two competing models attempt to explain the motions and changing brightness of the planets: ptolemy's geocentric model and copernicus' heliocentric model.

Here, a length of 20 go copperware is provided for us. Having a right-handed tiny dilates diameter of.8118 millimeters, it is shaped into a circular loop with a 17 centimeter radius.

Assume that the capital r is 17 centimeters, or.107 met, and that the magnetic field is growing from 0 to so that 1 is equal to 0 and b 2 is equal to 11 milli tesla, or 10 to the power of 11 minus 3 tesla, in time of.24 seconds. Okay, so you need to figure out the average power lost during this procedure. In addition, copper has a resistivity of 1.72 times 10 to the minus 8 right meter. Therefore, in this case, we first determine the induced emf in the loop.

In other words, emf will equal the change in magnetic flux, which is fi 2 minus pi 1 by t, right, and fight will equal b 2 a minus b 1 an area over here, b. 2 is we have got 11 times of 10 to the power of minus 3 times the area of the loop will be, so let me just show you here area will be equal to pi r square, which is equal to pi times of 0.17 square. We can therefore multiply it here by 10 to the power of.17 square right b, where 1 is 0.

As a result, we can plug it in here by times 10 to the power of.17 square right b. 1 is 0. Thus, the other period is not taken into account, and the time is.24 seconds, correct voltages. So let me assess how much you're getting and see. It is 4.16 x 10 to the minus 3 volt power to the right. The induced m f is therefore this.

This will be squared right in meters, and this is where home is. In order to determine the electrical power dissipated, which is equal to v squared by r right, the resistance, and v, let me evaluate and see how much we're getting. This is 0.035 right now. We already have a resistance of 0.035 radius and 4.16 times 10 to the power of -3 entire squared, and this will be in what way. The amount you receive is approximately 4.9 times 10 to the power of negative 4.

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Answer:

phase

Explanation:

Phases   :   solid   liquid  gas

Answer:

form or state. (Sometimes the teacher won't accept state as an answer.)

Explanation:

For matter to change when moving from a solid state, it would have to be physically altered to be in, say, a liquid state. It's still the same product, it just had to change form. Ex: Solid to liquid. When you take an ice cube and melt it, it is still the same water, it's just in a different form or state.

Hope this helps! :)

A whole oscillation, cycle, or vibration, for instance, is the movement from y = A to y = +A and back to y = A. The period is the amount of time T needed to finish one oscillation.

Simple harmonic motion, or SHM, is a specific type of repetitive or periodic motion that describes the oscillation of the pendulum. The oscillating object's position changes sinusoidally throughout time. Many things go back and forth. A youngster swinging can be thought of as basic harmonic motion since the motion is approximatively sinusoidal. Simple harmonic motion does not include some complex motions, such as turbulent ocean waves.

When an item is in simple harmonic motion, it is simple to calculate both its position in relation to time and the rate at which it oscillates back and forth. In this lab, you will examine two simple harmonic motion examples: a simple pendulum and a spring-mass system.

A particle in simple harmonic motion that vibrates vertically goes up and down between two extremes when y = A. The amplitude is the largest displacement, A.

A whole oscillation, cycle, or vibration, for instance, is the movement from y = A to y = +A and back to y = A.

The period is the amount of time T needed to finish one oscillation. The frequency f, or number of vibrations the system makes per unit of time, is a related quantity. The unit of measurement for frequency is Hertz (abbreviated as Hz), with 1 Hz equal to one second. Frequency is the reciprocal of time.

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At the top of his path, he comes to rest for a moment but he will not be in equilibrium at this point.

No, the boy is not in equilibrium. At the moment at which the boy is released from his father's grip, he is not in equilibrium.

Being in equilibrium means that the net force on the body is zero. When we talk about net force, it means that the net acceleration should be zero. But when the boy is released into the air, the boy's velocity will become zero at the highest point, but the acceleration is never zero. The velocity of the body has nothing to do with the equilibrium of the body.

The earth is constantly applying gravitational force to the body.

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Only the charge present inside the cavity can explain the electric field that exists there. The electric field inside the hollow would remain unchanged as a result.

Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field. To predict what would happen to electric charges nearby a specific point, one only needs to be aware of the value of the electric field there, without having any precise knowledge of what generated the field.

When one charge is thought of as the generator of an electric field that spreads outward into the surrounding space, the electric force is not thought of as a direct interaction of two electric charges that are separated from one another.

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(a) The impulse-momentum theorem (Eq. 9-31) results in (a) when m=0.30 kg.  (b) Applying Eq. The force exerted by the wall on the ball is 935.

J /Δt=(1.8/0.010) j ^ =(180N) j ^.

According to Newton's third law, the ball's force on the wall is (180N) j, meaning that it is 180N in magnitude and is directed directly at the wall.

Let the momentum ball go.

m = 0.37 k g

contacts the vertical wall at an incidence angle while traveling at v mph.

= 22 with the positive x-axis direction and it bounces back at the same speed and angle.

The velocity of hitting the wall can be expressed vectorially as v s = v cos I + v sin j.

Then the rebounce's velocity will be given by v b = v cos I + v sin j.

Here, the vertical component is unchanged, the horizontal component is reversed, and the effect of gravity is not taken into account.

The mass ball's impulse or change in momentum

m = 370 g = 0.37 k g

is

= m (=> v b − => v s) = − 2 m v cos θ ˆ i= − 2 × 0.37 × 3.9 × cos 22 ˆ i kgm/s

= − 2.675 ˆ I kgm/s

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Answer: C. brightness, temperature

Explanation: This question doesn't fully make sense because there are basically multiple correct answers. A star has the properties of distance, luminosity, temperature, brightness, radius, etc .

When Solid iron(II) sulfate and a solution of barium chloride react together, they form solid barium sulfate and a solution of iron (II) chloride. Here, exchange of anions and cations took place and is an example of a double displacement reaction.

A double Displacement reaction is a type of reaction in which, the cations and anions of the two ionic compounds exchange with each other to form new compounds. The overall reaction of double displacement looks like this,

X⁺Y⁻ + A⁺B⁻ ---------------> X⁺B⁻ + A⁺Y⁻

Precipitation reactions and neutralization reactions are two common examples of Double displacement reactions. In the given question, the reaction of Iron sulfate and Barium Chloride reaction is as follows;

FeSO₄ + BaCl₂ -------------> FeCl₂ + BaSO₄

Here the cations Fe²⁺ and Ba²⁺ are exchanged with the anions Cl⁻ and SO₄²⁻.

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The cyclist will accelerate because he changed his direction from west to south.

Acceleration is a vector quantity. It has both magnitude and direction.

Given is a bicyclist bikes to the west at a constant speed for 30 minutes before turning South and continuing at the same speed for an hour.

As learned above, acceleration is a vector quantity. This means that it has both the magnitude and the direction. If any one of that changes the acceleration will change. Now, since the direction changed from west to south, the resultant acceleration of the cyclist will change. Hence, the cyclist will accelerate.

Therefore, the cyclist will accelerate because he changed his direction from west to south.

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Current passing through his body is 1.67 A. power dissipated in his body is 27.8 kW and internal resistance is 20.0 MΩ .Low enough voltage levels allow the power supply to work with low resistance devices.

Voltage is the pressure from the power source of an electrical circuit that drives charged electrons (current) through a conducting loop, allowing them to perform tasks like lighting a lamp.

Briefly stated, voltage equals pressure and is measured in volts (V). The phrase honours Italian physicist Alessandro Volta (1745–1827), who developed the voltaic pile, the predecessor of the modern household battery. Voltage was first referred to as electromotive force in the early days of electricity (emf). Voltage is therefore represented by the letter E in equations like Ohm's Law, and the terms "voltage" and "potential difference" are sometimes used interchangeably. A better way to define potential difference is as the difference in potential energy between two places in a circuit. A simple indicator is the potential difference or voltage.

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31.64 m/s with velocity fast is it moving 1.8 s after it was thrown vertically downwards at a speed of 14 m/s from the top of a tall building.

V= u + gt= 14 + 9.8×1.8 = 14 + 17.64 = 31.64 m/s

When a body is travelling in a straight line, its estimated "rate of change of displacement in relation to time" is referred to as its velocity.

Speed is a scalar number since it lacks a direction and the value it receives from the distance-to-time ratio simply indicates its magnitude. It doesn't provide any guidance information. Because it always has a direction, velocity is a vector. As a result, when the displacement to time ratio for linear velocity is determined, it provides both the direction and the magnitude.

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The component of the forces and the frictional force of the bodies are as follows

6. The frictional force is approximately 37°

7. The frictional force is 0, while the force holding the mass is approximately 49.05 N

8. Please find attached the drawing showing the three forces acting on the block and their direction.

The forces are; [tex]F_{fr}[/tex] = [tex]F_{W}[/tex] ≈ 33.55 N, [tex]F_{N}[/tex] ≈ 92.18 N

9. The steepest angle of the slope is approximately 37.6°

Frictional force is the force that is generated and serves to prevent the relative motion of two bodies in contact.

6. The angle made by the rope with the horizontal = 37°

The tension in the rope = 10 N

Velocity of the crate = Constant

Given that the velocity of the crate is constant:

The frictional force = The horizontal component of the tension in the rope

Which gives: Frictional force = 10 N × cos(37°) ≈ 7.99 N

7. The frictional force is given by the formula: [tex]F_{fr} = m\cdot g \cdot cos(\theta)\cdot \mu[/tex]

Given that the plane is frictionless, we have: μ = 0

Therefore: Frictional force, [tex]F_{fr} = m\cdot g \cdot cos(\theta)\times 0 = 0[/tex]

The force holding the mass, F = m·g·sin(θ)

Where:

θ = 30.0°
g = The acceleration due to gravity ≈ 9.81 m/s²

∴ F ≈ 10.0 kg × 9.81 m/s² × sin(30°) = 49.05 N

8. Please find attached the drawing showing the weight, the friction force and the normal reaction of the block.

Given that the block slides down at a constant speed, the frictional force is equivalent to the weight component down the incline

The weight components of the block are:

Frictional force, [tex]F_{fr}[/tex] = Weight component down the incline, [tex]F_{W}[/tex], which gives;

Frictional force, [tex]F_{fr}[/tex] = 10.0 kg × 9.81 m/s² × cos(20) × μ = 10.0 kg × 9.81 m/s² × sin(20) ≈ 33.55 N

Weight component down the incline, [tex]F_{W}[/tex] ≈ 33.55 N

The normal reaction, [tex]F_{N}[/tex] = m·g·cos(θ)

Therefore: Normal reaction, [tex]F_N[/tex] ≈ 10.0 kg × 9.81 m/s² × cos(20°) ≈ 92.18 N

9. When the crate moves at a steady speed, the required horizontal force = The frictional force = m·g·μ

Given that m = 79.4 kg, μ = 0.2, we have;

Friction force = Required force = 79.4 × 9.81 × 0.2 = 155.7828

The required horizontal force = 155.7828 N

10. Given that the coefficient of static friction, μ = 0.77, we have:

When the car slips; friction force = weight of the car acting on the incline

m·g·cos(θ)·μ = m·g·sin(θ)

[tex]\mu = \dfrac{m \cdot g\cdot sin(\theta)}{m\cdot g\cdot cos(\theta)} = tan(\theta)[/tex]

The steepest angle, θ = arctan(μ)

Which gives;

Steepest angle, θ = arctan(0.77) ≈ 37.6°

The steepest angle is, θ ≈ 37.6°

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Answer:

Range of values: [9.97, 10.13] or 0.16 ml

Percentage uncertainty = 0.0.796%

Explanation:

Since there is an uncertainty of ±0.08 ml, the minimum is
10.05 - 0.08 = 9.97

Maximum with uncertainty = 10.05 + 0.08 = 10.13

So the min, max range is [9.97, 10.13] which is a spread of 0.16

Uncertainty as a percentage

= (0.08/10.05) x 100

= 0.0.796%

Answer:

Explanation:

here you need to draw a distance time graph for the car
like put 1-5 which indicates hours on x axis and
you need to covert the km into m by using the unitary method as we know 1km-1000m
then 40km=40000m and 20km=20000km like this 10-50 you need to convert in metres, then write them in y axis.

then you draw a graph  for motion with constant speed in  that distance time graph and plot them

then you will get your answer

The net power output for this heat engine will be 50 MW. The thermal efficiency for this heat engine will be 0.55 percent. The temperature of the furnace will be 15°c.

A heat engine is a device that generates power by rejecting some of the heat it receives from a source at high temperatures to a sink at low temperatures, such as the atmosphere. A Carnot engine is a reversible heat engine that operates between the two temperatures with optimal efficiency.

The heat engine's efficiency is always lower than the Carnot engine's. There are presented the heat transfer rates to and from a heat engine. Both the thermal efficiency and the net power output must be determined.

There is very little heat loss through the pipes and other parts.

This heat engine uses the river as the low temperature reservoir and the furnace as the high temperature reservoir. Keep in mind that the heat engine uses 37.5% of the heat it receives to produce work.

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Answer:

When it is dropping into the sand.

The ratio of an object's mass to volume is known as its density. Density is defined as the product of mass and volume, or D = m/v. Because of the size, mass, and arrangement of each substance's atoms or molecules, each substance has a unique characteristic density.

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The weight of a person on the planet Pluto with mass 85 kg is 52.36 N.

What is Pluto?

Pluto is a dwarf planet in the Kuiper belt, a ring of planets beyond Neptune's orbit. The ninth-largest and tenth-most massive object known to exist, it orbits the Sun directly. The largest trans-Neptunian object by volume, it is only slightly larger in mass than Eris. Like other Kuiper belt objects, Pluto is substantially smaller than the inner planets and is primarily made of ice and rock. The moon of Earth is only one-sixth the mass and one-third the volume of Pluto.

At first, lets calculate the acceleration due to gravity at Pluto:

The formula to calculate the acceleration due to gravity is:

[tex]a_g = G \times \frac{m}{r^2}[/tex]

where, a = acceleration due to gravity, m = mass, r = radius, G = gravitational constant

The mass is 1.303 x 10^22 kg

The radius is 1.1883 x 10^6 m

G is 6.67408 x 10^-11 m^3/kg•s²

So

a = 6.67408 x 10^-11 m^3/kg•s^2 • 1.303 x 10^22 kg / (1.1883 x 10^6 m)^2

a = 8.69632624 x 10^11 m^3/s^2 / 1.41205689 x 10^12 m^2

a = 6.1586 x 10^-1 m/s² or 0.616 m/s²

Now, lets calculate the weight:

w = ma

where, w = weight, m = mass

putting the values in question, we get,

w = 85 (0.616)  

w = 52.36 N

Note: Some correction in the value of mass and radius needs to be done in the question.

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A magnetic force that is given by acts on a wire when a current I passes through it while it is in a consistent magnetic field (B).  F = B I L  where L is the conductor's length.

For thousands of years, people have been aware of magnets and magnetism. The earliest records are from Asia Minor, specifically from a place called Magnesia, which is where words like magnet first appeared.

Ancient people were intrigued by the magnetic rocks that were discovered in Magnesia, which is today a region of western Turkey. When people first discovered magnetic rocks, it's possible that they noticed that some of these rocks were more magnetically drawn to iron or other magnetic rocks than other portions.

The poles of a magnet are these regions. A magnet's magnetic pole is the area that attracts other magnets or magnetic materials, such iron, with the greatest force.

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The acceleration of each block is 1.225m/s^2

The string exerts 2.315N on 210g block, and 2.976N on 270g block

It will take 1.28s for each block to traverse

Part a

Acceleration, a of the block:

m1=270g

m2=210g

g=9.8

Acceleration=(m1-m2)*g/(m1+m2)

                    =(270-210)*9.8/(270+210)

                    =1.225m/s^2

Part b

Force that the string exerts on each block:

Force, T1 on smaller block:

T1=m2(g+a), where m2=0.21kg, g=9.8, and a=1.225m/s^2

T1=0.21(9.8+1.225)

T1=2.315N

Force exerted on smaller block=2.315N

Force, T2 on larger block

Here, m1=0.27kg, g=9.8, and a=1.225m/s^2

T2=0.27(9.8+1.225)

    =2.976N

Force exerted on larger block=2.976N

Part c

How long it will take each block to traverse 1.0m

h=1.0m

a=1.225m/s^2

[tex]t=\sqrt{\frac{2h}{a} }[/tex]

[tex]t=\sqrt{\frac{2*1}{1.225} }[/tex]

t=1.28s

The question was incomplete, complete question is given below:

A person holds a 210-g block that is connected to a 270-g block by a string going over a light pulley with no friction in the bearing (an Atwood machine). After the person releases the 210-g block, it starts moving upward and the heavier block descends. Part A: What is the acceleration of each block? Part B: What is the force that the string exerts on each block? Part C: How long will it take each block to traverse 1.0 m?

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Answer:

reaction

Explanation:

Newtons third law states that for every action there is an equal but opposite reaction

and for that object (rocket, missile, jet,) as the engine is ignited the force of the burning fuel pushes backward while the rocket moves forward so the rate at which the fuel burns is equal to the rate at which the object moves forward

the force at which the burning fuel pushes backward is equal but opposite to the rate at which the object moves forward

The fact that both spools travel same distance over same period of time and have equal mass, both will reach the top of the ramp at same time.

The same tension inextensible threads are used to draw two identical spools of similar mass, A and B, from rest and up identical ramps. The thread is wrapped repeatedly around spool A, but it is secured to a fixed spot on spool B, preventing rotation of spool B. The ramps and the objects don't rub against each other. From the bottom of the ramp to the same spot at the top of the ramp, both spools are hauled.

The tension from the thread force and a part of the force of gravity are forces acting on both spools along the ramp. Due to the equal spool masses and tension forces, the net forces operating on both are also the same. As a result, both spools' centers move with the same acceleration. Both begin at zero speed, hence the speed of both spools at any one time is the same. The distance and duration of travel for both spools are the same. So, they both arrive at the ramp's top simultaneously.

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Will spool A reach the top of the ramp before, after, or at the same instant as spool B? If you do not have enough information, state so explicitly. Explain your reasoning.

Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m

ANSWER:

1. C. Wave X and Wave Y share the same speed.

2. D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.

STEP-BY-STEP EXPLANATION:

The amplitude of a wave does not affect the speed at which the wave travels. Both wave A and wave B travel at the same speed. The speed of a wave is only altered by alterations in the properties of the medium through which it travels.

Therefore, in the first art the correct answer is C. Wave X and Wave Y share the same speed.

If the medium is uniform (does not change), the speed of the wave will be constant.

Therefore, the correct answer is: D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.

Given:

Speed of the toy car max speed = 15 m/s

Time taken before the battery dies = 30 minutes.

Let's find how far the car went.

To find the distance the car travelled, aply the formula:

Where:

Speed = 15 m/s

time = 30 min

Convert the speed to meters per hour

Convert the time to hour.

Where:

1 hour = 60 mins = 3600 seconds

Thus, we have:

• Speed in m/h:

• Time in hour:

To find the distance, we have:

Therefore, the toy car travelled 27000 meters.

ANSWER:

27000 meters.

Answer:

91 kg

Explanation:

F = m a

893 = m *9.81 m/s^2

91 kg

If an astronaut weighs 148 N on the Moon and 893 N on Earth, his terrestrial mass is 91 kg

Therefore,

F = m a

893 = m × 9.81 m/s^2

91 kg

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(a) The force of friction increases as the applied force increases.

(b) The force of friction at each value of X (applied force ) can determined by subtracting the net force on the block from the  applied force.

The coefficient of static friction is the ratio of the maximum static friction force between the surfaces in contact before movement commences to the normal force.

Mathematically, the coefficient of static friction is given as;

μ = F/N

where;

Before the block start moving, the static friction must be overcame since it prevents the block from moving.

The net force on the block is determined by applying Newton's second law of motion.

F - Ff = ma

F = ma + Ff

where;

From the formula above, as the applied force increases the force of friction increases as well.

The force of friction at each value of X (applied force ) is calculated as follows;

Ff = F - ma

Ff = F - F(net)

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Answer: angle = 2°

Explanation:

Let the angle of inclination be θ,

as shown in figure the forces equation on the block are as follows

Fsinθ = ma , where F=mg

mgsinθ = ma

sinθ = [tex]\frac{a}{g}[/tex]....................eq1

now we know that s = ut  + 1/2at*t

3 = 0+1/2at*t

6 = a*[16.81]

a = 0.357m/s*s

now put value of a in eq1

therefore sinθ = 0.357/9.8=0.0364

angle θ = 2°

Answer:

See below

Explanation:

If you draw the vectors, you will see the 40 N 's cancel out

 and you are left with 20 N at 270   and 50 N at 60   (see diagram)

    find R...   then the 'balancing'  R  will be of same magnitude in opposite (+180 degrees) direction

x component of 50 N       50 cos 60 = 25 N

y component of 50 N        50 sin 60 = 43.3 N

So now you have    25 N in x direction    and   (43.3 -20) = 23.3 N at 90 deg

R   Magnitude = sqrt(  25^2 + 23.3^2 ) = 34.2 N

R angle = arctan ( 23.3/25) = ~43 degrees

So balancing force would be   34.2 N  at  (43+180) = 223 degrees