Using Postulates and/or Theorems, determine whether ABC~AXY.
explain why the triangles are similar or why they are not.

Answer: Check the picture below.

Make sure your calculator is in Degree mode.

the question "how long is the kite?" is not quite clear, i suppose it was asking how far it was from the ground (b) or horizontally (a). I calculated both, I hope this helps

Answer:

3 times 7 is 21

Step-by-step explanation:

Answer:

3x7=21

Step-by-step explanation:

7+7+7=21 or   3+3+3+3+3+3+3=21

Brainliest

Answer:D

Step-by-step explanation:got it right on my test

Answer:

The answer is C i got a 100 on the test

Step-by-step explanation:

Answer:2.5

Step-by-step explanation:5/2=2.5

Answer:

(i) 64°

(ii) 26°

Step-by-step explanation:

Answer:

(i) m<ADB = 64°

(ii) m<ACD = 26°

Step-by-step explanation:

I use this to mean the measure of angle ADC: m<ADC

(i)

m<BEC = 52°

<DEA and <BEC are vertical angles, so they are congruent.

m<DEA = m<BEC = 52°

Polygon ABCD is a rectangle. When the diagonals, AC and BD, of a rectangle are drawn, 4 triangles are formed. Each two opposite triangles are congruent, and all 4 triangles are isosceles.

Triangle ADE is an isosceles triangle with congruent sides ED and EA. That makes opposite angles ADB and DAC congruent. Also the sum of the measures of the angles of a triangle is 180°.

m<ADB + m<DAC + m<DEA = 180°

m<ADB = m<DAC; m<DEA = 52°

2m<ADB + 52° = 180°

2m<ADB = 128°

m<ADB = 64°

(ii)

Angles DEC and BEC form a linear pair. That means the angles are supplementary, and the sum of their measures is 180°.

m<DEC + m<BEC = 180°

m<DEC + 52° = 180°

m<DEC = 128°

Triangle DEC is an isosceles triangle with congruent sides ED and EC. That makes opposite angles ACD and BDC congruent.

m<ACD + m<BDC + m<DEC = 180°

2m<ACD + 128° = 180°

2m<ACD = 52°

m<ACD = 26°

Answer:

[tex]x=1,\:x=4[/tex]

Step-by-step explanation:

[tex]x-2=\sqrt{x}\\\\(x-2)^2=x\\\\x^2-4x+4=x\\\\x^2-5x+4=0\\\\(x-1)(x-4)=0\\\\x=1,\:x=4[/tex]

x=1 and x=4 are real value or values of x satisfy the equation x−2=√x

Two or more expressions with an Equal sign is called as Equation.

Given,

Equation is x−2=√x

We need to find for which values of x satisfy the equation.

x−2=√x

Take square on both the sides

(x-2)²=√x²

We know the algebraic identity

(a-b)²=a²+b²-2ab

(x-2)²=√x²

x²+2²-2(2)x=x

x²+4-4x=x

x²+4-4x-x=0

x²-5x+4=0

x²-4x-x+4=0

x(x-4)-(x-4)=0

(x-1)(x-4)=0

x-1=0

x=1

x-4=0

x=4

Hence, x=1 and x=4 are real value or values of x satisfy the equation x−2=√x

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Answer: D. -30

Step-by-step explanation: EDGE 2022 I GOT 100%

Answer:

5m+4

Step-by-step explanation:

Open the bracket

i.e 5m+5-1

5m+4.

[tex] \text{Given Equation is } \frac{x}{1} = \frac{ \sqrt[3]{m + 1{ }} + \sqrt[3]{m - 1} }{ \sqrt[3]{m + 1} + \sqrt[3]{m - 1} }[/tex]

[tex]\text{On Applying componendo and dividendo, we get:-}[/tex]

[tex] \frac{x + 1}{x - 1} = \frac{( \sqrt[3]{m + 1} + \sqrt[3]{m - 1} )+ ( \sqrt[3]{m + 1}) - \sqrt[3]{m - 1} }{ (\sqrt[3]{m + 1} + \sqrt[3]{m - 1}) - ( \sqrt[3]{m + 1}) - \sqrt[3]{m - 1} } [/tex]

[tex] \implies \: \frac{x + 1}{x - 1} = \frac{2( \sqrt[3]{m + 1)} }{2( \sqrt[3]{m - 1)} } \\ \\ \implies \frac{ x + 1}{x - 1} = \frac{ \sqrt[3]{m + 1} }{ \sqrt[3]{m - 1} } [/tex]

[tex] \text{On Cubing both sides, we get} \\ \frac{(x + 1) {}^{3} }{(x - 1) {}^{3} } = \frac{m + 1}{m - 1} [/tex]

[tex]\text{Again, Applying componendo and dividendo, we get:-}[/tex]

[tex] \frac{(x + 1) {}^{3} + (x - 1) {}^{3} }{(x + 1) {}^{3} - (x - 1) {}^{3} } = \frac{m + 1 + m - 1}{m + 1 - (m - 1)} [/tex]

[tex] \implies \frac{ {x}^{3} + 1 {}^{3} + 3 {x}^{2} \times 1 + 3x \times {1}^{2} + ( {x}^{3} - 1 {}^{3} - 3x {}^{2} \times 1 + 3x \times 1 {}^{2} ) }{x {}^{3} + 1 {}^{3} + 3 {x}^{2} \times 1 + 3x \times {1}^{2} - (x {}^{3} - 1 {}^{3} - 3 {x}^{2} \times 1 + 3x \times {1}^{2}) } = \frac{2m}{2} [/tex]

[tex] \implies \frac{2x {}^{3} + 6x}{ {6x}^{2} + 2 } = \frac{m}{1} [/tex]

[tex] \implies \frac{2(x {}^{3 } + 3x) }{2(3 {x}^{2} + 1) } = \frac{m}{1} [/tex]

[tex] \implies \: x {}^{3} + 3x = 3m {x}^{2} + m \\ \\ \implies {x}^{3} - 3mx {}^{2} + 3x \\ = m[/tex]

Hope This Helps!!

Based on the calculations, the value of [tex]x^3-3mx^2+3x[/tex] is equal to m.

Given the following data:

[tex]x=\frac{\sqrt[3]{m+1} +\sqrt[3]{m-1}}{\sqrt[3]{m+1} +\sqrt[3]{m-1}}[/tex]

In order to simplify the given mathematical expression, we would apply the componendo and dividendo rule because it would the number of expansions as follows:

[tex]\frac{x}{1} =\frac{\sqrt[3]{m+1} +\sqrt[3]{m-1}}{\sqrt[3]{m+1} -\sqrt[3]{m-1}}\\\\\frac{x+1}{x-1} =\frac{(\sqrt[3]{m+1} +\sqrt[3]{m-1})+(\sqrt[3]{m+1} -\sqrt[3]{m-1})}{(\sqrt[3]{m+1} +\sqrt[3]{m-1})-(\sqrt[3]{m+1} -\sqrt[3]{m-1})}\\\\\frac{x+1}{x-1} =\frac{\sqrt[3]{m+1} +\sqrt[3]{m-1}+\sqrt[3]{m+1} -\sqrt[3]{m-1}}{\sqrt[3]{m+1} +\sqrt[3]{m-1}-\sqrt[3]{m+1} +\sqrt[3]{m-1}}\\\\\frac{x+1}{x-1} =\frac{2(\sqrt[3]{m+1})}{2(\sqrt[3]{m-1})} \\\\\frac{x+1}{x-1} =\frac{\sqrt[3]{m+1}}{\sqrt[3]{m-1}}[/tex]

Taking the cube of both sides, we have:

[tex](\frac{x+1}{x-1})^3 =(\frac{\sqrt[3]{m+1}}{\sqrt[3]{m-1}})^3\\\\\frac{(x+1)^3}{(x-1)^3}=\frac{m+1}{m-1}[/tex]

Applying the componendo and dividendo rule, we have:

[tex]\frac{(x+1)^3+(x-1)^3}{(x-1)^3-(x-1)^3}=\frac{m+1+(m-1)}{m-1-(m-1)}\\\\\frac{(x+1)^3+(x-1)^3}{(x-1)^3-(x-1)^3}=\frac{2m}{2} \\\\\frac{(x+1)^3+(x-1)^3}{(x-1)^3-(x-1)^3}=m\\\\\frac{2x^3+6x}{6x^2+2} =m\\\\\frac{2(x^3+3x)}{2(3x^2+1)} =m\\\\\frac{x^3+3x}{3x^2+1} =m\\\\x^3+3x=m(3x^2+1)\\\\x^3+3x=3mx^2+m\\\\x^3-3mx^2+3x=m[/tex]

Read more on componendo and dividendo here: https://brainly.com/question/134857

Answer:

-2

-Step-by-step explanation:

As, -6+(-2)= -6-2=-8

Thus, solved.

Hope it helps...

Answer:

y = -3

Step-by-step explanation:

y = x - 7

when x = 4

y = 4 - 7

y = -3

Answer:

See below.

Step-by-step explanation:

If x is 4, then replace x with 4 and simplify.

y=4-7

y=-3

-hope it helps

Answer:

(7, -3)

Step-by-step explanation:

If M is the midpoint you can use the same translation from A to M as M to B.

The movement from A to M is 5 units up and 3 units left, or (x+5, y-3). If we do the same movement to point M (Which is (2) +5, (0) -3) we will get (7, -3).

Answer:

the coordinates of B is B(7,-3)

Step-by-step explanation:

Solution,

Here, M(2,0) is the midpoint of a line segment joining the points A(-3,3)

and B(a,b)

Let,

(x,y)=(2,0)

(x1,y1)=(-3,3)

(x2,y2)=(a,b)

Now,

Using midpoint formula

[tex]x=\frac{x_1+x_2}{2} ,y=\frac{y_1+y_2}{2} \\\\2=\frac{-3+a}{2} ,0=\frac{3+b}{2} \\\\[/tex][Cross multiply]

[tex]4=-3+a,0=3+b\\\\4+3=a,0-3=b\\\\a=7,b=-3[/tex]

Answer:

y = -2x -1

Step-by-step explanation:

y-5=-2(x+3)

Distribute -2 × x and -2 × 3

y - 5 = -2x -6

y + 5 = -2x -6

y = -2x - 1

The expression is equivalent to [tex]5^2[/tex].

Given

Expression; [tex]\rm \dfrac{(5^2)^{-3}\times 5^4}{5^{-4}}[/tex]

The definition of exponential form is a way of writing a number that is multiplied by itself more than once.

To solve the exponential equation follow all the steps given below.

Therefore,

The expression is equivalent to;

[tex]\rm =\dfrac{(5^2)^{-3}\times 5^4}{5^{-4}}\\\\=\rm \dfrac{(5)^{-6}\times 5^4}{5^{-4}}\\\\=\rm \dfrac{(5)^{-6+4}}{5^{-4}}\\\\=\rm \dfrac{5^{-2}}{5^{-4}}\\\\=5^{-2+4}\\\\=5^2[/tex]

Hence, the expression is equivalent to [tex]5^2[/tex].

To know more about expression click the link given below.

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Answer:

676.8

Step-by-step explanation:

#carry on learning

Answer:

10

Step-by-step explanation:

b

Answer:

Constant of proportionality: [tex]\frac{1}{3}[/tex]

Equation: [tex]y=\frac{1}{3}x[/tex]

Step-by-step explanation:

The constant of proportionality is the ratio between y and x, according to the following formula

constant of proportionality = k = y/x

Take the given pairs and replace the data.

1.

[tex]k=\frac{\frac{2}{3}}{2}[/tex]

[tex]k = \frac{1}{3}[/tex]

2.

[tex]k = \frac{1}{3}[/tex]

3.

[tex]k=\frac{\frac{10}{3}}{10}[/tex]

[tex]k = \frac{1}{3}[/tex]

4.

[tex]k = \frac{4}{12}[/tex]

[tex]k = \frac{1}{3}[/tex]

As you can see, the constant is the same for all the pairs.

constant of proportionality = [tex]\frac{1}{3}[/tex]

Now, in order to know the equation make a graph of the given data.

The graph is in the picture

Since it is a line, use the equation of the line in point slope form

[tex]y- { y }_{ 1 } = m \left( x- { x }_{ 1 } \right)[/tex]

where (x1, y1) = any pair of the data

m = slope = constant of proportionality

Replace the data in the equation

[tex]y-1 = \dfrac{ 1 }{ 3 } \left( x-3 \right)[/tex]

Use the distributive property to multiply [tex]\frac{1}{3}[/tex] by x - 3

[tex]y-1=\frac{1}{3}x-1[/tex]

Add 1 to both sides

[tex]y = \dfrac{ 1 }{ 3 } x-1+1[/tex]

Add −1 and 1 to get 0

[tex]y=\frac{1}{3}x[/tex]

or

[tex]y=\frac{x}{3}[/tex]

Answer:

  no. A proportional relationship has a starting value of 0.

Step-by-step explanation:

The starting value of 200 means the relationship cannot be proportional. The starting value is always zero in a proportional relationship.

Answer:$3,170 is the answer

Step-by-step explanation:

The area of a circle with a radius of 5 cm is 50.272 [tex]cm^2[/tex] bigger than a circle with a radius of 3 cm.

Given the following data:

Mathematically, the area of a circle is given by the formula:

[tex]Area = \pi r^2[/tex]

Where:

For circle A:

[tex]Area = 3.142 \times 5^2\\\\Area = 3.142 \times 25[/tex]

Area = 78.55 [tex]cm^2[/tex].

For circle A:

[tex]Area = 3.142 \times 3^2\\\\Area = 3.142 \times 9[/tex]

Area = 28.278 [tex]cm^2[/tex].

Now, we can calculate the difference:

Difference = [tex]78.55-28.278[/tex]

Difference = 50.272 [tex]cm^2[/tex].

Read more on circle here: brainly.com/question/14478195

I've attached some theories related to angles have a look at it

Angle y and angle KJF are co-interior angles so they add up to 180°

132 + y = 180

y = 180 – 132

y = 48

y + z = 143 ( alternate angles )

48 + z = 143

z = 143 – 48

z = 95

Answer:

Yes they are.

Explanation:

x + y = 5

=

5 + 0 = 5

3x + y = 15

=

(3 × 5) + 0 = 15

Answer:

Train A is 168 tons and Train B is 122 tons

Step-by-step explanation:

well, the opening price was "x", which oddly enough is the 100%, however during the trading of the day the company gained 3.5%, so that'd be 100% + 3.5% = 103.5%, and we know that that is 16.56, so

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 16.56&103.5 \end{array}\implies \cfrac{x}{16.56}=\cfrac{100}{103.5}\implies 103.5x=1656 \\\\\\ x=\cfrac{1656}{103.5}\implies x=16[/tex]

Answer:

If R is supposed to be $ then the answer is $771 or estimated is $780

Step-by-step explanation:

131 = 130

246 = 250

394 = 400

For the expression 5.6j - 0.12 = 4 + 1.1j, the value of variable j is 0.92.

The operations of addition, subtraction, multiplication, and division do not change the truth value of any equation is called the property of equality.

The given expression is 5.6j - 0.12 = 4 + 1.1j.

To solve the above expression, we will use the following steps.

Step 1:

By the subtraction property of equality, subtract 1.1j on both sides. We get the expression,

[tex]5.6j - 0.12 -1.1j = 4 + 1.1 j - 1.1 j[/tex]

[tex]4.5 j -0.12 = 4[/tex]

Step 2:

By the addition property of equality, add 0.12 on both sides. We get the expression,

[tex]4.5j -0.12 + 0.12 = 4 + 0.12[/tex]

[tex]4.5 j = 4.12[/tex]

Step 3:

By the division property of equality, divide the above expression by 4.5. We get the expression,

[tex]\dfrac {4.5j}{4.5 }= \dfrac {4.12}{4.5}[/tex]

[tex]j = \dfrac {4.12}{4.5}[/tex]

[tex]j = 0.92[/tex]

Hence we can conclude that the value of variable j is 0.92.

To know more about the property of equality, follow the link given below.

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Answer:

[tex]{2}^{3} = 2 \times 2 \times 2 = 8[/tex]

Step-by-step explanation:

*We're focusing on 2 to the power of 3.

2^3 is represented as 2 x 2 x 2, 2 is being multiplied by itself 2 times.

When we multiply, we find the product of 8.

Therefore,

[tex] {2}^{3} = 2 \times 2 \times 2 = 8[/tex]

3.25 • 5 + 2.50 • 3 + 2 • 3 = x

16.25 + 7.50 + 6 = x

29.75 = how much they spent all-together