use special right triangle:
What is the length of (BD)

What is the length of (BC)

Answer:

too much salt will not bring taste to the cup cakes

Step-by-step explanation:

Answer:

here summation x = sum of all number

Answer:

eight two point baskets

Step-by-step explanation:

3 points = 9 points

1 points = 5 points

9+5= 14

30-14= 16

= 16/2

=8

A= 346.5cm^2, thats the answer

The function operation (f/g)(x) in the functions f(x) = 10x-15 and g(x) =2x-3 is 5.

A function is simply a relationship that maps one input to one output.

Given that;

First, we replace the function designators in f/g with the actual functions.

(f / g )(x) = f(x) / g(x)

(f / g )(x) = ( 10x - 15 ) / ( 2x - 3 )

Now, factor out 5 from 10x and -15

(f / g )(x) = 5( 2x - 3 ) / ( 2x - 3 )

Cancel the common factor of 2x - 3

(f / g )(x) = 5( 1 ) / ( 1 )

(f / g )(x) = 5 / 1

(f / g )(x) = 5

Therefore, the function operation (f/g)(x) equals 5.

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Answer:

36

Step-by-step explanation:

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Given:

[tex]\mu = 359 \ \ \ \ \ \sigma = 33\\\\[/tex]

Using formula:

[tex]\to P(X = x) = P\left ( z < \frac{x-\mu }{\sigma } \right )[/tex]

For point a:

[tex]\to x= 406\\\\P(X < 406 ) = P\left ( z < \frac{406-359 }{33 } \right )\\\\[/tex]

                   [tex]= P\left ( z <1.4242\right )\\\\= 0.9222[/tex]

For point b:

[tex]\to x= 461\\\\P(X > 461 ) = P\left ( z > \frac{461 -359 }{33 } \right )\\\\[/tex]

                   [tex]= 1 - P\left ( z < 3.0909 \right )\\\\= 1 - 0.9990\\\\= 0.0001[/tex]

For point c:

[tex]\to x= 406\ \ and \ \ 461\\\\P(406 <X < 461 ) = P(X < 461) - P (X < 406)\\\\[/tex]

                              [tex]= 0.9990 - 0.9222\\\\= 0.0768\\\\[/tex]

For point d:

[tex]P(X < 406) = 0.9222 = 92.22 \%\ that \ is \ greater \ than\ 50\%[/tex]

Hence, the correct choice is "i".

For point e:

[tex]\to P(X > z) = 0.1\\\\\to 1 - P(X < z) = 0.1\\\\\to P(\frac{x-\mu }{\sigma }) = 0.9\\\\\to \frac{x-359}{33 } = 1.28\\\\ \to x = 401.24\\\\[/tex]

Answer:

80

Step-by-step explanation:

4x20=80

Answer:

not sure lol but, like it up

Step-by-step explanation:

1. 40°

2. 50°

3. 45°

4. a. draw a line from angle P to downward but make it so it can cut angle OPQ from the half

b. 70°

c. angle TPQ = angle OPQ ÷2

angle TPQ = 140÷2= 70°

Answer:

$3000

Step-by-step explanation:

$150 / 1 sq ft * 20 sq ft

$150 / 1 sq ft = this means $150 per square feet :

Given that there area 20 Square feets, then

Cost in $ will be :

$150 * 20 sq feet

= $3000

Answer:

this is the answer Hope's it helps

Answer:

4a

Step-by-step explanation:

Answer:

$462.5

Step-by-step explanation:

Given the cost function expressed as;

C = 37000/100−p

To get C(20), we will substitute p = 20 into the expression and get C as shown;

C(20) = 37000/100-20

C(20) = 37000/80

C(20) = 462.5

Hence the cost needed to clean 20% of the stream is $462.5

Answer:

The 98% confidence interval for the mean of the population is (59, 68.2).

Step-by-step explanation:

Before building the confidence interval, we need to find the sample mean and the sample standard deviation.

Sample mean:

[tex]\overline{x} = \frac{55+64+58+61+69+64+59+69+72+65}{10} = 63.6[/tex]

Sample standard deviation:

[tex]s = \sqrt{\frac{(55-63.6)^2+(64-63.6)^2+(58-63.6)^2+(61-63.6)^2+(69-63.6)^2+(64-63.6)^2+(59-63.6)^2+(69-63.6)^2+(72-63.6)^2+(65-63.6)^2}{10}} = 5.142[/tex]

Confidence interval:

We have the standard deviation for the sample, and thus, we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 2.821

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.821\frac{5.142}{\sqrt{10}} = 4.6[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 63.6 - 4.6 = 59

The upper end of the interval is the sample mean added to M. So it is 63.6 + 4.6 = 68.2.

The 98% confidence interval for the mean of the population is (59, 68.2).

Answer:

90 answer plss brainless me

Answer:

19

Step-by-step explanation:

6.802 = 7

6.1844 = 6

6.318 = 6

7 + 6 + 6 = 19

I hope this helps!

Answer:

183

Step-by-step explanation:

The perimeter of the rectangle measured in centimeters is 26 cm.

Perimeter of a straight sided figures or objects is the total length of it's boundary.

Given a rectangle in the figure.

The length of the rectangle = 7 cm

Width of the rectangle = 6 cm

We have to find the perimeter of the rectangle.

Perimeter of the rectangle = 2(l + w), where l is the length and w is the width.

Perimeter = 2(7 + 6)

                = 2 × 13

                = 26 cm

Hence the perimeter is 26 cm.

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Answer:

(1,1)

Step-by-step explanation:

Answer:

14x

Step-by-step explanation:

14x = 14 x (x) = 14(x)

Answer:

-2,0

Step-by-step explanation:

See the steps below:)

Answer:

x=9

Step-by-step explanation:

Answer:

Ordinal

Step-by-step explanation:

When dealing with categorical variables who doesn't permit mathematical or numerical evaluation of values or inputs, the ordinal variable atleast gives a method of scaling which allows us to rank variables on terms of importance, magnitude and so on. Such that the even though we can't measure the difference between the variables, we can tell that one is much better, important or higher in hierarchy than the other. Such is the categorical variable, of class when traveling. This could be Economy, Business, First class.

The Economy class is the lowest, followed by Business class then the First class. Here, there is an order or rnak in the classes but not measurable.

Solution :

The sample proportion [tex]$(\hat p)=\frac{24}{1000}$[/tex]

                                           = 0.024

90% confidence interval

The standard deviation  = [tex]$\sqrt{\frac{\hat p(1-\hat p)}{n}$[/tex]

                                        = [tex]$\sqrt{\frac{0.024(1-0.024)}{1000}$[/tex]

                                        = 0.00484

z = 1.645 for 90% CI

Upper band = 0.024 + (0.00484 x 1.645 ) = 0.03196

Lower band = 0.024 - (0.00484 x 1.645 ) = 0.01603

Therefore, the 90% CI is (0.016, 0.032)

99% confidence interval

z = 2.576 for 99% CI

Upper band = 0.024 + (2.576 x 0.00484 ) = 0.0365

Lower band = 0.024 - (2.576 x 0.00484 ) = -0.0115

Therefore, the 99% CI is (0.0115, 0.0365)

Using the z-distribution, it is found that:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which z is the z-score that has a p-value of [tex]\frac{1+\alpha}{2}[/tex].

24 out of 1000 people who were surveyed had type 2 diabetes, hence:

[tex]n = 1000, \pi = \frac{24}{1000} = 0.024[/tex]

90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so [tex]z = 1.645[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.024 - 1.645\sqrt{\frac{0.024(0.976)}{1000}} = 0.016[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.024 + 1.645\sqrt{\frac{0.024(0.976)}{1000}} = 0.032[/tex]

The 90% confidence interval to estimate the proportion of people who have type 2 diabetes is (0.016, 0.032).

99% confidence level, hence[tex]\alpha = 0.99[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.99}{2} = 0.995[/tex], so [tex]z = 2.575[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.024 - 2.575\sqrt{\frac{0.024(0.976)}{1000}} = 0.012[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.024 + 2.575\sqrt{\frac{0.024(0.976)}{1000}} = 0.036[/tex]

The 99% confidence interval to estimate the proportion of people who have type 2 diabetes is (0.012, 0.036).

The relationship is that a higher confidence level leads to a higher value of z, making the interval wider.

A similar problem is given at https://brainly.com/question/15850972

Answer:

The best estimate of the proportion of adults who say that the law goes easy on celebrities is 0.7435.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

In this question:

CI is between 0.645 and 0.842. So the best estimate of the proportion is:

(0.645+0.842)/2 = 0.7435

The best estimate of the proportion of adults who say that the law goes easy on celebrities is 0.7435.

Answer:

it is babylonia huming by chris