Answer:
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
Explanation:
De acuerdo con el enunciado, el conductor nota la luz roja, empieza a decelerar 0.5 segundos después y decelera hasta detenerse. La distancia total recorrida por el automóvil desde el instante en que el conductor nota la luz roja ([tex]\Delta s_{T}[/tex]), medida en metros:
[tex]\Delta s_{T} = \Delta s_{1}+\Delta s_{2}[/tex] (1)
Donde:
[tex]\Delta s_{1}[/tex] - Distancia recorrida a velocidad constante, medida en metros.
[tex]\Delta s_{2}[/tex] - Distancia recorrida hasta alcanzar el reposo, medida en metros.
Si suponemos que la segunda etapa describe un movimiento uniformemente acelerado, entonces la distancia recorrida total que representada por la siguiente fórmula:
[tex]\Delta s_{T} = v_{o}\cdot \Delta t_{o} + \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial del automóvil, medida en metros por segundo.
[tex]v_{f}[/tex] - Velocidad final del automóvil, medida en metros por segundo.
[tex]\Delta t_{o}[/tex] - Tiempo de reacción del conductor, medido en segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Si conocemos que [tex]v_{o} = 16.667\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex], [tex]\Delta t_{o} = 0.5\,s[/tex] y [tex]a = -40\,\frac{m}{s^{2}}[/tex], entonces la distancia recorrida total es:
[tex]\Delta s_{T} = \left(16.667\,\frac{m}{s} \right)\cdot (0.5\,s)+\frac{\left(0\,\frac{m}{s} \right)^{2}-\left(16.667\,\frac{m}{s}\right)^{2}}{2\cdot \left(-40\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\Delta s_{T} = 11.806\,m[/tex]
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How much energy was lost to air friction during this jump
Answer:
769,048.28Joules
Explanation:
A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How much energy was lost to air friction during this bump
The energy lost due to friction is expressed using the formula;
Energy lost = Potential Energy + Kinetic Energy
Energy lost = mgh + 1/2mv²
m is the mass
g is the acceleration due to gravity
h is the height
v is the speed
Substitute the given values into the formula;
Energy lost = 56(9.8)(1400) + 1/2(56)(5.10)²
Energy lost = 768,320 + 728.28
Energy lost = 769,048.28Joules
Hence the amount of energy that was lost to air friction during this jump is 769,048.28Joules
Helpppp!! I will make you a brainlist Calculate the force exerted on
this test dummy with a mass of 75 kg hits an airbag accelerating at 12m/s2??
Answer:
900 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question is we have
force = 75 × 12
We have the final answer as
900 NHope this helps you
How might the temperatures on Mercury be different if it had the same mass as Earth?
Answer:
well, mercury is the closest planet to the sun, making it MUCH hotter than earth. that being said, just because mercury is closest to the sun, it doesnt mean its the hottest planet.
Since Mercury is the planet that is nearest to the sun, it is much hotter than the earth. However, because Mercury is nearest to the sun doesn't automatically make it the hottest planet.
What is a Planet?A huge, spherical celestial object, it is neither a star it nor remnant is called a planet. The nebular concept, which holds how an interplanetary cloud collapse out of a nebula to produce a young white dwarf orbited by a planetary system, is the best theory currently available for explaining planet formation.
The slow buildup of matter propelled by gravity—a practice called as accumulation, to the formation of planets in this disk. The rocky planets Mercury, Venus, Earth, and Mars, as well as the giant planets Jupiter, Saturn, Uranus, and Neptune, make up the Solar System's minimum number of eight planets. Each of these planets revolves around an axis that really is inclined with regard to its orbit pole.
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th weight of an object is
Answer:
the weight of an object is the force acting on the object due to gravity. the gravitational force acting on the object. Others define weight as a scalar quantity, the magnitude of the gravitational force.
Explanation:
9. A student notices that wearing darker colors in sunlight makes him feel warmer, so he decides to conduct an experiment. He takes five pieces of different
colored cloth and wraps
each one around a water bottle. He then places all five bottles in direct sunlight and measures the temperature of the water in each bottle an hour later
What is the dependent variable in this experiment?
O the time he leaves it in the sunlight
O the amount of water in each bottle
O the color of the cloth
O the temperature of the water
Answer: 4
Explanation:
The dependent variable is the temperature of the water.
It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone?
Answer: The work done on the flagstone is 20178 J
Explanation:
Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.
[tex]Work=Power\times time[/tex]
Given : work = ?
Power = 342 W = 342J/s
Time = 59 s
[tex]Work=342J/s\times 59s=20178J[/tex]
Thus the work done on the flagstone is 20178 J
What is the frequency of a light wave if its wavelength is 4.70 x 10-7 meters?
A. 1.57 x 10-15 Hz
B. 1.57 x 10-8 Hz
O
C. 6.32 x 107 HZ
O
D. 6.38 x 1014 Hz
Answer:
6.38 * 10^14 Hz
Explanation:
how has evidence changed our views on the universe
Answer:
We found out more about how the universe had started (Big Bang theory), how the planets were created and how stars are born.
What type of reaction in the diagram?
B.Fission,because the reaction absorbed energy
C.Fusion,because the reaction formed heavier nuclei
D.Fission,because the reaction formed lighter nuclei
Answer:
b, i think
Explanation:
A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it
Answer:
F = -8820 N
Explanation:
Given that,
The weight of a car, W = 19600 N
Initial speed of the car, u = 30 m/s
It is brought to rest, final velocity, v = 0
Distance, d = 100 m
We need to find the average friction force acting on it.
Firstly we find the acceleration of the car using third equation of motion. Let it is a.
[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]
Average frictional force,
F = ma
m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]
F = 1960 kg × -4.5 m/s²
= -8820 N
So, the average friction force acting on it is 8820 N.
) prove that the acceleration due to gravi
is independent to the mass of the falling body
Explanation:
Let the mass of the body is m. The gravitational force acting on the object is given by :
[tex]F=\dfrac{GMm}{r^2}[/tex] ....(1)
G is universal gravitational constant
M is mass of Earth
r is the distance between the body
The acceleration of falling objects due to the gravitational force of Earth is equal to the acceleration due to gravity (g).
F = mg ...(2)
g is acceleration due to gravity
From equation (1) and (2) :
[tex]\dfrac{GMm}{r^2}=mg\\\\g=\dfrac{GM}{r^2}[/tex]
Here, M is mass of Earth and r is the distance. Hence, the acceleration due to gravi ty is independent to the mass of the falling body
here avarose566 you need this
Answer:
ooooooooooooooooo
Explanation:
*makes holy water*
I need help with science homework
Answer:
4. atmosphere and geosphere
5. atmosphere and hydrosphere
6. hydrosphere and geosphere (? not sure about this one sorry)
7. hydrosphere and geosphere
8. biosphere and geosphere
To control whether an object is solid or incorporeal (things can pass through it) you would use the:
Answer:
Gamma radiation or Cathode rays
Explanation:
by striking incident gamma or cathode rays onto the solid when placed on a photographic plate
Queremos un cilindro de simple efecto que utilice en su funcionamiento un volumen de aire a presión atmosférica de 13,122 litros, cuya presión de trabajo sea de 8,5Kgf/ cm2 y cuya longitud sea de 20 cm. -hallar el diámetro de este cilindro. - calcular las fuerzas de este cilindro.
Answer:
1) El diámetro es de aproximadamente 913,987 cm.
2) La fuerza del cilindro es 5576850 kgf
Explanation:
1) Los parámetros dados son;
El volumen del aire = 13,122 litros = 13122000 cm³
La presión de trabajo = 8.5 kgf / cm²
La longitud del cilindro = 20 cm.
Por lo tanto, tenemos;
El área de la base del cilindro = π · r² = 13122000 cm³ / (20 cm) = 656100 cm²
r = √ (656100 / π) ≈ 456,994 cm
El diámetro = 2 × r ≈ 2 × 456.994 ≈ 913.987 cm
El diámetro ≈ 913,987 cm
2) La fuerza del cilindro = El área de la base del cilindro × La presión de trabajo
∴ La fuerza del cilindro = 656100 cm² × 8.5 kgf / cm² = 5576850 kgf
La fuerza del cilindro = 5576850 kgf
URGENT! 40 POINTS! For each situation below, find the work done on the box using both energy and forces.
1. A 2 kg box initially at rest slides down a frictionless ramp (at 15ᵒ from the ground) for
1 second.
2. A 2 kg box is thrown upward with an initial speed of 3.5 m/s. Consider the box from
the time it was thrown until it reaches its maximum height.
3. A 2 kg box is dropped from an initial height of 10 m.
I have some physics, I just don't know what formulas to use or where to start. Help is much appreciated.
Answer:
i’m not sure one second let me try to figure it out
Explanation:
Which of the following actions will induce an emf in a conductor?
a. Move a magnet near the conductor.
b. Move the conductor near a magnet.
c. Rotate the conductor in a magnetic field.
d. Change the magnetic field strength.
e. all of the above
Answer:
b . Move the conductor near a magnet
Answer:
(e) all the above....
Explanation:
That's all
Cause you know.......
When is the object traveling at a constant velocity?
A
B
C
D
It is moving at a constant velocity the entire time
d
I think the most common way of doing it was for the first
the center of mass of a donut is located ?
a. in the hole
b. in material making up the donut
c. near the center of gravity
d. over a point of support
Answer:
A
Explanation:
where the hole is because it's a rigid object with uniform density.
If the velocity of an object changed from 30 m/s to 60 m/s over a period of 10 seconds what would the average acceleration be ?
Question 5 of 15
Hertz (Hz) is the unit used to measure a wave's
A. frequency
B. period
C. amplitude
D. wavelength
SUBMIT
I believe that it’s frequently?
Answer:
Hertz is the S.I. unit of frequency and is used to measure a wave's frequency . So, option A frequency is the correct answer.
The masses of four vehicles and the net forces acting on them as they enter a highway are recorded in the table below. Vehicles Entering a Highway Vehicle Mass (kg) Force (N) Sedan 1500 4500 Coupe 1200 4500 SUV 1800 4500 Truck 2000 4500 Which vehicle has the greatest acceleration as it enters the highway?
Answer:
Coupe
Explanation:
It has the least amount of mass
The acceleration of each vehicles with same force decreases with an increase in mass. Thus, the vehicle with greatest acceleration is the light vehicle which is coupe here.
What is acceleration?Acceleration of a body is the rate of change of its velocity. Acceleration is a vector quantity thus it is characterized by its magnitude and direction. The acceleration of a body depends on the mass, speed and the force acting on the body.
According Newton's second law of motion, the force acting on a body is the product of its mass and acceleration.
Thus, F = ma.
Force increases with both acceleration and mass.
From this relation, it is clear that the mass and acceleration of a body are in inverse relation. Thus, a massive body requires more force to accelerate it.
Here all the vehicles have equal force on it but their masses are different. The greater mass is for truck here which is associated with least acceleration anb the light vehicle, coupe will have the greatest acceleration.
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Which is the metric standard for measuring energy?
Which unit is used for specific heat capacity?
If you wanted to compare the abilities of olive oil and peanut oil to gain or lose thermal energy, which unit would you use?
Answer:
1. Joule
2. Specific heat capacity is defined as the amount of heat required to raise the temperature of 1 kilogram of a substance by 1 kelvin (SI unit of specific heat capacity J kg−1 K−1).
3. heat capacity units
Heat is a thermal energy, so by using heat capacity units you can compare the ability of olive oil and peanut oil to gain or lose thermal energy by varying its temperature.
Answer:
Which is the metric standard for measuring energy?
✔ joules
Which unit is used for specific heat capacity?
✔ J/g°C
If you wanted to compare the abilities of olive oil and peanut oil to gain or lose thermal energy, which unit would you use?
✔ J/g°C
Explanation:
did it on edge 2023
A battery is the power source for what type of current
Answer: DC Current
Explanation:
Battery is a source of constant potential difference and it will create a constant voltage across any conductor
due to this constant voltage difference the current in this conductor will remain constant
So here since the voltage across the conductor is constant so we can say that current in the conductor will remain constant and hence this is known as DC current.
While for variable current in direction and magnitude is to be obtained only when the conductor is connected with AC voltage source as we know that AC voltage is variable with magnitude and direction both
A battery is the power source for DC type of current. A battery is a source of constant potential difference that produces a constant current unlike in AC source where the voltage and hence the current changes its polarity continuously.Hence, the current produced by battery is direct current and not Alternating current.
Hope this helps........ Stay safe and have a Merry Christmas!!!!!! :D
A student used apparatus as shown above. The beaker held 750 g of a liquid. The current from the power supply was 1.8 A and the potential difference of the supply was 230 V. The temperature rose from 12 °C to 40 °C over a period of 2 minutes.
Calculate the specific heat capacity of the liquid.
Answer:
[tex]2365.71\ \text{J/kg}^{\circ}\text{C}[/tex]
Explanation:
V = Voltage = 230 V
I = Current = 1.8 A
[tex]\Delta T[/tex] = Temperature change = [tex](40-12)^{\circ}\text{C}[/tex]
t = Time taken = 2 minutes
m = Mass of liquid = 750 g
c = Specific heat capacity of the liquid
Energy required to heat the water is equal to the heat released due to current passing
[tex]mc\Delta T=VIt\\\Rightarrow c=\dfrac{VIt}{m\Delta T}\\\Rightarrow c=\dfrac{230\times 1.8\times 2\times 60}{0.75\times (40-12)}\\\Rightarrow c=2365.71\ \text{J/kg}^{\circ}\text{C}[/tex]
The specific heat capacity of the liquid is [tex]2365.71\ \text{J/kg}^{\circ}\text{C}[/tex]
A car drives 500m in 2 minutes.What is the cars speed? A.2m/s B.4m/s C.5 m/s
Answer:
B
Explanation:
1 minute = 60 seconds
2 minutes = 2 * 60 = 120 seconds.
d = r * t
t = 120 seconds
d = 500 meters
r = d/t
r = 500 / 120 = 4.167 m/s
The closest answer is B
A satellite is on orbit 35600 km above the surface of the earth.its angular velocity is 7.25×10–5 rad/sec.What is the vrlocity of the satellite?(The radius of the earth is 6400 km
Answer: 3.045 km/s
Explanation:
When an object is doing a circular motion, the velocity of the object is written as;
v = r*w
where;
r = radius of the circle
w = angular velocity.
In this case, we know that:
w = 7.25*10^(-5) s^-1
And the radius will be equal to the radius of the Earth, plus the height of the satellite, this is:
R = radius of the Earth + 35600 km = 6400km + 35600 km = 42000 km
Then the velocity of the satellite will be:
v = 42000 km*7.25*10^(-5) s^-1 = 3.045 km/s
The velocity of a satellite with an orbit 35600 km above the surface of the earth and an angular velocity of 7.25×10–5 rad/sec = 3045 m/s
Velocity: This is the rate of change of displacement.
To solve this problem we need to use the formula for calculating the velocity of an object in circular motion
The Velocity of the satellite is given as
V = ωr................ Equation 1
where V = velocity of the satellite, ω = angular velocity of the satellite, r = radius of the circle.
Note: r = height of the satellite above the surface of the earth+Radius of the earth
From the question,
Given: ω = 7.25×10⁻⁵ rad/sec, r = 35600+6400 = 42000 km = 4.2×10⁷ m
Substitute these values into equation 1
V = (7.25×10⁻⁵)(4.2×10⁷ )
V = 30.45×10²
V = 3045 m/s
Hence, the velocity of the satellite is 3045 m/s
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Cellular respiration occurs in the body 24 hours per day. During exercise, the rate of cellular respiration increases. Why does increased cellular respiration cause people to breathe faster?
More oxygen is needed to produce energy, and more carbon dioxide waste must be removed from the body.
More nutrients are needed to produce more energy, and more oxygen must be removed from the body.
More heat is generated by the body, and breathing cools the body quickly.
More water is lost from the body, and breathing hydrates the body.
Answer: I think is C
Explanation:
Answer: more oxygen is needed to produce energy
A 250-kg moose stands in the middle of the railroad tracks in Sweden, frozen by the lights of an oncoming 10,000kg train traveling at 20m/s. Even though the engineer attempted in vain to slow the train down in time to avoid hitting the moose, the moose rides down the remaining track sitting on the train’s cowcatcher. What is the final velocity of the train and moose after the collision?
(Momentum & Impulse)
Answer:
The final velocity of the train and the moose after collision is approximately 19.51 m/s
Explanation:
The given mass of the moose, m₁ = 250 kg
The velocity of the moose, v₁ = 0
The mass of the oncoming train, m₂ = 10,000 kg
The velocity of the train, v₂ = 20 m/s
The velocity of the moose and the train after collision = v₃
By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision
m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃
Therefore, by substitution, we have;
250×0 + 10,000× 20 = (10,000 + 250) × v₃
200,000 = 10,250 × v₃
v₃ = 200,000/10,250 ≈ 19.51 m/s
The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s
Question
3.2
Calculate the value of critical angle for light passing from glass to air (given that refractive index of
glass - 1.5)
Answer:
42°
Explanation:
From the question given above, the following data were obtained:
Refractive index (n) = 1.5
Critical angle (C) =?
The refractive index and the critical angle are related according to the following reaction:
n = 1 / Sine C
Thus, with the above formula, we can obtain the critical angle as follow:
Refractive index (n) = 1.5
Critical angle (C) =?
n = 1 / Sine C
1.5 = 1 / Sine C
Cross multiply
1.5 × Sine C = 1
Divide both side by 1.5
Sine C = 1 / 1.5
Sine C = 0.6667
Take the inverse of sine
C = Sine¯¹ (0.6667)
C = 41.8 ≈ 42°
Thus, the critical angle is approximately
42°.