Una esfera de aluminio de 250 g a una temperatura de 230 °C se introduce en 450 g de alcohol a una temperatura de 18 °C. Determine la temperatura de equilibrio del sistema. El calor específico del aluminio es 911 J kg-1 °C-1 y para el alcohol 2100 J kg-1 °C-1.

Answers

Answer 1

Answer:

La temperatura de equilibrio del sistema es de aproximadamente 59,17 °C

Explanation:

La masa de la esfera de aluminio, m₁ = 250 g

La temperatura inicial de la esfera de aluminio, T₁ = 230 °C

La capacidad calorífica específica del aluminio, c₁ = 911 J / (kg·°C)

La masa del alcohol, m₂ = 450 g

La temperatura inicial del alcohol, T₂ = 18 ° C

La capacidad calorífica específica del alcohol, c₂ = 2,100 J/(kg·°C)

Observamos que el punto de ebullición del alcohol ≈ 78,37°C

Sea 'T' la temperatura de equilibrio del sistema, obtenemos;

ΔQ₁ = ΔQ₂

ΔQ₁ = Calor transferido desde el aluminio = m₁ · c₁ · (T₁ - T)

ΔQ₂ = Calor transferido al alcohol = m₂ · c₂ · (T - T₂)

∴ m₁ · c₁ · (T₁ - T) = m₂ · c₂ · (T - T₂)

Por lo tanto, por sustitución, obtenemos

250 × 911 × (230 - T) = 450 × 2100 × (T - 18)

Usando una calculadora gráfica, tenemos;

T = 277570/4691 °C ≈ 59,17 °C

La temperatura de equilibrio del sistema, T ≈ 59.17 °C


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Have a good day :)

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[tex] \\ [/tex]

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Answers

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Answers

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