Answer:
Domain: x < 5
Range: all numbers, -∞, ∞
This is because the problem will be able to be solved with multiple solutions as long as there are no specific values assigned to x. The problem will have a solution from a range of negative infinity to infinity, meaning every number or solution you can think of.
Factor the expressions below using the greatest
common factor:
a. 4m³ - 32m
b. 63x¹2 - 35x6
C. -28v² - 8v - 36
Answer:
a=4m
b=63x¹2 - 35x6 maybe you formatted/typed this wrong, but this is impossible..?
c=4
Cosmo’s family has a pool like this.
A pool is a cylinder, height 120 centimetre and width 5.4 metre.
What is the volume of the pool?
How many litres of water will the pool hold?
How long will it take to fill the pool at a rate of 50 L/min?
a. The volume of the pool is 27.483 m³
b. The number of litres of water the pool will hold is 27483 L
c. The pool will fill at a rate of 50 L/min in 549.7 min
The pool is a cylinder, so, we need to find its volume
a. What is volume of the pool?Since the pool is a cylinder, its volume is, V = πd²h/4 where
d = width of pool = 5.4 m and h = height of pool = 120 cm = 1.20 mSo, V = πd²h/4
= π(5.4 m)² × 1.20 m/4
= π × 29.16 m² × 1.20 m/4
= 34.992π m³/4
= 8.748π m³
= 27.483 m³
So, the volume of the pool is 27.483 m³
b. How many litres of water will the pool hold?Since the volume of the pool, V = 27.483 m³ and 1000 Litres = 1 m³
So, the volume of the pool in litres is V = 27.483 m³
= 27.483 × 1 m³
= 27.483 × 1 000 L
= 27483 L
So, the number of litres of water the pool will hold is 27483 L
c. How long will it take to fill the pool at a rate of 50 L/min?Since the volume of the pool is V = 27483 L, the time it will take the pool to fill at a rate of 50 L/min is given by t = Volume/rate
= 27483 L/50 L/min
= 549.66 min
≅ 549.7 min
So, how long will it take to fill the pool at a rate of 50 L/min is 549.7 min
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Which of the following inequalities is graphed on the coordinate plane?
A. y > 30 +5
B. y ≤ 3r +5
C. y < 3x + 5
D. > 31 +5
Based on the scenario above, the inequalities that can be graphed on the coordinate plane is y < 3x + 5.
What is the inequalities about?In graphing inequalities, one can graph inequality on the coordinate plane.
Note that the solutions for a linear inequality can be seen in the area of the coordinate plane. The boundary line used are > ,<, ≥ and ≤.
Note also that the inequalities graphed on the coordinate plane known to be y < 3x + 5 is shown in the image attached. When you look at option A, B and D, you will see that they are incomplete and missing some values but option C gave the correct example of an inequalities.
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Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question. There are 15 questions on the test and the students have been given 55 minutes to complete it
Let
x------> the number of multiple choice question
y------> the number of free response question
we know that
-----> equation A
-----> equation B
Substitute equation B in equation A
Find the value of x
therefore
the answer is
the number of multiple choice question are
the number of free response question are
11+7+(75÷(16+9))+4x(20÷10)+(28-27)
by the way the x in 4x is not a variable it means multiplication
Answer:
30
Step-by-step explanation:
You have a 3-gallon and a 5-gallon jug that you can fill from a fountain of water. The problem is to fill one of the jugs with exactly 4 gallons of water. How do you do it?
Answer:
See below
Step-by-step explanation:
Fill the 5 and pour into the 3 ....this will leave 2 gal in the 5 bucket
empty the 3 bucket and put that 2 gallon in to it.....
then fill the 5 bucket again......pour 1 gallon into the 3 gallon bucket to fill it....then there will be 4 gallons left in the 5 bucket
Solve the equation. 5/x+3 + 4/x+2 = 2
Please explain this step by step
Answer:
Step-by-step explanation: If I have to Write In Slope- Intercept form, This Is how I explain it.
Since x = −3 is a vertical line, there is no y-intercept and the slope is undefined.
Slope: Undefined
y-intercept: No y-intercept
8. Jaime has 20 min to get to her after- school job. Despite her best efforts, she is
frequently late and has recorded her travel time (in minutes) as {18, 20, 22, 27, 16, 23, 25,
26, 19, 28). Her boss has told her that unless she shows more consistency, she will lose her
job. Over the next two weeks, Jaime records her travel time: (22, 20, 22, 24, 24, 23, 25, 21,
19, 21). Should Jaime lose her job? Use statistics (mean and standard deviation) to justify
your answer. [8 marks]
The calculation of the mean shows that Jamie should not lose her job as she was faster after the talk from the boss.
How to calculate the mean?The mean of the travel time in the first scenario will be:
= (18, 20, 22, 27, 16, 23, 25,26, 19, 28)/10
= 224/10
= 22.4
She she shows consistency, the mean will be:
= (22, 20, 22, 24, 24, 23, 25, 21, 19, 21)/10
= 221/10
= 22.1
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Expand and simplify
(5x + 2)(x + 2)
Answer:
5x²+12x+4
Step-by-step explanation:
5x²+10x+2x+4
5x²+12x+4
Answer:
[tex]5x^{2}+12x+4[/tex]
Step-by-step explanation:
Use the FOIL method to expand.
5x*x+
2*x+
5x*2+
2*2
which is
5x^2+2x+10x+2
combining the two x s we get
5x^2+12x+4
If α and β are the zeros of the quadratic polynomial f(x) = 6x²+x-2, then the value of
1. α²+β²
2. 1/α+1/β
Can Someone Answer This Quick Thank You<3
Answer:
Given function:
[tex]f(x)=6x^2+x-2[/tex]
To find the zeros of the function, set the function to zero and factor:
[tex]\implies 6x^2+x-2=0[/tex]
[tex]\implies 6x^2+4x-3x-2=0[/tex]
[tex]\implies 2x(3x+2)-1(3x+2)=0[/tex]
[tex]\implies (2x-1)(3x+2)=0[/tex]
Therefore, the zeros are:
[tex]\implies (2x-1)=0 \implies x=\dfrac{1}{2}[/tex]
[tex]\implies (3x+2)=0 \implies x=-\dfrac{2}{3}[/tex]
If α and β are the zeros of the function:
[tex]\textsf{Let } \alpha=\dfrac{1}{2}[/tex][tex]\textsf{Let } \beta=-\dfrac{2}{3}[/tex]Question 1
[tex]\begin{aligned}\implies \alpha^2+\beta^2 & =\left(\dfrac{1}{2}\right)^2+\left(-\dfrac{2}{3}\right)^2\\\\& = \dfrac{1}{4}+\dfrac{4}{9}\\\\& = \dfrac{9}{36}+\dfrac{16}{36}\\\\& = \dfrac{25}{36}\end{aligned}[/tex]
Question 2
[tex]\begin{aligned}\implies \dfrac{1}{\alpha}+\dfrac{1}{\beta} & = \dfrac{1}{\frac{1}{2}}+\dfrac{1}{-\frac{2}{3}}\\\\& = 1 \times \dfrac{2}{1}+1 \times -\dfrac{3}{2}\\\\& = 2 - \dfrac{3}{2}\\\\& = \dfrac{1}{2}\end{aligned}[/tex]
Answer:
[tex]1) ~\alpha^2+\beta^2 = \dfrac{25}{36}\\\\\\2)~\dfrac 1 {\alpha} + \dfrac 1{\beta} = \dfrac 12[/tex]
Step-by-step explanation:
[tex]\text{Given that,}\\\\f(x) = 6x^2 +x -2~ \text{and the roots are}~ \alpha, \beta\\\\\text{Now,}\\\\\alpha + \beta = -\dfrac{b}{a} = -\dfrac{1}{6}~~~~~;[\text{Compare with the standard form}~ ax^2 +b x + c = 0]\\\\\alpha \beta = \dfrac ca = -\dfrac2 6 = - \dfrac 13\\\\\\\textbf{1)}\\\\\alpha^2 +\beta^2\\\\\\=\left(\alpha +\beta \right)^2 - 2 \alpha \beta \\\\\\=\left( -\dfrac 16 \right)^2 -2 \left(- \dfrac 13 \right)\\\\\\=\dfrac{1}{36}+\dfrac 23\\\\\\=\dfrac{25}{36}[/tex]
[tex]\textbf{2)}\\\\\dfrac 1{\alpha} + \dfrac 1{\beta} \\\\\\=\dfrac{\alpha + \beta}{\alpha \beta }\\\\\\=\dfrac{-\tfrac16}{-\tfrac 13}\\\\\\=\dfrac{1}{6} \times 3\\\\\\=\dfrac{1}{2}[/tex]
Independent Assessment 2
Directions: Use the data in the line graph below to answer the following questions.
Pieces of Bibingka Sold Per Day
60
50
40
30
20
10
0
Monday
Tuesday Wednesday Thursday
1. How many bibingka were sold on
Tuesday and Wednesday?
2. What days have the same number of
bibingka sold?
3 How many more bibingka were sold
on Monday than on Wednesday?
4. What is the average pieces of
bibingka sold for the first three days?
5. In your opinion, what other kind of rice
cake do you prefer to sell? Give your
reason
Pieces of Bibingka Sold
Friday
0000
Answer
Answer
Answer
Answer
Answer
Answer:
are you from Philippines?
Step-by-step explanation:
because I want to know gehe
this is a lot more clear
Please answer this question, i request
If cot θ = 7/8 , evaluate :-
(1 + sin θ)(1 – sin θ)/(1 + cos θ)(1 - cos θ)
[tex]{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}[/tex]
[tex] \star \: \tt \cot \theta = \dfrac{7}{8} [/tex]
[tex] {\large{\textsf{\textbf{\underline{\underline{To \: Evaluate :}}}}}}[/tex]
[tex] \star \: \tt \dfrac{(1 + \sin \theta)(1 - \sin \theta) }{(1 + \cos \theta) (1 - \cos \theta) }[/tex]
[tex]{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}[/tex]
Consider a [tex]\triangle[/tex] ABC right angled at C and [tex]\sf \angle \: B = \theta [/tex]
Then,
‣ Base [B] = BC
‣ Perpendicular [P] = AC
‣ Hypotenuse [H] = AB
[tex] \therefore \tt \cot \theta = \dfrac{Base}{ Perpendicular} = \dfrac{BC}{AC} = \dfrac{7}{8}[/tex]
Let,
Base = 7k and Perpendicular = 8k, where k is any positive integer
In [tex]\triangle[/tex] ABC, H² = B² + P² by Pythagoras theorem
[tex] \longrightarrow \tt {AB}^{2} = {BC}^{2} + {AC}^{2} [/tex]
[tex] \longrightarrow \tt {AB}^{2} = {(7k)}^{2} + {(8k)}^{2} [/tex]
[tex]\longrightarrow \tt {AB}^{2} = 49{k}^{2} + 64{k}^{2} [/tex]
[tex]\longrightarrow \tt {AB}^{2} = 113{k}^{2} [/tex]
[tex]\longrightarrow \tt AB = \sqrt{113 {k}^{2} } [/tex]
[tex]\longrightarrow \tt AB = \red{ \sqrt{113} \: k}[/tex]
Calculating Sin [tex]\sf \theta [/tex]
[tex] \longrightarrow \tt \sin \theta = \dfrac{Perpendicular}{Hypotenuse}[/tex]
[tex] \longrightarrow \tt \sin \theta = \dfrac{AC}{AB}[/tex]
[tex]\longrightarrow \tt \sin \theta = \dfrac{8 \cancel{k}}{ \sqrt{113} \: \cancel{ k } }[/tex]
[tex]\longrightarrow \tt \sin \theta = \purple{ \dfrac{8}{ \sqrt{113} } }[/tex]
Calculating Cos [tex]\sf \theta [/tex]
[tex] \longrightarrow \tt \cos \theta = \dfrac{Base}{Hypotenuse}[/tex]
[tex] \longrightarrow \tt \cos \theta = \dfrac{BC}{ AB} [/tex]
[tex] \longrightarrow \tt \cos \theta = \dfrac{7 \cancel{k}}{ \sqrt{113} \: \cancel{k } }[/tex]
[tex]\longrightarrow \tt \cos \theta = \purple{ \dfrac{7}{ \sqrt{113} } }[/tex]
Solving the given expression :-
[tex] \longrightarrow \: \tt \dfrac{(1 + \sin \theta)(1 - \sin \theta) }{(1 + \cos \theta) (1 - \cos \theta) } [/tex]
Putting,
• Sin [tex]\sf \theta [/tex] = [tex]\dfrac{8}{ \sqrt{113} }[/tex]
• Cos [tex]\sf \theta [/tex] = [tex]\dfrac{7}{ \sqrt{113} }[/tex]
[tex] \longrightarrow \: \tt \dfrac{ \bigg(1 + \dfrac{8}{ \sqrt{133}} \bigg) \bigg(1 - \dfrac{8}{ \sqrt{133}} \bigg) }{\bigg(1 + \dfrac{7}{ \sqrt{133}} \bigg) \bigg(1 - \dfrac{7}{ \sqrt{133}} \bigg)} [/tex]
Using (a + b ) (a - b ) = a² - b²
[tex]\longrightarrow \: \tt \dfrac{ { \bigg(1 \bigg)}^{2} - { \bigg( \dfrac{8}{ \sqrt{133} } \bigg)}^{2} }{ { \bigg(1 \bigg)}^{2} - { \bigg( \dfrac{7}{ \sqrt{133} } \bigg)}^{2} } [/tex]
[tex]\longrightarrow \: \tt \dfrac{1 - \dfrac{64}{113} }{ 1 - \dfrac{49}{113} } [/tex]
[tex]\longrightarrow \: \tt \dfrac{ \dfrac{113 - 64}{113} }{ \dfrac{113 - 49}{113} } [/tex]
[tex]\longrightarrow \: \tt { \dfrac { \dfrac{49}{113} }{ \dfrac{64}{113} } }[/tex]
[tex]\longrightarrow \: \tt { \dfrac{49}{113} }÷{ \dfrac{64}{113} }[/tex]
[tex]\longrightarrow \: \tt \dfrac{49}{ \cancel{113}} \times \dfrac{ \cancel{113}}{64} [/tex]
[tex]\longrightarrow \: \tt \dfrac{49}{64} [/tex]
[tex]\qquad \: \therefore \: \tt \dfrac{(1 + \sin \theta)(1 - \sin \theta) }{(1 + \cos \theta) (1 - \cos \theta) } = \pink{\dfrac{49}{64} }[/tex]
[tex]\begin{gathered} {\underline{\rule{300pt}{4pt}}} \end{gathered} [/tex]
[tex] {\large{\textsf{\textbf{\underline{\underline{We \: know :}}}}}}[/tex]
✧ Basic Formulas of Trigonometry is given by :-
[tex]\begin{gathered}\begin{gathered}\boxed { \begin{array}{c c} \\ \bigstar \: \sf{ In \:a \:Right \:Angled \: Triangle :} \\ \\ \sf {\star Sin \theta = \dfrac{Perpendicular}{Hypotenuse}} \\\\ \sf{ \star \cos \theta = \dfrac{ Base }{Hypotenuse}}\\\\ \sf{\star \tan \theta = \dfrac{Perpendicular}{Base}}\\\\ \sf{\star \cosec \theta = \dfrac{Hypotenuse}{Perpendicular}} \\\\ \sf{\star \sec \theta = \dfrac{Hypotenuse}{Base}}\\\\ \sf{\star \cot \theta = \dfrac{Base}{Perpendicular}} \end{array}}\\\end{gathered} \end{gathered}[/tex]
[tex]{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}[/tex]
✧ Figure in attachment
[tex]\begin{gathered} {\underline{\rule{200pt}{1pt}}} \end{gathered} [/tex]
f(x) = x². What is g(x)? g(x) -5
A. g(x)=x²
B. g(x) = -2x²
C. g(x) = x² - 2
D. g(x) = -x² - 2
Answer:
D. g(x) = -x² - 2
Explanation:
Parent function: x²
Graph g(x) is inverted so -x² and then shifted down 2 units so -x² - 2
Hence: g(x) = -x² - 2
Which of the statements are true about the function f given by f(x) = 100-e? Select all that apply.
a The values of increase when x increases.
b The value off when x = 5 is less than 1.
d
e The value of is never 0.
E
The value of f when x=-1 is a little less than 40.
The y-intercept of the graph off is at (0, 100).
From the above function, it is clear that the value of f is never 0. Hence the statement that is true is (Option E), See explanation of same below.
What is the explanation for the above function?Note that the function is related to Euler's number which is depicted as:
e ≈ 2.7182. The function is given as:
f(x) = 100 * [tex]e^{-x}[/tex]
Assuming x = -2, we'd have:
100 * 2.7182[tex]^{-2}[/tex]
= 271.82[tex]^{-2}[/tex]
= 0.00001353354
Hence, even when x tends < 0 the function f(x) thus, is never 0. See the attached graph for confirmation.
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What is the sum of the first 6 terms of the sequence defined by an = 3n - 2?
Answer:
51
Step-by-step explanation:
when n=1
t 1=1when n=2
t2=4
as first term is 1 and second term is 4 so the common difference is 3 ,for 6 term if you put this in formula for sum to the n term you will get 51
t1 =1
d=3
n=6
than S6=51
Solve:
4(x + 7) = 5x = 2
Answer:
x = 26
Step-by-step explanation:
4(x+7) = 5x+2 1. (4) with x and 7
4x+28 = 5x+2 2. -5x on both sides
-x+28 = 2 3. -28 on both sides
-x = -26 4. /-1 on both sides
x = 26
The input of a function can also be identified as the ____?
Answer:
Domain of the function
Step-by-step explanatio
Quadrilateral ABCD below is a parallelogram. Use the figure to select the best answer from the choices provided. If AD = 3x + 5, AB = 7x – 3, and BC = 8x – 10, what is the value of x? Select the best answer from the choices provided. A. 2 B. 3 C. 7 D. 8
Answer: 3
Step-by-step explanation:
Opposite sides of a parallelogram are congruent, so AD=BC.
[tex]3x+5=8x-10\\5=5x-1015=5x\\x=\boxed{3}[/tex]
Can you please help me with this
Answer:
dilation by a factor of 1/3 about the origin
Step-by-step explanation:
Each side of triangle B is 1/3 the length of the corresponding side of triangle A. This tells you dilation using a scale factor of 1/3 is involved.
Lines joining corresponding points of triangles A and B converge on the origin. This tells you the center of dilation is the origin.
The one transformation that maps A to B is ...
dilation by a factor of 1/3 about the origin
_____
Additional comment
No rotation, reflection, or translation are needed, since the triangles have the same orientation, and dilation fully accounts for their relative position.
what is the simplified forom of i^14
Answer:
i4=1
Step-by-step explanation:
Explanation: Rewrite i14 as (i4)3×i2 . If i=√−1, then i2=−1 . From here (i2)2=(−1)2 , so i4=1
Simplify the expression. Write your answer as a power.
8¹⁰x8⁴
The simplified expression is
Answer:
[tex]8^{14}[/tex]
Step-by-step explanation:
When we multiply exponents with the same base, the product it the base to the power of the exponents added together. In this case, the base will remain as 8 and the exponent will be 10 + 4 = 14. Therefore, the answer is [tex]8^{14}[/tex].
Answer:
[tex]\large\boxed{\sf \sf 8^{14}}[/tex]
Explanation:
[tex]\rightarrow \sf 8^{10} \ \ x \ \ 8^4[/tex]
apply exponent rule: [tex]\sf \bf a^b\cdot \:a^c=a^{b+c}[/tex]
[tex]\rightarrow \sf 8^{10+4}[/tex]
[tex]\rightarrow \sf 8^{14}[/tex]
The function ((-1,2),(9-1),(-8,5),(2,-8)(?,9)has the same set for its domain and range.
Find the missing value from the function. The missing value is _____.
=======================================================
Explanation:
The range is {2, -1, 5, -8, 9} which sorts to {-8, -1, 2, 5, 9}. This is the set of y coordinates of the points given. Each point is of the form (x,y).
Since the domain and range are the same set in this case, we must have those value mentioned as x coordinates of the points.
The domain is the set of x coordinates of the points given.
The values -8, -1, 2, and 9 are already used as x coordinates. The only thing missing is the 5.
An unusual number cube (with 6 sides) has the numbers 2, 2, 4, 4, 6, and 6 on its faces.
It is rolled once.
Match the outcome to its probability.
Answer:
1. P(2 or 4) - 2/3
2. P(multiple of 2) - 1
3. P(multiple of 3) - 1/3
4. P(odd prime numbers) - 0
Step-by-step explanation:
Hope this helps
P(2 or 4) = 2/3
p(multiple of 2) = 1
p(multiple of 3) = 1/3
P(odd prime numbers) = 0
What are the probabilities?Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
P(2 or 4) = (number of sides that have a value of 2 / total number of sides) + (number of sides that have a value of 2 / total number of sides) = 2/6 + 2/6 = 2/3
p(multiple of 2) = number of sides that are a multiple of 2 / total number of sides
6/6 = 1
p(multiple of 3) = number of sides that are a multiple of 3/ total number of sides
= 2/6 = 1/3
P(odd prime numbers) = number of odd prime numbers / total number of sides = 0
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ASAP!
What is the value of x, given that the two prisms are similar?
5
20
2 25
1.5
A. 2
OB. 10
OC. 2.5
OD. 1.5
3
1
1
Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. The value of x is 10. Thus, the correct option is B.
What are Similar Figures?Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. It is denoted by the symbol "~".
Since the two prisms are similar, their sides will be in a common ratio. The value of the common ratio will be,
Common ratio = 4/2 = 5/2.5 = 3/1.5 = 2
Since the common ratio of every side is equal to 2, the value of x can be written as,
Common Ratio = 20/x = 2
20/x = 2
x = 10
Hence, the value of x is 10. Thus, the correct option is B.
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Don’t know how to solve
Answer:
Hi,
Step-by-step explanation:
I don't know the name in Enghish but in French it is "une règle de 3"
(may be linear rule)
arc length= 2*π*r/360*100=50*π/9
area= π*r²*100/360=250*π/9
28. Which of the following is the correct measure of
angle ABC?
A. 30°
B. 88°
C. 132°
D 44°
Answer:
D) 44°Step-by-step explanation:
According to the diagram we observe:
∠ACD is the exterior angle of triangle ABC.As we know the exterior angle is same as the some of the remote interior angles.
It can be shown as:
m∠ACD = m∠CAB + m∠CBA
Substitute the values and solve for x:
5x - 18 = 3x - 2 + x + 145x - 18 = 4x + 125x - 4x = 12 + 18x = 30Find the measure of m∠ABC:
x + 14 = 30 + 14 = 44The matching answer choice is D.
Look at the pattern below.
step 1 step 2 step 3 step 4
How many squares will be in the pattern at the 8th step?
Choose 1 answer:
8 squares
12 squares
B
There will be 36 squares in the 8th step of the pattern
How to determine the number of squares?The pattern and the squares are represented as:
Pattern Squares
1 1
2 3
3 6
4 10
This can be rewritten as:
Pattern Squares
1 1
2 1 + 2
3 1 + 2 +3
4 1 + 2 + 3 +4
So, the number of squares on the 8th pattern is:
8th pattern = 1 + 2 + 3 +4 + 5 + 6 + 7 + 8
Evaluate
8th pattern = 36
Hence, there will be 36 squares in the 8th step
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kadeem has 58m of fencing to build a four-sided fence around a rectangular plot of land. the area of the land is 204 square meters. solve the dimensions of the field. (length and width)
The dimensions of the rectangular plot of the land is 17 × 12 square units.
What is perimeter?The perimeter of a shape is the distance around the shape. It is the total length of the shape's sides.
What is the formula for the perimeter of rectangle?Perimeter of rectangle = 2( length + width)
What is area?The area can be defined as the space occupied by a flat shape or the surface of an object.
What is formula for the area of rectangle?Area of rectangle = length × width
According to the given question.
Let the length and width of the rectangular plot be x and y respectively.
Kadeem has 58m of fencing.
⇒ Perimeter of the rectangular plot of land = 58m
⇒ 2(length + width) = 58
⇒ x + y = 29...(i)
Also, area of plot land = 204 square units.
⇒ x × y = 204
⇒ x × (29 - x) = 204
⇒ [tex]29x -x^{2} = 204[/tex]
⇒ [tex]x^{2} -29x + 204=0[/tex]
⇒ [tex]x^{2} -12x -17x +204=0[/tex]
⇒ [tex]x(x-12)-17(x -12)=0[/tex]
⇒ [tex](x -12)(x -17) = 0[/tex]
⇒ x = 12 or x = 17
When, [tex]x = 12[/tex]
[tex]y = 29-12 = 17m[/tex]
And when, [tex]x = 17[/tex]
[tex]y = 29 - 17 = 12m[/tex]
Hence, the dimensions of the rectangular plot of the land is 17 × 12 square units.
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algebra 2 pls help lol
Answer:
right -2down 2reflected in the y-axiscompressed by a factor of 1/2Step-by-step explanation:
The order of the transformations affects the values used for translation. Here, the translation is described before the reflection and compression.
__
reflectionThe grayed-out graph of the square root function opens to the right. The darker graph of the transformed function opens to the left, so the reflection is across the y-axis.
__
compressionThe square root function goes through the point (1, 1), that is, 1 unit right of the vertex, and 1 unit up. The transformed function goes through the point (1, -1/2), that is, 1 unit left of the vertex and 1/2 unit up. The vertical height of 1 unit on the original graph is compressed to a height of 1/2 unit on the transformed graph. Vertical compression is by a factor of 1/2.
__
translationThe description of the transformation gives the translation before the reflection and compression. So, to find where the uncompressed and unreflected vertex is, we need to reverse those transformations.
Expanding the transformed square root graph by a factor of 2 will undo its compression by a factor of 1/2. That will move the vertex from (2, -1) to (2, 2×(-1)) = (2, -2).
Reflecting this expanded function back across the y-axis will undo the original reflection. That moves the vertex from (2, -2) to (-2, -2). This is where the original translation left the function's vertex before the reflection and compression moved it to the location shown.
The translation is right -2 and down 2.
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Additional comment
It is possible that you will get pushback on these answers. If so, you should have your teacher demonstrate the transformations in the order described.
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In the order described, we have ...
[tex]f(x)=\sqrt{x}\\\\f_1(x)=\sqrt{x-(-2)}=\sqrt{x+2}\qquad\text{translation right -2}\\\\f_2(x)=\sqrt{x+2}-2\qquad\text{translation down 2}\\\\f_3(x)=\sqrt{-x+2}-2\qquad\text{reflection in the y-axis}\\\\g(x)=\dfrac{1}{2}(\sqrt{-x+2}-2)\qquad\text{compression vertically by $\dfrac{1}{2}$}[/tex]
The attached graph shows the result of this sequence of transformations.
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If the reflection and compression were done before the translation, then the translation would be 2 right and 1 down.