Which physical activity is NOT aerobic exercise?
A) Hip-hop dancing
B) Jump roping
C) Yoga
D) Jogging
Answer:
C
Explanation:
Answer:
Hip-hop Dancing
Explanation:
Aerobic exercises are light (somewhat, a more accurate word would be bearable) workouts that you can endure over long periods of time. Anaerobic workouts describe workouts that require sudden burst of energy, like the ones you seen in most forms of dance, such as Hip-hop dance.
Hope this helps!
A boy pulls his 9.0 kg sled, applying a horizontal force of 14.0 N (rightward). The coefficient of friction between the snow and the sled is 0.12. Determine the net force and the acceleration of the sled. Draw a free-body diagram for the sled; use appropriate force symbols to label the type of each force acting on the sled.
Here is the answer, dud
A ferris wheel with radius 12 m makes a revolution every 3 minutes. Find the linear (tangental) speed of a passenger. How far does a person move in a 5 minute ride?
Answer:
The linear (tangential) speed of a passenger is 0.4188 m/s
The distance traveled by the person in 5 minutes ride is 125.64 m
Explanation:
Given;
radius of the Ferris, r = 12 m
1 revolution per 3 minutes, [tex]\omega = \frac{2\pi (radian)}{3\ (minutes)} *\frac{1\ minute}{60 \ seconds} = 0.0349 \ rad/s[/tex]
The linear (tangential) speed of a passenger is given by;
v = ωr
v = (0.0349)(12)
v = 0.4188 m/s
The distance traveled by the person in 5 minutes ride is given by;
d = vt
d = (0.4188)(5 x 60)
d = 125.64 m
How would you go about measuring the speed of a vehicle? What measurements would you have to take? What calculations would you have to perform?
Answer:
For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.
hii i need these answers please!! as soon as possible and if you can’t see anything jus let me know and ill tell you what it says
Answer:
Explanation:
CANT SEE ITS TOO PIXELATED
A squirrel falls from this tree after being shocked by the falling apples. If the
squirrel was 3.5 meters above the ground, how long until the squirrel hits the
ground?
Answer:
0.85m
Explanation:
Given parameters:
Height of fall = 3.5m
Unknown:
Duration of fall = ?
Solution:
To solve this problem, we apply the right motion equation.
Since we know the height, we can use the equation below;
S = ut + [tex]\frac{1}{2} gt^{2}[/tex]
S is the height
u is the initial velocity = 0m/s
t is the time
g is the acceleration due to gravity
3.5 = 0 + [tex]\frac{1}{2}[/tex] x 9.8 x t²
3.5 = 4.9t²
t² = [tex]\frac{3.5}{4.9}[/tex]
t² = 0.71
t = √0.71 = 0.85m
During a football workout, two linemen are pushing the coach on the sled. The
combined mass of the sled and the coach is 300 kg. The coefficient of friction between
the sled and the grass is 0.800. The sled accelerates at the rate of 0.580 m/s^2.
Determine the force applied to the sled by the lineman.
Answer:
F_{players} = 2528.4[N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.
On the sled act two forces, the force of friction and The Force executed by the football players.
The movement of the football players will be taken as positive, while the friction will be taken as negative, since it is opposed to the movement of the sled.
ΣF = m*a
where:
F = force [N]
m = mass [kg]
a = acceleration = 0.580 [m/s²]
[tex]F_{players} - f_{friction} = m*a[/tex]
The friction force is defected as the coefficient of friction by the normal force, the normal force on a horizontal surface can be calculated as the product of mass by gravitational acceleration.
[tex]f_{friction}=0.8*(300*9.81)\\f_{friction}=2354.4[N][/tex]
Now we can calculate the force exerted by the players.
[tex]F_{players}-2354.5=300*0.580\\F_{players}=2528.4[N][/tex]
1) An object travels 15 m in 3 s. What is its' speed?
Answer:
5m/s
Explanation:
Distance/Time= Speed
D/T=S
15/3=S
5=S
The first excited state of a particular atom in a gas is 5.8 eV above the ground state. A moving electron collides with one of these atoms, and excites the atom to its first excited state. Immediately after the collision the kinetic energy of the electron is 3.7 eV. What was the kinetic energy of the electron just before the collision?
Ki = ____eV
Answer:
E₀ = 9.5 eV
Explanation:
In the processes of absorption, excitation and shocks the energy must be conserved therefore the energy before the shock is
E₀ = E_excitation + E_residual
E₀ = 5.8 + 3.7
E₀ = 9.5 eV
this is the energy of the electron before the collision
6. Which of the following types of energy is not lost when energy is
transferred between one of the Earth's four physical systems?*
heat
light
sound
nuclear
vibration
movement
Answer:
heat light sound viberation
Explanation:
i'm built different
Maria wrote the following steps in the formation of igneous rocks. Step 1: Rocks pushed under Earth due to movement of tectonic plate Step 2: Rocks melt Step 3: Molten rocks are heated Step 4: Rocks solidify Which step contains an error?
Answer:
Step 1: Rocks pushed under Earth due to movement of tectonic plate
Step 2: Molten rocks are heated
Step 3: Rocks melt
Step 4: Rocks solidify
Explanation:
Step 1: Rocks pushed under Earth due to movement of tectonic plate
Step 2: Rocks melt
Step 3: Molten rocks are heated
Step 4: Rocks solidify
In the formation of igneous rocks, rocks are pushed under the earth due to the movement of tectonic plate.
As the rocks are pulled beneath the crust, they are heated and begin to melt to form magma.
Then, with time, the magma solidify to form an igneous rock.
Step 2 is wrong.
Step 3 should come first
Step 1: Rocks pushed under Earth due to movement of tectonic plate
Step 2: Molten rocks are heated
Step 3: Rocks melt
Step 4: Rocks solidify
A Carnot engine takes in heat at a temperature of 790 K and releases heat to a reservoir at a temperature of 470 K. What is its efficiency?
Answer: 1280 kilometers :D
Explanation:
790 K ' 470 K = 1280 KM (KILOMETERS)
Answer:
GIVE DIS GUY BRAINLIST
Explanation:
Block A of 15kg of the figure below slides on a surface where the coefficient of kinetic friction is uk=0.3. The block moves at 10m/s when it is s=4m from a second 10kg B block, initially at rest. Considering this situation, determine what will be the maximum compression of the spring, initially decompressed, after the collision if the coefficient of return between the blocks is e=0.6. Tip here, as the blocks are subject to friction forces, use the equation that relates mechanical energy and the work done by non-conservative forces.
Answer:
0.287 m
Explanation:
The velocity of block A when it reaches block B is:
KE₀ = KE + W
½ mv₀² = ½ mv² + Fd
½ mv₀² = ½ mv² + mg μ d
v₀² = v² + 2g μ d
v² = v₀² − 2g μ d
v² = (10 m/s)² − 2 (9.8 m/s²) (0.3) (4 m)
v = 8.75 m/s
The coefficient of restitution is 0.6, so the relative velocity between A and B after the collision is:
e = |Δv after| / |Δv before|
0.6 = Δv / (8.75 m/s)
Δv = 5.25 m/s
Momentum is conserved, so the speed of block B after the collision is:
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
(15 kg) (8.75 m/s) + (10 kg) (0 m/s) = (15 kg) (v) + (10 kg) (v + 5.25 m/s)
131.2 m/s = 25v + 52.5 m/s
25v = 78.7 m/s
v = 3.15 m/s
Energy is conserved, so the compression of the spring is:
KE = EE + W
½ mv² = ½ kd² + Fd
½ mv² = ½ kd² + mg μ d
½ (10 kg) (3.15 m/s)² = ½ (1000 N/m) d² + (10 kg) (9.8 m/s²) (0.3) d
49.6 = 500 d² + 29.4 d
0 = 500 d² + 29.4 d − 49.6
d = [ -29.4 ± √(29.4² − 4(500)(-49.6)) ] / 1000
d = (-29.4 ± 316.2) / 1000
d = 0.287 m
what is the difference of dispersed phase and continuous phase?
Answer:
The phase existing as small droplets is called the dispersed phase and the surrounding liquid is known as the continuous phase. Emulsions are commonly classified as oil-in-water (O/W) or water-in-oil (W/O) depending on whether the continuous phase is water or oil.
Explanation:
Try to move the magnet back and forth between the two coils. Explain the motion of the magnet and what might be causing this.
Answer:
Please find the answer in the explanation.
Explanation:
When you try to move the magnet back and forth between the two coils, the motion of the magnet will be oscillatory and this action will cause current and EMF to induce
According to law of Faraday, current or EMF will be induced when a magnet is moved in the presence of coils
If the magnet continues to move back and forth between the two coils, what might be causing this will be the presence of the induced electromagnetic force between the two coils.
A 25 kg child is sitting at the top of a 4 m tall slide, what is his potential energy?
An ideal transformer has 60 turns in its primary coil and 360 turns in its secondary coil. If the input rms voltage for the 60-turn coil is 120 V, what is the output rms voltage of the secondary coil
a. 240 V
b. 720 V
c. 360 V
d. 480 V
e. 20 V
Answer:
720 V
Explanation:
Given that,
The number of turns in primary coil, N₁ = 60
The number of turns in secondary coil, N₂ = 360
The input rms voltage, V₁ = 120 V
We need to find the output rms voltage of the secondary coil . The relation between number of turns in primary coil - secondary coil to the input rms voltage to the output rms voltage is given by :
[tex]\dfrac{N_1}{N_2}=\dfrac{V_1}{V_2}\\\\V_2=\dfrac{N_2V_1}{N_2}\\\\V_2=\dfrac{360\times 120}{60}\\\\V_2=720\ V[/tex]
So, the output rms voltage of the secondary coil is 720 V. Hence, the correct option is (b).If the sound source is moving then the pitch of the sound will ___________________ to the observer.
Answer:
Increase
Explanation:
The frequency of sound determines the sound. If the frequency is lower the pitch will be lower. If the frequency is higher the pitch will be higher. This is affected by the motion of the sound source because when a sound source is moving faster the frequency will become higher.
1.
How does centripetal force due to gravity keep a satellite in orbit?
It continuously changes the direction of the satellite.
It provides the thrust to launch the satellite into space.
It prevents the satellite from falling toward Earth.
It keeps increasing the speed of the satellite.
Answer:
1st one,.
It changes the direction,
And satellite falls in earth infinity,
Its total workdone is zero
Answer:
It continuously changes the direction of the satellite.
Explanation:
our Welcome (; (:
An airplane with a mass of 5,000 kg needs to accelerate 5 m/s2 to take off before it reaches the end of the runway. How much force is needed from the engine
Answer:
25000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 5000 × 5
We have the final answer as
25000 NHope this helps you
A 12-volt battery maintains a 4.5A current through a resistor. What is the resistance of the resistor.
The difference between a law and a theory is the diffrence between what and why . Explain
Answer:
A law is defined as a description or a statement given after an observed phenomenon. A theory is a simplification of certain observational data as to how and why it happened.
Explanation:
I hope this helped solve your question.
A red blood cell contains 4.8 107 free electrons. What is the total charge of these electrons in the red blood cell?
Answer:
Charge, [tex]q=7.68\times 10^{-12}\ C[/tex]
Explanation:
It is given that,
The number of electron in a RBCs, [tex]n=4.8\times 10^7[/tex]
We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :
q = ne
e is the change on electron
[tex]q=4.8\times 10^7\times 1.6\times 10^{-19}\\\\q=7.68\times 10^{-12}\ C[/tex]
So, the net charge is [tex]7.68\times 10^{-12}\ C[/tex].
The towel has better blank
than that towel.
A.duplication
B.formation
C.qualification
D.absorption
Answer:
D
Explanation:
Towels Absorb
A cannonball is fired straight up at a speed of 25 m/s. What is the maximum altitude that it will reach?
Answer:
When the projectile is launched straight up, there isn't a horizontal ... The initial acceleration was 9.8 m/s2 pointing up, so the acceleration at any other point should be the same.
Explanation:
Hope it helped =)
The maximum altitude that the cannonball will reach if fired straight up at a speed of 25 m/s is; 31.86 m
According to the question;
The cannonball is fired straight up at a speed of 25 m/s
Additionally, the cannonball is fired against the force of gravity.
Consequently, the motion is in the opposite direction of the acceleration due to gravity.
From the equation of motion;
V² = U² - 2gHAt the maximum altitude, V = 0.
0² = 25² - (2× 9.81) H19.62H = 625H = 625/19.62H = 31.86mThe maximum altitude that it will reach is;
H = 31.86mRead more:
https://brainly.com/question/20352766
anybody wanna play among us?
Answer:
yess
Explanation:
Answer:
yes me
mark me brainliestWhat is the relationship between lightning and atoms?
A. Electrons colliding in the air create lightning
B. The nucleus of atoms colliding creates an atom
C. Lightning is made of atoms
D. Lightning is created by the collision of protons
Answer:
C. Lighting is made of atoms
Explanation:
Everything is made of atoms that are, in turn, made out of charged particles. All charged particles come in one of two types: positive and negative (or plus and minus). The minus particles are the electrons, and the plus particles are the much heavier protons which are buried deep in the nucleus.
A cannonball is launched diagonally with an initial horizontal speed of 51.0m/s
and an initial vertical speed of 24.0m/s. Label the hypotenuse, opposite side and
adjacent side, and determine all unknowns.
m/s
initial speed:
initial horizontal speed:
initial vertical speed:
m/s
m/s
At what angle () was the cannonball launched?
• initial horizontal speed: 51.0 m/s
• initial vertical speed: 24.0 m/s
• initial speed: √((51.0 m/s)² + (24.0 m/s)²) ≈ 56.4 m/s
• angle: tan(θ) = (24.0 m/s) / (51.0 m/s) → θ ≈ 25.2º
Using Pythagoras, the initial speed and the launch angle of the cannon ball are 56.36 m/s and 25.20° respectively.
The initial speed can be obtained using length of the diagonal :
v² = 51² + 24²
v² = 2025
v = √3177
v = 56.36 m/s
The launch angle, θ :
Tanθ = opposite / Adjacentθ = tan¯¹(24/51)
θ = tan¯¹(0.4705)
θ = 25.20°
Hence, the angle of launch is 25.20°
Learn more : https://brainly.com/question/18766174
A 5 kg block is released from rest at the top of a quarter- circle type curved frictionless surface. The radius of the curvature is 3.8 m. When the block reaches the bottom o the curvature it then slides on a rough horizontal surface until it comes to rest. The coefficient of kinetic friction on the horizontal surface is 0.02.
a. What is the kinetic energy of the block at the bottom of the curved surface?
b. What is the speed of the block at the bottom of the curved surface?
c. Find the stopping distance of the block?
d. Find the elapsed time of the block while it is moving on the horizontal part of the track.
e. How much work is done by the friction force on the block on the horizontal part of the track?
Answer:
a. 186.2 J b. 8.63 m/s c. 190 m d. 43.2 s e. 186.2 J
Explanation:
a. From conservation of energy, the potential energy loss of block = kinetic energy gain of the block.
So, U + K = U' + K' where U = initial potential energy of block = mgh, K = initial kinetic energy of block = 0, U' = final potential energy of block at bottom of curve = 0 and K' = final kinetic energy of block at bottom of curve.
So, mgh + 0 = 0 + K'
K' = mgh where m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s², h = initial height above the ground of block = radius of curve = 3.8 m
So, K' = 5 kg × 9.8 m/s² × 3.8 m = 186.2 J
b. Since the kinetic energy of the block K = 1/2mv² where m = mass of block = 5 kg, v = velocity of block at bottom of curve
So, v = √(2K/m)
= √(2 × 186.2 J/5 kg)
= √(372.4 J/5 kg)
= √(74.48 J/kg)
= 8.63 m/s
c. To find the stopping distance, from work-kinetic energy principles,
work done by friction = kinetic energy change of block.
So ΔK = -fd where ΔK = K" - K' where K" = final kinetic energy = 0 J (since the block stops)and K' = initial kinetic energy = 186.2 J, f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance
ΔK = -fd
K" - K' = - μmgd
d = -(K" - K')/μmg
Substituting the values of the variables, we have
d = -(0 J - 186.2 J)/(0.02 × 5 kg × 9.8 m/s²)
d = -(- 186.2 J)/(0.98 kg m/s²)
d = 190 m
d. Using v² = u² + 2ad where u =initial speed of block = 8.63 m/s, v = final speed of block = 0 m/s (since it stops), a = acceleration of block and d = stopping distance = 190 m
So, a = (v² - u²)/2d
substituting the values of the variables, we have
a = (0² - (8.63 m/s)²)/(2 × 190 m)
a = -74.4769 m²/s²/380 m
a = -0.2 m/s²
Using v = u + at, we find the time t that elapsed while the block is moving on the horizontal track.
t = (v - u)/a
t =(0 m/s - 8.63 m/s)/-0.2 m/s²
t = - 8.63 m/s/-0.2 m/s²
t = 43.2 s
e. The work done by friction W = fd where
= μmgd where f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance = 190 m
W = 0.02 × 5 kg × 9.8 m/s² × 190 m
W = 186.2 J
The potential energy of the loss of the block will be equal to the kinetic energy gain. The kinetic energy of the block is 186.2 J at the bottom of the curved surface.
The potential energy of the loss of the block will be equal to the kinetic energy gain.
So,
[tex]U = mgh[/tex]
Where,
[tex]U[/tex] - potential energy
[tex]m[/tex] - mass of block = 5 kg
[tex]g[/tex] - gravitational acceleration = 9.8 m/s²
[tex]h[/tex] = height = radius of curve = 3.8 m
Put the values in the formula,
[tex]U = 5 \times 9.8 \times 3.8 \\\\ U = 186.2 \rm \ J[/tex]
Therefore, the kinetic energy of the block is 186.2 J at the bottom of the curved surface.
Learn more about kinetic energy:
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The frequency of an electromagnetic wave is 1.0 x 105 Hz. Calculate the wavelength in meters. Show your work,
and be sure to keep track of the units.
Answer:
wavelength = 3000 m
Explanation:
We use the formula for the relationship between the speed (c), frequency (v), and wavelength [tex](\lambda)[/tex]:
[tex]c=\lambda\,*\,\nu\\300000000 \,\,m/s = \lambda\,*100000 \,\,1/s\\\lambda \,=\,3000\,\,m[/tex]