Based on this, a 90% confidence interval for the proportion, p. of adult residents who are parents in this county is 0.787 < p < 0.873.
The point estimate for the proportion is calculated by dividing the number of adults with kids by the total sample size. In this case, the point estimate is 166/200 = 0.83.
To construct the confidence interval, we can use the formula:
[tex]p \pm z \times \sqrt{\frac{p \times (1 - p )}{n}}[/tex]
Where:
p is the point estimate
z is the z-score corresponding to the desired confidence level (90% confidence corresponds to a z-score of approximately 1.645)
n is the sample size
Substituting the values into the formula, we get:
[tex]= 0.83 \pm 1.645 \times \sqrt{\frac{0.83 \times (1-0.83)}{200}}[/tex]
Calculating the values, we can obtain the 90% confidence interval for the proportion of adult residents who are parents.
To construct a 90% confidence interval for the proportion of adult residents who are parents in the county, we can use the sample proportion and the standard error formula. Out of the 200 adult residents sampled, 166 had kids.
we calculate the sample proportion, p-hat:
p-hat = 166 / 200
= 0.83
Next, we calculate the standard error using the formula:
SE = √((p-hat × (1 - p-hat)) / n)
SE = √((0.83 × (1 - 0.83)) / 200) ≈ 0.025
To construct the confidence interval, we use the formula:
p-hat ± (z × SE)
where, z is the z-score corresponding to the desired confidence level.
For a 90% confidence interval, the z-score is approximately 1.645.
Substituting the values into the formula, we get:
= 0.83 ± (1.645 × 0.025)
Calculating the upper and lower bounds:
Lower bound = 0.83 - (1.645 × 0.025) ≈ 0.787
Upper bound = 0.83 + (1.645 × 0.025) ≈ 0.873
Therefore, the 90% confidence interval for the proportion of adult residents who are parents in the county is approximately 0.787 < p < 0.873.
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Which line has a y-intercept of -2?
A) L
B) P
C) T
D) Both L and T
Answer:
Answer is D
Step-by-step explanation:
hope that helps
8/9 + 2/3 + 1/6 = PLeASe HeLp
A. 11/8
B. 11/15
C. 1 13/18
D. 1 2/9
Answer:
C. 1 13/18
Explanation:
how to graph y = - x2 - 4x-3
Answer:
graph is in the attachment
Step-by-step explanation:
y=-x²-4x-3=-x²-4x-4+1=-(x+2)²+1
The integral / 5√1-4x² dx is to be evaluated directly and using a series approximation. (Give all your answers rounded to 3 significant figures.) a) Evaluate the integral exactly, using a substitution in the form ax = sin 0 and the identity cos²x = (1 + cos2x). Enter the value of the integral b) Find the Maclaurin Series expansion of the integrand as far as terms in x6. Give the coefficient of x4 in your expansion: C) Integrate the terms of your expansion and evaluate to get an approximate value for the integral. Enter the value of the integral: d) Give the percentage error in your approximation i.e. calculate.
a) the value of the integral 1.664. b) the coefficient of x4 is (3/1280). c) the value of the integral 2.14 d) the percentage error in the approximation is -28.67%.
a) To evaluate the integral exactly, we make a substitution in the form of ax = sin 0 where a = (1/2).
Substitute x = (sin θ)/2, dx = (cos θ)/2 dθ, and 1 - 4x² = cos² θ in the integral to get it in terms of θ.
∫5√(1-4x²)dx = ∫(5/2) cos²θ dθApply the identity cos²θ = (1 + cos 2θ)/2 to simplify the integrand as shown.∫(5/2) cos²θ dθ = (5/4)∫(1 + cos2θ) dθ = (5/4)θ + (5/8)sin 2θ
Evaluate the above expression from 0 to π/2 to get the value of the integral.
(5/4)θ + (5/8)sin 2θ = (5/4) π/2 + (5/8) sin π = 1.664
b) The integrand is f(x) = 5√(1-4x²).We can write it as shown below, using the binomial series. f(x) = 5(1 - 4x²)^(1/2) = 5∑_(n=0)^∞〖(1/2)_n (2n)!/n! (1/16)^n x^(2n) 〗
The above expression is the Maclaurin Series expansion of f(x) as required.In the expansion, the coefficient of x4 is (1/2)_2 (2.4)/(2!) (1/16)^2 = (3/1280)
c) Integrating each term of the expansion, we obtain the following expression.(5/4)θ + (5/8)sin 2θ = (5/4) π/2 + (5/8) sin π = 1.664
We approximate the value of the integral using the first three terms of the series expansion, and then add the values of the integrated terms.
The terms up to x4 are included in this calculation. I=5[1+(1/2) (-4x²) +(1/2)_2 (-4x²)²]I=5[1-2x²+3x^4/4] = (5/4) (π/2 + (5/16)π²) ≈ 2.14
d) The percentage error in the approximation is given by:%Error = [(Exact value - Approximation value)/ Exact value] x 100Substitute the appropriate values to calculate.%Error = [(1.664 - 2.14)/1.664] x 100 = -28.67% (correct to 3 significant figures)Thus, the percentage error in the approximation is -28.67%.
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Here are 36 points to you beautiful people
Answer:
Thank you so much
Step-by-step explanation:
ok so-
{[Math from BIM]}
ss below
Answer:
2 real solutions
Step-by-step explanation:
x=6i, -6i
HURRY WILL MARK BRAINLIEST subtract 2x from both sides = x+2=8
Then subtract 2 from both sides and you'll get x=6.
Answer:
x=6
Step-by-step explanation:
x+2=8
subtract 2 from both sides
x=6
consider a normally distributed population with mean =10 and standard deviation σ=2.5. suppose a random sample of size is selected from this population. Find the distribution of X and the indicated probability in each of the following cases. a. n = 7 P(X < 9)
b. n = 12, P(X> 11.5). c. n = 15, P(9.5 10.25). e. n=100, P(X <9.8 UX >0.2)
The probability P(Z < -1.06) is approximately 0.142. The probability P(Z > 2.386) is about 0.008. The probability P(-0.777 < Z < 0.777) is approximately 0.456.
The probability P(X < 9.8) ≈ 0.211. The probability P(X > 10.2) = = 0.212. The probability P(X < 9.8 or X > 10.2) = 0.423.
To locate the distribution of X and the indicated possibilities for the given instances, we need to use the residences of the everyday distribution. Given that the populace has a median (μ) of 10 and a widespread deviation (σ) of 2.5, we will continue as follows:
a. N = 7, P(X < 9):
For a pattern size of seven, the distribution of X follows a normal distribution with the equal mean (10) however a trendy deviation of σ/sqrt(n) = 2.5/[tex]\sqrt{7}[/tex] ≈ 0.944.
To discover P(X < nine), we need to standardize the cost of 9 with the use of the Z-rating formula: Z = (X - μ) / σ.
Substituting the values, we get Z = (9 - 10) / 0.944 ≈ -1.06.
Using a standard regular distribution table or calculator, we are able to locate that the chance P(Z < -1.06) is approximately 0.142.
B. N = 12, P(X > 11.5):
For a sample length of 12, the distribution of X follows a regular distribution with the same suggestion (10) but a well-known deviation of σ/[tex]\sqrt{n}[/tex] = 2.5/[tex]\sqrt{12}[/tex] ≈ 0.7217.
To discover P(X > 11.5), we standardize the value of 11.5 for the usage of the Z-rating method: Z = (X - μ) / σ.
Substituting the values, we get Z = (11.5 - 10) / 0.7217 ≈ 2.386.
Using a trendy everyday distribution table or calculator, we will locate that the chance P(Z > 2.386) is about 0.008.
C. N = 15, P(9.5 < X < 10.25):
For a sample size of 15, the distribution of X follows a normal distribution with identical implies (10) however a popular deviation of σ/sqrt(n) = 2.5/[tex]\sqrt{15}[/tex]≈ 0.6455.
To discover P(9.5 < X < 10.25), we need to standardize the values using the Z-score components.
Z1 = (9.5 - 10) / 0.6455 ≈ -0.777, and Z2 = (10.25 - 10) / 0.6455 ≈ 0.777.
Using a widespread ordinary distribution desk or calculator, we can locate that P(-0.777 < Z < 0.777) is approximately 0.456.
D. N = 100, P(X < 9.8 or X > 10.2):
For a sample size of 100, the distribution of X follows a regular distribution with the equal implies (10) however a general deviation of σ/sqrt(n) = 2.5/[tex]\sqrt{100}[/tex] = 0.25.
To find P(X < 9.8 or X > 10.2), we need to calculate the probabilities for each person's case and subtract them from 1.
P(X < 9.8) = P(Z < (9.8 - 10) / 0.25) ≈ P(Z < -0.8) ≈ 0.211.
P(X > 10.2) = P(Z > (10.2 - 10) / 0.25) ≈ P(Z < -0.8) ≈ 1 - P(Z < 0.8) ≈ 1 - 0.788 = 0.212.
Therefore, P(X < 9.8 or X > 10.2) ≈ P(X < 9.8) + P(X > 10.2) ≈ 0.211 + 0.212 = 0.423.
Remember to consult a trendy everyday distribution desk or use a calculator to locate the possibilities associated with the Z-scores.
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A bridge combines two cities X and Y. Cars cross this bridge according to a Poisson process of rate µ= 600/hour. Independently each car travels from X to Y with probability p = 0.XX XX is the last two digits of your student ID after the decimal point (for example: if your student ID is 63171234, you should use p = 0.34) and from Y to X with probability 1 - p. a. What is the probability that during a one minute period at noon 2 cars cross the bridge? b. What is the probability that during a one minute period at noon 2 cars travel from X to Y?
The probability of 2 cars crossing the bridge from X to Y in a 1-minute period is:
P(X = 2) = ((λ^x) / x!) * e^(-λ)
P(X = 2) = ((XX/100 * 10)^2 / 2!) * e^(-XX/100 * 10)
P(X = 2) = (XX/500) * e^(-XX/100 * 10)
P(X = 2) = (XX/500) * 0.000045
a) Let X be the number of cars that cross the bridge in a 1-minute period.
Since the Poisson process with a rate of µ = 600/hour, the rate of cars crossing the bridge is
λ = 600/60
= 10/min.
The probability that two cars will cross the bridge during the 1-minute period can be calculated by the following formula:
P(X = 2) = ((λ^x) / x!) * e^(-λ)
P(X = 2) = ((10^2) / 2!) * e^(-10)
P(X = 2) = 0.0045
b) Let Y be the number of cars that travel from X to Y in a 1-minute period.
Since the probability that a car travels from X to Y is p = 0.XX,
The probability that a car travels from Y to X is 1 - p.
As per the Poisson process, the probability of
λ = 10/min.
Let X be the number of cars that cross the bridge from X to Y in a 1-minute period.
Then X follows a Poisson distribution with a rate of
µ = 10*p
= XX/100 * 10.
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Juan is a teacher and takes home 618 papers to grade over the weekend. He can grade
at a rate of 6 papers per hour. How many papers would Juan have remaining to grade
after working for 7 hours?
Answer:
576
Step-by-step explanation:
6 papers an hour. 7 hours spent grading.
So 7•6 = 42
618-42
576
Hope this helps
Consider the sets of natural numbers, whole numbers, integers, rational numbers, and real numbers. Identify from the list above the first set that describes the given number. 8.7104 Choose the correct answer below. O Natural numbers O Integers Whole numbers Rational numbers Real numbers
The number 8.7104 belongs to the set of real numbers. The sets of natural numbers, whole numbers, integers, rational numbers, and real numbers are ordered from most specific to most inclusive.
Natural numbers: Also known as counting numbers, they include positive whole numbers starting from 1 (1, 2, 3, 4, ...).
Whole numbers: Similar to natural numbers, they include all positive integers starting from 0 (0, 1, 2, 3, ...).
Integers: This set includes both positive and negative whole numbers, including zero (-∞, ..., -3, -2, -1, 0, 1, 2, 3, ..., +∞).
Rational numbers: These are numbers that can be expressed as fractions, where the numerator and denominator are both integers. Rational numbers can be written as terminating or repeating decimals.
Real numbers: This set includes all rational and irrational numbers. Real numbers can be represented on the number line and include all possible decimal values, including non-terminating and non-repeating decimals.
In the case of the number 8.7104, it is a decimal number that can be expressed as a terminating decimal. Therefore, it falls within the set of real numbers. Real numbers encompass all possible decimal values, both terminating and non-terminating, making them the broadest set in terms of representation on the number line.
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Please help me out! You can just give me your answer! PLEASE AND THANK YOU!
Answer:
15°, 16°, 46°, 59°
Step-by-step explanation:
1.) so the entire angle is 89°, then you take off the 44° and the 30°
89° - 44° - 30° = 15°
So the answer to 1 is x = 15°
2.) 90° - 74° = 16°
3.) 180° - 134° = 46°
4.) the angles are vertical, so they're equal:
x = 59°
hope this helps:)
A: y=5x+7 b:y= 3x+5 c: y=2x+5
Answer: A: y=5x+7
Step-by-step explanation: Hope this help :D
XA ) -
Calculate the volume of the prism by first finding the total number of half-unit
cubes that will fill it. There are 8 half-unit cubes in every unit cube.
23
A. Number of half-unit cubes = 10
V = 2 cubic units
B. Number of half-unit cubes = 20
V=2 cubic units
O C. Number of half-unit cubes = 20
V = 10 cubic units
D. Number of half-unit cubes = 10
V = 5 cubic units
Answer:
Option B will be your answer
Step-by-step explanation:
V=2 1/2×1/2×2
=2.5 cube
volume of 1/2 cubic units =)(1/2×1/2×1/2=0.125cube^3
2.5/0.125=20
Hope it helps...
v = 2½
number of half unit cubes = 20
A die is rolled 100 times. A 1 is rolled 20 times, a 2 is rolled 14 times, a 3 was rolled 20 times, a 4 was rolled 15 times a 5 was rolled 19 times, and a 6 was rolled 12 times.
a) What is the experimental probability of rolling a 6?
b) What is the theoretical probability of rolling a 6?
Answer:
A) Experimental probability = 0.12
B) Theoretical probability = 1/6
Step-by-step explanation:
A) Experimental probability is based on the total number of times an event occurs with respect to the total outcome of the experiment in question.
Now, we are told that the die was rolled 100 times and that 6 was gotten 12 times for the 100 rolls.
Thus;
Experimental probability = 12/100
Experimental probability = 0.12
B) Theoretical probability is the number of ways that an event can occur in relation to the total outcomes.
Here, the number of ways 6 can occur is 1 and the total outcome is 6 possible due numbers.
Thus,
Theoretical probability = 1/6
Can someone help me , explain too it’s special right triangles
Answer:
10sqrt{2}
Step-by-step explanation:
This is a 45-45-90 right triangle. This means that the two legs are both the same length, call it x, and the hypotenuse is square root 2 times the given leg. There's a proof for this, but it's long, and you can find it online.
Find k given that these three points are collinear.
A(0, -2), B(2, 0), and C(5, k)
Answer:
k = 3.
Step-by-step explanation:
If they are collinear the slope of AB = the slope of BC, so :-
(0- (-2)) / (2 - 0) = (k - 0) / (5 - 2)
2/2 = k/3
1 = k/3
k = 3.
Which sets of shapes can be used as the net of a three-dimensional figure? Select two options.
1 hexagon and 6 rectangles
2 pentagons and 5 triangles
6 rectangles, none of which are squares
4 squares and two rectangles that are not squares
4 triangles, only 3 of which are congruent triangles
Answer:
C and D
Step-by-step explanation:
Got it right on the test.
1 hexagon and 6 rectangles and 4 squares and two rectangles that are not squares are sets of shapes which can be used as the net of a three-dimensional figure. Option A and option D are correct.
Hexagon and 6 rectangles: This combination of shapes can be used to create the net of a hexagonal prism.
The hexagon will be used as the base of the prism, and the six rectangles can be attached to the sides of the hexagon to form the remaining faces of the prism.
When folded along the edges, the net will result in a hexagonal prism.
4 squares and two rectangles that are not squares: This combination can be used to create the net of a rectangular prism or a cuboid.
The four squares will be used as the top, bottom, and side faces of the prism, while the two rectangles (which are not squares) can be attached to the remaining sides to complete the net.
When the net is folded along the edges and assembled, it will form a rectangular prism or cuboid.
Hence, Option A and option D are correct. 1 hexagon and 6 rectangles and 4 squares and two rectangles that are not squares are sets of shapes which can be used as the net of a three-dimensional figure.
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The sum of the lengths of the sides of triangle ABC is 25 in . The lengths of sides overline AB and overline BC are 9 inches and 8 inches . Find the length of side overline AC and classify the triangle.
Answer:
AC = 8 The classification is isosceles
Step-by-step explanation:
3
Which conical container holds more water?
1
1
-
1
1
k
8 cm
8 cm
or
1
4 cm
6 cm
Cone 1
Cone 2
Answer:
Find the radius of convergence, R, of the series. OD x40 Σ n = 1 n! R = Find the interval, I, of convergence of the series.
The interval of convergence, I, is (-∞, +∞), which means the series converges for all real values of x.
How did we arrive at this assertion?To find the radius of convergence, use the ratio test. The ratio test states that for a power series of the form:
Σ(aₙ × xⁿ)
where aₙ is the nth term of the series, the radius of convergence R is given by:
R = lim(n→∞) |aₙ / a_(n+1)|
In this case, the series:
Σ(n!) × xⁿ
Apply the ratio test to find the radius of convergence:
|aₙ / a_(n+1)| = |(n!) × xⁿ / ((n+1)!) × xⁿ⁺¹|
= |x / (n+1)|
Taking the limit as n approaches infinity:
lim(n→∞) |x / (n+1)| = |x / ∞| = 0
Since the limit is 0, the series converges for all values of x. This means that the radius of convergence, R, is infinite (R = ∞).
Now, let's find the interval of convergence, I. Since the radius of convergence is infinite, the series converges for all values of x. Therefore, the interval of convergence, I, is (-∞, +∞), which means the series converges for all real values of x.
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5/6 + 7/8 + 3/4
i need help
Answer:2 11/24
Step-by-step explanation:
Answer:
2.4583
Step-by-step explanation:
I helped you.
First
5÷6 and 7÷8 and again similarly 3÷4 and sum the all outcome come from these eqations
Factor 30-24x
6(15-12x)
6(5x-4x)
x(5-4x)
6(5 - 4x)
Answer:
the second option
Step-by-step explanation:
pretty sure it's the second option
hope this helped ;)
Answer:
6 (5 - 4x)Step-by-step explanation:
[tex]\sf 30-24x[/tex]
30 → 6 * 5
24 → 6 * 4
[tex]\sf 6* \:5-6* \:4x[/tex]
[tex]\sf 6\left(5-4x\right)[/tex]
Given that m<6=72 and m<14=72 determine which lines are parallel
Answer:
Lines m and n are parallel.
Step-by-step explanation:
< 6 and < 14 are both equal to 72 degrees and they are corresponding angles for lines m and n.
Cesar has 32 boxes of pasta and 48 jars of sauce that he will be putting into bags for
a food drive. He wants each bag to have the same amount of pasta and sauce and
wants to use all of the items.
Use the drop-down menus to complete the statements below about the number of
bags Cesar can make.
CLEAR
CHECK
The greatest number of bags Cesar can make is
Each of these bags will have
boxes of pasta and
jars of sauce.
If he made fewer bags,
He could use
bags, but this is not the greatest number he could use.
Can someone please help me with this? And please no links.
Answer:
1x + 15?
Step-by-step explanation:
Let W be the subspace spanned by u_{1} and u_{2} and write y as the sum of a vector v_{1} in W and a vector v_{2} orthogonal to W. y = [[- 5], [6], [- 8]] u_{1} = [[1], [2], [2]] u_{2} = [[6], [2], [- 5]]
v₁ = [[-1], [-2], [-2]] and v₂ = [[-4], [8], [-6]] are the vectors that satisfy the given conditions.
To write vector y as the sum of a vector v₁ in W and a vector v₂ orthogonal to W, we need to find the orthogonal projection of y onto the subspace W spanned by u₁ and u₂.
y = [[-5], [6], [-8]]
u₁ = [[1], [2], [2]]
u₂ = [[6], [2], [-5]]
To find v₁, we'll use the formula for the orthogonal projection
v₁ = ((y · u₁) / (u₁ · u₁)) × u₁
where "·" represents the dot product.
Calculating the dot products
y · u₁ = (-5 × 1) + (6 × 2) + (-8 × 2) = -5 + 12 - 16 = -9
u₁ · u₁ = (1 × 1) + (2 × 2) + (2 × 2) = 1 + 4 + 4 = 9
Substituting the values
v₁ = ((-9) / 9) × [[1], [2], [2]] = [[-1], [-2], [-2]]
Now, to find v₂, we'll subtract v₁ from y
v₂ = y - v₁ = [[-5], [6], [-8]] - [[-1], [-2], [-2]] = [[-4], [8], [-6]]
Therefore, we can write y as the sum of v₁ and v₂
y = v₁ + v₂ = [[-1], [-2], [-2]] + [[-4], [8], [-6]] = [[-5], [6], [-8]]
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According to a college survey, 22% of all students work full time. Find the mean for the number of students who work full time in samples of size 16. Round to the nearest tenth. A. 4.0 B. 3.5 C. 2.8 D. 0.2
The average number of full-time students in samples of size 16 is B) 3.5.
Because of the extraordinarily huge population, this can be regarded a binomial distribution if all students globally are considered. A normal distribution is commonly used to approximate the binomial distribution. As a result, the mean equals the expectation:
E[x] = np = (16)(0.22) = 3.52
μ = 3.52
The likelihood of success raised to the power of the number of successes is multiplied by the probability of failure raised to the power of the difference between the number of successes and the number of trials. The product is then multiplied by the sum of the number of trials and successes.
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Find the distance between the points ( -5,1) and (4,0) round to the nearest tenth
Answer:
9.1 units
Step-by-step explanation:
formula of a distance of two points:
[tex]\sqrt{(x1-x2)^2+(y1-y2)^2}[/tex] where x and y indicate the coordinates of the points
[tex]\sqrt{(4+5)^2 + (-1)^2} = \sqrt{81 + 1} = \sqrt{82} = 9.1 units[/tex]
Hello i would really appreciate it if you help!