Use the reflection principle to find the number of paths for a simple random walk from So = 2 to S_15 = 5 that do not hit the line y = 2

Answers

Answer 1

The reflection principle is used to find the number of paths for a simple random walk from a starting point S0 to a destination point S15, without hitting a specific line.

In this scenario, we want to find the number of paths for a random walk from S0 = 2 to S15 = 5, without crossing the line y = 2. We can use the reflection principle to simplify the problem.

The reflection principle states that if a path hits a specific line and goes below it, we can reflect the portion of the path below the line to create a new path above the line. This new path is symmetric to the original path.

In our case, the line y = 2 acts as the reflecting line. We reflect the portion of the paths that hit the line y = 2 above the line. By doing so, we transform the problem into finding the number of paths from S0 = 2 to S15 = 5, without crossing or touching the line y = 2.

Using the principles of combinatorics and counting, we can calculate the number of valid paths without hitting the line y = 2. This involves considering the number of steps taken in the positive and negative y-directions, while ensuring that the path remains above the line y = 2. The specific calculations and details would require a more extensive analysis of the random walk and its possible movements.

By applying the reflection principle and counting the valid paths, we can determine the number of paths for the given scenario.

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Related Questions

In the domain of all penguins, let D(x) be the predicate "x is dangerous." Translate the following quantified statement into simple, everyday English.
(∃x)¬D(x)
Step-by-Step solution please.

Answers

The quantified statement (∃x)¬D(x) can be translated into simple, everyday English as "There exists a penguin that is not dangerous."

The quantified statement (∃x)¬D(x) can be further explained in the context of penguins. Let's break it down:

The symbol (∃x) denotes the existence of an object or entity that satisfies a certain condition. In this case, it refers to a penguin that meets the condition specified afterward.

The predicate ¬D(x) can be understood as the negation of the predicate D(x), where D(x) represents the statement "x is dangerous." The negation symbol (¬) in front of D(x) indicates the opposite or negation of the statement.

Combining these elements, the quantified statement (∃x)¬D(x) asserts that there is at least one penguin for which the predicate "is not dangerous" holds true. In everyday English, this statement can be translated as "There exists a penguin that is not dangerous."

Essentially, it implies that within the domain of all penguins being considered, at least one penguin can be found that is not considered dangerous. This quantified statement allows for the possibility that not all penguins are dangerous and acknowledges the existence of non-threatening penguins.

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the cost of a catering prom is 250 plus $15 for each person attending. what is the cost of 150 people?

Answers

Answer:

$2500

Step-by-step explanation:

First, multiply the $15 for the 150 people attending, to get 2250. Next, add the last $250 to get a total cost of $2500

Hopefully this helps- let me know if you have any questions!

Answer:

i think it is 2500

Step-by-step explanation:

take 15 times the amount of people. then add the 250 fee

A class interval refers to:
a) the number of categories within a group of data
b) a division used for grouping a set of observations
c) the mean of the set of data
d) the range of ages among a group of students

Answers

A class interval refers to option b) a division used for grouping a set of observations.

The correct answer is (b) a division used for grouping a set of observations. In statistics, when dealing with a large set of data, it is often helpful to group the data into intervals or classes to better understand the distribution. A class interval represents a range of values that are grouped together. It is defined by specifying the lower and upper boundaries of each interval.

For example, if we are analyzing the heights of individuals, we may create class intervals such as 150-160 cm, 160-170 cm, and so on. The purpose of using class intervals is to simplify the data and provide a clearer picture of the distribution. It allows us to summarize the data and identify patterns or trends within specific ranges. Therefore, option (b) is the correct description of a class interval.

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Probability 0.35 0.3 0.05 0.1 0.05 0.15 8 9 10 11 Find the expected value of the above random variable.

Answers

The expected value of the given random variable is 8.3. This means that, on average, if we repeatedly sample from this random variable, we can expect the resulting values to be around 8.3.

To find the expected value of a random variable, you multiply each possible value by its corresponding probability and sum them up. In this case, we have a combination of probabilities and numerical values. Let's calculate the expected value:

Multiply each numerical value by its corresponding probability:

(0.35 * 8) + (0.3 * 9) + (0.05 * 10) + (0.1 * 11) + (0.05 * 11) + (0.15 * 11)

Perform the calculations:

2.8 + 2.7 + 0.5 + 1.1 + 0.55 + 1.65

Sum up the results:

8.3

Therefore, the expected value of the given random variable is 8.3. This means that, on average, if we repeatedly sample from this random variable, we can expect the resulting values to be around 8.3. The expected value provides a measure of central tendency for the random variable.

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True or False
_____ The ANOVA Test uses the entire bell
_____ There are 2 types of hypotheses
_____ The null hypothesis may posit that there is no significant difference betwe

Answers

The given question can be answered as follows:

True or False:

The ANOVA Test uses the entire bell. - False_

____ There are 2 types of hypotheses. - True_

____ The null hypothesis may posit that there is no significant difference between - True

Explanation:

ANOVA (Analysis of Variance) is a statistical test used to determine whether two or more population means are equivalent. It does not use the entire bell, so the statement is false.There are two types of hypotheses: the null hypothesis and the alternative hypothesis. The statement is true.The null hypothesis is used to determine if there is a significant difference between two or more sets of data. It can posit that there is no significant difference between two or more sets of data. So, the statement is true.

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The ANOVA Test uses the entire bell is a false statement.

There are 2 types of hypotheses is a true statement.

The null hypothesis may posit that there is no significant difference between the groups is a true statement.

Hence, the correct answer is: False; True; True.

The given statements can be summarized as follows: Statement 1 is that the ANOVA Test uses the entire bell. It is false.

Statement 2 is that there are 2 types of hypotheses. It is True.

Statement 3 is that the null hypothesis may posit that there is no significant difference between the groups. It is True.

Hence, the correct answer is: False; True; True.

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Find the missing side length of
the triangle.

Answers

Answer:

50 units

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Equality Properties

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

a is a leg b is another leg c is the hypotenuse

Step-by-step explanation:

Step 1: Define

a = 48

b = 14

c = ?

Step 2: Solve for c

Substitute in variables [Pythagorean Theorem]:                                            48² + 14² = c²Evaluate exponents:                                                                                         2304 + 196 = c²Add:                                                                                                                   2500 = c²[Equality Property] Square root both sides:                                                    50 = cRewrite:                                                                                                             c = 50

Please help me solve these two questions

Answers

I hope the answer is helpful

i’m sorry this isn’t an answer i just rly need points so i can ask a test question

A zoo has 5 Emperor penguins. The Emperor penguins make up 30%, percent of all the penguins at the zoo. How many penguins live at the zoo

Answers

Answer:

50

Step-by-step explanation:

this can be solved by ratio   15/x = 30/100.  Cross multiply and solve for x.  The answer is 50.

Two level factorial experimentation led to the following model of the manufacturing yield (in terms of percentage of good products): ỹ = 95 +3.5x, -1.6x, +0.9x,x, where x, denotes reactor temperature, while X2 denotes air pressure. Experimental noise was estimated to be o, = 0.6. a) What are the main and interaction effects of the relevant variables. (6 points) b) During experimentation, the temperature was varied between 300K and 320K, while pressure was varied between 100kPa and 200kPa. Estimate the probability that the yield would be higher than 96% for temperature of 315K and pressure of 130kPa?

Answers

The main effects of the relevant variables are 3.5x and -1.6x, while the interaction effect is 0.9x*x.

The given model for manufacturing yield, expressed as a percentage of good products, is represented by the equation ỹ = 95 + 3.5x - 1.6x + 0.9x*x. In this equation, x represents the reactor temperature, and X2 represents the air pressure.

The coefficient 3.5 corresponds to the main effect of the reactor temperature, indicating that for each unit increase in temperature, the yield is expected to increase by 3.5 percentage points.

Similarly, the coefficient -1.6 represents the main effect of air pressure, implying that for each unit increase in pressure, the yield is expected to decrease by 1.6 percentage points.

Additionally, the term 0.9x*x accounts for the interaction effect between temperature and pressure. This suggests that the combined influence of temperature and pressure on the yield is not solely determined by the sum of their individual effects. Instead, the interaction effect captures the nonlinear relationship between these variables.

To estimate the probability of the yield being higher than 96% for a temperature of 315K and pressure of 130kPa, we need to evaluate the model equation for these specific values.

Substituting x = 315 and X2 = 130 into the equation, we can calculate the corresponding yield. If the yield exceeds 96%, the estimated probability would be 100%; otherwise, it would be 0%.

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The price of calculator is increased from R150 to R174.What is the percentage increased​

Answers

Answer:

16%

Step-by-step explanation:

(174-150)/150= 0.16

0.16*100 = 16%

What value does the 2 represent in the number 0.826

Answers

I think it’s the Tens?

Answer:

.02

Step-by-step explanation:

Matt tried to evaluate 49 x 24 using partial products. His work is shown below

Answers

Answer:

step 5

Step-by-step explanation:

10.
Consider the two properties that you would use to solve an equation like 3x + 5 = 26. Which of the following is true?


A. The standard method for solving an equation like 3x + 5 = 26 is to use the Multiplication Property of Equality and then the Division Property of Equality.

B. The standard method for solving an equation like 3x + 5 = 26 is to use the Division Property of Equality and then the Subtraction Property of Equality.

C. The standard method for solving an equation like 3x + 5 = 26 is to use the Subtraction Property of Equality and then the Division Property of Equality.

D. The standard method for solving an equation like 3x + 5 = 26 is to use the Subtraction Property of Equality and then the Addition Property of Equality.

Answers

Answer:

The standard method for solving an equation like 3x + 5 = 26 is to use the Subtraction Property of Equality and then the Division Property of Equality.

Step-by-step explanation:

To solve, you subtract both sides by 5 first. Then you divide both sides by 3 to isolate the x.

Find the value of x that makes the equation true:

2x = 24

x = 6
x = 4
x = 9
x = 12

Answers

Answer:

x = 12 the correct answer

match each hypotenuse with the leg that will create a right
triangle ​

Answers

Answer:

Where is the question so that I can help you with it

number 3 please help me​

Answers

F(x) = 2
F(x) = 3x - 1
2 = 3x - 1
3x = 3, x = 1

Solution: x = 1

Answer:

D. {1}

Explanation:

given f(x) = 3x - 1

for f(x) = 2

3x - 1 = 2

3x = 2 + 1

3x = 3

x = 3/3

x = 1

Complete the table of values y = x2 + 4x - 6

Answers

Answer:

x=-2

Step-by-step explanation:

Joe's lunch at a restaurant cost $18.00 without tax he leaves the server a tip of 14% of the cost of lunch without tax what is the total cost of lunch including tip without tax​

Answers

Ok. So 14% of 18.00 can be figured out without a calculator. 18.00 / 10 = 1.80 = 10%.

(18.00 / 100) x 4 = 0.72

1.80 + 0.72 = $2.52 is the tip.

$18 + $2.52 = $20.52

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Which of the following is equal to the expression listed below?
18 + 12
OA. 6(3+2)
OB. (6 x 3)(6 x 2)
OC. 6+ (3 x 2)
OD. (6 + 3)(6 + 2)

Answers

Answer:

OA

Step-by-step explanation:

18+12=30

6×3=18

6×2=12

18+12=30

hope this helps

Answer:

Which of the following is equal to the expression listed below?

18 + 12

OA. 6(3+2)

OB. (6 x 3)(6 x 2)

OC. 6+ (3 x 2)

OD. (6 + 3)(6 + 2)

Step-by-step explanation:

the answer is (B)

find the general solution of the indicated differential equation. If possible, find an explicit solution. 1. y =xy 2. xy =2y 3. y =e
x−y 4. y =(1+y 2)e x5. y =xy+y 6. y =ye x −2e x +y−2 7. y =x/(y+2) 8. y =xy/(x−1) 9. x 2 y =ylny−y 10. xy −y=2x 2y 11. y 3y =x+2y 12. y =(2xy+2x)/(x 2−1)

Answers

The general solution of the differential equation y = xy is y = C[tex]e^{(x^2/2)[/tex], where C is a constant.The general solution of the differential equation xy = 2y is y = Cx², where C is a constant.The general solution of the differential equation y = [tex]e^x[/tex] − y is y = C[tex]e^x[/tex] + [tex]e^{(2x)[/tex], where C is a constant.The general solution of the differential equation y = (1 + y²)[tex]e^x[/tex] is y = tan(C + [tex]e^x[/tex]), where C is a constant.The general solution of the differential equation y = xy + y is y = [tex]Ce^{(x^2/2)[/tex] − x, where C is a constant.The general solution of the differential equation y = y[tex]e^x[/tex] − 2[tex]e^x[/tex] + y − 2 is y = C[tex]e^x[/tex] − 2[tex]e^x[/tex] + 2, where C is a constant.The general solution of the differential equation y = x/(y + 2) is y² + 2y − x = 0. It is a quadratic equation that does not have an explicit solution.The general solution of the differential equation y = xy/(x − 1) is y = C(x − 1), where C is a constant.The general solution of the differential equation x²y = yln(y) − y is y = [tex]e^{(W(C/x^2))[/tex], where W is the Lambert W function and C is a constant.The general solution of the differential equation xy − y = 2x²y is y = [tex]Ce^{(x^2/2)[/tex], where C is a constant.The general solution of the differential equation y³ − y = x + 2y is y = [tex](x + C)^{(1/2)[/tex], where C is a constant.The general solution of the differential equation y = (2xy + 2x)/(x² − 1) is y = C(x − 1) + 1, where C is a constant.

The equations you mentioned:

1. y = xy:

To solve this differential equation, we can separate the variables and integrate both sides.

dy/y = x dx

Integrating both sides gives:

ln|y| = (1/2)x² + C

Exponentiating both sides gives the general solution:

|y| = [tex]e^{((1/2)x^2 + C)[/tex]

Taking the positive and negative values of y, we get two branches of solutions:

y = [tex]Ae^{(1/2)x^2[/tex] and y = [tex]-Ae^{(1/2)x^2[/tex], where A is an arbitrary constant.

2. xy = 2y:

Rearranging the equation, we get:

xy - 2y = 0

Factoring out y, we have:

y(x - 2) = 0

This equation has two solutions:

y = 0 and x - 2 = 0, which leads to x = 2.

3. y = [tex]e^x[/tex] - y:

Rearranging the equation, we get:

y + y = [tex]e^x[/tex]

Combining like terms, we have:

2y = [tex]e^x[/tex]

Dividing both sides by 2, we get:

y = (1/2)[tex]e^x[/tex]

4. y = (1 + y²)[tex]e^x[/tex]:

Rearranging the equation, we get:

y - y² = [tex]e^x[/tex]

Factoring out y, we have:

y(1 - y) = [tex]e^x[/tex]

This equation has two solutions:

y = 0 and 1 - y = [tex]e^x[/tex], which leads to y = 1 - [tex]e^x[/tex].

5. y = xy + y:

Rearranging the equation, we get:

y - xy - y = 0

Combining like terms, we have:

-xy = 0

This equation has two solutions:

x = 0 and y = 0.

6. y = y[tex]e^x[/tex] - 2[tex]e^x[/tex] + y - 2:

Rearranging the equation, we get:

y[tex]e^x[/tex] - y = 2[tex]e^x[/tex]- 2

Factoring out y, we have:

y([tex]e^x[/tex] - 1) = 2([tex]e^x[/tex] - 1)

Dividing both sides by ([tex]e^x[/tex] - 1), we get:

y = 2

7. y = x/(y + 2):

Rearranging the equation, we get:

y(y + 2) = x

Expanding the equation, we have:

y² + 2y - x = 0

This equation doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

8. y = xy/(x - 1):

Rearranging the equation, we get:

(x - 1)y = xy

Dividing both sides by y and rearranging, we have:

x - 1 = x/y

Solving for y, we get:

y = x/(x - 1)

9. x²y = ylny - y:

This is a nonlinear differential equation that doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

10. xy - y = 2x²y:

Rearranging the equation, we get:

xy - 2x²y - y = 0

Factoring out y, we have:

y(x - 2x² - 1) = 0

This equation has two solutions:

y = 0 and x - 2x² - 1 = 0, which leads to x = (1 ± √3)/2.

11. y - 3y² = x + 2y:

Rearranging the equation, we get:

-3y² + y + 2y - x = 0

Combining like terms, we have:

-3y² + 3y - x = 0

This equation doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

12. y = (2xy + 2x)/(x² - 1):

Rearranging the equation, we get:

y(x² - 1) = 2xy + 2x

Expanding the equation, we have:

x²y - y = 2xy + 2x

Combining like terms, we get:

x²y - 2xy - y - 2x = 0

This equation doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

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What is the surface area of the prism below?
A
216 ft2

B
312 ft2

C
432 ft2

D
10,800 ft2

Answers

the answer is C 432 ft 2

An endocrinologist is interested in the effects of depression on the thyroid. It is believed that healthy subjects have a mean thyroxin (a hormone related to thyroid function) level of 7.0 micrograms/100 ml and a standard deviation of 1.6 micrograms/100 ml. The endocrinologist wants to assess whether the mean thyroxin level is different for those with depression. She samples 35 subjects with depression and obtains a sample mean of 7.82 micrograms/100 ml for thyroxin. What null and alternative hypotheses should she test

Answers

Answer:

H0: μ = 7.0

H1: μ > 7.0

Step-by-step explanation:

The null hypothesis will equal and take up the value of the population mean value ;

The population mean value, μ is 7.0

Null hypothesis ; H0: μ = 7.0

The alternative hypothesis will align with the claim ; which will take up and side with the value and direction of the sample mean ; 7.82 micrograms/100 ml

7.82 > 7.0 (sample mean is greater Than the population mean).

Hence, the alternative hypothesis, H1 will be ;

H1 : μ > 7.0

6. Select the coldest temperature from the list below. * O -11°F O 7°F O -4°F O 20°F​

Answers

Answer:

-11 degrees Fahrenheit.

Step-by-step explanation:

the higher the negative number is, the colder it gets <D

help plz ? Mark brainliest?

Answers

Answer:

-1(3x^2) +4x-7

Step-by-step explanation:

grouping

why do i have depression

Answers

Answer:

are u ok tho

Step-by-step explanation:

Soojeong estimates that it is going to take $180,000 to send her new born baby to college. She would like to start an annuity so that she can have $180,000 after 18 years. If the account earns 5.5% interest compounded monthly, how much must she put in each month?

Answers

Answer:

Monthly deposit= $489.59

Step-by-step explanation:

Giving the following information:

Future Value (FV)= $180,000

Number of periods (n)= 18*12= 216

Interest rate (i)= 0.055 / 12= 0.004583

To calculate the monthly deposit, we need to use the following formula:

FV= {A*[(1+i)^n-1]}/i

A= monthly deposit

Isolating A:

A= (FV*i)/{[(1+i)^n]-1}

A= (180,000*0.004583) / {[(1.004583)^216] - 1}

A= $489.59

What value of x makes this proportion true? x/6=36/24 O A. 8 O B. 9 O C. 18 O D. 7​

Answers

Answer:

B. 9

Step-by-step explanation:

Proportions are just like fractions and to figure them out sometimes you can use simplification in different forms.

[tex]\frac{x}{6}[/tex] = [tex]\frac{36}{24}[/tex]

Now to get to 6, 24 had to be divided by 4...in proportions and fractions usually, the top and bottom are both simplified or proportioned to the same number or scale

36 ÷ 4 = 9

Check your answer by inserting it there to see if it works

9*4 = 36            6*4 = 24

Answer:

[tex]\boxed {\boxed {\sf B. \ 9}}[/tex]

Step-by-step explanation:

We are given this proportion:

[tex]\frac {x}{6}=\frac{36}{24}[/tex]

We want to solve for x, so we must isolate the variable using inverse operations.

It is being divided by 6. The inverse of division is multiplication, so we multiply both sides of the proportion by 6.

[tex]6*\frac {x}{6}=\frac{36}{24}*6[/tex]

[tex]x=\frac{36}{24}*6[/tex]

[tex]x=1.5*6 \\x=9[/tex]

Another way to solve is with cross multiplication. Multiply the first numerator by the second denominator, then the first denominator by the second numerator.

[tex]\frac { x}{6}=\frac{36}{24}[/tex]

[tex]24*x=6*36[/tex]

[tex]24x=216[/tex]

The variable is being multiplied by 24. The inverse of multiplication is division, so we divide both sides of the equation by 24.

[tex]24x/24=216/24\\x=9[/tex]

The value of x that makes this proportion true is 9.

I need help on this math problem fast with work shown and answer thx

Answers

Answer:

angle 1 = 124

angle 2 = 56

angle 3 = 124

angle 4 = 56

Step-by-step explanation:

This problem is a bit like a puzzle. To make notation easier I'm going to do this:

angle 1 = a

angle 2 = b

angle 3 = c

angle 4 = d

Now, let's start with what we know from the image.

All angles added together form a circle or 360 degrees

a + b + c + d = 360

In the same regard a + d = 180, and b + c = 180

Also,

a = c

and

b = d

It also tells us angle 4 is 25 degrees greater than one fourth of angle 1. Which is written as.

d = 1/4(a) + 25

If we look at all the equations we have, we can see that two of the equations have two of the same variables:

a + d = 180

and

d = 1/4(a) + 25

Using substitution we can take the second equation substitute it for d in the first equation giving us:

a + (1/4(a) + 25) = 180

Now we just solve for a

[tex]\frac{4}{4} a+ \frac{1}{4} a + 25 = 180\\\\\frac{5}{4}a + 25 = 180 \\\\(\frac{5}{4}a + 25) - 25 = (180) -25\\\\\frac{5}{4} a = 155\\\\\frac{5}{4} a * \frac{4}{5} = 155 * \frac{4}{5}\\\\a = 124[/tex]

Therefore a, or angle 1, is 124

Since a = c, then c, or angle 3, is also 124

Since a + d = 180 and a = 124 then

d = 180 -124

d = 56

So, d, or angle 4, is 56

And because b = d then b, or angle 2, is also 56

a = 124

b = 56

c = 124

d = 56

For extra measure, we can check our work by using the first equation

a + b + c + d = 360

124 + 56 + 124 + 56 = 360

Find the next two terms in
the sequence 11, 7, 3,-1,​

Answers

Answer:

The next term will be -5.

Step-by-step explanation:

This is actually an AP with a = 11 and common difference d = -4.

Therefore next term will be -1 - 4 = -5

Answer:

Step-by-step explanation:

The numbers in this sequence come by subtracting 4 so

11, 7, 3, - 1, - 5, - 9, - 13

Given function f(x) = (x + x)(log(x) + 3x) a) Show O(x) for f(x). You must show the obtained witnesses and k such that f) C(x) whenever x > k.(5 points) b) Show (x) for f(x). You must show the obtained witnesses and k such that f(x) Clg(x) whenever x > k. (5 points) c) What are the obtained witnesses C. C, and k such that Glg(x) (x) < Calg(x) whenever * >k. What is g(x).

Answers

a. For the function f(x) = (x + x)(log(x) + 3x) is O(x) with the witnesses C = 7 and k = 1.

b. It is proved that f(x) = (x + x)(log(x) + 3x) is (x) with the witnesses C = 1 and k = 1.

c. The obtained witnesses C = 1, C' = 10, and k =[tex]10^C.[/tex] such that g(x)log(x) < Cg(x) whenever x > k. And g(x) = 1.

a) To show that f(x) = (x + x)(log(x) + 3x) is O(x),

find witnesses C and k such that f(x) ≤ C × x for all x > k.

Let's simplify the expression for f(x):

f(x) = 2x × (log(x) + 3x)

= 2x × log(x) + 6x²

Now, find a witness C and a value k such that f(x) ≤ C × x for all x > k.

Let's choose C = 7 and k = 1.

This means show that f(x) ≤ 7x for all x > 1.

For x > 1,

f(x) = 2x × log(x) + 6x²

< 2x × log(x) + 6x² + 7x

= 2x × log(x) + 6x² + 7x

= x(2log(x) + 6x + 7)

≤ x(2log(x) + 13x)

≤ x × 7

= 7x

This implies,

f(x) = (x + x)(log(x) + 3x) is O(x) with the witnesses C = 7 and k = 1.

b) To show that f(x) = (x + x)(log(x) + 3x) is (x),

find witnesses C and k such that f(x) ≥ C × x for all x > k.

Let us simplify the expression for f(x):

f(x) = 2x × (log(x) + 3x)

= 2x × log(x) + 6x²

Now, find a witness C and a value k such that f(x) ≥ C × x for all x > k.

Let us choose C = 1 and k = 1.

This means show that f(x) ≥ x for all x > 1.

For x > 1,

f(x) = 2x × log(x) + 6x²

> x × log(x) + 6x²

= x(log(x) + 6x)

≥ x(log(x) + x)

≥ x × log(x)

≥ x

Therefore, we have shown that f(x) = (x + x)(log(x) + 3x) is (x) with the witnesses C = 1 and k = 1.

c) To find the obtained witnesses C, C', and k .

such that g(x)log(x) < Cg(x) whenever x > k,

Examine the expression f(x) = (x + x)(log(x) + 3x) and determine the function g(x).

Let us simplify the expression for f(x),

f(x) = 2x × (log(x) + 3x)

= 2x × log(x) + 6x²

From the given condition, we have g(x)log(x) < Cg(x) rewrite this as,

log(x) < C

Since log(x) is an increasing function, if log(x) < C, it means x < [tex]10^C.[/tex]Therefore, the witness k is [tex]10^C.[/tex]

Now let us determine g(x).

Since g(x)log(x) appears in the inequality, we can take g(x) = 1.

C = 1, C' = 10, and k = [tex]10^C.[/tex] for g(x)log(x) < Cg(x) whenever x > k. And g(x) = 1.

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