Use the model to find the missing number in the pair of equivalent expressions.

15 + 9 = ?(5 + 3)

What number is missing from the expression?

Step-by-step explanation:

option D is correct.

hope this answer helps you dear! take care

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The additional information to prove the Triangles congruent is ~

The Triangles are congruent by SAS congruency criteria ~

Applying limits, it is found that since [tex]a \neq 0, \frac{a}{2} \neq 0[/tex], and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

The function is given by:

[tex]F(x) = \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}[/tex]

The horizontal asymptote is the limit of the function as x goes to infinity, hence:

[tex]y = \lim_{x \rigtharrow \infty} F(x) = \lim_{x \rigtharrow \infty} \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}[/tex]

Considering only the terms with the highest exponents:

[tex]y = \lim_{x \rigtharrow \infty} \frac{ax^2}{2x^2} = \frac{a}{2}[/tex]

Since [tex]a \neq 0, \frac{a}{2} \neq 0[/tex], and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

For more on horizontal asymptotes and limits, you can check https://brainly.com/question/11598999

Answer:

31:18:12

............................

Answer:

I might be wrong i think its C but double check and dont put it in until you are sure its right

Step-by-step explanation:

Answer:

Smaller angle : 30 degrees

Bigger Angle : 65 degrees

Step-by-step explanation:

85+6x+13x=180, 85+19x=180,19x=95,x=5

Smaller angle : 30

Bigger Angle : 65

Answer:

The key to developing a great credit score is not a formula, but there are certain general recommendations that may be followed. Make on-time payments on your debts on a consistent basis. One strategy to ensure that your payments are made on time is to set up automated payments or electronic reminders for your accounts. If you've fallen behind on your payments, get up to date and remain up to date.

Step-by-step explanation:

Hope it helps if this is what you mean;)

Answer:

velocity

Step-by-step explanation:

The velocity of the object is continually changing.  This velocity is the slope of the tangent line to the curve at a given point on the curve.

The corrected sentence is: When an object moves in a circle, the velocity of the object is continually changing.

Circular motion involves not only changes in the object's orientation or direction but also changes in its velocity.

Velocity includes both the speed of the object's movement and its direction. As an object moves around a circle, even if it maintains a constant speed, its velocity is changing because the direction in which it is moving is always changing.

This change in velocity is what allows the object to maintain its circular path rather than moving in a straight line.

Learn more about Velocity

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Answer:

0

Step-by-step explanation:

Sin 30° = ½

Cos 30° = √3/2

Sin 60° = √3/2

Cos 60° = ½

Therefore,

(½ + √3/2) - (√3/2 + ½)

[tex] \frac{1 + \sqrt[]{3} }{2} - \frac{ \sqrt{3 + 1} }{ 2 } [/tex]

[tex] \frac{1 + \sqrt{3} - \sqrt{3} - 1}{2} [/tex]

[tex] \frac{0 - 0}{2} [/tex]

Answer: 0

For more information on trigonometric refer to this link

Answer:

wedge

Step-by-step explanation:

Answer:

13 ≈ 10 miles

Step-by-step explanation:

Have a nice day

You start driving east for 5 miles, turn left, and drive north for another 12 miles. At the end of driving So, the straight-line distance from your starting point is 13 miles.

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

You start driving east for 5 miles, turn left, and drive north for another 12 miles. At the end of driving,

[tex]|AC|^2 = |AB|^2 + |BC|^2 \\\\|AC|^2 = |5|^2 + |12|^2 \\ \\|AC|^2 = 25 + 144 \\\\AC = \sqrt{169} \\\\AC = 13[/tex]

Learn more about Pythagoras' theorem here:

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Answer:

I believe that its C, but don't get mad at me if I get it wrong

Answer:

£120

Step-by-step explanation:

original_price = discounted_price / (1 - discount / 100)

78/(1-35/100)=120

[tex] \frac{2}{5} \times \frac{4}{7} + \frac{21}{35} \\ = \frac{8}{35} + \frac{21}{35} \\ = \frac{8 + 21}{35} \\ = \frac{29}{35} [/tex]

[tex] \frac{29}{35} [/tex]

Hope it helps.

Do comment if you have any query.

Answer: k = 3

-2k - 4k = -18

-2k - 4k = -18

-6k = -18

k = -18/-6

k = 3

Would appreciate brainly <3

Answer:

Step-by-step explanation:

=> -2k - 4k = -18

=> -6k = -18

[tex] = > k = \frac{ - 18}{ - 6} [/tex]

=> k = 3 (Ans)

Answer:

To change a rectangular equation to a polar equation just replace x with r cos θ and y with r sin θ .

Answer:

X over y or x/y since y is claire and she skated more

Step-by-step explanation:

Pls brainliest

Answer: $4526

Step-by-step explanation:

Ratio of employees to cash

157:710528

Divide both sides by 157 to find how much 1 employees is paid

1: 4526

Answer:

710 582 - salary of all employees in a month

157 - number of employees

The monthly salary of each employee is 4526.

The 4526 is obtained by dividing the salary of all employees to their number which is 157.

The question is, "What is the salary of 1 employee assuming all are paid EQUALLY?"

To get it, just multiply 4526 into 12 (annually). So the answer is 54312

Given info:- [tex]\textsf{If (√3+√2)/(3√2-2√3) = x+y√6,} [/tex]

[tex]\textsf{then find the value of x and y?}[/tex]

Explanation:-

[tex]\textsf{Consider LHS=}\\[/tex]

[tex] \rm \: \frac{ \sqrt{2 } + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \\ [/tex]

[tex] \rm \: = \frac{ \sqrt{2 } + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ [/tex]

[tex] = \rm \: \frac{( \sqrt{2 } + \sqrt{3} )(3 \sqrt{2} + 2 \sqrt{3} )}{(3 \sqrt{2} - 2 \sqrt{3})(3 \sqrt{2} + 2 \sqrt{3}) } \\ [/tex]

[tex] \rm \: = \frac{3 \sqrt{2 \times 2} + 2 \sqrt{3 \times 2} + 3 \sqrt{2 \times 3} + 2 \sqrt{3 \times 3} }{(3 \sqrt{2} {)}^{2} - (2 \sqrt{3} {)}^{2} } \\ [/tex]

[tex] \rm = \frac{3 \times 2 + 2 \sqrt{6} + 3 \sqrt{6} + 2 \times 3}{18 - 12} \\ [/tex]

[tex] \rm \: = \frac{12 + 5 \sqrt{6} }{6} \\ [/tex]

[tex] \rm \: = 2 + \frac{5}{6} \sqrt{6} \\ [/tex]

[tex] \rm \therefore \: 2 + \frac{5}{6} \sqrt{6} = x + y \sqrt{6} \\ [/tex]

[tex]\textsf{On, comparing with RHS we notice that:}\\[/tex]

[tex]\textsf{the value of x = 2 and y = 5/6.}\\[/tex]

[tex]\bf{Read more:}[/tex]

[tex]\textsf{Similar questions}\\[/tex]

[tex] \sqrt{6} + \sqrt{11} \div \sqrt{5} + \sqrt{3} [/tex] A. [tex] \sqrt{30} + 3 \sqrt{2} + \sqrt{55} + \sqrt{33} \div 8[/tex] B. [tex] \sqrt{30} - 3 \sqrt{2} ...

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Answer:

1. No

2. No

3. No

4. Yes

Step-by-step explanation:

Insert each y value into the equation. If it equals -14, then it is a solution to the equation. The only one of these y values that is a solution is the last one, -2.

8 * (-2) = -16

-16 + 2 = -14

So y = -2 is a solution.

Answer:

144 cm²

Step-by-step explanation:

Remember: If you are finding the area of a square and are given a side, you can simply square it and it will be the area. Thus:

12 x 12 cm = Area of tile.

=> 144 cm² = Area of tile.

Therefore, 144 cm² is the area.

Hoped this helped.

Anser

(b2 – 4ac). sorry if this doesnt help it doesnt make sense on my screen it shows a weird equation

Step-by-step explanation:

[tex](x + 4)(x - 5)[/tex]

#carryonlearning

see the attachment for the explanation

Answer:

Look at photo

Step-by-step explanation:

We want to find the distance that Jill and her friend must walk, we will see that the distance is (1 + 1/6) miles

So the total distance of the travel is:

(3 + 1/2) miles.

2/3 of that distance are made in the car, then the other 1/3 is the distance that they must walk. A rough sketch of the situation is shown at the end.

Then we must solve:

(1/3)*(3 + 1/2) miles = ((1/3)*3 + (1/3)*(1/2)) miles

= (1 + 1/6) miles

So the distance that they must walk is (1 + 1/6) miles

If you want to learn more, you can read:

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Step-by-step explanation:

According to the given we have following inequalities:

See the graph attached below.

Solution region is within the triangle with marked vertices.