x1y2 + x2y3 + ... + xn-1yn + xny1) - (y1x2 + y2x3 + ... + yn-1xn + ynx1)|

Let's apply this formula to find the area of quadrilateral QUAD:

Q (-4, 3)

U (3, 6)

A (6, 3)

D (1, -4)

Area = 1/2 × |(-4 × 6 + 3 × 3 + 6 × (-4) + 3 × (-1)) - (3 × 3 + 6 × (-4) + (-4) × (-1) + (-1) × (-4))|

Area = 1/2 × |(-24 + 9 - 24 - 3) - (9 - 24 + 4 + 4)|

Area = 1/2 × |(-42) - (-7)|

Area = 1/2 × |-42 + 7|

Area = 1/2 × |-35|

Area = 1/2 × 35

Area = 17.5

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Please answer ASAP I will brainlist

Answers

Answer:

x = - 2 , x = 4

Step-by-step explanation:

the x- intercepts are the points on the x- axis where the graph crosses

the graph crosses the x - axis at - 2 and 4 , then

x- intercepts are x = - 2 , x = 4

CAPM Elements
Value
Risk-free rate (rRF
)
Market risk premium (RPM
)
Happy Corp. stock’s beta
Required rate of return on Happy Corp. stock
An analyst believes that inflation is going to increase by 2.0% over the next year, while the market risk premium will be unchanged. The analyst uses the Capital Asset Pricing Model (CAPM). The following graph plots the current SML.
Calculate Happy Corp.’s new required return. Then, on the graph, use the green points (rectangle symbols) to plot the new SML suggested by this analyst’s prediction.
Happy Corp.’s new required rate of return is .

Answers

The new required rate of return for Happy Corp. can be calculated using the Capital Asset Pricing Model (CAPM). The formula for CAPM is:

Required rate of return = Risk-free rate + Beta * Market risk premium

Since the analyst believes that the market risk premium will be unchanged, the only factor that will affect the new required return is the risk-free rate.

Given that the analyst predicts a 2.0% increase in inflation, the risk-free rate will also increase by that amount. Therefore, the new required rate of return for Happy Corp. will be the current risk-free rate plus the product of Happy Corp.'s beta and the market risk premium.

To plot the new Security Market Line (SML) on the graph, we would use the new required return calculated above and plot it against the corresponding beta values. The SML represents the relationship between risk (beta) and return (required rate of return).

By incorporating the new required return, we can determine the new expected returns for various levels of beta and create the updated SML.

It is important to note that without specific values provided for the risk-free rate, market risk premium, and Happy Corp.'s beta, it is not possible to calculate the exact new required return or plot the new SML accurately.

These values are crucial in determining the precise position of the SML on the graph.

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The graph below shows the solution to which system of inequalities?
O A. x< 1 and yz x
OB. ys 1 and y> x
O C. x≤ 1 and y> x
OD. y< 1 and yz x
6

Answers

The system of inequalities shown in this problem is defined as follows:

d) y < 1 and y ≥ x.

How to obtain the system of inequalities?

The line in the image has an intercept of zero and slope of 1, hence it is given as follows:

y = x.

Points above the solid line are plotted, hence the first condition is:

y ≥ x.

The upper bound, represented by the dashed horizontal line, is y = 1, hence the second condition is:

y < 1.

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How much fencing is required to enclose a circular garden whose radius is 21 m

Answers

Answer:182.12 meters of fencing required.

Step-by-step explanation:

Find the measure of the indicated angle.
20°
161°
61°
73°
H
G
F
73 ° E
195 °

Answers

Answer:

Step-by-step explanation:

You want the measure of the external angle formed by a tangent and secant that intercept arcs of 73° and 195° of a circle.

External angle

The measure of the angle at F is half the difference of intercepted arcs HE and EG.

(195° -73°)/2 = 122°/2 = 61°

The measure of angle F is 61°.

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a) Write a linear system to model the situation:
For the school play, the cost of one adult ticket is $6 and the cost of one student ticket is $4. Twice as many student tickets as adult tickets were sold. The total receipts were $2016.

b) Use substitution to solve the related problem:
How many of each type of ticket were sold?

Answers

Answer:

There were 126 student tickets sold and 252 adult ticket sold.

Step-by-step explanation:

Let x be the number of adult tickets sold

y be the number of students tickets sold

Twice as many student tickets as adult tickets were sold

x = 2y ---equation 1

6x + 4y = 2016 ---equation 2

Substitute equation 1 to equation 2

6(2y) + 4y = 2016

12y + 4y = 2016

16y = 2016

Divide both sides of the equation by 16

16y/16 = 2016/16

y = 126

Substitute y = 126 to equation 1

x = 2y

x = 2(126)

x = 252

determine the surface area and volume

Answers

The surface area and the volume of the rectangular prism are 280 and 300

How to determine the surface area and volume

From the question, we have the following parameters that can be used in our computation:

The rectangular prism

The surface area is caculated as

Surface area = 2 * (10 * 5 + 10 * 6 + 5 * 6)

Evaluate

Surface area = 280

For the volume, we have

Volume = 10 * 5 * 6

Evaluate

Volume = 300

Hence, the surface area and the volume are 280 and 300