The final position of the object after 2 s is 11 m.
Motion: This can be defined as the change in position of a body.
⇒ Formula:
x = x₀+v₀t+1/2(at²)........................ Equation 1⇒ Where:
x = Final position of the objectx₀ = Starting positionv₀ = Starting velocityt = timea = accelerationFrom the question,
⇒ Given:
x₀ = 4.5 m/st = 2 sx₀ = 2ma = 0 m/s²⇒ Substitute these values into equation 1
x = 2+(4.5×2)+1/2(0²×2)x = 2+9+0x = 11 mHence, The final position of the object after 2 s is 11 m
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What would the single sample Cohen's d value be if the difference in sample mean and hypothesized mean was 16, and the sample standard deviation was 4?
Answer:
Explanation:
To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).
A ball has the energy to move 30 m/s with the mass of 5. What is the energy
True or False. What makes faith genuine is its object.
Answer:true
Explanation:
A cylinder with a radius of 1.8 cm is floating in water as shown below. The mass of the cylinder is 1.80 kg. Calculate the depth of the bottom end of the cylinder
Answer:
Explanation:
I will ASSUME that the cylinder floats with the axis through the center of its flat ends is perpendicular to the water surface.
The cylinder will displace it's mass in water.
water density has a value of 1000 kg/m³
if the depth of the bottom is "h" in meters
1.80 kg = π(0.018² m²)(h m)(1000) kg/m³
h = 1.768388256...
or about 1.77 m
a car moving at 5 m/s accelerates at a rate of 10 m/s2 for 25 seconds. How far does it move during this time?
Answer:
t is time in s For example, a car accelerates in 5 s from 25 m/s to 3 5m/s. Its velocity changes by 35 - 25 = 10 m/s. Therefore its acceleration is 10 ÷ 5 = 2 m/s2
Explanation:
Convert the decimal number 61078 to binary by using sum-of-weights method
Answer:
1110111010010110
Explanation:
I am not able to upload the working out using the sum of weights method sorry
a 2000kg car initially traveling at a speed of 15 m/s is accelerated by a constant force of 10000 n for 3 seconds. the new speed of the car is
Answer:
The new speed of the car is 30 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Model how solutes dissolve into solvents. Describe how different types of solutes and solvents might attract or repel each other.
A solvent is any substance which is able to interact with a solute and dissolve it.
A solute is any substance that is able to interact with a solvent and dissolve in it. Usually, the solute must posses similar intermolecular forces as the solvent.
For this reason, polar solutes dissolve in polar solvents while nonpolar solutes dissolve in nonpolar solvents. In polar solutes, the ions or dipoles of the solute are able to interact with the dipoles of the solvent thereby pulling the solute particles apart in order to have solvent - solute interaction.
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Hey guys can you help me solve this problem "how long will it take a car travelling 30m/s to come to stop ifs its acceleration is -3 m/s2".
Answer:
10 seconds.
Explanation:
We can use a kinematic equation where we know the final velocity, initial velocity, acceleration, and need to determine the time t:
[tex]\displaystyle v_f = v_i + at[/tex]
The initial velocit is 30 m/s, the final velocity is 0 m/s (as we stopped), and the acceleration is -3 m/s².
Substitute and solve for t:
[tex]\displaystyle \begin{aligned} (0\text{ m/s}) & = (30 \text{ m/s}) + (-3 \text{ m/s$^2$}) t \\ \\ t & = \frac{-30\text{ m/s}}{-3 \text{ m/s$^2$}} \\ \\ & = 10 \text{ s} \end{aligned}[/tex]
Hence, it will take the car 10 seconds to come to a stop.
A 4.0 kilogram projectile is fired horizontally from a 500 kilogram cannon initially at rest. The momentum of the projectile after being fired is 600 kilogram-meters per second to the north
(neglecting friction).
What is the speed of the cannon after firing?
0.83 m/s
1.2 m/s
o
3.3 m/s
150 m/s
The speed of the cannon after firing is 1.2 m/s
This can be solved using the law of conservation of momentum.
From the law of conservation of momentum,
⇒ The momentum of the projectile is equal to the momentum of the cannon.
MV = P................ Equation 1⇒ Where :
M = mass of the cannon,V = velocity of the cannonP = momentum of the projectile.⇒ make V the subject of the equation
V = P/M.................. Equation 2From the question,
⇒ Given:
P = 600 kgm/sM = 500 kg⇒ Substitute these values into equation 2
V = 600/500V = 1.2 m/sHence, The speed of the cannon after firing is 1.2 m/s
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The range of a Cannon ball fired horizontally from a laboratory table equals to 8/ 3 times the height of the table . what is the direction of the velocity of the projectile as it strikes the ground?
A,450 from the horizontal
B,600 from the horizontal
C,530 from the horizontal
D,370 from the horizontal
Theprojectile launch allows to find the correct answer for the question about the direction of the ball when it hits the ground is:
D) θ = 37º measured clockwise from the x-axis.
projectile launch is an application of kinematics where there is no acceleration on the horizontal axis and the acceleration on the vertical axis is the gravity acceleration.
The horizontal distance traveled until it reaches the ground is
x = v₀ₓ t
The height of the bullet is
y = y₀ + [tex]v_o_y[/tex] t - ½ g t²
The initial vertical velocity is zero and when it reaches the ground its height is zero.
0 = y₀ - ½ g t²
t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]
We substitute
[tex]x = v_{ox} \ \sqrt{\frac{2y_o}{g} }[/tex]
They indicate that the distance is:
x = [tex]\frac{8}{3} \ y_o[/tex]
We substitute
[tex]\frac{8}{3} y_o = v_{ox} \sqrt{\frac{2y_o}{g} }[/tex]
[tex]v_{ox} = \frac{8}{3} \sqrt{\frac{y_o g}{2} }[/tex]
The vertical speed when reaching the ground is:
[tex]v_y = v_{oy} - g t \\v_y = - g t \\v_y = - g \sqrt{\frac{2y_o}{g} }[/tex]
Let's use trigonometry for the direction at the point of hitting the ground.
tan θ = [tex]\frac{v_y}{v_x}[/tex]
θ = tan⁻¹ ( [tex]- \frac{3}{8} \ \frac{\sqrt{2y_o/g}}{\sqrt{y_o g /2} }[/tex] )
θ = tan⁻¹ ( [tex]tan ^{-1} (- \frac{3}{8} \sqrt{4} )= tan^{-1 } \ (- \frac{3}{4} )[/tex]
θ = -36.9º
The negative sign indicates that the angle is clockwise from the x-axis.
In conclusion, using the projectile launch we can find the correct answer for the question about the direction of the bullet when it hits the ground is:
D) θ = 37º measured clockwise from the x-axis.
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A model shows a machine that works using electric fields. What would this machine need for the electrical field to function properly
As a truck rounds a curve, a box in the bed of the truck slides to the side farthest from the center of the curve. This movement of the box is a result of
Answer:
inertia
Explanation:
the mass of the box will want to continue on its straight line motion.
As centripetal force on the wheel treads causes the truck to turn, frictional force between the box and truck bed is insufficient to keep the box turning at the same rate that the truck turns, so relative velocity occurs between box and bed until the centripetal force is increased by contact with the truck side wall farthest from the center of curvature.
The diagram shows the tropic levels in a lake in a farm. Suppose the farmer sprays a field with a chemical fertilizer. Based on the flow of energy in the lake, which organisms would contain the highest concentration of the chemical fertilizer?
Based on the flow of energy that's in the lake, it can be deduced that the diatoms and algae will have the highest concentration.
Energy flow refers to the flow of energy through living organisms that are within an ecosystem. Energy is passed from one trophic level to the next trophic level.
If the farmer sprays a field with chemical fertilizer, the organism that would contain the highest concentration of the chemical fertilizer are diatoms and algae since they're at the bottom of the ecosystem.
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Water pumps use electrical energy to create mechanical energy needed to move water.
A 1875 W water pump is plugged into a 110 V electrical outlet.
Answer:
n/a
Explanation:
this question is not feasible
If a rocket experiences an acceleration generated by the gravity force between the earth and itself, what is this acceleration if the rocket flies 1000 km above the ground and the Earth's radius is 6.378 * 10 ^ 6 * r m. We know the Earth has a mass of 5.97*10^ 24 kg(in m/s^ 2 , G=6.67*10^ -11 N(m/kg)^ 2 ) ?
a 8.97
b 7.32
c 9.81
d 5.5
e 11.45
This question involves the concepts of Gravitational Force and Weight force.
The value of acceleration is "b. 7.32 m/s²".
At the given height the weight of the rocket must be equal to the gravitational force between rocket and the Earth:
[tex]W=F_G\\mg=\frac{GmM}{R^2}\\\\g=\frac{GM}{R^2}[/tex]
where,
g = acceleration = ?
G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = mass of earth = 5.97 x 10²⁴ kg
R = Radius of Earth + Height = 6.378 x 10⁶ m + 1 x 10⁶ m = 7.378 x 10⁶ m
Therefore,
[tex]g=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{(7.378\ x\ 10^6\ m)^2}[/tex]
g = 7.32 m/s²
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Hello I am absolutely stumped on these six physics problems. Please help me on them.
Answer:
Explanation:
20° from the normal = 110° from parallel
1a) τ = (200sin90)[6] + (75sin110)[3] - (100sin110)[3]
τ = 1,129.52305... = 1100 N•m CCW
1b) τ = 200(6)(sin90) + 75(-3)(sin(360-110)) + 100(3)(sin(270 + 20)
τ = 1,129.52305... = 1100 N•m CCW
1c) My directions agree, both are positive z by right hand rule.
1d) Moment of inertia for a thin rod about an axis perpendicular to its center is
I = (1/12)mL²
τ = Iα
α = τ/I = 1129.523 / ((1/12)(200)(12²)) = 0.4706 rad/s²
θ = ½αt²
θ = ½(0.4706)(2•60)² = 3,388.56916... radians
θ = 3400 radians
at which time is is spinning about 9 revolutions per second
An accessory such as a coupling that performs a mechanical rather than an electrical function is called?
which alkali metal is most reactive
help me i have little time left i will give brainliest
Answer:
Explanation:
Conservation of momentum
Initial momentum is zero
3.0(6.0) + 7.0v = 0
v = -18/7 = - 2.57142857...
|v| = 2.6 m/s
Why is it important that we learn about our solar system, the sun, and planets in our solar system other than Earth?
Answer:
To understand all the different kind of elements and how they work. Nature is a beautiful thing and it is important we understand how they survive and how we can help. The solar system is a mandatory nature. Learning about other planets also helps us feel safe and more knowledgable.
Blonde hair is produced by inheriting double recessive alleles (bb) from one’s parents. What is the probability of their offspring having blonde hair?
plz help
Answer:
over 50% power ability
Explanation:
I believe it's half and half chance that The Offspring or the child will have that trait
PLEASE HELP ASAP
I need help understanding this question, form my guess I’m thinking it’s C but I’m not to sure
Answer:
Explanation:
Without the diagram, we have to bracket our answers.
Total energy is constant, so we eliminate options A and B.
C is correct if position 1 is closer to the star than position 2
D is correct if position 2 is closer to the star than position 1
state all kinds of errors
Answer:
Instrumental error
Environmental error
Observational error
Theoritical error
VERY EASY QUESTION FOR HIGH SCHOOL STUDENTS:
Which of the following frequencies would you expect a young person to be able to hear? 500 Hz, 6000 Hz, 25000 Hz, 15 Hz, 15000 Hz
Answer:
Explanation: 6000z
A car is moving north on a freeway. If a bug is flying south on the freeway, is the momentum of the bug positive or negative?
Neither
Positive
Negative
Can be both depending on the weather
Negative
Because the car is moving up and the bug is moving down. but it also depends on the weather so choice between one of those two I think is Negative but I may be wrong.
A baseball player throws a baseball at a speed of 40 meters per second at an angle of 30 degrees. What is the velocity of projectile at 2 second?
Answer:
The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 . To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.
Hope it helpss :)
Answer:35m/s
Explanation:The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 (check this on your Regents Reference Tables or on your calculator). To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.
An electrician reads a resistance of 65 ohms and when energize the circuit runs 1.77 amps. what voltage to the system run on?
Answer:
115.05 Volts
Explanation:
We can use Ohm's Law!
V=IR
V= 1.77 * 65
V=115.05 Volts
E
D
С
B
A
Column
Column
1.
Electron Cloud
B
2
Nucleus
b. A
3.
Electron
CD
4.
Neutron
d.
5.
Proton
ec
Answer:
1. D electron cloud
2. A nucleus
3. E electron
4. B neutron
5. C proton
Explanation:
electrons are located outside the nucleus. The nucleus holds the protons and neutrons. Protons have a positive symbol (+). electron cloud holds the electrons.
Explanation:
Electron cloud : D
Nucleus : A
Electron : E
Neutron : B
Proton : C
hope this helps you.
23 A 2-kg rock is moving at a speed 6 m/s, What constant force is needed to stop the rock in 7x10-52
Answer:
Explanation:
Do you mean 7 x 10⁻⁵² seconds? Who can even measure that small a time period?
If that time is incorrect, just redo the math with the correct time to get the force.
An impulse will cause a change of momentum
FΔt = mΔv
F = mΔv/Δt
F = 2(0 - 6)) / (7 x 10⁻⁵² - 0)
F = - 1.7 x 10⁵² N
The magnitude of that force would pretty much crush any rock it hit.