Two children are playing on a seesaw. The child on the left weighs 50 lbs. And the child on the right weighs 100 lbs. If the child on the left is 3 feet from the pivot, how far must the child on the right be from the pivot fro the seesaw to be balanced.

Answers

Answer 1

Given :

Two children are playing on a seesaw. The child on the left weighs 50 lbs. And the child on the right weighs 100 lbs.

To Find :

If the child on the left is 3 feet from the pivot, how far must the child on the right be from the pivot from the seesaw to be balanced.

Solution :

We know, for seesaw to balance :

[tex]m_1gd_1=m_2gd_2[/tex]

Here, [tex]d_1\ and \ d_2[/tex] is distance from origin from pivot point.

Putting all the values in the equation, we get :

[tex]50\times g\times 3=100\times g\times d_2\\\\d_2=1.5\ feet[/tex]

Therefore, distance of right child from pivot to balance the seesaw is 1.5 feet.

Hence, this is the required solution.


Related Questions

Problem 10.012 SI A vapor-compression refrigeration cycle operates at steady state with Refrigerant 134a as the working fluid. Saturated vapor enters the compressor at 2.6 bar, and saturated liquid exits the condenser at 12 bar. The isentropic compressor efficiency is 80%. The mass flow rate of refrigerant is 7 kg/min. Determine: (a) the compressor power, in kW. (b) the refrigeration capacity, in tons. (c) the coefficient of performance.

Answers

Answer:

a) 4.1 kw

b) 4.68 tons

c) 4.02

Explanation:

Saturated vapor enters compressor at ( p1 ) = 2.6 bar

Saturated liquid exits the condenser at ( p2 ) = 12 bar

Isentropic compressor efficiency = 80%

Mass flow rate = 7 kg/min

A) Determine compressor power in KW

compressor power = m ( h2 - h1 )

                                = 7 / 60 ( 283.71 - 248.545 )

                                = 4.1 kw

B) Determine refrigeration capacity in tons = m ( h1 - h4 )

                                                                       = 7/60 ( 248.545 - 107.34 )

                                                                       = 16.47 kw = 4.68 tons

C) coefficient of performance ( COP )

= Refrigeration capacity / compressor power

= 16.47 / 4.1 = 4.02

Attached below is the beginning part of the solution

   

Store the amount of the minimum loan in min_loan and the amount of the maximum loan in max_loan Then, store the name of the country that received the largest loan in max_country and the smallest loan in min_country Hint: max and min are built in Python functions that you can use to find the minimum value or maximum value in any sequence.

Answers

Answer:

See Explanation

Explanation:

The question has missing details;however, I'm able to pick the following points from the question

There's supposed to be a list of loan amountsThere's also supposed to be a list of countries that took loans. This list will correspond to the loan list

Having said that, the question can be solved in two ways.

I prompt the user to enter loan amounts and corresponding country I assume any value for the loan amounts and the country

I'll answer this question using the first method and the solution is as follows (See Comments for line by line explanation):

#This line prompt user for number of countries

n = int(input("Number of countries: "))

#This initializes an empty list for loan amounts

loan_amounts = []

#This initializes an empty list for country

country = []

#The following iteration gets names of countries and their respective loan amounts

for i in range(0,n):

    country_name = input("Name of country: ")

    loan = int(input("Loan Amount: "))

    country.append(country_name)

    loan_amounts.append(loan)

#This gets the maximum loan

max_loan = max(loan_amounts)

#This gets the index of the maximum loan

iindex = loan_amounts.index(max_loan)

#This gets the country with the maximum loan

max_country = country[iindex]

#This gets the minimum loan

min_loan = min(loan_amounts)

#This gets the index of the minimum loan

iindex = loan_amounts.index(min_loan)

#This gets the country with the minimum loan

min_country = country[iindex]

#This prints the country with the maximum loan and the loan amount

print(str(max_country)+": "+str(max_loan))

#This prints the country with the minimum loan and the loan amount

print(str(min_country)+": "+str(min_loan))

I need help with part (C). Pleasee help me. It’s due in a few hours.

Answers

Answer:

u do the same thing as part B but only add 100 k, I think, cuz I'm still in middle school but I mean if u see it asks u to do the same thing as B but C says that instead, u do it at half pressure and 100 k is higher temp so what its asking is to repeat b but the twist is u do it at half pressure and 100 k is the higher temp

hope this helps :)  

calculate the quantities of materials required for the first class brickwork in 1:6 cement mortar for 10 cu.m. assume the suitable data.

Answers

How to Calculate the Amount of Mortar Mix Needed
Find the area of your brick structure by multiplying length and width. ...
Multiply the square footage by seven to estimate the number of bricks you use in your project. ...
Divide the total number of bricks by 30 to estimate how many 60-pound bags of mortar mix you need.

Which of the following is a basic type of weld? O Groove O Lap O Edge O Corner​

Answers

Knnmnnnmnbbnm. Bonn. By. B

Find R subscript C and R subscript B in the following circuit such that BJT would be in the active region with V subscript C E end subscript equals 5 V and I subscript C equals 25 m A V subscript C C end subscript equals 15 space V comma space V subscript D 0 end subscript equals 0.7 space V comma space beta equals 100 comma space V subscript A equals infinity.. Ignore the early effect in biasing calculations.

Answers

Answer: Rc = 400 Ω and Rb = 57.2 kΩ

Explanation:

Given that;

VCE = 5V

VCC = 15 V

iC = 25 mA

β = 100

VD₀ = 0.7 V

taking a look at the image; at loop 1

-VCC + (i × Rc) + VCE = 0

we substitute

-15 + ( 25 × Rc) + 5 = 0

25Rc = 10

Rc = 10 / 25

Rc = 0.4 k

Rc = 0.4 × 1000

Rc = 400 Ω

iC = βib

25mA = 100(ib)

ib = 25 mA / 100

ib = 0.25 mA

ib = 0.25 × 1000

ib = 250 μAmp

Now at Loop 2

-Vcc + (ib×Rb) + VD₀ = 0

-15 (250 × Rb) + 0.7 = 0

250Rb = 15 - 0.7

250Rb = 14.3

Rb = 14.3 / 250

Rb = 0.0572 μ

Rb = 0.0572 × 1000

Rb = 57.2 kΩ

Therefore Rc = 400 Ω and Rb = 57.2 kΩ

A battery with an f.e.m. of 12 V and negligible internal resistance is connected to a resistor of 545 How much energy is dissipated by the resistor in 65 s?​

Answers

Answer:

When are resistors in series? Resistors are in series whenever the flow of charge, called the current, must flow through devices sequentially. For example, if current flows through a person holding a screwdriver and into the Earth, then  

R

1

 in Figure 1(a) could be the resistance of the screwdriver’s shaft,  

R

2

 the resistance of its handle,  

R

3

 the person’s body resistance, and  

R

4

 the resistance of her shoes.

Figure 2 shows resistors in series connected to a voltage source. It seems reasonable that the total resistance is the sum of the individual resistances, considering that the current has to pass through each resistor in sequence. (This fact would be an advantage to a person wishing to avoid an electrical shock, who could reduce the current by wearing high-resistance rubber-soled shoes. It could be a disadvantage if one of the resistances were a faulty high-resistance cord to an appliance that would reduce the operating current.)

Two electrical circuits are compared. The first one has three resistors, R sub one, R sub two, and R sub three, connected in series with a voltage source V to form a closed circuit. The first circuit is equivalent to the second circuit, which has a single resistor R sub s connected to a voltage source V. Both circuits carry a current I, which starts from the positive end of the voltage source and moves in a clockwise direction around the circuit.

Figure 2. Three resistors connected in series to a battery (left) and the equivalent single or series resistance (right).

To verify that resistances in series do indeed add, let us consider the loss of electrical power, called a voltage drop, in each resistor in Figure 2.

According to Ohm’s law, the voltage drop,  

V

, across a resistor when a current flows through it is calculated using the equation  

V

=

I

R

, where  

I

 equals the current in amps (A) and  

R

 is the resistance in ohms  

(

Ω

)

. Another way to think of this is that  

V

 is the voltage necessary to make a current  

I

 flow through a resistance  

R

.

So the voltage drop across  

R

1

 is  

V

1

=

I

R

1

, that across  

R

2

 is  

V

2

=

I

R

2

, and that across  

R

3

 is  

V

3

=

I

R

3

. The sum of these voltages equals the voltage output of the source; that is,

V

=

V

1

+

V

2

+

V

3

.

 

This equation is based on the conservation of energy and conservation of charge. Electrical potential energy can be described by the equation  

P

E

=

q

V

, where  

q

 is the electric charge and  

V

 is the voltage. Thus the energy supplied by the source is  

q

V

, while that dissipated by the resistors is

q

V

1

+

q

V

2

+

q

V

3

.

Explanation:

A power washer is being used to clean the siding of a house. Water enters at 20 C, 1 atm, with a velocity of 0.2 m/s .A jet of water exits at 20 C, 1 atm, with a velocity of 20 m/s an elevation of 5 m. At steady state, the magnitude of the heat transfer rate from the power unit to the surroundings is 10% of the power input. Determine the power input to the motor, kW.

Answers

A power washer is being used to clean the siding of a house. Water at the rate of 0.1 kg/s enters at 20°c and 1 atm, with the velocity 0.2m/s. The jet of water exits at 23°c, 1 atm with a velocity 20m/s at an elevation of 5m. At steady state, the magnitude of the heat transfer rate from power unit to the surroundings is 10% of the power input. Determine the power input to the motor in kW.

Answer:

Net power of 1.2 KW is being extracted

Explanation:

We are given;

Mass flow rate; m' = 0.1kg/s

Inlet temperature; T1 = 20°C = 293K

Inlet pressure; P1 = 1 atm = 10^(5) pa

Inlet velocity; v1 = 0.2 m/s

Exit Pressure; P2 = 1 atm = 10^(5) pa

Exit Temperature; T2 = 1 atm = 296K

Exit velocity; V2 = 20m/s

Change in elevation; h = Z2 - Z1 = 5m

We are told that the magnitude of the heat transfer rate from the power unit to the surroundings is 10% of the power input.

Thus;

Q = -0.1W

From Bernoulli equation;

Q - W = ∆Potential energy + ∆Kinetic energy + ∆Pressure energy

Where;

∆Potential energy = mg(z2 - z1)

∆Kinetic energy = ½m(v2² - v1²)

∆Pressure energy = mc_p(T2 - T1)

Thus;

-0.1W - W = [m'g(z2 - z1)] + [½m'(v2² - v1²)] + [m'c_p(T2 - T1)]

Where C_p is specific heat capacity of water = 4200 J/Kg.k

Plugging in the relevant values, we have;

-1.1W = (0.1 × 9.81 × 5) + (½ × 0.1(20² - 0.2²)) + (0.1 × 4200 × (296 - 293))

-1.1W = 4.905 + 19.998 + 1260

-1.1W = 1284.903

W = -1284.903/1.1

W ≈ -1168 J/s ≈ -1.2 KW

The negative sign means that work is extracted from the system.

The reversible and adiabatic process of a substance in a compressor begins with enthalpy equal to 1,350 kJ/kg, and ends with enthalpy equal to 3,412 kJ/kg. If the compressor efficiency is 0.85, find the actual specific work required by the compressor to operate, in kJ/kg.

Answers

Answer:

the actual specific work required by the compressor to operate is 2425.88 kJ/kg

Explanation:

Given that;

h₁ = 1350 kJ/kg

h₂₅ = 3412 kJ/kg

compressor efficiency П_ise = 0.85

we know that;

compressor efficiency П_ise = isentropic work / actual work

П_ise = (h₂₅ - h₁) / (h₂ - h₁ )

so

0.85 =  (h₂₅ - h₁) / (actual work )

Actual work = (h₂₅ - h₁) / 0.85

Actual work = (3412 - 1350) / 0.85

Actual work = 2062 / 0.85

Actual work = 2425.88 kJ/kg

Therefore the actual specific work required by the compressor to operate is 2425.88 kJ/kg

Scientists say that it takes over 50 years for trees to fully grow back after a fire. Most trees do not grow well under extreme environmental conditions.

If the climate continues to get warmer, do you think forests will be able to completely recover?

Yes
No

Explain your answer.

Answers

Answer:

no

Explanation:

How many trees would it take to reverse climate change?

1.2 trillion trees

Crowther says planting 1.2 trillion trees would give a reduction "way above" that figure. To put that in context, global CO2 emissions are around 37 billion tons per year.Apr 17, 2019

Discuss why TVET Institutions need advice of the business community in order
to provide good programmes.​

Answers

Answer:

Without the indispensable advice of the business community, TVET Institutions will be unable to cover the gap in career knowledge required by the business community.  To develop workers who possess the knowledge and skills required by today's business entities, there is always the continual need for the educational institutions (gown) to regularly meet the business community (town).  This meeting provides the necessary ground for the institutions to develop programs that groom the workforce with skills that are needed in the current workplace.  Educational institutions that do not seek this important advice from the business community risk developing workers with outdated skills.

Explanation:

TVET Institutions mean Technical and Vocational Education and Training Institutions.  They play an important role in equipping young people to enter the world of work.  They also continue to develop programs that will improve the employability of workers throughout their careers.  They regularly respond to the changing labor market needs, adopt new training strategies and technologies, and expand the outreach of their training to current workers while grooming the young people for work.

Thermoplastic parts are
A.commonly used for outer mirror housings.
B. commonly used for grilles
C.formed by stamping a plastic sheet in a mold
D.formed by forcing a molten solution into a mold.

Answers

Answer:

c

Explanation:

Thermoplastic parts are formed by forcing a molten solution into a mold.

Thus option D is correct.

Here,

Thermoplastic are plastic parts made from thermoplastic materials. These materials have the ability to be melted and remolded several times without undergoing any chemical change.

The thermoplastic parts are commonly used for different purposes such as in automotive industries, construction, medical, consumer goods, and much more. These parts are easily moldable and can be made into different shapes and sizes. They are also lightweight, strong, and durable, making them ideal for a wide range of applications.

They are commonly used for applications that require high strength and durability, such as in the automotive and aerospace industries.

Therefore option D is correct.

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What is the name given to the vehicles that warn motorists about oversized loads/vehicles?

a) Pilot Car

b) Advanced Car

c) Trail Car

d) Leader Car​

Answers

The answer is b I did this and I got the answer right

The car that is used to warn drivers about oversized loads is the Pilot Car.

What is a Pilot Car?

The Pilot Car is also called Escort Car. It is a vehicle used to warn other vehicles of the presence of an over-sized vehicle.

The role of Pilot vehicle operators is to warn road users (motorists) to be cautious of over-sized loads or vehicles.

The cars are used to guide motorists that are making use of roads in construction sites.

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trevor moves a magnetic toy train away from a magnet that cannot move. what happens to the potential energy in the system of magnets during the movement?

Answers

Answer:a

Ieieksdjd snsnsnsnsksks

An open-circuit wind tunnel draws in air from the atmosphere through a well-contoured nozzle. In the test section, where the flow is straight and nearly uniform, a static pressure tap is drilled into the tunnel wall. A manometer connected to the tap shows that static pressure within the tunnel is 45 mm of water below atmospheric. Assume that the air is incompressible, and at 25 C, 100 kPa absolute. Calculate the air speed in the wind-tunnel test section

Answers

Answer:

Air speed in the wind-tunnel [tex]v_{2}[/tex] = 27.5 m/s

Explanation:

Given data :

Manometer reading ; p1 - p2 = 45 mm of water

Pressure at section ( I ) p1 = 100 kPa ( abs )

temperature ( T1 ) = 25°C

Pw ( density of water ) = 999 kg/m3

g = 9.81 m/s^2

next we apply Bernoulli equation at section 1 and section 2

p1 - p2 = [tex]\frac{PairV^{2} _{2} }{2}[/tex]     ----------  ( 1 )

considering  ideal gas equation

Pair ( density of air ) = [tex]\frac{P}{RT}[/tex] ------------------- ( 2 )

R ( constant ) = 287 NM/kg.k

T = 25 + 273.15 = 298.15 k

P1 = 100 kN/m^2 = 100 * 10^3 or N/m^2

substitute values into equation ( 2 )

= 100 * 10^3 / (287 * 298.15)

= 1.17 kg/m^3

Also note ; p1 - p2 = PwgΔh  ------- ( 3 )

finally calculate the Air speed in the wind-tunnel test section by equating equation ( 1 ) and ( 3 )

[tex]\frac{PairV^{2} _{2} }{2}[/tex]   =  PwgΔh  

[tex]V^{2} _{2}[/tex] = [tex]\frac{2*999* 9.81* 0.045}{1.17}[/tex]  =  753.86

[tex]v_{2}[/tex] = 27.5 m/s

A beam of span L meters simply supported by the ends, carries a central load W. The beam section is shown in figure. If the maximum shear stress is 450 N/cm2 when the maximum bending stress is 1500 N/cm2. Calculate the value of the centrally applied point load W and the span L. The overall height of the I section is 29 cm.

Answers

Answer:

W = 11,416.6879 N

L ≈ 64.417 cm

Explanation:

The maximum shear stress, [tex]\tau_{max}[/tex], is given by the following formula;

[tex]\tau_{max} = \dfrac{W}{8 \cdot I_c \cdot t_w} \times \left (b\cdot h^2 - b\cdot h_w^2 + t_w \cdot h^2_w \right )[/tex]

[tex]t_w[/tex] = 1 cm = 0.01

h = 29 cm = 0.29 m

[tex]h_w[/tex] = 25 cm = 0.25 m

b = 15 cm = 0.15 m

[tex]I_c[/tex] = The centroidal moment of inertia

[tex]I_c = \dfrac{1}{12} \cdot \left (b \cdot h^3 - b \cdot h_w^3 + t_w \cdot h_w^3 \right )[/tex]

[tex]I_c[/tex] = 1/12*(0.15*0.29^3 - 0.15*0.25^3 + 0.01*0.25^3) = 1.2257083 × 10⁻⁴ m⁴

Substituting the known values gives;

[tex]I_c = \dfrac{1}{12} \cdot \left (0.15 \times 0.29^3 - 0.15 \times 0.25^3 + 0.01 \times 0.25^3 \right ) = 1.2257083\bar 3 \times 10^{-4}[/tex]

[tex]I_c[/tex] = 1.2257083[tex]\bar 3[/tex] × 10⁻⁴ m⁴

From which we have;

[tex]4,500,000 = \dfrac{W}{8 \times 1.225708\bar 3 \times 10 ^{-4}\times 0.01} \times \left (0.15 \times 0.29^2 - 0.15 \times 0.25^2 + 0.01 \times 0.25^2 \right )[/tex]

Which gives;

W = 11,416.6879 N

[tex]\sigma _{b.max} = \dfrac{M_c}{I_c}[/tex]

[tex]\sigma _{b.max}[/tex] = 1500 N/cm² = 15,000,000 N/m²

[tex]M_c[/tex] = 15,000,000 × 1.2257083 × 10⁻⁴ ≈ 1838.56245 N·m²

From Which we have;

[tex]M_{max} = \dfrac{W \cdot L}{4}[/tex]

[tex]L = \dfrac{4 \cdot M_{max}}{W} = \dfrac{4 \times 1838.5625}{11,416.6879} \approx 0.64417[/tex]

L ≈ 0.64417 m ≈ 64.417 cm.

Technician A says that an A-pillar may be designed to transfer collision energy
Technician B says that a floor pan reinforcement may be designed to transfer collision energy
Who is right?
A. Aonly
B. B only
C. Both A and B
D. Neither Anor B

Answers

C both A and b cause they are technician both technicians so they both measure out the floor pan reinforcement be designed to transfer collision energy so I say both A and B

Technicians A and B both are right with respect to their thinking and determination. Thus, the correct option is C.

What is Collision energy?

Collision energy may be defined as a circumstance in which two or more bodies or particles come together with a resulting exchange of energy and alteration of direction.

Both pillar and floor pan reinforcement may be designed to transfer collision energy through the most prominent way to explain this mechanism of collisions.

A pillar exerts complete pressure on the floor in order to support the roof of the building, while floor pan reinforcement performs the same mechanism of collision energy with a different mechanism of action.

Therefore, technicians A and B both are right with respect to their thinking and determination. Thus, the correct option is C.

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Waste that is generated by a business is called a _____________.
A) Waste stream
B) Surplus
C) Hazard assessment
D) Trash stream

(This is for my Automotive class)

Answers

Answer: Waste Stream

Answer:

waste stream

Explanation:

i got it right on sp2

How do you describe sound? (SELECT ALL THAT APPLY.) PLEASE HELP AND SELECT ALL THAT APPLY PLEASE!! A. Sound waves have to have a medium to travel through. B. The volume of a sound is known as amplitude. C. Loud sounds have high amplitude and vibrate with more energy than soft sounds. D. Sound waves are compression waves that cause energy transfer in air molecules.

Answers

Answer:

Sound waves are compression waves that cause energy transfer in air molecules

Sound waves have to have a medium to travel through

Loud sounds have high amplitude and vibrate with more energy than soft sounds

Explanation:

Sound waves is a form of energy composed of compression and rare factions. Sound waves are compression waves that cause energy transfer in air molecules.

Sound is an example of a mechanical wave hence it requires a material medium for propagation.

The amplitude of a sound wave determines its loudness or volume. A larger amplitude implies that we will have a louder sound, and a smaller amplitude means that we will have a softer sound.

using credit reduces future income

Answers

Answer:

lol

Explanation:r

Un material determinado tiene un espesor de 30 cm y una conductividad térmica (K) de 0,04 w/m°C. En un instante dado la distribución de temperatura en función de "x" el cual es la distancia desde la cara izquierda de una pared, está dado por la siguiente función: T(x) = 150x2 -30x, donde x está en metros. Calcúlese el flujo de calor por unidad de área cuando x=0 y x=30, para cada caso menciones si se está enfriando o calentando el sólido.

Answers

Answer:

Para x=0:

[tex]\phi=1.2 W/m^{2}[/tex]  

Para x=30 cm:

[tex]\phi=-2.4 W/m^{2}[/tex]  

Explanation

Podemos utilizar la ley de Fourier par determinar el flujo de calor:

[tex]\phi=-k\frac{dT}{dx}[/tex](1)

Por lo tanto debemos encontrar la derivada de T(x) con respecto a x primero.

Usando la ley de potencia para la derivda, tenemos:

[tex]\frac{dT(x)}{dx}=300x-30[/tex]

Remplezando esta derivada en (1):

[tex]\phi=-0.04(300x-30)[/tex]

Para x=0:

[tex]\phi=0.04(30)[/tex]

[tex]\phi=1.2 W/m^{2}[/tex]  

Para x=30 cm:

[tex]\phi=-0.04(300*0.3-30)[/tex]

[tex]\phi=-2.4 W/m^{2}[/tex]    

Espero que te haya ayudado!

entor" by
What type of signal word is used in this sentence?
need and
en who was
generalization
description
thought
feeling

Answers

Answer:

generalization

Explanation:

Please mark me brainliest I need to level up

Forcing a solid piece of heated aluminum through a die forms:
A. a stamped part
B.a cast part
C.an extruded part.
D.a forged part

Answers

Answer:

B a cast part

Explanation:

Extrusion is defined as the process of shaping material, such as aluminum, by forcing it to flow through a shaped opening in a die. Extruded material emerges as an elongated piece with the same profile as the die opening.

Forcing a solid piece of heated aluminum through a die forms: a cast part. Hence, option B is correct.

What is cast part?

A liquid element is more often filled with concrete that has a hollow chamber in the correct form during the casting manufacturing process, and the item is then let to harden.

A casting, which is the term for the solidified component, is ejected or broken out of the mould to complete the procedure.

Thus, option B is correct.

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what is heat unit?in X ray machine​

Answers

Answer:

joule

Explanation:

heat is express in joules in x Ray equipment

Which of the following is a disadvantage of using a resistor in place of an inductor in a power-supply filter.
A The output DC voltage will be lower
B. The life of the capacitors will be shorter
C. A resistor will cost much more than an inductor
D. A resistor weighs much more than an inductor

Answers

Answer: A. The output DC voltage will be lower

Explanation:

Using a resistor in a power-supply filter instead of an inductor will lead to a lower DC voltage output as resistors reduce voltage.

It would therefore be ideal to use an inductor as it does not lower DC voltage but inductors are expensive and can be quite large which is why it is more common to see resistors used in power-supply filter circuits.

Poems that focus on one image usually have what purpose? PLEASE HELP MEH!!

A. to make readers understand how one event leads to another
B. to make readers look at something in a new and different way
C. to make a point about how two or three things are alike

Answers

Answer:

A. to make readers understand how one event leads to another

Explanation:

Hope this helped have an amazing day!

Poems that focus on one image usually make readers understand how one event leads to another. The correct option is A.

What is poetry?

Poetry is literature that uses words chosen and arranged for their meaning, sound, and rhythm to elicit a focused imaginative awareness of experience or a particular emotional response.

Narrative, dramatic, and lyrical poetry are the three basic categories. Sometimes it is difficult to distinguish between them.

For instance, lyrical poems can have narrative sections, just as epic poems can include lyrical passages.

Poetry is a genre of writing that is essential to life, art, and culture. Readers can typically comprehend how one occurrence leads to another in poems that concentrate on a single image.

Thus, the correct option is A.

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The quantity of bricks required increases with the surface area of the wall, but the thickness of a masonry wall does not affect the total quantity of bricks used in the wall

True or False

Answers

Answer:

false

Explanation:

False is the answer:)!

Think about all the things that you have learned about wildfire in this module.

In light of climate change, explain how this risk map might look different in 100 years.

Answers

Answer:

CLIMATE CHANGE HAS inexorably stacked the deck in favor of bigger and more intense fires across the American West over the past few decades, science has incontrovertibly shown. Increasing heat, changing rain and snow patterns, shifts in plant communities, and other climate-related changes have vastly increased the likelihood that fires will start more often and burn more intensely and widely than they have in the past.

Explanation:

Let be a real-valued signal for which when . Amplitude modulation is preformed to produce the signal . A proposed demodulation technique is illustrated below where is the input, is the output and the ideal low-pass filter has a cutoff frequency of and a passband gain of 2. Determine . x(t) X(jω) = 0 g(t) = x(t)sin(2000πt) g(t) y(t) 2000π y(t) EENG 311: Signals and Systems Page 7 of 8 × lowpass filter y(t) cos(2000πt) g

Answers

Answer:

hello your question is incomplete attached below is the complete question

answer : attached below

Explanation:

let ; x(t)  be a real value signal for x ( jw ) = 0 , |w| > 200[tex]\pi[/tex]

g(t) = x ( t ) sin ( 2000 [tex]\pi t )[/tex]

[tex]x_{1} (t) = \frac{1}{2} x(t) sin ( 4000\pi t )[/tex]

next we apply Fourier transform

attached below is the remaining part of the solution

What is the primer coating that protects the metal from rusting on a Aftermarket part.. Flat Primer
Primer Sealer
Shipping Primer

Answers

Primer sealer is the correct option choice for your question! Hope this helps
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