What are the solutions to the following system of equations?
y = 3x - 7
5x - y = 11
A(2, -1)
B (3, 4)
C (-3, 3)
D (-6, 1)

Answer: No solutions

Step-by-step explanation: If you solve the problem all the way, you get 0 = 4 which is not valid so there is simply no solution

The given equation 3(2x−1)+5=6(x+1) has no solution. Option B is correct.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Given equation ⇒

⇒= 3(2x−1)+5=6(x+1)

Simplify the above expression,
⇒ 6x - 3 + 5 = 6x + 1
⇒    2 ≠ 1

Thus, the given equation has no solution.

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Answer:

(A) B h(x)= -2x-5.5

(B) The y intercept is (0,-5.5)

(C) The rate of change is -2

(D) The x intercept is (-2.75,0)

Answer:

B

Step-by-step explanation:

A will equal the sine inverse (arc sine or sin^-1 ) of 0.3571. Using a calculator, sin^-1(0.3751) = 22.03 degrees (B)

To solve the equation y - 4.5 = 12.2 we have to add 4.5 on both sides of the equation.

Two or more expressions with an Equal sign is called as Equation.

The given equation is y - 4.5 = 12.2

y minus four point five equal to twelve point two.

In the equation y is the variable and minus is the operator in the equation.

To solve the equation we have to isolate the variable y.

To isolate the variable y we have to add 4.5 on both sides of the equation

y-4.5+4.5=12.2+4.5

y=16.7

Hence, to solve the equation y - 4.5 = 12.2 we have to add 4.5 on both sides of the equation.

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The approximate area under the curve from x = 2 to x = 5, using a left endpoint approximation with 3 subdivisions, is 13.5 square units.

To approximate the area under the curve, we divide the interval from x = 2 to x = 5 into three equal subdivisions, each with a width of (5 - 2) / 3 = 1. The left endpoint approximation involves using the leftmost point of each subdivision to approximate the height of the curve.

In this case, we evaluate the function at x = 2, x = 3, and x = 4, and use these values as the heights of the rectangles. The width of each rectangle is 1, so the areas of the rectangles are calculated as follows:

Rectangle 1: Height = f(2) = 2, Area = 1 * 2 = 2 square units.

Rectangle 2: Height = f(3) = 4, Area = 1 * 4 = 4 square units.

Rectangle 3: Height = f(4) = 7, Area = 1 * 7 = 7 square units.

Finally, we add up the areas of the three rectangles to obtain the approximate area under the curve: 2 + 4 + 7 = 13 square units. Therefore, the approximate area under the curve from x = 2 to x = 5 using a left endpoint approximation with 3 subdivisions is 13.5 square units.

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Answer:

34.55556%

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

[tex]2x^{3} +10[/tex]

Step-by-step explanation:

[tex]x*2x*x+10=2x^{3} +10[/tex]

Answer:

A

Step-by-step explanation:

the y intercept (where x is 0) should be -3 because of y<3x-3

Answer:

72

Step-by-step explanation:

Multiply all the numbers, and you get the answer

(a) The probability that X is less than 3, P(X < 3), is 0.

(b) The mean of X, denoted as E(X), is 71/24, which is approximately 2.9583 when rounded off to four decimal places.

(c) Given Y = e^X, the mean of Y, denoted as E(Y), is approximately 15.75 when rounded off to two decimal places.

(a) It is required to compute P(X<3). Since the range for which f(x) is not equal to 0, is the interval from 2 to 4 for f(x), the probability that X is less than 3 is 0.

Similarly, for X > 4, P(X > 4) = 0.

P(2 ≤ X ≤ 4) = ∫f(x)dx from 2 to 4= ∫ (x/24 - 7/3) dx from 2 to 4= [x^2/(2 × 24) - 7x/3] from 2 to 4= 1/4 - 28/3 + 8/(2 × 24) + 14/3= 71/24= 2.9583(rounded off to four decimal places)

(b) The mean of X can be computed as follows:

E(X) = ∫xf(x)dx from -∞ to ∞= ∫ (x/24 - 7/3) dx from 2 to 4= [x^2/(2 × 24) - 7x/3] from 2 to 4= 1/4 - 28/3 + 8/(2 × 24) + 14/3= 71/24= 2.9583(rounded off to four decimal places)

(c) Y = e^X

The mean of Y can be computed as follows:

E(Y) = E(e^X)= ∫ e^x f(x) dx from -∞ to ∞= ∫ e^x (x/24 - 7/3) dx from 2 to 4= [e^x (x - 31)/(24)] from 2 to 4= (e^4/6 - 31e^4/24 - e^2/6 + 31e^2/24) ≈ 15.75(rounded off to two decimal places).

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Using the standard deviation, mean, and z-score, the 7% of items with the shortest lifespan will last less than approximately 1.59 years.

To find the number of years that the 7% of items with the shortest lifespan will last, we need to determine the z-score corresponding to the 7th percentile of the normal distribution.

Step 1: Convert the given percentile to a z-score using the standard normal distribution table or a statistical calculator. The 7th percentile corresponds to a z-score of approximately -1.405.

Step 2: Use the formula for z-score to find the corresponding value in terms of years:

x = μ + z * σ

where x is the value we are looking for, μ is the mean, z is the z-score, and σ is the standard deviation.

Plugging in the values:

x = 4.4 + (-1.405) * 1.2

x = 1.59 years

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Answer:

w = [tex]\sqrt{147}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

w² + 7² = 14²

w² + 49 = 196 ( subtract 49 from both sides )

w² = 147 ( take the square root of both sides )

w = [tex]\sqrt{147}[/tex]

Answer:

12 mph

Step-by-step explanation:

Given that:

Total distance traveled = 78 miles

Time taken, t = 6 hours

Average speed for first 30 miles = 15 mph

Time taken = distance / speed

Time taken = 30 / 15

Time taken = 2 hours

Average speed for last 48 miles = x

Time taken to travel last 48 miles = (6 - 2) = 4 hours

Average speed for last 48 miles :

Distance traveled / time taken

48 miles / 4 hours

= 12 mph

YOUR ANSWER IS ANGLE BAC

General solution of the second order differential equation:

-6Ae^(-3x) / x + 9Bxe^(-3x) * ln(x) - Be^(-3x) / x^2

To find the general solution of the given second-order differential equation: y" + 6y' + 9y = e^(-3x) * ln(x)

We will use the method of undetermined coefficients to find a particular solution and then combine it with the complementary solution to obtain the general solution.

Step 1: Finding the particular solution

Since e^(-3x) * ln(x) is a product of exponential and logarithmic functions, we assume a particular solution in the form of:

yp = (A + Bx) * e^(-3x) * ln(x)

where A and B are constants to be determined.

Step 2: Find the first and second derivatives of yp.

yp' = (Ae^(-3x) * ln(x) - 3(A + Bx)e^(-3x) * ln(x) + (A + Bx) * e^(-3x) / x

yp" = (Ae^(-3x) * ln(x) - 3(A + Bx)e^(-3x) * ln(x) + (A + Bx) * e^(-3x) / x)'

yp" = (-9(A + Bx)e^(-3x) * ln(x) + 3(A + Bx)e^(-3x) * ln(x) - 3(A + Bx)e^(-3x) / x + (A + Bx) * (-e^(-3x) / x^2 + e^(-3x) / x))

Simplifying, we have:

yp" = -9(A + Bx)e^(-3x) * ln(x) - 6(A + Bx)e^(-3x) / x + (A + Bx) * (-e^(-3x) / x^2 + e^(-3x) / x)

Step 3: Substitute yp, yp', and yp" into the original differential equation to find the values of A and B.

yp" + 6yp' + 9yp = e^(-3x) * ln(x)

Substituting the expressions we found for yp and its derivatives:

(-9(A + Bx)e^(-3x) * ln(x) - 6(A + Bx)e^(-3x) / x + (A + Bx) * (-e^(-3x) / x^2 + e^(-3x) / x))

6((Ae^(-3x) * ln(x) - 3(A + Bx)e^(-3x) * ln(x) + (A + Bx) * e^(-3x) / x))

9((A + Bx) * e^(-3x) * ln(x))

= e^(-3x) * ln(x)

Expanding and simplifying, we get:

-9Ae^(-3x) * ln(x) + 3Bxe^(-3x) * ln(x) - 6Ae^(-3x) / x + 6Bxe^(-3x) / x + Ae^(-3x) / x - Be^(-3x) / x^2 + Be^(-3x) / x + 9Ae^(-3x) * ln(x) + 9Bxe^(-3x) * ln(x)

= e^(-3x) * ln(x)

Combining like terms, we have:

-6Ae^(-3x) / x + 9Bxe^(-3x) * ln(x) - Be^(-3x) / x^2

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Answer:

I believe the answer to be 5 and 4

The exterior angles of the given triangle are angles 4 and 5

A triangle is a polygon with three sides, angles and vertices.

Given that, a triangle, with angles, 1, 2, 3, 4, 5 we need to find the exterior angles,

An exterior angle of a polygon is the angle that lies outsides of the polygon,

Here, we can see, that only two angles 4 and 5 lies outsides of the triangles

Therefore, the exterior angles are 4 and 5

Hence, the exterior angles of the given triangle are angles 4 and 5

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Answer:

128 fluid ounces

Step-by-step explanation:

We were told that:

During the experiment was poured from a beaker after the water was poured 1/4 gallon of water was left in the beaker

Hence, this means that the total gallon of water in the beaker is 1 gallon

Convert 1 gallon to fluid ounces

1 gallon =128 fluid ounces

Therefore, the total number of fluid ounces of water in the beaker before the water was poured by the 12 students is 128 fluid ounces.

Answer:

3125

Step-by-step explanation:

first, find the unit rate.

2500/4=625

625= amount of oxygen needed to supply a family of one(or just one single person)

625*5=3125

***with these problems, always try to find the unit rate first which is the amount of something per one unit. it'll be helpful to solve the questions following it.

Answer:

c

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

b-4x

Plug in 4 as b and -2 as x

= (4)-4(-2)

Multiply 4 and 2

= 4-(-8)

Two negatives make a positive

= 4+8

= 12

I hope this helps!

Answer:

Step-by-step explanation:

Answer:

52 cubic units

Step-by-step explanation:

got it right on edg

Answer:

37h 900

Step-by-step explanation:

Answer:

huh?

Step-by-step explanation:

did you forget a pic?

Answer:

whatdo u need help with love?

Step-by-step explanation:

The solution to the differential equation (D^2 + 4)y = 6 sin(2x) + 3x^2 is y = (3/4)x^2 + A sin(2x) + B cos(2x).

To solve the given differential equation (D^2 + 4)y = 6 sin(2x) + 3x^2, where D represents the derivative operator, we can use the method of undetermined coefficients.

y = y_h + y_p

y = A sin(2x) + B cos(2x) + (3/4)x^2

Here, A and B are arbitrary constants that can be determined by applying initial or boundary conditions, if given.

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In simple linear regression, we desire the residuals to have certain characteristics. Specifically, we want the residuals to be:

Random: The residuals should not follow a specific pattern or exhibit any systematic behavior. Random residuals indicate that the model captures the underlying relationship between the variables adequately.

1. Normally distributed: The residuals should follow a normal distribution. This assumption allows for the use of statistical inference and hypothesis testing techniques based on normality.

2. Zero mean: The average of the residuals should be close to zero. A zero mean indicates that, on average, the model is not biased and accurately represents the data.

3. Homoscedastic: The residuals should have constant variance across all levels of the independent variable. Homoscedasticity ensures that the model's performance is consistent throughout the range of values.

By satisfying these criteria, we can ensure that the model is valid, reliable, and provides accurate predictions.

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