Answer:
-6 x 10^-6 C
Explanation:
The two spheres will equilibrate to the same charge on each
-6 x 10^-6 C
The two spheres are touched together and then separated. The total number of excess electrons on sphere A is 3.75×10¹³ electrons after the separation.
What is electric charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.
When the spheres touch together, they obtain equal charges. Since the spheres are same in dimension, they obtain equal charges.
Given,
q₁ = −4.0 × 10⁻⁶ C
q₂ = −8.0 × 10⁻⁶ C
q₁ + q₂ = −4.0 × 10⁻⁶ C + −8.0 × 10⁻⁶ C = -12.0 × 10⁻⁶ C
When two charged spheres touch together, they will have equal amount of charge. Means there attain equilibrium of charge.
Hence each charged sphere will have -6.0 × 10⁻⁶ C of charge.
The number of excess electrons on both the spheres will be,
(6.0 × 10⁻⁶ C) ÷ (1.6 × 10⁻¹⁹C) = 3.75 × 10¹³
The number 1.6 × 10⁻¹⁹C is called as Elementary charge.
Hence the number of excess electrons on Sphere A is 3.75 × 10¹³.
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Type the correct answer in the box.use numerals instead of words. if necessary, use / for the fraction bar. δabc is a right triangle in which ∠b is a right angle, ab = 1, ac = 2, and bc = . cos c × sin a =
From the diagram The value of cos C × sin A = [tex]\frac{3}{4}[/tex]
Determine the numerical value of cos C × sin AFirst step : determine the values of cos C and sin A
cos C = adjacent / hypotenuse
= a / b
= [tex]\sqrt{3} / 2[/tex]
= √3/2
sin A = sin 60⁰
= √3/2
Therefore the numerical value of cos C * sin A = [tex]\frac{3}{4}[/tex]
In conclusion From the diagram The value of cos C × sin A = [tex]\frac{3}{4}[/tex]
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What can you infer about the changes in the environment over time at the mystery fossil dig site? Record your inferences in the spaces provided.
Describe the environment in Egypt before the mystery fossil organism emerged.
the fossil informed us about the climatic and geographical changes that occurs in the environment over time.
What the mystery fossil dig site informed us about environment?We can infer about the climate and geographical changes in the environment over time at the mystery fossil dig site because the fossil provides us information about the climatic condition as well as the geography of land when this fossil organism were alive.
So we can conclude that the fossil informed us about the climatic and geographical changes that occurs in the environment over time.
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mention part of generetor and write the uses of each part
Answer:
Explanation:
If generator really means alternator as used in cars, the following can be said:
The rotor is fed with a variable voltage ranging from 0 volt to 12 volts. The 2 brushes (fixed, not rotating, like the stator) make contact with two rings that are rotating with the rotor. The rotor acts like a fixed magnet, but the magnetic field strength is constantly updated to provide a constant output voltage, even if the load current change or the motor speed change.
The stator is basically 3 coils and 6 diodes that convert the 3 phases of AC output to an almost ripple-free DC.
Note that as more energy is extracted from the alternator (for example, adding 10 amps by turning on the headlights) the shaft resists more rotation. This can be easily tested by holding an alternator in your hand, and trying to rotate the shaft by hand with no load (rotate easily, keep rotating for a few seconds), then short-circuiting the output (much harder to rotate, stop rotating immediately). The quest for magical perpetual energy where a motor is powered by an alternator is a child's dream.
Please answer if you know :)
Answer1. :(20/25)*200/*25 2. Increase the radius or apply the force perpendicular to the wrench
Explanation:torque =force*distance*sine of the angle between applied force and axis of wrench
If the net force acting on a moving object CAUSES NO CHANGE IN ITS VELOCITY, what happens to the object's momentum?
A. It decreases.
B. It remains equal to the force.
C. It increases.
D. It stays the same.
If the net force acting on a moving object causes no change in its velocity, the object's momentum will stay the same.
What is momentum?Momentum of a body in motion refers to the tendency of a body to maintain its inertial motion.
The momentum is the product of its mass and velocity.
This suggests that if the net force acting on a moving object causes no change in its velocity, the momentum of the object will remain the same.
Therefore, if the net force acting on a moving object causes no change in its velocity, the object's momentum will stay the same.
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C. A rocket moves from the velocity
2000ms ¹ to 6000 ms¹ after
moving as far as 80km. Calculate
the time taken by the rocket.
(20s)
Answer:
20s
Explanation:
t=d/(V2-V1)
t= 80000m/(6000-2000)
t= 20s
to complete the statement.
Atoms of elements in the same group have the same number of
chemical properties.
This is why they have similar chemical properties.
Answer:
Valence electrons
Explanation:
I don't exactly understand the question. However, I do know that the main commonality between elements of the same group (column) is their valence electrons. Valence electrons are very important when it comes to bonding, ionization, etc.
Which describes an image that a concave mirror can make?
The image is always virtual.
The image can be either virtual or real.
The image is never upside down.
The image can only be the same size as the object.
Answer:
B. The image can either be virtual or real.
Explanation:
Concave mirrors can either produce real or virtual images. The image is upright given that it is virtual or real given that it is in front of the mirror. The images produced by the concave mirrors can also be reduced (in height), enlarged (in terms of size) or having same size as that of the object.
I hope this helps you understand about the images formed by concave mirrors.
Have a nice studies.
In a hard disk drive, a constant torque of 14 N⋅m is applied to the magnetic disk when the drive starts recording data. The magnetic disk has a mass of 0.2 kg and radius 2m. Determine the magnitude of the angular acceleration of the disk? [please solve if you know]
The angular acceleration of the magnetic disk is determined as 35 rad/s².
Conservation of angular momentum
The angular acceleration of the disk is determined from the principle of conservation of angular momentum.
τ = Iα
where;
τ is torqueI moment of inertia of the diskα is angular acceleration of the diskI = ¹/₂MR²
I = ¹/₂ x 0.2 x 2²
I = 0.4 kgm²
α = τ/I
α = (14)/(0.4)
α = 35 rad/s²
Thus, the angular acceleration of the disk is determined as 35 rad/s².
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75m X A car moves with a uniform velocity 21 ms-1 from position P and a truck moves from rest with uniform acceleration 2 ms-2 from position Q in the same time in the same direction.
i) Determine the distance travelled in 20 seconds.
ii) How many times the private car will meet? Analyze mathematically.
Velocity after 20s for both
Car=21m/sTruck=2(20)=40m/s.Distance traveled for car
20(21)=420mDistance traveled by truck=
s=ut+1/2at²s=1/2(2)(20)²s=400m#b
Distance from Q
for car
420-75=345mFor truck
400mThe truck will meet the car after 75/21≈4s
Then for 6s the car keeps meeting because after 7 s Truck will archive 22m/s velocity
Total meet ups=6+1=7timesA delivery van has 80000j of kinetic energy. if the brakes can supply a force of 12,500n to bring the van to stop, how far will the van travel while coming to rest after the brakes are applied?
The distance, van travels while coming to rest after brake applied is 6.4m
What is Work energy theorem?It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Given is a delivery van whose kinetic energy K.E = 80000J and the force applied to brake F = 12500 N.
The brakes are applied to stop the van, so, final velocity is zero. Then, change in kinetic energy will be
According to work energy theorem, work done is
W = ΔK.E = K.Ef - K.Ei
W = - 80000J
Work done is also defined as the product of force applied and the distance it travelled.
W = Fs
80000 = 12500 x s
s = 6.4 m
Thus, the distance, van travels while coming to rest after brake applied is 6.4m
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Is the universe endless?
The universe may indeed have an end one day according but it is yet to be shown in science.
Is the universe endless?While there is certainly no way a person will live long enough to know if the universe will end or not, nevertheless certain scientific calculations are helpful.
From astronomical calculations, the universe is anticipated to have existed for about 13.8 million years. Thus, the universe may indeed have an end one day according but it is yet to be shown in science.
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Find the tension in the ropes shown in the figure if the supported object weighs 600N.
By Newton's second and third laws, we have the following net forces at
point A:[tex]\sum F_x = -T_1 \cos(60^\circ) + T_2 \cos(60^\circ) = 0[/tex]
[tex]\sum F_y = T_1 \sin(60^\circ) + T_2 \sin(60^\circ) - 600 \,\mathrm N = 0[/tex]
Together, these equations tell us [tex]\boxed{T_1=T_2\approx 346 \,\mathrm N}[/tex].
point B:[tex]\sum F_x = T_3 \cos(20^\circ) - T_2 \cos(60^\circ) - T_5 = 0[/tex]
[tex]\sum F_y = T_3 \sin(20^\circ) - T_2 \sin(60^\circ) = 0[/tex]
point C:[tex]\sum F_x = -T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5 = 0[/tex]
[tex]\sum F_y = T_4 \cos(20^\circ) - T_1 \sin(60^\circ) = 0[/tex]
Combining the horizontal force equations for points B and C and using the fact that [tex]T_1=T_2[/tex] gives
[tex](T_3 \cos(20^\circ) - T_2 \cos(60^\circ) - T_5) + (-T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5) = 0 + 0[/tex]
[tex]\implies (T_3 - T_4) \cos(20^\circ) = 0 \implies T_3=T_4[/tex]
Then combining the vertical force equations for B and C, we find
[tex](T_3 \sin(20^\circ) - T_2 \sin(60^\circ)) + (T_4 \sin(20^\circ) - T_1 \sin(60^\circ)) = 0 + 0[/tex]
[tex]\implies 2 T_3 \sin(20^\circ) - 2 T_1 \sin(60^\circ) \implies T_3 = \dfrac{\sin(60^\circ)}{\sin(20^\circ)} T_1[/tex]
so that [tex]\boxed{T_3 = T_4 \approx 877 \,\mathrm N}[/tex]
Lastly solve for [tex]T_5[/tex] using either horizontal force equation for B or C.
[tex]-T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5 = 0[/tex]
[tex]\implies T_5 = \left(\dfrac{\sin(60^\circ)}{\sin(20^\circ)} - \cos(60^\circ)\right) T_1 \implies \boxed{T_5 \approx 651\,\mathrm N}[/tex]
Estimate how long a 2500 W electric kettle would take to boil away 1.5 Kg of water . The specific latent heat of vaporization of water is 4000000 J / Kg .
The time it would take a 2500 W electric kettle to boil away 1.5 Kg of water is 2400 seconds
How to calculate the timeUse the formula:
Power × time = mass × specific heat
Given mass = 1. 5kg
Specific latent heat of vaporization = 4000000 J/ Kg
Power = 2500 W
Substitute the values into the formula
Power × time = mass × specific heat
2500 × time = 1. 5 × 4000000
Make 'time' the subject
time = 1. 5 × 4000000 ÷ 2500 = 6000000 ÷ 2500 = 2400 seconds
Therefore, the time it would take a 2500 W electric kettle to boil away 1.5 Kg of water is 2400 seconds.
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An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the positive direction, what is the sign associated with the average velocity of the object
The sign associated with the average velocity of the object is negative.
Average velocity of the object
The average velocity of the object is calculated as follows;
Average velocity = (v1 + v2)/2
v1 = -20/30 = -0.667 m/s
v2 = 20/50 = 0.4 m/s
Average velocity = (-0.667 + 0.4)/2
Average velocity = -0.134 m/s
Thus, the sign associated with the average velocity of the object is negative.
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Q2
Radioactive waste from nuclear power stations is a man-made source of background
radiation.
(a) Give one other man-made source of background radiation
Answer:
the clock hand of watch which have radium-226 for luminance
Which two options would INCREASE the electric force between two charged particles?
A. Increase the distance between the particles. B. Decrease the charge of one of the particles. C. Decrease the charge of both particles
D. Decrease the distance between the particles
E. Increase the charge of one of the particles.
The electric force between two charged particles can be increased by decreasing the distance between the two particles.
How to increase electric force between two charged particles.The technique of decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. while
increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.
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A 0.3Kg mass of liquid is heated from 20°C to 53°C. The specific heat capacity of the
liquid is 22001/Kg C. How much energy is transferred to the liquid?
The total energy is transferred to the liquid is = 217809.9 J
Given:-It is given in the question that—
weight of the liquid= 0.3kg
specific heat capacity=22001/kg C
temperature changes between 20°C to 53°C
Solution:-we can easily solve this problem by using the formula of the calorimetry principle.
The formula is —
Q= m×s×t [Q=total energy is transferred, m= mass of the substance, s= specific heat, t= final temperature - initial temperature]
by putting the value on what is given in this question —
Q= 0.3×22001×(53-20)
= 217809.9 J
So energy transferred to the liquid is=217809.9 J
A 12-kilogram mass has a kinetic energy of 150 joules. The speed of the object is
A.25.0 B.12.5 c.3.55 D.5.00
Answer:
OPTION D 5 m/s
Explanation:
0.5 × 12 × v² = 150
sqrt(150/6) = v
v = 5 m/s
Would young rocks be found near a volcano?
Answer:
maybe
Explanation:
young rocks may be found near volcanoes
Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second?
Answer:
V / T is the slope of the graph
S = V / T so the slope of the graph will be the displacement at that point
Even tho the above assumes uniform quantities, the instantaneous displacement at any time is the slope of the graph at that point in case one has a graph that is not a straight line.
Diverse crops can become vulnerable to pests, disease, and climate change. Which part of this statement is false?
The statement 'diverse crops can become vulnerable to pests, disease, and climate change' is considered false regarding this last point (climate change).
What is adaptation?Adaptation is an evolutionary process where a species fits certain environmental conditions.
Plant species are intrinsically vulnerable to climate change because they are adapted to certain climate (temperature) conditions.
In conclusion, the statement 'diverse crops can become vulnerable to pests, disease, and climate change' is considered false regarding this last point (climate change).
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which wave carries the least energy?
Answer:
B
Explanation:
The answer is B, because the waves are farther apart then the others. And it also looks like radio waves, which carries the least energy.
Answer: The third one
Explanation: there isnt many waves in that one les waves = less energy and i took the quiz/test.
Where do nebulae come from, in the opinion of science?
*
1 point
It was made from a giant rabbit's skin.
It formed from the same cloud of dust that our entire galaxy is made from
It formed from hydrogen, the first element created in the universe.
It formed debris that was left over after a nova or supernova
Answer:
It formed from the same cloud of dust that our entire galaxy is made from
What happens to the light in a
concave lens?
a. the light diverges when it passes
through the lens.
b. the light diverges before it enters the
lens.
c. the light converges when it enters the
lens.
Answer:
a. the light diverges when it passes through the lens.
Explanation:
All the light rays after passing through the concave lens diverge and when produced backwards appear to meet at a point on the principal axis of the lens. This point is known as principal focus of a concave lens.
Calculate the total distance travelled by the motorcyclist over 0-60
A uniform cylindrical rod is 0.63m long and it has cross sectional area of 0.1m. calculate the depth of immersion
The depth of immersion of the uniform cylindrical rod is 0.63m.
What is Depth of immersion?This is defined as the distance in which a body reaches when it is submerged.
Depth of immersion = Volume/Cross-sectional area
Volume = Cross-sectional area × length
= 0.1m² × 0.63m = 0.063m³
Depth of immersion = 0.063m³ / 0.1m²
= 0.63m
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The chart lists the masses and velocities of four objects.
A 3-column table with 4 rows titled Motion of 4 Objects. The first column labeled Object has entries W, X, Y, Z. The second column labeled Mass (kilograms) has entries 58, 34, 89, 60. The third column labeled Velocity (meters per second) has entries 1, 2, 0.5, 2.
Which object requires the greatest change in momentum in order to stop its motion?
W
X
Y
Z
The object which requires the greatest change in momentum in order to stop its motion is object Z.
What is momentum?Momentum of any object is the product of the velocity of the object and its mass.
p =mv
Given is the chart lists the masses and velocities of four objects.
Object Mass (kg) Velocity (m/s)
W 58 1
X 34 2
Y 89 0.5
Z 60 2
Calculate the momentum for all the objects.
Momentum for W, p = 58 x 1 = 58 kg.m/s
Momentum for X, p = 34 x 2= 68 kg.m/s
Momentum for Y, p = 89 x 0.5 = 44.5 kg.m/s
Momentum for Z, p = 60 x 2 = 120 kg.m/s
On comparing the data from calculated momentum, we have a conclusion that highest momentum is for object Z.
Therefore, the object which requires the greatest change in momentum in order to stop its motion is object Z.
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Answer:
z
Explanation:
:)
A 1-kg block is lifted vertically 1 m at constant speed by a boy. The work done by the boy is about:
Answer:
[tex]9.8\; {\rm J}[/tex], assuming that the gravitational field strength is [tex]g = 9.8\; {\rm N \cdot kg^{-1}}[/tex].
Explanation:
Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.
By Newton's Second Law, the net force on this block would be [tex]0[/tex]. External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.
Let [tex]m[/tex] denote the mass of this block. It is given that [tex]m = 1\; {\rm kg}[/tex]. The weight of this block would be:
[tex]\begin{aligned}\text{weight} &= m\, g \\ &= 1\; {\rm kg} \times 9.8\; {\rm N \cdot kg^{-1}} \\ &= 9.8\; {\rm N}\end{aligned}[/tex].
Hence, the force that the boy applies on this block would be upward with a magnitude of [tex]F = 9.8\; {\rm N}[/tex].
The mechanical work that a force did is equal to the product of:
the magnitude of the force, and the displacement of the object in the direction of the force.The displacement of this block (upward by [tex]s = 1\; {\rm m}[/tex]) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:
the magnitude of the force that this boy exerted, [tex]F = 9.8\; {\rm N}[/tex], andthe displacement of this block in the direction, [tex]s = 1\; {\rm m}[/tex].[tex]\begin{aligned}\text{work} &= F\, s \\ &= 9.8\; {\rm N} \times 1\; {\rm m} \\ &= 9.8\; {\rm J}\end{aligned}[/tex].
A boat crossing a 153.0 m wide river is directed so that it will cross the river as quickly as possible. The boat has a speed of 5.10 m/s in still water and the river flows uniformly at 3.70 m/s. Calculate the total distance the boat will travel to reach the opposite shore.
We have the relation
[tex]\vec v_{B \mid E} = \vec v_{B \mid R} + \vec v_{R \mid E}[/tex]
where [tex]v_{A \mid B}[/tex] denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.
We're given speeds
[tex]v_{B \mid R} = 5.10 \dfrac{\rm m}{\rm s}[/tex]
[tex]v_{R \mid E} = 3.70 \dfrac{\rm m}{\rm s}[/tex]
Let's assume the river flows South-to-North, so that
[tex]\vec v_{R \mid E} = v_{R \mid E} \, \vec\jmath[/tex]
and let [tex]-90^\circ < \theta < 90^\circ[/tex] be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that
[tex]\vec v_{B \mid R} = v_{B \mid R} \left(\cos(\theta) \,\vec\imath + \sin(\theta) \, \vec\jmath\right)[/tex]
Then the velocity of the boat relative to the Earth is
[tex]\vec v_{B\mid E} = v_{B \mid R} \cos(\theta) \, \vec\imath + \left(v_{B \mid R} \sin(\theta) + v_{R \mid E}\right) \,\vec\jmath[/tex]
The crossing is 153.0 m wide, so that for some time [tex]t[/tex] we have
[tex]153.0\,\mathrm m = v_{B\mid R} \cos(\theta) t \implies t = \dfrac{153.0\,\rm m}{\left(5.10\frac{\rm m}{\rm s}\right) \cos(\theta)} = 30.0 \sec(\theta) \, \mathrm s[/tex]
which is minimized when [tex]\theta=0^\circ[/tex] so the crossing takes the minimum 30.0 s when the boat is pointing due East.
It follows that
[tex]\vec v_{B \mid E} = v_{B \mid R} \,\vec\imath + \vec v_{R \mid E} \,\vec\jmath \\\\ \implies v_{B \mid E} = \sqrt{\left(5.10\dfrac{\rm m}{\rm s}\right)^2 + \left(3.70\dfrac{\rm m}{\rm s}\right)^2} \approx 6.30 \dfrac{\rm m}{\rm s}[/tex]
The boat's position [tex]\vec x[/tex] at time [tex]t[/tex] is
[tex]\vec x = \vec v_{B\mid E} t[/tex]
so that after 30.0 s, the boat's final position on the other side of the river is
[tex]\vec x(30.0\,\mathrm s) = (153\,\mathrm m) \,\vec\imath + (111\,\mathrm m)\,\vec\jmath[/tex]
and the boat would have traveled a total distance of
[tex]\|\vec x(30.0\,\mathrm s)\| = \sqrt{(153\,\mathrm m)^2 + (111\,\mathrm m)^2} \approx \boxed{189\,\mathrm m}[/tex]