QUESTION 1
1.1 Define the term acceleration in words
Answer:
To be better at something
Explanation:
I have Accelerated at cooking
Answer:
Acceleration means to speed up
Explanation:
1. Use the picture on page 3 of the lesson in Connexus to help you label each part of the wave below:
a.
b.
c.
d.
An 95 Watt TV is plugged into a 115 volt circuit.
The TV operates for 120 minutes. If the cost of energy is
8¢ per kW-hr, how much does it cost to run the TV
for 120 minutes?
120 min = 2 hours
95 x 2 : 1000 =0.19 kwh
8¢ x 0.19 kwh = 1.52¢
The cost of running the 95 W TV for 120 minutes if charged at 8 ¢ per kWhr is 1.52 ¢
How to determine the energyPower ( P) = 95 W = 95 / 1000 = 0.095 KWTime (t) = 120 mins = 120 / 60 = 2 hrEnergy (E) =?E = Pt
E = 0.095 × 2
E = 0.19 KWhr
How to determine the cost of operationEnergy (E) = 0.19 KWhrCost per KWhr = 8 ¢ Cost =?Cost = Energy × Cost per KWhr
Cost = 0.19 × 8
Cost = 1.52 ¢
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3. Classify the different types of spectra by how they are created. Physical science
Answer:
Most light sources can be classified into three main types: continuous, absorption, and emission. A hot, opaque object, like the filament in an incandescent light bulb, emits a continuous spectrum, having light of all wavelengths. A hot, dense gas is another example of an object that emits a continuous spectrum.
Explanation:
Write down at least 3 equations as you solve them
Answer:
3+7= 7x3= 21➗7=
Explanation:
3+7= 10 7 8 9 10
7x3= 21 7 14 21
21➗7=3 21 14 7
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The mass of 1 dozen dimes is 27.22 g. the numerical value of the mass of 5 dozen dimes can be obtained by
Answer:
by obtaining the total mass of the dimes present:
d = 27.22 g / dozen the density of dimes
M = n * d = 5 dozen * 27.22 g / dozen = 126.1 g
Two rocks, a and b, are thrown horizontally from the top of a cliff. rock a has an initial speed of 10 meters per second and rock b has an initial speed of 20 meters per second. how would you describe the time it takes for the rocks to reach the ground and the horizontal distance they travel? both rocks hit the ground at the same time and at the same distance from the base of the cliff. both rocks hit the ground at the same time, but rock b lands twice as far as rock a from the base of the cliff. both rocks hit the ground at the same time, but rock a lands twice as far as rock b from the base of the cliff. rock b hits the ground before rock a, and rock b lands twice as far as rock a from the base of the cliff.
Both rocks hit the ground at the same time and at the same distance from the base of the cliff. Option A is correct.
What is speed ?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its SI unit is m/sec.
If the resistance is ignored, things falling near the Earth's surface have the same estimated acceleration due to gravity of 9.8 meters per second.
As a result, the objects' acceleration is the same, and their velocity is growing at a consistent pace.
So that both rocks hit the ground at the same time and at the same distance from the base of the cliff.
Hence, option A is correct.
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A car moving with a velocity of 30 ms-1 is stopped by the application of brakes which imparts a radiation of 6 ms-2 to the car.
1. how long does it take for the car to come to stop
2. how far does the car travel during the time the brakes are applied
somebody please help me solve this and do explain..
[tex]\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}} [/tex]
1) 5 seconds
2) 75 meters
Explanation:
Refer to the attachment
Help me pleaseee
a battery-operated toy draws 0.2 a of current from a battery pack. if the total resistance
of the boy is 362, what is the voltage of the battery pack?
the earth had a mass of 6,000,000,000,000,000,000,000,000 kg. and a radius of 6,371,000 m, what will be the gravitational force experienced by a puppy with a mass of 4.6 kg playing on the earth sur face
Answer:
Mass of Earth (M1) = 6×10^24 kg
Mass of Puppy (M2) = 3.6 kg
Radius (R) = 6371000 m
Universal Gravitational Constant (G) = 6.67 × 10^11
Now,
Gravitational Force = G×M1×M2 / R^2
GF = 6.67 × 10^11 × 6 × 10^24 × 3.6 / (6371000)^2
GF = 144.072 × 10^35 / 40,589,641,000,000
GF = 3549.477 × 10^20
if it takes you 10 n of force to push your bike 30 m how much work did you do>
Answer:
300 J
Explanation:
GIVEN:
Force (F) = 10 N
Displacement (s) = 30 m
or displacement (d) = 30m
Work done (W) = ?
Therefore,
W = F×s
or W= F × d
= 10×30
= 300 J
Hope it helps
7,293 ÷ 8 what is this
Answer: 911.625
Explanation:
Answer:
911.625 is the answer of your question
Amber likes riding her bicycle through her neighborhood where there are lots of hills. she rides down a very steep hill, and then goes up a small hill. she doesn't need to pedal as her bicycle carries her up the small hill. how do amber's kinetic energy and potential energy change as she goes uphill
Answer:
Her kinetic energy decreases and her potential energy increases.
Explanation:
I need help with this ASAP!!
Answer:
C
Explanation:
High pitch due to high frequency b/c of doppler effect. The sound waves in front of the vehicle are being squashed together by the moving ambulance. This causes more vibrations to reach your ear per second.
How far did an object travel if they rode a bike at 15m/s for 5 seconds?
A. 75m
B. 3 m/s
C.20 m
Answer:
A) 75m
Explanation:
distance = speed x time taken
Here given:
speed: 15 m/s
time: 5 second
So, distance covered:
15 x 5
75 m
Distance
Speed×Time15(5)75mA Ball A and a Ball B collide elastically. The initial momentum of Ball A is 14.0kgm/s and the initial momentum of Ball B is -9.00kgm/s. Ball A has a mass of 2.00kg and is traveling at -5.00 m/s after the collision. What is the velocity of ball B if it has a mass of 3.00kg
The total momentum before collision is
14.0 kg•m/s + (-9.00 kg•m/s) = 5.00 kg•m/s
If v is the velocity of ball B after colliding with ball A, the total momentum after collision is
(2.00 kg) (-5.00 m/s) + (3.00 kg) v
Momentum is conserved, so these quantities are equal. Solve for v :
5.00 kg•m/s = (2.00 kg) (-5.0 m/s) + (3.00 kg) v
5.00 kg•m/s = -10.0 kg•m/s + (3.00 kg) v
15.0 kg•m/s = (3.00 kg) v
v = (15.0 kg•m/s) / (3.00 kg) = 5.00 m/s
Can someone please answer this, ill give you brainliest Would be very appreciated.
Answer:
O ice
Explanation:
Albedo refers to the proportion of the incident light that is reflected by a surface to the amount of incoming light.
Here, only ice will reflect even some amount of light. Pavement and dirt do not reflect at all, meanwhile, where glass reflects slightly.
A company is creating an advertisement for colored contact lenses. In the ad, the company wants to include the
phrase "Each contact lens is like a second
Which part of the eye would be most accurate in completing the phrase?
retina
sclera
iris
pupil
Answer:
option C) the iris
Explanation:
2023
lookup the composition for air. what is the percentage of nitrogen and oxygen present in the air we breathe
78 percent nitrogen and 21 percent oxygen
What is one way that light waves differ from sound waves?(1 point)
Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground. what is the approximate horizontal component of the initial velocity? 0.64 m/s 0.77 m/s 10.3 m/s 12.3 m/s
The horizontal component of the velocity with which Ronnie kicks a playground ball is 12.3 m/s.
Horizontal component of the velocity
The horizontal component of the velocity with which Ronnie kicks a playground ball is calculated as follows;
Vx = Vcosθ
where;
V is the initial velocityθ is the angle of projectionVx = 16 x cos(40)
Vx = 12.3 m/s
Thus, the horizontal component of the velocity with which Ronnie kicks a playground ball is 12.3 m/s.
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Answer:
D) 12.3
Explanation:
took the test
A motorcycle starts 20m west of a reference point. It moves at a constant velocity for 5s, reaching a position of 10m east of the reference point.
What is the motorcycle’s average velocity?
The motorcycle's average velocity will be 6 m/sec. The ratio of the overall distance traveled to the total time taken by the body is the average velocity.
What is average velocity?The average velocity is the ratio of the total distance traveled to the total time taken by the body. Its unit is m/sec.
Total distance travelled by the motorcycle;
d=20 m+10 m
d=30 m
The average velocity is found as;
[tex]\rm v_{avg}=\frac{d}{t} \\\\ \rm v_{avg}=\frac{30}{5} \\\\ v_{avg}= 6 \ m /sec[/tex]
Hence,the motorcycle’s average velocity will be 6 m/sec.
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Please help me guys please help please
Answer:
C = frequency × wavelength, where C is the speed of the photons which is the speed of light ~3×10^8
frequency = C/wavelength
f = 3×10^8/400×10^-9m
f = 3/4 × 10^15Hz
f = 0.75×10^15Hz
f = 7.5×10^14Hz
Why do you think there are so many more autotrophs than consumers on Earth?
Helppp
There are many Autotrophs than consumers because : Autotrophs are the bases of any food chain/web
Function of AutotrophsAutotrophs capture the energy required for every food chain or web from which sustains other organisms in the food chain form sunlight and chemicals. Also there is always more biomass present in the lower levels of the trophic system as biomass decreases as we move up the food chain.
Since autotrophs are producers, for a healthy food chain there would be more autotrophs than consumers.
Hence we can conclude that There are many Autotrophs than consumers because : Autotrophs are the bases of any food chain/web
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what temperature change is required to change the length of a 5.5-m steel beam by 0.0012m?
Answer:
Length of steel = 5.5 m
Increase in length = 0.0012 m
α of steel = 12 x 10-6/K
To find:
Temperature change needed ?
Calculation:
Let the required temperature change be ∆T. (in the photo)
So, temperature change of 18.1 Kelvin is required
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The diagram shows different body planes.
X: frontal; Y: sagittal; Z: transverse
X: sagittal; Y: frontal; Z: transverse
X: transverse; Y: sagittal; Z: frontal
X: frontal; Y: transverse; Z: sagittal
The diagram shows different body planes. X shows sagittal,Y shows frontal and Z shows transverse axis. Option B is correct.
What is frame of reference?A frame of reference is a mathematical and physical coordinate system whose origin, direction, and scale are given by a collection of reference points.
1. Frontal Plane divides the body into front and posterior sections.
2. The Sagittal Plane divides the body into left and right halves.
3. The transverse plane divides the body into superior and inferior halves.
The diagram shows different body planes. X shows sagittal,Y shows frontal and Z shows transverse axis.
Hence,option B is correct.
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One evening, a student tells her sister that the Sun only appears brighter than other stars because the Sun and stars are different distances from Earth. Her sister disagrees, so the student supports her argument by asking her sister to observe the brightness of streetlights throughout their neighborhood. Which observation would support the student’s argument?
Comparing and analyzing the brightness of near and farther streetlight would support the student’s argument.
Which observation would support the student’s argument?The brightness of nearer streetlight is more as compared to the brightness of the farther light because brightness decreases with the increase in distance.
So we can conclude that comparing and analyzing the brightness of near and farther streetlight would support the student’s argument.
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how can we change the frequency of the wave
Answer:
.Also we can change the frequency by decreasing wavelength , or increasing velocity
Explanation:
A newly developed military robot has a sense of self-preservation and can also make decisions for itself in warfare. what form of ai is this?
the robot exhibits signs of
ai, which is a sub-form of
ai
The type of artificial intelligence used in the area of military operations is deep learning artificial intelligience.
What is artificial intelligence?
The term artificial intelligence has to do with the simulation of the decision making ability of the brain in machines.
This has also been experimented in the area of military operations. This type of artificial intelligence is called deep learning artificial intelligience.
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calculate the depth of water of density 1020 kg/m³ where the pressure is 3.0 x 10⁶ Pa
Answer:
Here is your answer
Explanation:
Given:
Given:Density of sea water (d) = 1020 kgm^{3}3
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g\therefore∴ h = P/dg
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g\therefore∴ h = P/dg\begin{gathered} = \frac{10200000}{1020 \times 10} \\ \\ = 1000 \: m \\ \\ = 1 \: km.\end{gathered}=1020×1010200000=1000m=1km.
Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g\therefore∴ h = P/dg\begin{gathered} = \frac{10200000}{1020 \times 10} \\ \\ = 1000 \: m \\ \\ = 1 \: km.\end{gathered}=1020×1010200000=1000m=1km.Hence, depth of sea is 1 km