To be launched, a glider is uniformly accelerated from rest by a cable pulled by a motor that exerts a horizontal force on the glider throughout the launch. The glider reaches its launch speed of 51.0 m/s after accelerating for 17.0 s. Assume that the glider moves horizontally until it leaves the ground. Calculate the total distance travelled by the glider before it leaves the ground.

The average force exerted as the displacement from 0 to x changes is 12kx. W = 12kx² is the work done when stretching or compressing a spring a distance x from its equilibrium position.

The Hooke's Law Calculator employs the formula Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, or distance the spring is stretched. Hooke's Law states that when a spring is stretched, the force exerted is proportional to the increase in length from the equilibrium length. The spring constant can be calculated as follows: k = -F/x, where k is the spring constant. The Young's modulus (E) is a material property that indicates how easily it can stretch and deform. It is defined as the ratio of tensile stress () to tensile strain ().

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When Solid iron(II) sulfate and a solution of barium chloride react together, they form solid barium sulfate and a solution of iron (II) chloride. Here, exchange of anions and cations took place and is an example of a double displacement reaction.

A double Displacement reaction is a type of reaction in which, the cations and anions of the two ionic compounds exchange with each other to form new compounds. The overall reaction of double displacement looks like this,

X⁺Y⁻ + A⁺B⁻ ---------------> X⁺B⁻ + A⁺Y⁻

Precipitation reactions and neutralization reactions are two common examples of Double displacement reactions. In the given question, the reaction of Iron sulfate and Barium Chloride reaction is as follows;

FeSO₄ + BaCl₂ -------------> FeCl₂ + BaSO₄

Here the cations Fe²⁺ and Ba²⁺ are exchanged with the anions Cl⁻ and SO₄²⁻.

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Answer: C. brightness, temperature

Explanation: This question doesn't fully make sense because there are basically multiple correct answers. A star has the properties of distance, luminosity, temperature, brightness, radius, etc .

The ratio of an object's mass to volume is known as its density. Density is defined as the product of mass and volume, or D = m/v. Because of the size, mass, and arrangement of each substance's atoms or molecules, each substance has a unique characteristic density.

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Therefore, the current mass will be 0.0017002 times the sample's initial mass.

Given:

half life of the sample in question, t^=5 x 108 years

We are aware that the solar system formed roughly 4.6 x 109 years ago.

Let the starting amount for the solar system's formation sample be, mo

The current ultimate quantity would then be:

m = mo x (1/2) (t^/t)

m= mo x (1/2) 4.6 x 10^9/(5x10^8)

m= mo x 0.0017002

Therefore, the current mass will be 0.0017002 times the sample's initial mass.

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I'm guessing that you need the force, since the question doesn't specify I'll just use the force equation. If this is not what you wanted let me know in the comments section of this answer.

- F = 300 x 4

- F = 1200 N (newtons)

Answer: 1.62 m/s

Explanation:

Distance/time=speed

12 hours in minutes is 720

12x60=720

720 minutes in seconds is 43200

720x60=43200

70000/43200=1.62037

1.62 m/s

a. Expression for magnitude of the acceleration is GM/16R² b. magnitude of the acceleration is 1.33 e^-5 ms^-2 .

Because the direction is always shifting, motion on a circle accelerates even while the speed is constant. Both effects add to the acceleration for all other types of motion. It is a vector quantity because acceleration has both a magnitude and a direction. Another vector quantity is velocity. The velocity vector change during a certain period of time, divided by that period of time, is the definition of acceleration. Acceleration requires a change in speed, direction, and rate of change. An object experiences constant acceleration when its velocity changes at the same rate every second. Whether an object is accelerating or decelerating determines the direction of acceleration. The force of gravity causes an item in free fall to fall. An object has positive acceleration when it is going faster than it was previously. Positive acceleration was demonstrated by the moving car in the first scenario. The acceleration is in the same direction as the car's motion since the vehicle is moving ahead and accelerating.

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Answer:

A.BB is 000 with A.B is 0.00

Dark energy has been hypothesized to solve The expansion of the universe is accelerating.

Functional behavioural assessment, or FBA for short, is used to examine a student's behaviour in order to determine the fundamental driving force behind the behaviour.As they apply the scientific method to learn more about the world, hypotheses are the questions that scientists ponder. People also employ the procedure of forming then attempting to refute a hypothesis in their daily lives. The purpose of the hypothesis is to organise the process of comprehending how the world operates. After the behaviour has been identified and information about the circumstances surrounding the student's activities has been gathered, the next step is to construct a hypothesis, which is a declaration that enumerates the conduct, what came before it, and its presumed purpose.

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This acceleration will be expressed in decimal terms as 1.8 m/s square, and the direction of this investigation will be downhill and vertical.

There is an elevator, and it weighs a whopping 5000 kg. assuming that it has also been revealed that the elevator is supported by a cable. And it has been noted that the 40,000 newtons of tension in the wire holding this elevator. Four into ten is thus equal to four newtons. Additionally, we must ascertain the elevator's magnitude and acceleration. So let's think about E. S. The acceleration that we must here calculate. Wheat will therefore follow the accelerator and will be moving downward. We multiply mass by the gravitational acceleration to obtain weight.

The mass is 5000, then. This is multiplied by 9.8 To obtain the weight of 49,000 Newtons, it is necessary to apply 40,000 Newtons of tension. Therefore, it can be seen that the downward force is greater than the tension. Therefore, we can infer that the acceleration in this case will be in the downward direction and that the net force will also be in that direction. Additionally, the mass of the accelerator will be divided by the net force to get the acceleration. So let's start by calculating the net force. Therefore, that will be MG – t. And according to Newton's second law, this will be equal to mass times the acceleration.

Therefore, from this point on, we will receive 9000 when we subtract the tension from the weight. And when we divide by 5000, which is the elevator's mass, we arrive at the acceleration, which works out to be roughly nine by five m per second square. The acceleration will be expressed in decimal terms as 1.8 m/s square, and this exploration will be conducted vertically downward.

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The fact that both spools travel same distance over same period of time and have equal mass, both will reach the top of the ramp at same time.

The same tension inextensible threads are used to draw two identical spools of similar mass, A and B, from rest and up identical ramps. The thread is wrapped repeatedly around spool A, but it is secured to a fixed spot on spool B, preventing rotation of spool B. The ramps and the objects don't rub against each other. From the bottom of the ramp to the same spot at the top of the ramp, both spools are hauled.

The tension from the thread force and a part of the force of gravity are forces acting on both spools along the ramp. Due to the equal spool masses and tension forces, the net forces operating on both are also the same. As a result, both spools' centers move with the same acceleration. Both begin at zero speed, hence the speed of both spools at any one time is the same. The distance and duration of travel for both spools are the same. So, they both arrive at the ramp's top simultaneously.

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Will spool A reach the top of the ramp before, after, or at the same instant as spool B? If you do not have enough information, state so explicitly. Explain your reasoning.

Answer:

reaction

Explanation:

Newtons third law states that for every action there is an equal but opposite reaction

and for that object (rocket, missile, jet,) as the engine is ignited the force of the burning fuel pushes backward while the rocket moves forward so the rate at which the fuel burns is equal to the rate at which the object moves forward

the force at which the burning fuel pushes backward is equal but opposite to the rate at which the object moves forward

Answer:

10 floors

Explanation:

We are told that a bell of mass 20 kg is atop a tower and has 8829 J of gravitational energy. The question asks us to estimate the number of floors the tower has.

To do this, we must first calculate how high above the ground the bell is. We can do that using the formula for gravitational potential energy:

[tex]\boxed{g.p.e = mgh}[/tex],

where:

• g.p.e = gravitational potential energy (8829 J)

• m = mass of object (20 kg)

• g = acceleration due to gravity (approximately 10 m/s²)

• h = height of object above ground (? m).

Using the above information and formula, we can solve for h:

g.p.e = [tex]20 \times 10 \times h = 8829[/tex]

       ⇒ [tex]200 h = 8829[/tex]

       ⇒ [tex]h = \frac{8829}{200}[/tex]

       ⇒ [tex]h = \bf 44.145 \ m[/tex]

Therefore the bell is 44.145 m above the ground, which means that the height of the tower is also 44.145 m.

One floor of a building can be estimated to be around 4.3 m, therefore the number of floors the tower has is:

44.145 ÷ 4.3

≈ 10

Therefore there are 10 floors in the tower.

The cyclist will accelerate because he changed his direction from west to south.

Acceleration is a vector quantity. It has both magnitude and direction.

Given is a bicyclist bikes to the west at a constant speed for 30 minutes before turning South and continuing at the same speed for an hour.

As learned above, acceleration is a vector quantity. This means that it has both the magnitude and the direction. If any one of that changes the acceleration will change. Now, since the direction changed from west to south, the resultant acceleration of the cyclist will change. Hence, the cyclist will accelerate.

Therefore, the cyclist will accelerate because he changed his direction from west to south.

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Only the charge present inside the cavity can explain the electric field that exists there. The electric field inside the hollow would remain unchanged as a result.

Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field. To predict what would happen to electric charges nearby a specific point, one only needs to be aware of the value of the electric field there, without having any precise knowledge of what generated the field.

When one charge is thought of as the generator of an electric field that spreads outward into the surrounding space, the electric force is not thought of as a direct interaction of two electric charges that are separated from one another.

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Answer:

phase

Explanation:

Phases   :   solid   liquid  gas

Answer:

form or state. (Sometimes the teacher won't accept state as an answer.)

Explanation:

For matter to change when moving from a solid state, it would have to be physically altered to be in, say, a liquid state. It's still the same product, it just had to change form. Ex: Solid to liquid. When you take an ice cube and melt it, it is still the same water, it's just in a different form or state.

Hope this helps! :)

The component of the forces and the frictional force of the bodies are as follows

6. The frictional force is approximately 37°

7. The frictional force is 0, while the force holding the mass is approximately 49.05 N

8. Please find attached the drawing showing the three forces acting on the block and their direction.

The forces are; [tex]F_{fr}[/tex] = [tex]F_{W}[/tex] ≈ 33.55 N, [tex]F_{N}[/tex] ≈ 92.18 N

9. The steepest angle of the slope is approximately 37.6°

Frictional force is the force that is generated and serves to prevent the relative motion of two bodies in contact.

6. The angle made by the rope with the horizontal = 37°

The tension in the rope = 10 N

Velocity of the crate = Constant

Given that the velocity of the crate is constant:

The frictional force = The horizontal component of the tension in the rope

Which gives: Frictional force = 10 N × cos(37°) ≈ 7.99 N

7. The frictional force is given by the formula: [tex]F_{fr} = m\cdot g \cdot cos(\theta)\cdot \mu[/tex]

Given that the plane is frictionless, we have: μ = 0

Therefore: Frictional force, [tex]F_{fr} = m\cdot g \cdot cos(\theta)\times 0 = 0[/tex]

The force holding the mass, F = m·g·sin(θ)

Where:

θ = 30.0°
g = The acceleration due to gravity ≈ 9.81 m/s²

∴ F ≈ 10.0 kg × 9.81 m/s² × sin(30°) = 49.05 N

8. Please find attached the drawing showing the weight, the friction force and the normal reaction of the block.

Given that the block slides down at a constant speed, the frictional force is equivalent to the weight component down the incline

The weight components of the block are:

Frictional force, [tex]F_{fr}[/tex] = Weight component down the incline, [tex]F_{W}[/tex], which gives;

Frictional force, [tex]F_{fr}[/tex] = 10.0 kg × 9.81 m/s² × cos(20) × μ = 10.0 kg × 9.81 m/s² × sin(20) ≈ 33.55 N

Weight component down the incline, [tex]F_{W}[/tex] ≈ 33.55 N

The normal reaction, [tex]F_{N}[/tex] = m·g·cos(θ)

Therefore: Normal reaction, [tex]F_N[/tex] ≈ 10.0 kg × 9.81 m/s² × cos(20°) ≈ 92.18 N

9. When the crate moves at a steady speed, the required horizontal force = The frictional force = m·g·μ

Given that m = 79.4 kg, μ = 0.2, we have;

Friction force = Required force = 79.4 × 9.81 × 0.2 = 155.7828

The required horizontal force = 155.7828 N

10. Given that the coefficient of static friction, μ = 0.77, we have:

When the car slips; friction force = weight of the car acting on the incline

m·g·cos(θ)·μ = m·g·sin(θ)

[tex]\mu = \dfrac{m \cdot g\cdot sin(\theta)}{m\cdot g\cdot cos(\theta)} = tan(\theta)[/tex]

The steepest angle, θ = arctan(μ)

Which gives;

Steepest angle, θ = arctan(0.77) ≈ 37.6°

The steepest angle is, θ ≈ 37.6°

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At the top of his path, he comes to rest for a moment but he will not be in equilibrium at this point.

No, the boy is not in equilibrium. At the moment at which the boy is released from his father's grip, he is not in equilibrium.

Being in equilibrium means that the net force on the body is zero. When we talk about net force, it means that the net acceleration should be zero. But when the boy is released into the air, the boy's velocity will become zero at the highest point, but the acceleration is never zero. The velocity of the body has nothing to do with the equilibrium of the body.

The earth is constantly applying gravitational force to the body.

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Answer: angle = 2°

Explanation:

Let the angle of inclination be θ,

as shown in figure the forces equation on the block are as follows

Fsinθ = ma , where F=mg

mgsinθ = ma

sinθ = [tex]\frac{a}{g}[/tex]....................eq1

now we know that s = ut  + 1/2at*t

3 = 0+1/2at*t

6 = a*[16.81]

a = 0.357m/s*s

now put value of a in eq1

therefore sinθ = 0.357/9.8=0.0364

angle θ = 2°

Answer:

91 kg

Explanation:

F = m a

893 = m *9.81 m/s^2

91 kg

If an astronaut weighs 148 N on the Moon and 893 N on Earth, his terrestrial mass is 91 kg

Therefore,

F = m a

893 = m × 9.81 m/s^2

91 kg

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The weight of a person on the planet Pluto with mass 85 kg is 52.36 N.

What is Pluto?

Pluto is a dwarf planet in the Kuiper belt, a ring of planets beyond Neptune's orbit. The ninth-largest and tenth-most massive object known to exist, it orbits the Sun directly. The largest trans-Neptunian object by volume, it is only slightly larger in mass than Eris. Like other Kuiper belt objects, Pluto is substantially smaller than the inner planets and is primarily made of ice and rock. The moon of Earth is only one-sixth the mass and one-third the volume of Pluto.

At first, lets calculate the acceleration due to gravity at Pluto:

The formula to calculate the acceleration due to gravity is:

[tex]a_g = G \times \frac{m}{r^2}[/tex]

where, a = acceleration due to gravity, m = mass, r = radius, G = gravitational constant

The mass is 1.303 x 10^22 kg

The radius is 1.1883 x 10^6 m

G is 6.67408 x 10^-11 m^3/kg•s²

So

a = 6.67408 x 10^-11 m^3/kg•s^2 • 1.303 x 10^22 kg / (1.1883 x 10^6 m)^2

a = 8.69632624 x 10^11 m^3/s^2 / 1.41205689 x 10^12 m^2

a = 6.1586 x 10^-1 m/s² or 0.616 m/s²

Now, lets calculate the weight:

w = ma

where, w = weight, m = mass

putting the values in question, we get,

w = 85 (0.616)  

w = 52.36 N

Note: Some correction in the value of mass and radius needs to be done in the question.

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The acceleration of each block is 1.225m/s^2

The string exerts 2.315N on 210g block, and 2.976N on 270g block

It will take 1.28s for each block to traverse

Part a

Acceleration, a of the block:

m1=270g

m2=210g

g=9.8

Acceleration=(m1-m2)*g/(m1+m2)

                    =(270-210)*9.8/(270+210)

                    =1.225m/s^2

Part b

Force that the string exerts on each block:

Force, T1 on smaller block:

T1=m2(g+a), where m2=0.21kg, g=9.8, and a=1.225m/s^2

T1=0.21(9.8+1.225)

T1=2.315N

Force exerted on smaller block=2.315N

Force, T2 on larger block

Here, m1=0.27kg, g=9.8, and a=1.225m/s^2

T2=0.27(9.8+1.225)

    =2.976N

Force exerted on larger block=2.976N

Part c

How long it will take each block to traverse 1.0m

h=1.0m

a=1.225m/s^2

[tex]t=\sqrt{\frac{2h}{a} }[/tex]

[tex]t=\sqrt{\frac{2*1}{1.225} }[/tex]

t=1.28s

The question was incomplete, complete question is given below:

A person holds a 210-g block that is connected to a 270-g block by a string going over a light pulley with no friction in the bearing (an Atwood machine). After the person releases the 210-g block, it starts moving upward and the heavier block descends. Part A: What is the acceleration of each block? Part B: What is the force that the string exerts on each block? Part C: How long will it take each block to traverse 1.0 m?

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It takes her 4.17s to complete 10 dribbles as frequency is 2.40hz

What do you mean by frequency ?

In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time .A body traveling in periodic motion is considered to have experienced one cycle or one vibration after passing through a series of circumstances or locations and then returning to its starting point.. The frequency is 2 per second if the period, or time interval, needed to complete one cycle or vibration is 1/2 second; it is 100 per hour if the duration is 1/100 of an hour. In most cases, the frequency is equal to the period, or time interval, reciprocally, therefore frequency = 1/period = 1. (time interval)

frequency = 2.40hz

2.40 dribble is finished in one second

1 dribble takes 0.60 seconds to complete.

10 dribbles are finished in 1*10/2.40 = 4.17 seconds.

She completes 10 dribbles in 4.17 seconds since the frequency is 2.40 hertz.

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The horizontal component of force in the flanged join and the indicator of whether the joint is in the tension of compression are

This is further explained below.

Generally,

[tex]A_1 Y_1=A_2 V_2 \\\\ A_1=\frac{\pi}{4}(0.30)^2, A_2=\frac{\pi}{4}(0.15)^2, \quad V_1=1.5 \mathrm{~m} / \mathrm{s}\end{gathered}\\ \\$eqn $A_1 V_1 &=A_2 V_2 \\\\ \frac{\pi}{4}(0.30)^2 \times(1.5) &=\frac{\pi}{4}(0.15)^2 V_2 \\\\\frac{\pi}{4}(0.09) \times(1.5) &=\frac{\pi}{4}(0.0225) V_2 \\[/tex]

0.07 *1.5 =0.01767 V_2

0.106 =0.01767 V_2

V_2 =0.10610 .01767

[tex]V_2=5.998 \approx 6m/s[/tex]

By moment Equation

[tex]\begin{aligned}&\quad \sum F_x=n^{\circ}\left(V_2 x-V_1 x\right] \\\\&P_x+P_1 A_1=\left(P_1 A_1 V_1\right)\left[V_2 \cos 30^{\circ}-V_1\right] \\\\&P=15 \mathrm{k} \quad 1000 \mathrm{~kg} / \mathrm{m}^3, V_1=10^3, A_1=\frac{\pi}{4}(0.30)^2, V_1=1.5 \mathrm{~m} / \mathrm{s} / \mathrm{s}\end{aligned}[/tex]

[tex]P=100kg/m^3 , V_2=6m/s[/tex]

[tex]\begin{aligned}R_x+P_1 A_1=\left(P A_1 V_1\right)\left[V_2 \cos 30^{\circ}-V_1\right] \\\\R_x+\left(15 \times 10^3\right)\left(\frac{\pi}{4}(0.30)^2\right) &=\left(1000 \times \frac{\pi}{4}(0.30)^2 \times 1.5\right)(6 \cos 30-1.5) \\\\R_x+\left(15 \times 10^3\right)(0.07) &=(1000 \times 0.106)(5.196-1.5) \\\\R_x+1050 \quad &=(106)(3.696) \\\\R_x &=391.776-1050 \\\\R_x &=-658.224\end{aligned}[/tex]

In conclusion, Hence the sign is negative, which means the force acts to the left.

Therefore, the force is compression

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CQ is attached below

A magnetic force that is given by acts on a wire when a current I passes through it while it is in a consistent magnetic field (B).  F = B I L  where L is the conductor's length.

For thousands of years, people have been aware of magnets and magnetism. The earliest records are from Asia Minor, specifically from a place called Magnesia, which is where words like magnet first appeared.

Ancient people were intrigued by the magnetic rocks that were discovered in Magnesia, which is today a region of western Turkey. When people first discovered magnetic rocks, it's possible that they noticed that some of these rocks were more magnetically drawn to iron or other magnetic rocks than other portions.

The poles of a magnet are these regions. A magnet's magnetic pole is the area that attracts other magnets or magnetic materials, such iron, with the greatest force.

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Answer:

See below

Explanation:

If you draw the vectors, you will see the 40 N 's cancel out

 and you are left with 20 N at 270   and 50 N at 60   (see diagram)

    find R...   then the 'balancing'  R  will be of same magnitude in opposite (+180 degrees) direction

x component of 50 N       50 cos 60 = 25 N

y component of 50 N        50 sin 60 = 43.3 N

So now you have    25 N in x direction    and   (43.3 -20) = 23.3 N at 90 deg

R   Magnitude = sqrt(  25^2 + 23.3^2 ) = 34.2 N

R angle = arctan ( 23.3/25) = ~43 degrees

So balancing force would be   34.2 N  at  (43+180) = 223 degrees

Answer:

Range of values: [9.97, 10.13] or 0.16 ml

Percentage uncertainty = 0.0.796%

Explanation:

Since there is an uncertainty of ±0.08 ml, the minimum is
10.05 - 0.08 = 9.97

Maximum with uncertainty = 10.05 + 0.08 = 10.13

So the min, max range is [9.97, 10.13] which is a spread of 0.16

Uncertainty as a percentage

= (0.08/10.05) x 100

= 0.0.796%

Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m