Two wires made of the same Two wires made of the same material are
stretched by equal forces. The second wire
is twice as long as the first one and also has
twice the diameter of the first wire.
If the first wire is stretched by 7.7 cm, then
by how long is the second wire stretched?

Answer:

Net Force. when all combinations of force acting on an object. Force. A push or pull

So it's the third answer

( the combination of all forces acting on it )

Answer:

Force can be defined as the product of mass and acceleration.

Explanation:

~Cornasha_Weeb

Answer:b

Explanation: If you look at the line on the graph, you can see that it is going downward, meaning it has a negative slope, and choice b is the only one that has a negative slope

Explanation:

refraction is the change in direction of a wave passing from one medium to another or from a gradual change in the medium.

Peak expiratory flow readings are higher when patients are well, but lower when a  patient's airway is constricted.

This term is used in medicine to refer to the maximum rate of a person's exhalation or to how fast and how long can they exhale.

This rate is measured by using the peak expiratory flow test that requires you to deeply inhale and then exhale as fast as hard as possible.

This rate is closely related to the amount of air flowing out of the lungs. This implies the peak expiratory flow is lower if there is a disease such as asthma that can constrict the airways.

Learn more about asthma in: https://brainly.com/question/7646693

Answer:2

Explanation:When the ball is released from the top of the hill then it's initial velocity (u)=0 And it's final velocity will be after 5 second (v)=2.

Answer:

Explanation:

a ball is placed at the top of the hill and then released after five seconds and has a speed of 20 m/s. What is the average acceleration of the ball?

The charge on the capacitor 2 (C₂) is 48μF.

In the circuit diagram, C₁ and C₂ are in series connection, while C₃ is parallel to C₁ and C₂.

[tex]Q_1 = Q_2 = Q\\\\V = \frac{Q}{C_1} + \frac{Q}{C_2} \\\\V = Q(\frac{1}{C_1}+ \frac{1}{C_2} )\\\\V = Q(\frac{C_2 + C_1}{C_1 C_2} )\\\\Q = V(\frac{C_1 C_2}{C_2+ C_1} )\\\\Q = 24 \times (\frac{6\times 10^{-6} \times 3 \times 10^{-6}}{6\times 10^{-6} \ + \ 3\times 10^{-6}} )\\\\Q = \frac{4.32 \times 10^{-10}}{9\times 10^{-6}} \\\\Q = 4.8\times 10^{-5} \ C\\\\Q = 48 \ \mu C[/tex]

Thus, the charge on the capacitor 2 (C₂) is 48μF.

Learn more about charge on capacitor here: https://brainly.com/question/13578522

As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

Since the static frictional force between the block and the plane is given by F = μN where

Now, F = μN

F = μWcosθ

Since μ and W are constant, we see that

F ∝ cosθ and cosθ ∝ θ

So, F ∝ θ

Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.

So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

Learn more about static frictional force here:

https://brainly.com/question/25958331

Answer:

497 m/s

Explanation:

(8.864 x 10^3 m)/(0.297 * 60 sec) = 497 m/s

The  velocity (in metres per second) of a Canadian Forces CF-18 fighter jet would be 497.41 meters/second.

The total distance covered by any object per unit of time is known as speed.

As given in the problem we have to find out the  velocity (in meters per second) of a Canadian Forces CF-18 fighter jet that travels 8.864 kilometers [S] in 0.297 minutes,

The distance traveled by the  CF-18 fighter jet =  8.864 kilometers

1 kilometer = 1000 meters

8.864 kilometers = 8.864× 1000 meters

                             =8864 meters

The time taken by  CF-18 fighter jet = 0.297 minutes

1 minute = 60 seconds

0.297 minutes = 0.297 ×60 seconds

                        =17.82 seconds

The velocity of the CF-18 fighter jet =8864 meters/17.82 seconds

                                                         = 497.41 meters/second

To learn more about speed from here, refer to the link;

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#SPJ2

Answer:

yes !

Explanation:

a mirror transforms and flips , but nonetheless produces a real image.

Answer:

3600 N

Explanation:

F=ma

1200*3 = 3600

Answer:

Im pretty sure they're equal, i could be wrong though. Hope i helped have an amazing day :D

Explanation:

Answer:

B: equal

Explanation:

To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.

Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: [tex]\frac{∆v}{t}[/tex]

If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 [tex]\frac{feet}{second}[/tex] then sped up to 5 [tex]\frac{feet}{second}[/tex], then the change in my speed would be 2 [tex]\frac{feet}{second}[/tex], because I started walking 2 [tex]\frac{feet}{second}[/tex] faster!

Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 [tex]\frac{meters}{second}[/tex] to 16 [tex]\frac{meters}{second}[/tex]  in 4 seconds. What would the acceleration be? Let's set up an equation:

a = [tex]\frac{∆v}{t}[/tex]

a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.

Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 [tex]\frac{meters}{second}[/tex] by 4 [tex]\frac{meters}{second}[/tex]. That makes sense, right? Back to the equation.

a = [tex]\frac{∆v}{t}[/tex]
a = [tex]\frac{16-4}{4}[/tex]

(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)

a = [tex]\frac{12}{4}[/tex]

a = 3 ([tex]\frac{meters}{second^{2}}[/tex])

We have our answer! The car's acceleration is 3 meters per second^{2}.

(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit [tex]\frac{\frac{meters}{second}}{second}[/tex], which can be simplified down to [tex]\frac{meters}{second^{2} }[/tex])

Let me know if you need clarification on anything I explained here!
- breezyツ

Answer:

  72.5 A

Explanation:

There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.

  V = πr²h  . . . . .  volume of a cylinder

  V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s

Then the charge flow rate is ...

  (13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s

The magnitude of the current is about 72.5 amperes.

______

Additional comment

The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.

Answer:

10 m/s

Explanation:

KE = 1/2 • m • v^2

250 J = 1/2 • 5 kg • v^2
(2 • 250 J / 5 kg )^1/2 = v

(100)^1/2 = v

10 = v

Hi there!

We can begin by doing a summation of forces for each block.

Block A:

This block has the force of tension (in direction of acceleration +) and static friction (opposite direction -) acting on it. Thus:

[tex]\Sigma F_A = T - F_s\\\\m_Aa = T - \mu m_Ag[/tex]

Block B:

This block has the force of tension (opposite of acc. -) and gravity (in direction of acc +), working on it.

[tex]\Sigma F_B = m_Bg - T\\\\ m_Ba = m_Bg - T[/tex]

Add both of the expressions and solve for the maximum mass of Block B.

[tex]\Sigma F = m_Bg - T + T - \mu m_Ag\\\\a(m_A + m_B) = m_Bg - \mu m_Ag[/tex]

To find the minimum value, we can set a = 0, so:

[tex]0 = m_Bg - \mu m_Ag\\\\\mu m_Ag = m_B g\\\\0.8(20)(9.8) = m_B (9.8)\\\\m_B = \frac{0.8(20)(9.8)}{9.8)} = \boxed{16 kg}[/tex]

The block must weigh > 16 kg for block A to move.

Answer:

30N

Explanation:

30N of force was applied

quizlet

Answer:

1.25 sec, 2 m/s

Explanation:

Period = 2 * 0.625 sec = 1.25 sec

speed = 2.5/1.25 = 2 m/s

Answer:

The inner planets are less dense than the outer planets

Please brainliest my answer iam begging you for god sake

Answer:

The inner planets are less dense than the outer planets .

Explanation:

Answer:

average speed= total distance/total time

Explanation:

Related to the distance traveled by the object which means, it is only represented by the magnitude and direction of travel is not important. so average speed= total distance/total time

Answer: individuality, specificity, progression, overload, adaptation, recovery, and reversibility.

Explanation:

individuality, specificity, progression, overload, adaptation, recovery, and reversibility.

Answer:

1. individuality

2. specificity

3. overload

4. adaptation

5. recovery

6. reversibility

7. progression

Explanation:

I learned this last year.

Answer:

the ball is in the air for 10 seconds

Explanation:

let gravity = 10m/s/s

height = 1/2 acceleration • time^2

125 m = 1/2 •  10 m/s/s • time ^2

125m = 5 m/s/s • time^2

25s = time^2

5 s = time

5 seconds is the time required for half of the flight

time total = 2 • time

time total = 2 • 5s

time total = 10 s

Answer:

All compounds can be classified as molecules, but not all molecules can be called compounds. Molecules are formed by two or more atoms that are bonded by chemical bonding's. Compounds are constructed by two or more elements where the elements are mixed in fixed ratios.

Answer:

Molecules are formed by two or more atoms that are bonded by chemical bondings.
Compounds are constructed by two or more elements where the elements are mixed in fixed ratios

*All compounds can be classified as molecules, but not all molecules can be called compounds.

Explanation:

 pls brainliest if you don't mind

anyway i hope this helped have an awesome day bye byee

Given :-

To Find :-

Solution :-

Here it's given that a car of mass 1000kg moving with velocity of 25m/s North . Another car of mass 1200kg is moving with velocity 30m/s East.

So that ,

[tex]v_{1}= 25m/s \ E= 25 \hat{i} m/s [/tex]

And ,

[tex]v_{2}= 30m/s \ N = 30 \hat{j} m/s [/tex]

See attachment .

From Triangle law of vector addition , the resultant of both vectors will be given by third side of the triangle taken in opposite direction.

So , if the resultant velocity makes an angle [tex]\theta[/tex] . Then ,

[tex] tan\theta = \dfrac{v_2}{v_1} [/tex]

Substituting the respective values,

[tex]tan\theta =\dfrac{30m/s}{25m/s} [/tex]

Simplify ,

[tex]tan\theta =\dfrac{6}{5}[/tex]

Take arctan both sides ,

[tex]\theta = tan^{-1}\bigg(\dfrac{6}{5}\bigg)[/tex]

Hence the cars move at an angle of tan-¹(6/5) NE after the collision .