What experimental evidence led to the development of the atomic model before the one before it?

Answer: Matter is made up of atoms that also come together to form molocules. Atoms contain Electrons (Negetive), nutronons (nuaetral), and protons (positive).

Answer:

time period of the wave

Answer:

The Frequency of a wave is the reciprocal of its Period

The Period of a wave is the reciprocal of its frequency

Explanation:

A P E X

Answer:

The answer is D & B

Explanation:

I took the quiz on this.  I hope this helps!

The two statements describe events that help drive tectonic plate movement are:

B. Convection currents cause hotter magma to rise and cooler magma to sink

D. Subduction plates cause cooling at convergent boundaries

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere.

Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest.

Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).

Tectonic plates, large slabs of rock that divide Earth’s crust, move constantly to reshape the Earth’s landscape. The system of ideas behind plate tectonics theory suggests that Earth's outer shell (lithosphere) is divided into several plates that glide over the Earth’s rocky inner layer above the soft core (mantle).

The plates act like a hard and rigid shell compared to Earth's mantle. The mantle sits between Earth's dense, very hot core and its thin outer layer, the crust.

At subduction zones, a convergent boundary occurs when two tectonic plates push together. When an ocean plate and a continental plate collide, the ocean plate slides under the continental plate, and bends downward.

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Answer:

7kg

Explanation:

Given parameters:

Force on the rock  = 28N

Acceleration  = 4m/s²

Unknown:

Mass of the rock  = ?

Solution:

According to newton's second law of motion;

           Force  = mass x acceleration

Insert the given parameters to find the mass;

         28  = mass x 4

             mass  = [tex]\frac{28}{4}[/tex]   = 7kg

Answer:

960N

Explanation:

Given parameters:

Mass of the motorcycle = 240kg

Acceleration of the motorcycle  = 4m/s²

Unknown:

Driving force of the motorcycle  = ?

Solution:

According to the Newton's second law of motion "the force on a body is the product of mass and acceleration".

    Force  = mass x acceleration

Insert the parameters and solve;

   Force  = 240 x 4  = 960N

Answer: A

Explanation: Your body gets pulled down, causing ur body to have more weight but not mass.

The weight of an object

Answer: B) weight

Got it right on E2020

Answer:

Power = 5.916 Kw

Explanation:

Given:

Current = 290 A

Volt = 20.4 V

Find:

Power

Computation:

Power = IV

Power = (290)(20.4)

Power = 5916 w

Power = 5.916 Kw

Answer:

Explanation:

we know that

F=ma

F=28 N

a=4 m/s²

m=F/a

m=28/4

m=7 kg

Answer:

1.6s

Explanation:

Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,

To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.

Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh

Where h = 5.2sin25

h = 2.2 m

P.E = 1.2 × 9.8 × 2.2

P.E = 25.84 j

At the bottom, K.E = P.E

1/2mv^2 = 25.84

Substitutes mass into the formula

1.2 × V^2 = 51.69

V^2 = 51.69/1.2

V^2 = 43.07

V = 6.56 m/s

Using the third equation of motion

V^2 = U^2 + 2as

Since the object started from rest,

U = 0

6.56^2 = 2 × a × 5.2

43.07 = 10.4a

a = 43.07/10.4

a = 4.14 m/s^2

Using the first equation of motion,

V = U + at

Where U = 0

6.56 = 4.14t

t = 6.56/4.14

t = 1.58s

Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s

Answer:

Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.

If the mass increases, it's harder to accelerate

Because force tends to rise with mass while mass tends to decrease with force, mass is sometimes referred to as the difficulty of accelerating an item. As a result, the greater mass's inverse effect balances out the larger force exerted on more massive objects.

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#SPJ2

Answer:

It's A v=2pi/T

Explanation:

I took the test and got it correct.

The correct formula that can be used to find the tangential speed of an orbiting object is : ( A ) v = 2π r /T

Tangential speed is the speed or velocity of an object moving in a circular path is calculated as 2π r/T where T = time it takes to complete one rotation and   2π r is angular velocity( w ).

Therefore from the options listed above the correct expression for the tangential speed is v =2π r /T

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Answer:

A.

Explanation:

I got it right ;)

Answer:

Chemical energy ---> Electrical energy ---> Light energy

Explanation:

Answer:

a)   y ’= 0.068 m ,  b)   m_lead = 2,599 kg

Explanation:

a) To solve this exercise, let's use Archimedes' law, which establishes that the pressure of the water is equal to the weight of the dislodged liquid.

Let's write the forces in the equilibrium condition

            B - W = 0

            B = W

Thrust is

            B = ρ_liquid g V_water

Body weight is

             W = m g

the definition of density

           ρ_body = m / V

we substitute

            W = ρ_body g V_body

The volume of the body is

          V_body = L³

The volume of water is

          V_agua = y L²

we substitute

           ρ_liquid g and L2 = rho_body g L3

           ρ_liquid y = ρ_body L

           y = L ρ_body /ρ_liquid

let's calculate

          y = 651/100 0.195

          y = 0.1269 m

this is the distance from the bottom of the cube, the distance from the top of the cube

          y ’= 0.195 -y

          y '= 0.195 - 0.1269

          y ’= 0.068 m

b) In this case the equilibrium equation is

          B - W_body - W_lead = 0

          B = W_body + W_lead

          ρ_liquido g V_liquido = ρ_body g V_body + m_lead g = 0

          ρ_liquid L3 = ρ_body L3 + m_lead = 0

          m_lead = L3 (ρ_liquid - ρ_body)

let's calculate

          m_lead = 0.195 3 (1000 - 651)

          m_lead = 2,599 kg

Answer:

A

Explanation:

Answer:

Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.

Explanation:

Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.

Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.  

The first direction is parallel to resultant force on the barge.

These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].

The second direction is perpendicular to the resultant force on the barge.

These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.

That gives a system of two equations and two unknowns:

The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:

[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].

Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].

In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].

The tension in each of the rope is 3,535.5 N

The given expression:

the resultant force, R = 5 kN = 5000 N

the angle in between the forces, α = 45

To find:

The tension in  each of the ropes  is calculated as follows;

The tension in vertical direction

[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]

The tension in horizontal direction;

[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]

Thus, the tension in each of the rope is 3,535.5 N

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answers 93 bar

The atmosphere of Venus is the layer of gases surrounding Venus. It is composed primarily of carbon dioxide and is much denser and hotter than that of Earth. The temperature at the surface is 740 K (467 °C, 872 °F), and the pressure is 93 bar (9.3 MPa), roughly the pressure found 900 m (3,000 ft) underwater on Earth.

bhai I know this answer if you mark as brain last you see my attachment

Answer:

79.6kg  

127.5N

Explanation:

Given parameters:

Weight of the person on earth = 780N

 Now, we are to find;

Mass on earth;

Mass on moon;

Weight on moon

Solution:

The mass on earth and on the moon are the same. Mass is the amount of matter in a substance.  

   Weight  = mass x acceleration due to gravity

     780  = mass x 9.8

           mass  = [tex]\frac{780}{9.8}[/tex]   = 79.6kg

Mass on earth and moon  = 79.6kg  

The acceleration due to gravity on the moon is 1.6m/s²

  Weight on moon = 79.6 x 1.6  = 127.5N

Answer:

20.4 meters

Explanation:

KE = 1/2 m v^2 = mgh = PE (convert all kinetic energy to potential energy, because at the highest point the coaster can climb, it will be stopped!)

=> h = (1/2 m v^2) / (mg) = v^2/(2*g) = (20 m/s)^2 / (2*9.8 m/s^2) = 20.4 m

The tallest height that the roller coaster can climb is 20 m.

A roller coaster is a device in which energy conversions from potential to kinetic energy takes place. Hence the roller coaster can easily be used to demonstrate the conversion of mechanical energy from one form to another.

Given that the velocity of the roller coaster at the bottom of the hill is  20.0 m/s, potential energy is converted into kinetic energy.

Hence;

mgh = 1/2mv^2

gh =1/2v^2

h = 1/2v^2/g

h = 0.5 × (20)^2/10

h = 20 m

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The ball is hit with an initial vertical velocity of

(147 m/s) sin(38º) ≈ 90.5 m/s

Recall that

v ² - u ² = 2 a ∆y

where u and v are initial and final velocities, respectively; a is acceleration; and ∆y is displacement.

Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude g = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (v = 0) and the displacement is equal to the maximum height, so

0² - (90.5 m/s)² = 2 (-g) ∆y

∆y = (90.5 m/s)² / (2g)

∆y ≈ 418 m

Answer:

Electron shell

Nucleus

Neutrons

Explanation:

An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.

Answer is 3,300N

Explanation

Answer:

Explanation:

The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:

[tex]s(t)=-4.9t^2+13[/tex] which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:

[tex]v(t)=-9.8t[/tex]. We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:

a(t) = -9.8

It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.

Answer:

Velocity and frequency

Explanation:

Answer:

  force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO

Explanation:

This complementation exercise refers to the magnetic force that the formula has

         F = q v x B

where the bold letters indicate vents and the x the vector product. The module of this product is

         F = qv B sin θ

where θ  is the angle between the speed and direction of the magnetic field.

It can be seen that for the force to be different from zero, the angle must not be parallel θ  = 0

        sin 0 = 0

the maximum value is obtained for an angle of θ  = 90º

       sin 90 = 1

Using these concepts we see that the missing words are.

  force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO_______