To determine the density of an irregularly shaped object, a student immersed the object in 22.2 mL of water in a
graduated cylinder, causing the level of the water to rise to 37.8 ml. If the object had a mass of 22.4 g, what is the
density of the object?

Answers

Answer 1

Answer:

Explanation:

The density would be 4.


Related Questions

A teacher asks students to describe the physical properties of 10 mL of vinegar and 10 mL of milk. When the students finish listing the physical properties in their science notebooks, the teacher pours the vinegar and milk into the same beaker. The students are surprised to see a white solid substance form within the beaker as the two substances are combined.

What occurs within the beaker as the teacher mixes the vinegar and milk?
1. A chemical change that produces a precipitate
2. A physical change that creates a new substance
3. A physical change that produces a precipitate
4. A chemical change that produces no new substances

Answers

Answer:

1. A chemical change that produces a precipitate

Explanation:

A solid substance that is formed from a liquid phase is called a precipitate.

A reaction that produces a precipitate is called a precipitation reaction.

Precipitation reactions are an example of a chemical change.

Thus the correct answer is option 1: A precipitate was formed when vinegar and milk were mixed (as there were no solid substances when they were apart).

The enthalpy of combustion of gasoline (C8H18) is 5471 kJ mol-1. How much heat will be produced by burning 1 gallon of gasoline at 25°C? (Density of gasoline = 0.703 g/mL; 1gallon = 3.78 L) Show your work clearly.

Answers

Answer:

127529 KJ

Explanation:

Since 1gallon = 3.78 L= 3780 ml

The density of C8H18= 0.703 g/mL

Density = mass/volume

Mass= Density × volume

Mass= 0.703 g/mL × 3780 ml

Mass= 2657.34 g

Molar mass of C8H18= 114 g/mol

Number of moles= mass/molar mass

Number of moles= 2657.34/114

Number of moles= 23.31 moles

Since 1 mole evolved=5471 kJ

23.31 moles = 5471 kJ × 23.31 = 127529 KJ

If 240.0 g NaOH reacts, how many grams of Cu(OH)2 should precipitate out in the reaction? Show work

Answers

Answer:

292.7 g

Explanation:

Note: the reaction is missing but I looked it up on the web and found it.

Step 1: Write the balanced equation

CuSO₄(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)

Step 2: Calculate the moles corresponding to 240.0 g of NaOH

The molar mass of NaOH is 40.00 g/mol.

240.0 g × 1 mol/40.00 g = 6.000 mol

Step 3: Calculate the moles of Cu(OH)₂ formed from 6.000 moles of NaOH

The molar ratio of NaOH to Cu(OH)₂ is 2:1. The moles of Cu(OH)₂ formed are 1/2 × 6.000 mol = 3.000 mol.

Step 4: Calculate the mass corresponding to 3.000 moles of Cu(OH)₂

The molar mass of Cu(OH)₂ is 97.56 g/mol.

3.000 mol × 97.56 g/mol = 292.7 g

1. What kinds of metals are REALLY reactive? why?
2. What kinds of non-metals are REALLY reactive? why?
3. What group on the periodic table doesn’t react at all? why?

Answers

Answer:

1. Alkali metals (group 1)

2. halogens (Group 17)

3. noble gasses (group 18)

Explanation:

1. alkali metals only have one valence electron meaning that they really want to lose that one valence electron to get a full octet.

2. halogens have 7 valence electrons meaning that they just need to gain 1 to get a full octet.

3. Nobel gasses already have a full octet meaning that they don't want to react. (atoms only react to get a full octet)

I hope this helps.  Let me know if anything is unclear.

The small intestine is over 30 feet in length! Why do you think the small intestine is so long

Answers

because intestines are gross

Answer:

Explanation:

Better digestion!!

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