ill give brainliest
What would happen if the weather became very calm and the wind was not blowing for a few days around the wave hub?
Answer:
the world will become different
5. How many years does the first 10 yards represent? What events are within the first 10 yards of the football field from the TODAY end zone? Explain what this means in terms of expansion of life on Earth.
Based on the length of a football field and the timeline of earth's history, the first 10 yards represents 460 million years.
Beginning from 460 million years ago, there was massive explosion and expansion of life on earth.
What is a timeline of earth's history?A timeline of earth's history shows the events that occurred from the beginning when earth was formed 4.6 billion years ago until today.
In this activity, a football field is used to represent the timeline of earth's history.
Each end of the football field represents the two end zones, Earth's beginning and TODAY end zone.
A football field is 100 yards long.The earth is 4,600,000,000 years old.Each yard equals 46,000,000 yearsThus, the first 10 yards equals = 46,000,000 × 10 The The first 10 yards = 460,000,000 years.
From the TODAY end zone, the the first 10 yards = 460,000,000 years.
460,000,000 years ago marked the time from the appearance of the first plants until humans and all life on earth as it is today.
This, meant that within this period, there was massive explosion and expansion of life on earth.
Learn more about timeline of earth's history at: https://brainly.com/question/13580987
Worth 25 points on my exam
(will give brainliest btw)
A squirrel runs out in front of a car moving at +20m/s. The driver slams on the brakes and begins decreasing at -8m/s^2. Determine the fate of the squirrel if it was initially 26 meters from the car when braking began.
We need to verify the thrid equation of kinematics here
[tex]\\ \tt\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \tt\longmapsto 20^2=2(-8)s[/tex]
[tex]\\ \tt\longmapsto 400=-16s[/tex]
[tex]\\ \tt\longmapsto s=|400/-16|[/tex]
[tex]\\ \tt\longmapsto s=25m[/tex]
The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .
Explanation:
According to the Question
A squirrel runs out in front of a car moving at +20m/s ( initial speed u) . The driver slams on the brakes and begins decreasing at -8m/s² ( here the acceleration is acting in opposite directions of motion a )
When Squirrel was 26 metres ( Distance from the car initially )
Using Kinematic Equation
v² = u² + 2asOn substituting the value we obtain
➥ 0² = 20² + 2 × -8 × s
➥ 0 = 400 - 16 × s
➥ -400 = -16 × s
➥ 400/16 = s
➥ 25 = s
So, the squirrel is 25 metres from the car .
Name the two factors that will determine the state of a substance at room temperature
Which of the following is an example of a behavioral adaptation?
Answer:
b. migration
A migration can be defined as the changes that occur in the behavior, structure, physiology of the organism so as to allow it to survive in unfavorable environmental conditions. Behavioral adaptation can be defined as the changes that occur in an organism's behavior which affects it's actions and helps it to survive like choice of mating partner, calling the mates for copulation and migration to different location all are the examples of the behavioral adaptations
Explanation: Behavioral adaptations are the things organisms do to survive. For example, bird calls and migration are behavioral adaptations. Adaptations are the result of evolution. Evolution is a change in a species over long periods of time.
PLS HELP HELP I DONT WANT TO FAIL
An airplane accelerates down a 1000-m stretch of runway at +5m/s^2. How fast is it moving at the end of this stretch of runway?
Apply thrid equation of kinematics
[tex]\\ \tt\longmapsto v^2=u^2+2as[/tex]
[tex]\\ \tt\longmapsto v^2=2(5)(1000)[/tex]
[tex]\\ \tt\longmapsto v^2=10000[/tex]
[tex]\\ \tt\longmapsto v=100m/s[/tex]
What simple machine would you use to chop down a tree?
Explanation:
i will use chainsaw to cut a tree and even if that doesn't work I will use axe to make my work easy.
hope this helps you
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I only need 25. What is the skiers kinetic energy at point B? Hint mechanical energy equals potential energy plus kinetic energy
Difference in height = 10 - 5 = 5 meters
Kinetic energy = Energy ( 500 N) x height (5 m) = 2,500 N/m = 2,500 joules
Answer: 2,500 joules
What term is used to describe a specific metric that often determines the success or failure of a task?.
How long (in seconds) would it take a machine to do 13,771 joules of work if the power rating of the machine is 0.38 horsepower? (Give the answer without units and round it to the nearest whole number.)
A star such as the Sun starts out as a protostar with a diameter a hundred times larger than its diameter during its main-sequence lifetime. Accordingly, the protostar's temperature is much less than its main-sequence temperature. Assume that while the Sun was a protostar it had a diameter 95.00 times that of the present-day Sun. How many times greater was the protostar's surface area
The protostar's surface area was 1.1 times greater.
Surface area of the star
The surface of the star can be assumed be circular and the surface area can determined as follows;
initial diameter = 100dfinal diameter = 95dArea = πr²
[tex]Area = \frac{\pi d^2}{4} \\\\Area = \frac{(100d)^2}{(95d)^2} \\\\[/tex]
Surface area = 1.1 times greater
Thus, the protostar's surface area was 1.1 times greater.
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A 2.0 mass has j of kinetic energy
What is the speed?
Answer:
v= 4.8 m/s
Explanation:
m= 2.0
KE= 1/2 mv^2
v= ?
v= 1/2 (2.0)^2
v= 4.8 m/s
WHICH ONE IS CORRECT???
Answer:
A
Explanation:
Answer:
According to Pascals law, THE PRESSURE EXERTED TO A CONFINED LIQUID IS TRANSMITTED EQUALLY AND UNDIMINISHED IN ALL DIRECTIONS THROUGHOUT THE MASS OF THE LIQUID--Blaise Pascal
so the pressure at A2 must be equal to A1
buy however the F1 will be less than F2 since:
P1=F1/A1 and P2=F2/F1
P1=P2 according to Pascal
so, F1/A1=F2/A2
with less amount of force at P1 THE force gets multiplied.
Therefore it's obvious that option A and B is wrong. I can't see option C properly.
but, you are going to have this option.
C.F1>F2
so the option with F1>F2 is correct
PLEASE MARK BRAINLIEST
A mass on a spring is first placed on a table and set in SHM and then held vertically and set in SHM. What variable/s would change between the two scenarios?
The variable that changes is the period of the motion.
What is simple harmonic motion?The term simple harmonic motion refers to a regular repeating motion. The acceleration of the SHM is always directed towards the center. The spring is an example of a system undergoing simple harmonic motion.
From the description in the question, the variable that changes is the period of the motion.
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On one stretch of road, any vehicle travelling faster than 25 m/s is breaking the speed limit. The detectors are placed 1.2 m apart. Calculate the speed of a car that takes 0.050 s to travel this distance. Is it breaking the speed limit?
Answer:
Speed = 24 m/s.
No! It doesn't break the speed limit.
Explanation:
The formula we'll be using to find the car's speed:
[tex] \boxed{ \mathsf{speed = \frac{distance}{time} }}[/tex]
The detectors are placed 1.2 m apart.
==> Distance the car travels = 1.2 m
The car, it says, takes 0.050 s to travel that distance.
==> Time taken by the car to travel 1.2 m = 0.050 s
Using the formula mentioned above, let's calculate the speed of the car:
[tex] \sf{speed = \frac{distance}{time} }[/tex]
[tex] \implies \sf{speed = \frac{1.2}{0.050} }[/tex]
On dividing 12 by 0.050 we obtain 24.
[tex] \implies \sf{speed = 24 \: m/s }[/tex]
Any car traveling with a speed that is greater than or equal to 25 m/s is breaking the speed limit.
And since the car in our focus is traveling at 24 m/s that is less than 25 m/s, it doesn't break the speed limit.
Social cognitive theory centers around learning cognition and spirituality psychoanalysis economic status
Social cognitive theory centers around: A. learning.
What is cognitive development?Cognitive development can be defined as the development of thought processes, learning skills, knowledge and problem-solving abilities in living organisms such as humans, especially from infancy through adulthood.
What is social cognitive theory?Social cognitive theory refers to a theoretical perspective which states that human behavior is typically learned and developed based on interactions with other people and the natural world.
In conclusion, social cognitive theory centers around learning.
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I have a physics mid year exam tomorrow and I'm already so late with my studies AND it's 10:30pm should I study each chapter or just start answering questions and correcting?
Answer:
Depends
Explanation:
If you understand the content rush through questions. If you dont understand learn the key concepts of all the chapters then on the commute tomorrow test your self on the concepts. Good luck!
If an object has an initial velocity of 2.0 m/s and its rate of change in velocity is 3.0 m/s2
calculate its final velocity after 4.0 seconds.
Answer:
14m/s2
Explanation:
initial velocity=2m/s
final velocity =?
time=4s
acceleration=3.0m/s
v=u+at
v=(2)+(3*4)
v=14m/s
by substituting the values in the equation we get the value 14m/s.
A basketball and a bowling ball are relatively the same size or volume. Explain which ball is denser and why.
Answer:
The Bowling Ball is Denser.
Explanation:
If we consider both balls in terms of mass they are very different. Size and volume can be the same though.
What makes the mass? Think of what fills each of the balls.
A Basketball is filled with air, which weighs very little.
Meanwhile, a bowling ball is filled with coverstock, made up of plastic, urethane and resin. These materials weigh considerably more than air!
A fishing boat uses a sonar device which sends sound waves to the water that travel at 1000 m/s. The fishing boat detects a signal from a school of fish 1 second after the sonar signal leaves the boat. How far is the school of fish below the boat?
A.1000 m
B.500 m
C.250 m
D.10,000 m
I think its D answer
sorry I dont have explanation but I think its D
There are 100 steps to get from the ground-floor of a building to its rooftop. Person A walks up to the roof in 100 steps, while person B climbs up, skipping every other step. It takes person A two minutes to reach the top, while person B does it in half the time. From the information provided one can deduce that: __________
a. Both A and B perform the same amount of work, but A delivers more power output than B.
b. Both A and B perform the same amount of work, but delivers more power output than A.
c. A perform more work because he has to walk twice as many steps.
d. B performed less work because it takes him a shorter time to make the climb.
e. B performed less work becuase he only has to work half time
Answer:
C is the correct answer of this question.
A kid jumping on a trampoline reaches a height of 0.925 m. What was his speed when he left the trampoline?
Answer:
4.26 m/s
Explanation:
h = 0.925
v = 0
u = ?
v = u^2 - 2gh
0 = u^2 - 2gh
u = sqrt 2gh
= sqrt 2*9.8*0.925
= 4.258
= 4.26
Aball is thrown horizontaly from the top of a building with an initial velocity of 15 meters per second. At the same instant, a second ball is dropped from the top of the building. Which of the following is the
same for the two balls?
Answer:
Both balls have the same downward acceleration (and speed)
Help please :((((
Four movers pushed different boxes across a floor for the same distance. The table shows how much force each mover used, the time it took to move the box, and the mass of the
box.
Force Time. Mass of box
Akira: 155 5 15
Maddie: 120 10 15
Jayden: 90 3 18
Hamid: 160 10 22
Please help!!! I really need to pass this class!
Answer:
Hamid
Explanation:
I got it right on my test
A block of aluminum measures 4.0 cm x 5.0 cm x 2.0 cm is completely immersed in a tank of water.
Calculate the buoyant force and the mass of the displaced water (Remember the density of water is 1 g/mL) (g=10m/s2)
Answer:
upthrust or BUOYANT FORCE =Vdg
volume=LWH
upthrust=(4cm×5cm×2cm)×1g/cm²×g
upthrust=40cm³×1g/cm³×g
upthrust=40gf or 0.04kg×10m/s²=0.4N
weight of the displaced liquid is upthrust.
so mass=40g or 0.04kg
upthrust=40gf or 0.4Nand mass of the displaced liquid=40g or 0.04kg
please mark brainliest, hope it helped
Which of the following statements is NOT true about good communication? A. Good communication makes it difficult to express wants and needs. B. Good communication helps prevent misunderstandings. C. Good communication allows for expression. D. Good communication builds healthy relationships. Please select the best answer from the choices provided. A B C D.
Communication is the act of conveying information from one person to another. .'Good communication makes it difficult to express wants and needs.'These statement is not true about good communication.
What is communication?Communication is the act of conveying information from one location, person, or organization to another. There is a sender, a message, and a recipient for every message.
Communication, while it may appear to be a simple notion, is actually a very complex topic. The message's path from sender to the destination might be influenced by a multitude of circumstances.
Hence the option 'A' is right. 'Good communication makes it difficult to express wants and needs this statement is not true about good communication.
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the answer is A
Explanation : took the quiz on edge 2020
The energy of random atomic and molecular motion is called.
Why do two electrons repel when they interact? (1 point)
O because they both have similar negative electric charge
O because they both have similar mass
o because they both form part of different atoms
o because they both are subatomic particles
Answer:
In order to minimize the potential energy, they repel each other (in the case of a positive and negative charge, potential energy is minimized by bringing them together, so they attract).
Explanation:
Hope it helps
Two electrons repel when they interact, because they both have similar negative electric charge.
What is the property of interacting charges?When the two charges or the charged bodies interact each other, the force of attraction or repulsion acts between them. This force of attraction or repulsion can be find out using the coulombs law.
According to the Coulombs law, the force of attraction of repulsion between charged two bodies is directly proportional to the product of charges of them and inversely proportional to the square of distance between them. It can be given as,
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
Here, (k) is the coulombs constant, (q1 and q2) is the charges of two bodies and (r) is the distance between the two charges.
This force of attraction or repulsion is identified by the sign of the particular charge. According to the property of interacting charges-
Like charges-For the like charges, when two charges interact to each other, then the charges attract each other.Unlike charges-For the unlike charges, when two charges interact to each other, then the charges repel each other.As the electrons are negatively charges. Therefore, two electrons repel when they interact, because they both have similar negative electric charge.
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A block with a mass of 55 kg is pulled with a force of 220 N. Assuming a frictionless surface, what will be the acceleration of the block?
OA
0.25 m/s2
о
B
4.0 m/s2
O.
9.8 m/s2
Oo. 22 m/s2
2022 huminate Education
PLS HELP HELO ME!!!
Answer:
B) 4 m/s²
Explanation:
Since the surface it's kept on is frictionless, the net external force acting on the block will be 220 N.Mass of the block = 55 kg[tex] \boxed{ \sf{ F= m \times a}}[/tex]
Here,
F is the net external force applied to an object,m is the mass of that object, anda is the acceleration it acquires.Substituting the respective values for F and m:
==> 220 = 55 × a
==> 220 = 55 × a
dividing the equation by 55:
==> 4 = a
Therefore, an object of 55 kg when pulled across a frictionless surface by a force of 220 N accelerates at 4 (m/s)/s
[tex]\bold{\huge{\underline{ Hola \: Brainlians!!! }}}[/tex]
Three particles A, B and C are situated at the vertices of an equilateral triangle ABC of side d at time t = 0. Each of the particles moves with constant speed v. A always has its velocity along AB, B along BC and C along CA. At what time will the particles meet each other ?
- Don't want spam or copied answers
- Don't be greedy for points
- Best answer will be awarded with brainliest.
Given :-
Three particles A, B and C are situated at the vertices of an equilateral triangle ABC.The side of the triangle is d .A always has its velocity along AB, B along BC and C along CA.To Find :-
Time at which the particles will meet .Solution :-
See attachment .
Firstly break the velocity of A , into it's vertical components . That will be ,
[tex] v_A = v_A cos60^o + v_A sin60^o [/tex]
Now the component , [tex]v_A cos60^o [/tex] coincides on side AC and is directed from A to C . Along CA, the velocity of particle C is directed . So both are in opposite directions.
So , the relative velocity of C with respect to A will be ,
[tex] v_{CA}= v_C - v_A [/tex]
Substitute ,
[tex] v_{CA}= v - ( - v cos 60^o) [/tex]
Value of cos 60° is 1/2 ,
[tex] v_{CA}= v + v\bigg(\dfrac{1}{2}\bigg)=v +\dfrac{v}{2}[/tex]
Add the terms,
[tex] v_{CA}= \dfrac{2v + v}{2}=\dfrac{3v}{2}[/tex]
Hence , now we can find the time taken by A and C ,to meet each other will be ,
Since the speed is constant , we can use distance = speed*time , as ;[tex]s = v t [/tex]
Substitute ,
[tex]d = \dfrac{3v}{2} t [/tex]
Multiplying both sides by 2 ,
[tex] 2d = 3vt [/tex]
Dividing both sides by 3v ,
[tex] t = \dfrac{2d}{3v} [/tex]
Similarly , taking any two particles you will get the same time .
Hence the particles meet after 2d/3v time .
I hope this helps .
Answer:
never
Explanation:
Particles moving on paths that don't meet at a point will be particles that never meet. Even if the paths meet at a point, which these don't, the particles may not meet if they arrive at different times.
__
Consider the diagrams in the attachments. In order, they show the positions of the particles shortly after takeoff, midway along the line, and after they have gone farther than the length of the line. The point of closest approach is shown in the second attachment, when the particles are halfway along the line.
Consider particles A and C. Their north/south direction is 'north' for each of them. They both have the same velocity in the 'north' direction, but have started at different points, so can never meet. Those two particles have opposite velocities in the east/west direction, so can pass each other (which they do in the second attachment), but cannot meet.