Va A rail wagon of mass
5000 kg moving at a velocity
of 1.6 ms-1 collides with a
stationary wagon of mass
3000 kg (see Figure 4). After
the collision, the 3000 kg wagon
moves away at a velocity of
1.5 ms-1. Calculate the speed
and direction of the 5000 kg
wagon after the collision.

Answers

Answer 1

Answer:

0.7m/s

Explanation:

According to the conservation of linear momentum, the moment before a collision is equal to the moment after the collision. The equation is written as follows: [tex]m_{a}u_{a} + m_{b}u_{b} = m_{a}v_{a} + m_{b}v_{b}[/tex], where [tex]m[/tex] is the mass of the object, [tex]u[/tex] is the initial velocity, and [tex]v[/tex] is the final velocity.

Let's say the object [tex]a[/tex] is our moving wagon and the object [tex]b[/tex] is our stationary wagon. [tex]m_{a} = 500kg, u_{a} = 1.6ms^{-1}[/tex],  [tex]m_{b} = 3000kg, u_{b} = 0[/tex], since the wagon is stationary, it doesn't have any initial velocity. After collision, the mass remains the same, but the velocity changes: [tex]v_{a} = ?, v_{b} = 1.5ms^{-1}[/tex]

We can observe that [tex]v_{a}[/tex] is what we're looking for according to the question. Now let's substitute our values.

[tex](5000 * 1.6) + (0) = 5000v_{a} + (3000 * 1.5)[/tex]

[tex]v_{a} = \frac{(5000 * 1.6) - (3000*1.5)}{5000}[/tex] = 0.7m/s


Related Questions

What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2?

Answers

Answer:

This is the answer that I got.

Explanation:

Hope it is right.

If you were to mix 10 grams of salt into 100 grams of water, how much will the total mass of the solution be?
Group of answer choices

90 grams

100 grams

110 grams

10 grams

Answers

110 grams

mass of salt + mass of water

10 + 100

110g

Answer:

110 grams

Explanation:

If you were to mix 7 grams of sugar into 100 grams of water, how much will the total mass of the solution be?

No mass was gained or lost, so the mass would be 107 grams.

100 grams

107 grams

93 grams

95 grams

No mass was gained or lost, so the mass would be 107 grams.

(For your problem it would be 10+ 100= 110g)

will mark brainliest if answer​

Answers

I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.

On average, how many stars would we have to search before we would expect to hear a signal? assume there are 500 billion stars in the galaxy.

Answers

We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.

To find out the number of stars that we will need to search to find a signal, we need to use the following formula:

total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)

This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.

Note: This question is incomplete; here is the complete question.

On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.

Assuming 100 civilizations existed.

Learn more about stars in: https://brainly.com/question/2166533

If there were no dark energy in the universe, the value of __________ would solely determine the evolution and fate of the universe.

Answers

Answer:

Ωmass

Explanation:

If there were no dark energy in the universe, the value of Ωmass would determine the evolution and fate of the universe.

‍12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?

Answers

Answer:

192 m/s

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question we have

c = 8 × 24 = 192

We have the final answer as

192 m/s

Hope this helps you

what class of motion did aristotle attribute to the moon?

Answers

The Moon has a Natural class of motion

A projectile is to be launched at an angle of 30° so that it falls beyond the pond of length 20 meters as shown in the figure.
a) What is the range of values of the initial velocity so that the projectile falls between points M and N?

Answers

Answer: A

Explanation:

I want my points so yea

Dan is working as a family resources coordinator. Which of these statements are true about him?
Dan is responsible for overseeing the administrative functions and daily operations of a childcare center. He also helps families with children
who have special needs to uphold the rights of the children. He assists daycare teachers in carrying out their everyday duties. He also helps
families make use of early intervention services.
Reset
Next
rights reserved

Answers

The true statement about Dan is that "he also helps  families make use of early intervention services."

Family resource coordinators are experts whose job it is to help families to ensure that children get along in early intervention services. They always work with families and school age children.

If Dan is  working as a family resources coordinator, then a true statement about him is that "he also helps  families make use of early intervention services."

Learn more about family resource coordinator: https://brainly.com/question/8949872

Answer:

-He also helps families make use of early intervention services.

-He also helps families with children who have special needs to uphold the rights of the children

Explanation:

Got it right on plato.

If the half-life of iodine-131 is 8 days, how much of a 5.00 sample is left after 32 days?

A) 0.31

B) 2.5

C) 1.25

D) 0.62

Answers

Answer:

Option A, 0.31

Explanation:

n = Time taken / half life

n = 32/ 8

= 4

Remaining fraction = 1/2^n

= 1/2⁴

= 1/16

Amount of iodine-131 left = 1/16 × 5

= 0.3125

a 25 kg crate is pushed horizontally with a force of 70N. if the coefficient of friction is .20, calculate the acceleration of the crate.

Answers

From Newton's second law of motion, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]

Given that a 25 kg crate is pushed horizontally with a force of 70N and the coefficient of friction is 0.20

To calculate the acceleration of the crate, We will consider the net force acting on the crate. The net force will be sum of the applied force F and the frictional force [tex]F_{r}[/tex].

Let us first calculate the frictional force [tex]F_{r}[/tex]. That is,

[tex]F_{r}[/tex] =- μN

[tex]F_{r}[/tex] = μmg

[tex]F_{r}[/tex] = 0.2 x 25 x 9.8

[tex]F_{r}[/tex] = 49N

Using Newton's second law,

F = ma

F - [tex]F_{r}[/tex] = ma

70 - 49 =  25 a

21 = 25a

a = 21 / 25

a = 0.84 m/[tex]s^{2}[/tex]

Therefore, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]

Learn more here: https://brainly.com/question/1141170

If the 0.10 kg baseball on the right has a
kinetic energy of 5 J, what is its velocity?

Answers

Answer:

10 m/s

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

Since we're finding the velocity we make v the subject

That's

[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]

From the question

k = 5 J

m = 0.1 kg

We have

[tex]v = \sqrt{ \frac{2 \times 5}{0.1} } = \sqrt{ \frac{10}{0.1} } = \sqrt{100} \\ = 10[/tex]

We have the final answer as

10 m/s

Hope this helps you

where in space did the expansion of the universe begin?

Answers

Answer:

The big bang

Explanation:

It is theorized the expansion of the universe began with the big bang, the universes expansion therefore did not begin in a spot of the universe rather the universe expanded from the big bang.

If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, what must be true of the magnitude of the reaction force?

Answers

According to Newton third law of motion,  what must be true of the magnitude of the reaction force is that the reaction force will be equal and opposite to the action force of 110 newtons

From Newton third law of motion which state that in every action of force, there will be equal and opposite reaction.

If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, the mass 35 kg will produce a reaction force which is equal and opposite to the action force 110 newton received from mass 75 kg.

Therefore, what must be true of the magnitude of the reaction force from mass 35 kg is that the mass will produce an equal and opposite force equal to 110 Newtons.

Learn more about collision here: https://brainly.com/question/7579673

3. Suppose Earth orbited a star whose mass was double the mass of the sun. If the radius of Earth's orbit remained
the same as it is now, then compared with gravitational force between Earth and the sun, the gravitational force
between Earth and the star would be -
A. half as much
B. the same
C. two times as much
D. four times as much

Answers

Answer:

F1 = G M m / R^2       current force on earth

F2 = G M * 2 m / R^2     force if mass were doubled

F2 / F1 = 2         the force would be twice as large

The gravitational force between two objects not only depends on the mass but also the distance between them. If the distance to the star is same as to sun, then by doubling mass force also doubles. Thus option C is correct.

What is universal law of gravitation?

Gravitational force is the attractive force by which an object attracts other objects into its centre of mass. We are all standing in the ground because of the gravitational pull by earth.

The gravitational force between two objects of mass M1 and M2 at a distance r is written as follows:

g = G M1 M2/ r ² . where, G is gravitational constant.

As per this relation, gravitational force is directly proportional to the mass and inversely proportional to the square of the distance.

If the star has a distance from earth equal to the distance between sun and earth, but its mass is double the mass of sun, then the gravitational force will be two times compared with the sun.

To find more on gravitational force, refer here:

https://brainly.com/question/12528243

#SPJ2

If you move two objects with opposite charges apart, what happens to the potential energy between them? Explain your response.

Answers

I have read it in the ncert science book

That any material charged with the same energy they repels each other while if they have opposite energy they attracts each other.

Hope it helps.

Please Mark as brainliest

Express the sum of 2.52 kg + 131 g in kilograms with the correct number of significant
figures.

Answers

Convert second term into kg

131 = 0.131

Term has become:

2.52 + 0.131

The total is:

2.651 kg

A kilowatt-hour is a unit of
1. force
2. power
3. work
4. voltage
5. current
6. None of these
7. torque

(I tried 2 and 6, but they were both wrong :( )

Answers

Answer:

option 4 is the correct answer

Option 4 would be the answer

A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?

Answers

The initial velocity of the ball when it was projected is 15.64 m/s.

The given parameters:

Angle of the projection, θ = 37⁰The range of the projectile, R = 24 m

The initial velocity of the ball is calculated by applying formula for range of projectile as follows;

[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]

Thus, the initial velocity of the ball when it was projected is 15.64 m/s.

Learn more about range of projectile here: https://brainly.com/question/12870645

(50 POINTS) please answer each question:

what is the Distance from Earth (light years)

what is the Visual Luminosity in comparison to Sun

what is the Surface Temperature (Kelvin)

stars:

Sun




Alpha Centauri A




Sirius B




Barnard’s Star




Vega




Proxima Centauri

Answers

Answer:

i know the first one.

Explanation:

the distance from earth in light years is 6 trillion miles.

What is the control group

Answers

A control group in a scientific experiment is a group separated from the rest of the experiment, where the independent variable being tested cannot influence the results. This isolates the independent variable 's effects on the experiment and can help rule out alternative explanations of the experimental results.

Answer:

members of a control group receive a standard treatment, a placebo, or no treatment at all.

Explanation:

How far does an object travel if it is moving at a speed of 4 m/s for 3.2 seconds?

Answers

Answer:

12.8 meters

Explanation:

m/s means meters per second. So, to find how far it would travel in 3.2 seconds, you would multiply 4 meters every second by 3.2 seconds.

4×3.2=12.8 meters

Why are movie scenes in outer space often unrealistic?

Answers

Answer:

see explanation

Explanation:

by my calculations, i believe it may be because they have to pretend to be in space.

one of them is Space & Interstellar Travel

A car travels 120 miles in 12 hours. What is
the car's speed?

Select one:
O a. 10 m/s

b. 10 mph

c. 1200 mph

O d. 0.1 m/s

Answers

Answer:

I hope it will help you...

#CARRYONLERANING

1 kg ball has eight joules of kinetic energy. what is its speed?

Answers

[tex]\\ \sf\Rrightarrow KE=\dfrac{1}{2}mv^2[/tex]

[tex]\\ \sf\Rrightarrow 8=\dfrac{1}{2}v^2[/tex]

[tex]\\ \sf\Rrightarrow v^2=16[/tex]

[tex]\\ \sf\Rrightarrow v=√16[/tex]

[tex]\\ \sf\Rrightarrow v=4m/s[/tex]

Answer:

the answer is 4m/s


A type of matter in which two or more elements are combined
chemically is called a _______

Answers

Answer:

COMPOUND

Explanation:

???????????????????????????????????

Answers

What happened the thing is kinda glitched

A toaster oven indicates that it operates at 1500 W on a 110 V
circuit. What is the resistance of the oven?


Answers

[tex]P=U.I => I=\frac{P}{U}=\frac{1500}{110}=\frac{150}{11}<A>\\I=\frac{U}{R}=> R=\frac{U}{I} = \frac{110}{\frac{150}{11} }=8.06< ohm>[/tex]

The answer is: A. 8.06 ohm

ok done. Thank to me :>

define the unit of work​

Answers

[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]

An 50 kg student runs and jumps onto a 25 kg tire swing, which is initially at rest, and rides the swing up into the air. The swing (and the student) then rises a vertical distance of 1.5 m. What was the initial speed, in m/s of the swing? Remember the acceleration due to gravity near Earth's surface, g = 9.81 m/s^2

A. 29 m/s

B. 5.4 m/s

C. 1.7 m/s

D. 15. m/s

E. 3.8 m/s


Will mark brainliest

Answers

Answer:

Option B, 5.4m/s

Explanation:

Using the formula v² = u ² - 2gh

v = 0(final velocity is zero at maximum height), u = ?, g = 9.81m/s², h = 1.5m

0² = u² - 2×9.81×1.5

0 = u² - 29.43

29.43 = u²

u = √29.43

= 5.42m/s

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