Answer:
Step-by-step explanation:
If {0, 3, 6, 9} are are your x's or domain or input and there are no repeats, then yes TRUE it is a function.
The length of ribbons found at a seamstress are listed.
3, 11, 11, 13, 13, 21
What is the appropriate measure of variability for the data shown, and what is its value?
The mean is the best measure of variability and equals 11.
The median is the best measure of variability and equals 11.5.
The range is the best measure of variability and equals 18.
The IQR is the best measure of variability and equals 2.
5 hr, 30 min, 12 sec + 2 hr, 16 min, 25 'sec
The sum of the two time durations is 7 hours, 46 minutes, and 37 seconds.
To add the given time durations, we start by adding the seconds:
12 sec + 25 sec = 37 sec.
Since 60 seconds make a minute, we carry over any excess seconds to the minutes place, which gives us a total of 37 seconds. Moving on to the minutes, we add 30 min + 16 min = 46 min.
Again, we carry over any excess minutes to the hours place, resulting in a total of 46 minutes.
Finally, we add the hours: 5 hr + 2 hr = 7 hr.
Thus, the sum of the two time durations is 7 hours, 46 minutes, and 37 seconds.
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Evaluate the following expression when a = 5 and b = 1. Then, plot the resulting value on the provided number line. 12+2 (4 a²) ÷ 7 + 8
Answer:
To evaluate the expression when a = 5 and b = 1, we substitute the values into the expression:
12 + 2(4(5)²) ÷ 7 + 8
= 12 + 2(4 * 25) ÷ 7 + 8 (Note: 5² means 5 raised to the power of 2)
= 12 + 2(100) ÷ 7 + 8 (Note: 4 * 25 = 100)
= 12 + 200 ÷ 7 + 8
= 12 + 28.57 + 8 (Note: ÷ means divide)
= 48.57
To plot the resulting value on the provided number line , we would need to know the scale and range of the number line. Without this information, we cannot accurately plot the value.
Step-by-step explanation:
Lucas is selling protein bars for a fundraiser. He sold 12 bars on Saturday and 8 bars on Sunday. If each bar sold for $1.50, how much money did he raise?
The money raised by Lucas for the fundraiser is $30.
The bars sold on Saturday are 12 bars. Each bar costs $1.50.
So, the amount will be: 12 * 1.50 = 18
The bars sold on Sunday are 8 bars.
So, the amount will be: 8 * 1.50 = 12
Hence, the total amount: is 18+12= 30
For a recent year, 52.7 million people participated in recreational boating. Sixteen years later, that number increased to 57.3
million. Determine the percent increase. Round to one decimal place.
The percent increase was approximately
%.
The percent increase in recreational boating participation over the sixteen-year period is approximately 8.72%. This means that the number of participants increased by around 8.72% from 52.7 million to 57.3 million.
To determine the percent increase in recreational boating participation over the sixteen-year period, we can use the following formula:
Percent Increase = ((New Value - Old Value) / Old Value) * 100
Using the given information, we have an old value of 52.7 million and a new value of 57.3 million.
Percent Increase = ((57.3 million - 52.7 million) / 52.7 million) * 100
= (4.6 million / 52.7 million) * 100
= 0.0872 * 100
= 8.72%
This increase indicates a positive trend in recreational boating, reflecting a growing interest in this activity over time. Factors such as improved accessibility, marketing efforts, and increasing disposable income may have contributed to this upward trend.
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Calc II Question
Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the y axis.
Y = e^(-x^2)
Y = 0
X = 0
X = 1
Correct answer is pi (1 - (1/e))
I'm just not sure how to get to that answer
Answer:
[tex]\displaystyle \pi\biggr(1-\frac{1}{e}\biggr)[/tex]
Step-by-step explanation:
Shell Method (Vertical Axis)
[tex]\displaystyle V=2\pi\int^b_ar(x)h(x)\,dx[/tex]
Radius: [tex]r(x)=x[/tex]
Height: [tex]h(x)=e^{-x^2}[/tex]
Bounds: [tex][a,b]=[0,1][/tex]
Set up and evaluate integral
[tex]\displaystyle V=2\pi\int^1_0xe^{-x^2}\,dx[/tex]
Let [tex]u=-x^2[/tex] and [tex]du=-2x\,dx[/tex] so that [tex]-\frac{1}{2}\,du=x\,dx[/tex]Bounds become [tex]u=-0^2=0[/tex] and [tex]u=-1^2=-1[/tex][tex]\displaystyle V= -\frac{1}{2}\cdot2\pi\int^{-1}_0e^u\,du\\\\V= -\pi\int^{-1}_0e^u\,du\\\\V=\pi\int^0_{-1}e^u\,du\\\\V=\pi e^u\biggr|^0_{-1}\\\\V=\pi e^0-\pi e^{-1}\\\\V=\pi-\frac{\pi}{e}\\\\V=\pi\biggr(1-\frac{1}{e}\biggr)[/tex]
NO LINKS!! URGENT HELP PLEASE!!
Please help me with #31 & 32
Answer:
31. m∠E = 56.1°
32. c = 24.9 inches
Step-by-step explanation:
Question 31The Law of Sines relates the lengths of the sides of a triangle to the sines of its angles. It states that the ratio of the length of a side of a triangle to the sine of the opposite angle is constant for all three sides of the triangle.
[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}[/tex]
Given values of triangle DEF:
m∠D = 81°d = 25e = 21To find m∠E, substitute the values into the Law of Sines formula and solve for E:
[tex]\dfrac{\sin D}{d}=\dfrac{\sin E}{e}[/tex]
[tex]\dfrac{\sin 81^{\circ}}{25}=\dfrac{\sin E}{21}[/tex]
[tex]\sin E=\dfrac{21\sin 81^{\circ}}{25}[/tex]
[tex]E=\sin^{-1}\left(\dfrac{21\sin 81^{\circ}}{25}\right)[/tex]
[tex]E=56.1^{\circ}\; \sf(nearest\;tenth)[/tex]
Therefore, the measure of angle E is 56.1°, to the nearest tenth.
See the attachment for the accurate drawing of triangle DEF.
[tex]\hrulefill[/tex]
Question 32The law of cosines relates the lengths of the sides of a triangle to the cosine of one of its angles.
[tex]\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines} \\\\$c^2=a^2+b^2-2ab \cos C$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}[/tex]
From inspection of triangle ABC:
C = 125°a = 13 inchesb = 15 inchesTo find the length of side c, substitute the values into the Law of Cosines formula and solve for c:
[tex]c^2=a^2+b^2-2ab \cos C[/tex]
[tex]c^2=13^2+15^2-2(13)(15) \cos 125^{\circ}[/tex]
[tex]c^2=169+225-390 \cos 125^{\circ}[/tex]
[tex]c^2=394-390 \cos 125^{\circ}[/tex]
[tex]c=\sqrt{394-390 \cos 125^{\circ}}[/tex]
[tex]c=24.8534667...[/tex]
[tex]c=24.9\; \sf inches\;(nearest\;tenth)[/tex]
Therefore, the length of side c is 24.9 inches, to the nearest tenth.
Estimate the variation (strength) of the correlation of the scatter plot shown.
a.
moderate correlation
b.
no correlation
c.
strong correlation
d.
weak correlation
need now mamayang 11pm na pasahan
The strength of the correlation as shown in the scatter plot can be concluded to be: b) no correlation.
How to Estimate the variation (strength) of the correlation of a scatter plot shown?To estimate the strength of the correlation in a scatter plot, visually assess the clustering and linearity of the data points. If the points cluster tightly around a linear trend, it indicates a strong correlation, whereas dispersed and non-linear points suggest a weak correlation.
However, if the points on a scatter plot do not exhibit a discernible pattern (as shown in the image given above), it can be concluded that there is no correlation between the variables being plotted.
Therefore, the answer is: b. no correlation.
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This is one appointments the same distance from other points or lines geometry
The concept of equidistant points or lines is fundamental in geometry and plays a significant role in many geometric constructions and properties.
In geometry, an "equidistant" point is a point that is at the same distance from other points or lines. This concept is often used in various geometric constructions and proofs.
For example, in a circle, the center of the circle is equidistant from all points on the circumference. This property is what defines a circle.
In terms of lines, an equidistant point can be found by drawing perpendicular bisectors. A perpendicular bisector of a line segment is a line that is perpendicular to the segment and divides it into two equal parts. The point where the perpendicular bisectors of a triangle intersect is called the circumcenter, and it is equidistant from the vertices of the triangle.
Another example is the concept of an equidistant curve. In some cases, there may be a curve or path that is equidistant from two fixed points. This curve is called the "locus of points equidistant from two given points" and is often referred to as a "perpendicular bisector" when dealing with line segments.
All things considered, the idea of equidistant points or lines is essential to geometry and is important to many geometrical constructions and features.
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Margie has a $50.00 budget to purchase a $45.00 pair of boots. If
there is an 8% sales tax rate, then how much under budget will
Margie be?
Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.
x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
Answer:
Third option
Step-by-step explanation:
-3(2x - 5) < 5(2 - x)
-6x + 15 < 10 - 5x <-- Third option
15 < 10 + x
5 < x
x > 5
There only appears to be one option. The solution to the inequality is x>5, not x<5.
The veterinarian has prescribed carprofen 2.2 mg/kg BID x30d. Weight of patient is 34kg. Concentration is 75mg tablet. What is the amount of medication needed for 30 days?
The amount of medication needed for 30 days is approximately 59.84 tablets of carprofen.
To calculate the amount of carprofen medication needed for 30 days, we need to consider the prescribed dosage, the weight of the patient, and the concentration of the tablets.
The prescribed dosage is 2.2 mg/kg BID x 30d. This means that the patient should take 2.2 milligrams of carprofen per kilogram of body weight, twice a day, for 30 days.
The weight of the patient is 34 kilograms. So, we need to calculate the total amount of carprofen needed for the entire treatment period.
First, we calculate the daily dosage by multiplying the weight of the patient (34 kg) by the prescribed dosage (2.2 mg/kg).
Daily dosage = 34 kg * 2.2 mg/kg = 74.8 mg/day.
Since the medication is prescribed twice a day, we multiply the daily dosage by 2 to get the total dosage per day.
Total dosage per day = 74.8 mg/day * 2 = 149.6 mg/day.
Finally, to find the total amount of medication needed for 30 days, we multiply the total dosage per day by the number of days.
Total medication needed = 149.6 mg/day * 30 days = 4488 mg.
Since the concentration of the tablets is 75 mg, we divide the total medication needed by the tablet concentration to find the number of tablets required.
Number of tablets needed = 4488 mg / 75 mg = 59.84.
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What is the square root of m^6?
m²
m³
m^4
m^5
The square root of m^6 is always positive.
The square root of m^6 can be calculated by dividing the exponent 6 by 2, since taking the square root is equivalent to raising a number to the power of 1/2.
In this case, m^6 divided by 2 gives us m^3.
Thus, the square root of m^6 is m^3.
This means that if we square m^3, the result will be m^6.
It is important to understand that the square root operation yields the positive root, so the square root of m^6 is always positive.
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The shaded part of the circle represents the part of gas used to fill up the gas tank of a lawn mower what part of the container is needed to fill up the gas tank of the lawn mower 4 times is the answer 8/48 8/12 6/16 or 6/12
The fraction of the container needed to fill up the gas tank of the lawn mower four times is 6/12. Option D.
The shaded part of the circle represents the fraction of gas needed to fill up the gas tank of the lawn mower once. To determine the fraction needed to fill it up four times, we can simply multiply the fraction by 4.
Let's assume that the shaded part of the circle represents x part of the whole container. Therefore, the fraction needed to fill up the gas tank of the lawn mower once is x.
To fill up the gas tank four times, we need to multiply x by 4. Therefore, the fraction needed to fill up the gas tank four times is 4x.
Now, we can compare this to the answer choices given:
8/48: This can be simplified to 1/6, which is not equal to 4x.
8/12: This can be simplified to 2/3, which is not equal to 4x.
6/16: This can be simplified to 3/8, which is not equal to 4x.
6/12: This can be simplified to 1/2, which is equal to 4x.
Therefore, the correct answer is 6/12, which represents the fraction of the container needed to fill up the gas tank of the lawn mower four times. so Option D is correct.
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Note the complete question is
What is the sum of the series?
∑k=14(2k2−4)
Enter your answer in the box.
Answer:
44
Step-by-step explanation:
The sum of the series [tex]\sum_{k=1}^4[/tex] (2k²−4) is 44.
The series is: [tex]\sum_{k=1}^4[/tex] (2k²−4)
Let's find the value of each term for k=1, k=2, k=3, and k=4, and then add them up:
For k=1:
2(1)² - 4 = 2(1) - 4 = 2 - 4 = -2
For k=2:
2(2)² - 4 = 2(4) - 4 = 8 - 4 = 4
For k=3:
2(3)² - 4 = 2(9) - 4 = 18 - 4 = 14
For k=4:
2(4)² - 4 = 2(16) - 4 = 32 - 4 = 28
Now, let's add all the terms:
-2 + 4 + 14 + 28 = 44
So, the sum of the series [tex]\sum_{k=1}^4[/tex] (2k²−4) is 44.
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Gabby is going on holiday and needs to exchange some pounds (£) for euros (€)
. How many euros can she get for £21? Give your answer to 2 decimal places.
£1
Exchange rate
= €1.13
Gabby can get €23.73 for £21 when using the exchange rate of £1 = €1.13.
To calculate how many euros Gabby can get for £21, we need to use the exchange rate of £1 = €1.13.
To find the number of euros, we multiply the amount in pounds (£21) by the exchange rate (€1.13):
£21 * €1.13 = €23.73
Therefore, Gabby can get €23.73 for £21 when using the exchange rate of £1 = €1.13.
This means that for every pound exchanged, Gabby will receive €1.13. So, by multiplying the amount in pounds (£21) by the exchange rate (£1 = €1.13), we can determine the equivalent amount in euros.
It's important to note that exchange rates can fluctuate, and the rate provided here is just an example. When exchanging currency, it's always advisable to check the current exchange rates as they may vary. Additionally, some currency exchange services may charge fees or have different rates, so it's essential to consider those factors as well.
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are statistical questions?
Which subjects do the students What is the number of students
in my class like?
in my class?
How many servings of fruit did
I eat each day this month?
What is my height?
What is my favorite color?
What is the highest temperature
of each month this year?
Reset
Next
What is the height of each
student in my class?
What is my mother's favorite
fruit?
How many students from each
school in this city love football?
The statistical questions for this problem are given as follows:
Which subjects do the students like?How many servings of fruit did I eat each day this month?What is the highest temperature of each month this year?What is the height of each student in my class?How many students from each school in this city love football?What is an statistical question?A question is classified as statistical if it can receive answers of data that vary, that is, questions that do not have an exact answer.
When the answer is exact, it must be composed by a set of data, such as the number of students that like football in each school, the number will vary for each school.
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Tell whether the information in the diagram allows you to conclude that c is on the perpendicular bisect of ab
11. Yes, the information provided can be used to conclude that C is on the perpendicular bisector of AB because CE bisects AB.
12. Yes, the information provided can be used to conclude that C is on the perpendicular bisector of AB because C is equidistant from AB.
What is a perpendicular bisector?In Mathematics and Geometry, a perpendicular bisector divides or bisects a line segment exactly into two (2) equal halves, in order to form a right angle with a magnitude of 90° at the point of intersection.
Question 11.
By critically observing the geometric shape, we can logically deduce that there is enough information to conclude that C is on the perpendicular bisector of AB because CE bisects AB:
AC ≅ BC
CD ≅ CD
AE ⊥ EC
Question 12.
By critically observing the geometric shape, we can logically deduce that there is enough information to conclude that C is on the perpendicular bisector because C is equidistant from line segment AB.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
NO LINKS!! URGENT HELP PLEASE!!!
1. Find the sum of the measures of the interior angles of the indicated polygons. (NOT MULTIPLE CHOICE)
a. heptagon
b. 13-gon
2. The sum of the measures of the interior angles of a convex polygon is 1260°. Classify the polygon by the number of sides.
1a. Sum of interior angles of a heptagon:
[tex]\displaystyle \sf \text{Sum of interior angles} = (7 - 2) \times 180^\circ = 900^\circ[/tex]
1b. Sum of interior angles of a 13-gon:
[tex]\displaystyle \sf \text{Sum of interior angles} = (13 - 2) \times 180^\circ = 1980^\circ[/tex]
2. Number of sides for a polygon with a sum of interior angles of 1260°:
[tex]\displaystyle \sf (n - 2) \times 180^\circ = 1260^\circ[/tex]
[tex]\displaystyle \sf n - 2 = \frac{1260^\circ}{180^\circ}[/tex]
[tex]\displaystyle \sf n - 2 = 7[/tex]
[tex]\displaystyle \sf n = 7 + 2 = 9[/tex]
Therefore, the sum of the measures of the interior angles of a heptagon is 900°, the sum of the measures of the interior angles of a 13-gon is 1980°, and the polygon with a sum of interior angles of 1260° is a nonagon (9-gon).
[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]
♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]
Answer:
1. a. 900° b. 1980°
2. Nonagon
Step-by-step explanation:
In order to find the interior angles of a polygon, use the formula,
Sum of interior angles = (n-2)*180°
For
a. Heptagon
no of side =7
The sum of the interior angles of a heptagon:
(7-2)*180 = 900°
b. 13-gon
no. of side =13
The sum of the interior angles of a 13-gon:
(13-2)*180 = 1980°
2.
The sum of the interior angles of a convex polygon is 1260°,
where n is the number of sides.
In this case, we have
1260 = (n-2)*180
1260/180=n-2
n-2=7
n=7+2
n=9
Therefore, the polygon has 9 sides and is classified as a nonagon.
HELP PLEASE AND HURRYY
Answer:
Part A: Answer: D.
Part B:
true
false
true
Step-by-step explanation:
Part A:
Use a tree.
Round 1 Round 2 Round 3
W W W
W W L
W L W
W L L
L W W
L W L
L L W
L L L
All possibilities are:
WWW, WWL, WLW, WLL, LWW, LWL, LLW, LLL
Answer: d.
Part B:
Winning 3 games is WWW.
WWW, WWL, WLW, WLL, LWW, LWL, LLW, LLL
Out of the 8 possible outcomes shown above, only 1 of them is WWW.
p(WWW) = 1/8
Answer: true
Winning exactly 2 games happens when there are exactly 2 W's:
WWW, WWL, WLW, WLL, LWW, LWL, LLW, LLL
p(exactly 2 wins) = 3/8
Answer: false
Wining at least 2 games means winning exactly 2 or exactly 3 times.
WWW, WWL, WLW, WLL, LWW, LWL, LLW, LLL
p(winning at least 2 games) = 4/8 = 1/2
Answer: true
6. Juan y Roberto son dos hermanos que juegan Piedra, Papel y Tijera para determinar quien hace el aseo de su cuarto. ¿Cuántos serán los posibles resultados que podemos tener?, ¿Cuál es la probabilidad de que Juan no haga el aseo? *
Given, Juan y Roberto is two brothers who play Rock, Paper, and Scissors to determine who does the cleaning in their room. The total number of possible outcomes is 3. The possible outcomes are rock, paper, and scissors. So, the probability of Juan not doing the cleaning is 1/2 or 50 percent.
The probability that Juan will not do the cleaning is 1/2 or 50 percent. The possible outcomes for playing the game Rock, paper, and Scissors are given as follows. Rock can break scissors, Paper can cover rock, and Scissors can cut paper. Therefore, there are three possible outcomes in this game. The possible outcomes are rock, paper, and scissors.
The probability that Juan will not do the cleaning is 1/2 or 50 percent since there are two possible outcomes where Juan does not do the cleaning. The two possible outcomes are paper and scissors. Juan can pick the paper or scissors to win. Therefore, the probability of Juan not doing the cleaning is 1/2 or 50 percent.
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Solve the system of equations.
y=x+5y=x2+5x−7
Enter your answers in the boxes.
Here's the answer for you guys if you need it (:
Answer:
(2, 7) and (-6, -1)
Step-by-step explanation:
y = x + 5
y = x² + 5x − 7
Equatig the above,
x² + 5x − 7 = x + 5
⇒ x² + 4x −12 = 0
⇒ x² + 6x - 2x - 12 = 0
⇒ x(x + 6) - 2(x + 6) = 0
⇒ (x - 2)(x + 6) = 0
⇒ x = 2 or x = -6
Eq(1) : y = x + 5 (given)
When x = 2
y = 2 + 5 = 7
Point : (2, 7)
When x = -6
y = -6 + 5 = -1
Point: (-6, -1)
The cost to produce a bag of golf tees is modeled by the function that is graphed below.
Production Costs for Bags of Golf Tees
A graph has number of tees on the x-axis, and cost in dollars on the y-axis. A line goes through (0, 4) and (2, 5).
Which table shows this same function?
A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries negative 8, negative 4, 0, 4.
A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 0, 4, 0, 4.
A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 5, 6, 7.
A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 8, 12, 16.
The table that shows the same function as the given graph is: A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 5, 6, 7.
To determine which table shows the same function as the given graph, we need to find the values of y corresponding to the given values of x on the graph.
Point A: (0, 4)
Point B: (2, 5)
Let's check each table:
A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries negative 8, negative 4, 0, 4.
In this table, the corresponding y-values for x = 0 and x = 2 are incorrect. The correct values should be 4 and 5, respectively. Therefore, this table does not represent the same function as the given graph.A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 0, 4, 0, 4.
In this table, the corresponding y-values for x = 2 and x = 6 are incorrect. The correct values should be 5 and 7, respectively. Therefore, this table does not represent the same function as the given graph.A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 5, 6, 7.
In this table, the corresponding y-values for x = 0 and x = 2 match the given points on the graph. Therefore, this table represents the same function as the given graph.A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 8, 12, 16.
In this table, the corresponding y-values for x = 2 and x = 4 do not match the given points on the graph. Therefore, this table does not represent the same function as the given graph.For such more question on function:
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Given the equation y=mx+b fine the valué of y if x =10, m = 2.5, and b =2
Answer:
27
Step-by-step explanation:
Please answer ASAP I will brainlist
(a) The amount for total expenditures in 2015 was about $63.2 billion.
(b) The first full year in which expenditures exceeded $110 billion was 2027.
(a) To find the amount for total expenditures in 2015, we need to substitute x = 20 into the function h(x) = [tex]23.4(1.08)^{(x-5)[/tex].
h(x) = 23.4(1.0[tex]8)^{(20-5)[/tex]
= 23.4(1.0[tex]8)^{15[/tex]
≈ 23.4(2.717)
Rounding to the nearest tenth, the total expenditures in 2015 were about $63.2 billion.
(b) To determine the first full year in which expenditures exceeded $110 billion, we need to find the value of x when h(x) is greater than $110 billion.
110 = 23.4(1.0[tex]8)^{(x-5)[/tex]
Dividing both sides by 23.4:
4.7008547... = (1.0[tex]8)^{(x-5)[/tex]
Taking the logarithm base 1.08 of both sides:
log₁.₀₈(4.7008547...) = x - 5
Using a logarithm calculator or software, we find:
x - 5 ≈ 11.75
Adding 5 to both sides:
x ≈ 16.75
Rounding to the nearest whole number, the first full year in which expenditures exceeded $110 billion was 2027.
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Which of the following pairs show(s) two congruent triangles?
O B only
OB and C only
O A, B, and C
O A and C only
Answer:
B only
Step-by-step explanation:
Triangles A and C are similar, but not congruent to each other. Similar triangles have proportional sides and congruent angles, while congruent triangles have congruent sides and congruent angles.
Therefore, only B is correct
The question is asking for pairs of congruent triangles but lacks key information needed to accurately answer this, such as lengths or angles. Congruent triangles are identified in geometry based on either side-lengths or angles.
Explanation:The question is about congruent triangles, which in mathematics means triangles that have the same size and shape. But to accurately answer which pairs show two congruent triangles, we need more information. The options provided include 'A', 'B', and 'C' but without knowing more about these elements (for example their lengths or angles), it is impossible to determine which are congruent. Congruent triangles are identified in geometry based on either side lengths (SSS: Side-Side-Side, SAS: Side-Angle-Side, ASA: Angle-Side-Angle) or angles (AAS: Angle-Angle-Side, HL: Hypotenuse-Leg for right triangles). Without this vital information, we cannot definitively answer the question. Be sure to verify all the properties required to prove two triangles congruent.
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5. Journalise the following transactions:
1. Pater commenced business with 40,000 cash and also brought
into business furniture worth
*5,000; Motor car valued for ₹12,000 and stock worth 20,000.
2. Deposited 15,000 into State Bank of India.
3. Bought goods on credit from Sen ₹9,000
4. Sold goods to Basu on Credit for ₹6,000
5. Bought stationery from Ram Bros. for Cash ₹200
6. Sold goods to Dalal for ₹2,000 for which cash was received.
7. Paid 600 as travelling expenses to Mehta in cash.
8. Patel withdrew for personal use ₹1,000 from the Bank.
9. Withdrew from the Bank ₹3,000 for office use.
10. Paid to Sen by cheque 8,800 in full settlement of his account.
11. Paid ₹400 in cash as freight and clearing charges to Gopal,
12. Received a cheque for ₹6,000 from Basu.
The journal entries for the given transactions are as follows:
Cash A/c Dr. 40,000
Furniture A/c Dr. 5,000
Motor Car A/c Dr. 12,000
Stock A/c Dr. 20,000
To Capital A/c 77,000
Bank A/c Dr. 15,000
To Cash A/c 15,000
Purchase A/c Dr. 9,000
To Sen's A/c 9,000
Basu's A/c Dr. 6,000
To Sales A/c 6,000
Stationery A/c Dr. 200
To Cash A/c 200
Cash A/c Dr. 2,000
To Dalal's A/c 2,000
Travelling Expenses A/c Dr. 600
To Cash A/c 600
Drawings A/c Dr. 1,000
To Bank A/c 1,000
Cash A/c Dr. 3,000
To Bank A/c 3,000
Sen's A/c Dr. 8,800
To Bank A/c 8,800
Freight and Clearing A/c Dr. 400
To Cash A/c 400
Bank A/c Dr. 6,000
To Basu's A/c 6,000
Journal entries for the given transactions are as follows:
Pater commenced business with 40,000 cash and also brought into business furniture worth ₹5,000; Motor car valued for ₹12,000 and stock worth ₹20,000.
Cash A/c Dr. 40,000
Furniture A/c Dr. 5,000
Motor Car A/c Dr. 12,000
Stock A/c Dr. 20,000
To Capital A/c 77,000
Deposited ₹15,000 into State Bank of India.
Bank A/c Dr. 15,000
To Cash A/c 15,000
Bought goods on credit from Sen for ₹9,000.
Purchase A/c Dr. 9,000
To Sen's A/c 9,000
Sold goods to Basu on Credit for ₹6,000.
Basu's A/c Dr. 6,000
To Sales A/c 6,000
Bought stationery from Ram Bros. for Cash ₹200.
Stationery A/c Dr. 200
To Cash A/c 200
Sold goods to Dalal for ₹2,000 for which cash was received.
Cash A/c Dr. 2,000
To Dalal's A/c 2,000
Paid ₹600 as travelling expenses to Mehta in cash.
Travelling Expenses A/c Dr. 600
To Cash A/c 600
Patel withdrew for personal use ₹1,000 from the Bank.
Drawings A/c Dr. 1,000
To Bank A/c 1,000
Withdrew from the Bank ₹3,000 for office use.
Cash A/c Dr. 3,000
To Bank A/c 3,000
Paid to Sen by cheque ₹8,800 in full settlement of his account.
Sen's A/c Dr. 8,800
To Bank A/c 8,800
Paid ₹400 in cash as freight and clearing charges to Gopal.
Freight and Clearing A/c Dr. 400
To Cash A/c 400
Received a cheque for ₹6,000 from Basu.
Bank A/c Dr. 6,000
To Basu's A/c 6,000
These journal entries represent the various transactions and their effects on different accounts in the accounting system.
They serve as the initial records of the financial activities of the business and provide a basis for further accounting processes such as ledger posting and preparation of financial statements.
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For two invertible n by n matrices A, B,
where rank(A)=rank(B)=n,
is the following always true?
"rank(AB) = n"
If so,
I wonder how we can prove it.
If not,
I'd appreciate you if you show me a counterexample.
Thank you in advance.
The statement "rank(AB) = n" is not always true for invertible n by n matrices A and B with rank(A) = rank(B) = n.
Counterexample:
Consider the following counterexample:
[tex]A = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\\B = \begin{bmatrix} 1 & 0 \ 0 & 0 \end{bmatrix}[/tex]
Both matrices A and B are invertible, as they are both identity matrices. However, when we multiply them together, we get:
[tex]AB = \begin{bmatrix} 1 & 0 \ 0 & 0 \end{bmatrix}[/tex]
The rank of AB is 1, not n. In this case, n = 2, but rank(AB) = 1. Therefore, the statement "rank(AB) = n" is not always true for all invertible n by n matrices A and B with rank(A) = rank(B) = n.
In general, the rank of the product AB is less than or equal to the minimum of the ranks of A and B. So, in order for rank(AB) to be equal to n, both A and B need to have rank n individually, but that does not guarantee the rank of their product to be n as well.
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Geometric mean and Harmonic mean for the values 3, -11, 0, 63, -14, 100 are
Select one:
a. 0 and 0
b. 3 and -3
c. 3 and 0
d. Impossible
e. 0 and 3
Note: Answer C is NOT the correct answer. Please find the correct answer. Any answer without justification will be rejected automatically.
The correct answer is an option (d): Impossible.
Both the geometric mean and harmonic mean require positive values. However, in the given set of values, we have negative values (-11 and -14), which makes it impossible to calculate the geometric mean and harmonic mean. Therefore, the correct answer is that it is impossible to calculate the geometric mean and harmonic mean for the given values.
which of the following are solutions to the quadratic equation check all that apply x ^ 2 + 10x + 25 = 2
Answer:
to solve the equation you first need to bring it to factors and by doing that you first need to let the equation equal 0 hence you need to minus 2 on both sides of the equation therefore
x^2 + 10x + 25 - 2 =2 - 2
therefore
x^2 + 10x +23 = 0
now since the equation cannot be factored, we use the formula.
x= [tex]\frac{-b +- \sqrt{b^{2}-4ac } }{2a}[/tex]
where
a=1
b=10
c=23
note we use the coefficients only.
therefore x = [tex]\frac{-10 -+ \sqrt{10^{2}-4(1)(23) } }{2(1)}[/tex]
=[tex]\frac{-10-+\sqrt{100-92} }{2}[/tex]
=[tex]\frac{-10-+\sqrt{8} }{2}[/tex]
then we form two equations according to negative and positive symbols
x=[tex]\frac{-10+\sqrt{8} }{2} or x =\frac{-10-\sqrt{8} }{2}[/tex]
therefore x = [tex]-5+\sqrt{2}[/tex] or x=[tex]-5-\sqrt{2}[/tex]