hmmm I dunno sorry ......
Find the curvature k(t) of the curve r(t) = (-2 sin t)i + (-2 sin t)j + (-1 cost)k = 2sqrt2/(sqrt(8cost^2t+sin^2t)^(3/2))
The curvature k(t) of the Eequation r(t) = (-2sint) i + (-2sint) j + (-cost) k will be [tex]\frac{2\sqrt{2} }{(8cos^2t + sin^2t)^{3/2}}[/tex]
Given r(t) = (-2sint) i + (-2sint) j + (-cost) k
We can clearly see that r(t) is a vector equation of t.
If r(t): R→R³ is a vector-valued function of a real variable with independent scalar output variables x, y & z
where, r(t) = {x, y, z}
Where x = (-2sint) , y = -2sint and z = -cost
We know that the curvature to be
|| r'(t) X r"(t) || / ||r'(t)||³
This implies we need to find the determinant of the cross product of the derivative and double derivative of the equation r(t) for the numerator
r'(t) = (-2cost) i + (-2cost) j + (sint) k
r"(t) = (2sint) i + (2sint) j + (cost) k
hence we get || r'(t) X r"(t) || to be
[tex]\left|\begin{array}{ccc}i&j&k\\-2cost&-2cost&sint\\2sint&2sint&cost\end{array}\right|[/tex]
[tex]= \left|\begin{array}{ccc}-2cost&sint\\2sint&cost\end{array}\right| i - \left|\begin{array}{ccc}-2cost&sint\\2sint&cost\end{array}\right|j + \left|\begin{array}{ccc}-2cost&-2cost\\2sint&2sint\end{array}\right|k[/tex]
= -2i + 2j
Hence the magnitude will be
√(2² + 2²)
= 2√2 units
magnitude of r'(t) is
[tex]\sqrt{(2sint)^2 + (2sint)^2 + (cost)^2}[/tex]
= [tex]\sqrt{8cos^2t + sin^2t}[/tex]
Hence we get the curvature to be
[tex]\frac{2\sqrt{2} }{(\sqrt{8cos^2t + sin^2t})^3}[/tex]
simplifying this will give us
[tex]\frac{2\sqrt{2} }{(8cos^2t + sin^2t)^{3/2}}[/tex]
Hence the curvature k(t) will be [tex]\frac{2\sqrt{2} }{(8cos^2t + sin^2t)^{3/2}}[/tex]
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Correct Question
Find the curvature k(t) of the curve r(t) = (-2 sin t)i + (-2 sin t)j + (-1 cost)k
!PLEASE ANSWER ASAP! VERY IMPORTANT! THANK YOU!!
An experiment compares weight of fish for two different brands fish food. Nacho Average Minos
fish food has a mean fish weight 10 lbs. and a standard deviation of 1.5 lbs. Impossible Minos fish
food has a mean fish weight of 12 lbs. and a standard deviation of 1 lb. A fish is measured to be
11.25 lbs. Which brand of fish food, Nacho Average Minos or Impossible Minos, is more likely to have
been used to feed this fish?
Answer:
Nacho Average Minos
Step-by-step explanation:
z=11.25-10/1.5 = 1.25/1.5 = 0.834
z=11.25-12/1 = -0.75/1 = -0.75
if u know what to do pls help
Answer:
6.2 miles
Step-by-step explanation:
10 kilometers=.62 miles
.62*10= 6.2 miles
What is the product of (3y^-4)(2y^-4)?
Answer:
6/ y^8
Step-by-step explanation:
Which of the following polynomials is reducible over Q 4x3³ + x - 2 5x³ + 9x² - 3 This option 3x³ - 6x² + x - 2 This option 08 O This option None of choices This option Activ 74°F Sun
None of the options are reducible polynomial
How to determine the reducible polynomialFrom the question, we have the following parameters that can be used in our computation:
The list of options
The variable Q means rational numbers
So, we can use the rational root theorem to test the options
So, we have
(a) 4x³ + x - 2
Roots = ±(1, 2/1, 2, 4)
Roots = ±(1, 1/4, 2, 1, 1/2)
(b) 3x³ - 6x² + x - 2
Roots = ±(1, 2/1 ,3)
Roots = ±(1, 1/3, 2, 2/3)
(c) 5x³ + 9x² - 3
Roots = ±(1, 3/1 ,5)
Roots = ±(1, 1/5, 3, 3/5)
See that all the roots have rational numbers
And we cannot determine the actual roots of the polynomial.
Hence, none of the options are reducible polynomial
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The graph shows the height(t) of a model rocket t seconds after it is launched from the ground at 48 feet per second. Where is the height of the rocket increasing? Where is it decreasing?
A. The height of the rocket is always decreasing
B. The height of the rocket is always increasing
C. The height of the rocket is increasing when 0< t < 3 and decreasing when 3 < t < 6.
D. The height of the rocket is increasing when 3 < t< 6 and decreasing when 0 < t < 3
The height of the rocket is increasing when 0< t < 3 and decreasing when 3 < t < 6.
Option C is correct.
Increasing function:From the graph,
It is observed that , In interval 0< t < 3 , slope of graph is positive. Therefore, the height of the rocket is increasing
It is observed that , In interval 3 < t< 6 , slope of graph is negative. Therefore, the height of the rocket is decreasing.
Therefore, option C is correct.
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does anyone here know how to write negative 1 on there
Answer:
you fo to the fourth box on there and put - then go to the box after that and put 1
Step-by-step explanation:
sorry if im wrong
2 The table below shows the cost, s, to purchase p pounds of steak at a
local grocery store.
Cost of Steak
Number of
Pounds (p)
2.5
3.0
$23.98
$28.77
$33.57
$38.36
3.5
4.0
Which statement is true about the relationship shown in the table?
A The relationship is proportional, and the equation that represents this
relationship is s = 9.59 + p.
B. The relationship is proportional, and the equation that represents this
relationship is s = 9.59 + P.
The relationship is proportional, and the equation that represents this
relationship is s = 9.59p.
The relationship is not proportional.
Answer:
OMg whats there ikdd im tring
Step-by-step explanation: Im starting to solve it
interference is a property of a. light waves. b. sound waves. c. water waves. d. all of these e. none of these
Interference is a property of ALL the given wave options, which are light waves, sound waves, and water waves.
Interference is the phenomenon of two or more waves combining to form a resultant wave of greater, lower, or the same amplitude.
When two waves meet at the same point at the same time, they either combine constructively (resulting in the formation of a wave of greater amplitude) or destructively (resulting in the formation of a wave of lower amplitude).
For instance, when two sound waves or light waves meet, they create a resultant wave whose amplitude is equal to the sum of the two original waves.
This is known as constructive interference.
On the other hand, when two waves meet and their amplitudes are in opposite directions, they produce a resultant wave whose amplitude is equal to the difference between the two waves.
This is known as destructive interference.
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Sam is practising free-throws in basketball. She has a 4/5 chance of scoring each time she shoots from the free-throw line. (You should assume that the probability of scoring for each shot is independent of the result of other attempts.) What is the expected value of the number of free-throws that Sam will score before her first miss? 4/25 What is the variance of the number of free-throws that Sam will score before her first miss?
Sam has a 4/5 expected value of scoring each time she shoots from the free-throw line.
How is this so?
This means that the probability of her missing her first shot is 1/5. The expected value of the number of free-throws that Sam will score before her first miss is therefore 1/(1/5) = 5.
The variance of the number of free-throws that Sam will score before her first miss is (1−p)/p²
, where p is the probability of success.
In this case, p=4/5, so the variance is (1−4/5)/(4/5)²
=16/25.
= 4/5
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What is the numerical coefficient in y=−6x−3
The mean diastolic blood pressure of 144 individuals is 61 mmHg with a standard deviation of 10 mmHg Construct a 95% confidence interval for p. Select one: O a. (61.25, 62.63) O b. (-59.37, 60.59) O c. (59.37, 62.63) O d. (143.85, 145.56) O e. (-143.85, 145.56) Determine the success rate of the student from the following course list Course Score of student Standard Mean, deviation, Physics Mathematics 60 58 55 49 11 16 Select one: a. PHYS>MATH O b. PHYS=MATH = O c. NONE C. O d. MATH>PHYS
The the success rate of the student is PHYS>MATH. Therefore, the correct answer is Option A.
We can calculate the success rate of the student by calculating the z-score of each of the courses. The z-score is calculated as (x-μ)/σ, where x is the individual score, μ is the mean of the data, and σ is the standard deviation of the data.
For Physics, we have x=60, μ=49, and σ=11. So the z-score is (60-49)/11=1.09.
For Mathematics, we have x=58, μ=55, and σ=16. So the z-score is (58-55)/16=0.19.
Since the z-score of Physics is greater than the z-score of Mathematics, the student's success rate in Physics is greater than the student's success rate in Mathematics.
Therefore, the correct answer is Option A.
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A catering business purchased a light truck on April 5, 2019 to deliver breakfast
restaurants. The business paid $27,000 for the truck
Determine the total depreciation amount for 2020 assuming the taxpayer opted out of Sec. 179 and bos (if alable) in the your of pe In addition, assume all taxpayers use a calendar year tax period and that the property memmoned was the only property purchased a bey of acquisition. Use the appropriate depreciation table from your note sheet textbook where nocevary
OL None of the answers given here.
O $5,400
$8,640
OV $6,612
OV. $8,100
Using the appropriate depreciation table, MACRS 5 years, the total depreciation amount for 2020, assuming the taxpayer opted out of Sec. 179 in the year of purchase and other assumption, is B) $8,640.
What is depreciation?Depreciation refers to the gradual expensing of a long-term asset.
Under the MACRS 5 years for a light equipment, the depreciation rate applicable to the second year is 32%.
The cost of the truck = $27,000
Purchase date = April 5, 2019
Depreciation rate = MACRS 5 years
Depreciation rate for the second year under the MACRS 5 years table = 32%
Depreciation amount for 2020 = $8,640 ($27,000 x 32%)
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1. What number is 20% of 40?
Answer:
8
Step-by-step explanation:
0.20 x 40 = 8
Therefore, 20% of 40 is 8
Vincent paints 75% of his statues. He paints 60 statues. How many statues does Vincent have in total?
Answer:
80
Step-by-step explanation:
Let the total number of statues be s. Then 0.75s = 60, and s = (4/3)(60 statues) = 80
He has 80 statues total.
the path of a projectile launched from a 16-ft-tall tower is modeled by the equation y = −16t2 64t 16. which is the correct graph of the equation?
The graph is a downward-opening parabola opening downward with its vertex at (2,0). Therefore, the correct option is C.
The equation y = -16t^2 + 64t + 16 represents the path of a projectile launched from a 16-ft-tall tower. To determine the correct graph, we can analyze the equation. The coefficient of t^2 (-16) is negative, indicating a downward-opening parabola. The coefficient of t (64) determines the horizontal shift of the graph, and in this case, t = 4 represents the maximum height of the projectile. The constant term (16) represents the initial height of the tower.
Considering these factors, we find that the correct graph of the equation is option C. It depicts a downward-opening parabola with its vertex at (2,0). The parabola starts at an initial height of 16 ft (the tower's height) and descends symmetrically from its vertex.
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please help me with this one!!
Answer:
V = 960 cm^3
Step-by-step explanation:
Volume of a rectangular prism = L * W * H
V = 12 * 8 * 10
V = 960 cm^3
Answer:
d. 960 cm^3
Step-by-step explanation:
The formula for volume is length x width x height. To solve you have to multiply 12 by 8 by 10 to get 960
Five countries enter a race. The first three racers in order, Jamaica finished before Barbados, but behind Trinidad. Haiti finished before Guyana, but behind Barbados. Who won the Bronze (finished in 3rd place)?
Answer:
Barbados won the Bronze.
Step-by-step explanation:
The information indicates that Jamaica finished before Barbados, but behind Trinidad which means that Trinidad was the first one, then Jamaica and the third one was Barbados:
1. Trinidad
2. Jamaica
3. Barbados
Then, it indicates that Haiti finished before Guyana, but behind Barbados which indicates that Haiti was in 4th place after Barbados and the last one was Guyana:
1. Trinidad
2. Jamaica
3. Barbados
4. Haiti
5.Guyana
According to this, the answer is that Barbados won the Bronze.
Adan took a test at school and completed it in an hour and a half. The test had two sections. If he took 45 minutes to complete the first Section, how much time did he use to finish the second section?
Answer:
45 minutes
Step-by-step explanation:
1 1/2 hours = 90 minutes
90 - 45 = 45
In a survey of 100 men and 120 women, it was found that 40 of the men had group A blood. If sex and blood type are assumed to be independent variables, what is the expected number of women in the survey who have group A blood?
The expected number of women in the survey who have group A blood is 48.
To calculate the expected number, we assume that sex and blood type are independent variables. This means that the proportion of women with group A blood would be the same as the proportion of men with group A blood.
Out of 100 men surveyed, 40 had group A blood. This corresponds to a proportion of 40/100 = 0.4.
Since sex and blood type are assumed to be independent, we can assume that the proportion of women with group A blood is also 0.4.
To find the expected number of women with group A blood, we multiply the proportion by the total number of women surveyed:
Expected number of women with group A blood = Proportion of women with group A blood * Total number of women surveyed
Expected number of women with group A blood = 0.4 * 120 = 48
Therefore, the expected number of women in the survey who have group A blood is 48.
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two positive numbers x and y with maximum value 4 add up to 5. what is the difference between the maximum and minimum value of the product x^2y^3
The difference between the maximum and minimum value of x^2y^3 is determined by finding the product at the extreme values.
Given that two positive numbers x and y with a maximum value of 4 add up to 5, we can solve for the minimum value of x and y. Since the maximum value for x and y is 4, we assume that one number is 4 and the other number is 1, as they add up to 5.
Calculating the product x^2y^3 for these values, we have (4^2)(1^3) = 16. To find the maximum value of x and y, we need to distribute the sum of 5 unevenly between them. By assigning x = 1 and y = 4, we get (1^2)(4^3) = 64.
Therefore, the difference between the maximum and minimum value of x^2y^3 is 64 - 16 = 48.
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due soon! Please help :)
Answer:
Dining Hall = 24 square meters
Kitchen = 48 square meters
Together = 72 square meters
Actual sales for January through April are shown below.
Month Actual Sales (Yt)
January 18
February 25
March 34
April 40
May -
Use exponential smoothing with α = .3 to calculate smoothed values and forecast sales for May from the above data. Assume the forecast for the initial period (January) is 18. Show all the forecasts from February through April along with the answer.
The forecasted sales for February through April are as follows:
February: 19.5, March: 25.65, April: 30.755. The forecasted sales for May is approximately 35.928.
Exponential smoothing is a time series forecasting method that assigns weights to past observations, with the weights decreasing exponentially as the observations get older. The smoothed value for a particular period is a weighted average of the previous smoothed value and the actual value for that period.
To calculate the smoothed values and forecast sales using exponential smoothing with α = 0.3, we start with the initial forecast for January, which is given as 18. Then, for February, we use the formula:
Smoothed value (February) = α * Actual sales (February) + (1 - α) * Smoothed value (January)
= 0.3 * 25 + 0.7 * 18 = 19.5
Similarly, for March:
Smoothed value (March) = α * Actual sales (March) + (1 - α) * Smoothed value (February)
= 0.3 * 34 + 0.7 * 19.5 = 25.65
And for April:
Smoothed value (April) = α * Actual sales (April) + (1 - α) * Smoothed value (March)
= 0.3 * 40 + 0.7 * 25.65 = 30.755
Finally, for the forecasted sales in May:
Forecasted sales (May) = Smoothed value (April) = 30.755
Therefore, the forecasted sales for May, using exponential smoothing with α = 0.3, is approximately 35.928.
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(- x * y) ^ 2 - 8x ^ - 7 * y ^ - 2
I need help fast!!!
What is the answer??
Answer:
answer is \/
Step-by-step explanation:
If Lucy instead invested her $20,000 in an account with 5% simple interest,
how much would she end up with after 10 years?
Answer:
The 2009 Nobel Peace Prize was awarded to United States President Barack Obama for his "extraordinary efforts to strengthen international diplomacy and cooperation between people".
Step-by-step explanation:
The 2009 Nobel Peace Prize was awarded to United States President Barack Obama for his "extraordinary efforts to strengthen international diplomacy and cooperation between people".
According to a recent survey, the probability that the driver in a fatal vehicle accident is female (event F) is 0.2868. The probability that the driver is 24 years old or less (event A) is 0.1828. The probability that the driver is female and is 24 years old or less is 0.0576.
(a) Find the probability of FUA
(b) Find the probability of F'UA.
a. Using intersection of events probability of FUA is 0.0165
b. Using complement rule, the probability of F'UA is 0.9835
What is the probability of FUA?To find the probabilities, we can use the given information and apply the appropriate probability rules.
(a) FUA represents the event that the driver is female, 24 years old or less, and is involved in a fatal vehicle accident.
We can calculate this probability using the formula: P(FUA) = P(F ∩ A), where ∩ denotes the intersection of events.
P(FUA) = P(F) * P(A|F)
Given information:
P(F) = 0.2868 (probability that the driver is female)
P(A) = 0.1828 (probability that the driver is 24 years old or less)
P(A|F) = 0.0576 (probability that the driver is 24 years old or less given that the driver is female)
P(FUA) = 0.2868 * 0.0576 ≈ 0.0165
Therefore, the probability of FUA is approximately 0.0165.
(b) F'UA represents the event that the driver is not female, 24 years old or less, and is involved in a fatal vehicle accident.
We can calculate this probability using the complement rule: P(F'UA) = 1 - P(FUA).
P(F'UA) = 1 - P(FUA) ≈ 1 - 0.0165 ≈ 0.9835
Therefore, the probability of F'UA is approximately 0.9835.
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i'm really stuck on this part. once i figure out how i'll mark brainliest (however you spell it).
just the first one 11 ........
please helpppp to find the answer would really appreciate it !
Answer:
the answer is in the attachment
Social Networking sites A recent survey of 10 social networking sites has a mean of 12.67 million visitors for a specific month. The standard deviation was 4 million. Find the 99% confidence interval of the true mean. Assume the variable is normally distributed. Round your answers to at least two decimal places.
______million <μ< _____million
The 99% confidence interval of the true mean is given as follows:
8.56 million < μ < 16.78 million.
What is a t-distribution confidence interval?
The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the equation presented as follows:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
The variables of the equation are listed as follows:
[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.The critical value, using a t-distribution calculator, for a two-tailed 99% confidence interval, with 10 - 1 = 9 df, is t = 3.2498.
The parameter values for this problem are given as follows:
[tex]\overline{x} = 12.67, s = 4, n = 10[/tex]
The lower bound of the interval is then given as follows:
[tex]12.67 - 3.2498 \times \frac{4}{\sqrt{10}} = 8.56[/tex]
The upper bound of the interval is then given as follows:
[tex]12.67 + 3.2498 \times \frac{4}{\sqrt{10}} = 16.78[/tex]
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If the point (x,y) is in Quadrant IV, which of the following must be true?
x<0 and y>0
x>0 and y<0
The statement x > 0 and y < 0 must be true for any point (x, y) located in Quadrant IV.
If the point (x, y) is in Quadrant IV, it means that the x-coordinate is positive and the y-coordinate is negative. In Quadrant IV, the x-values are positive, as they are to the right of the y-axis, and the y-values are negative, as they are below the x-axis.
Therefore, the correct statement is:
x > 0 and y < 0.
In Quadrant IV, the x-values are greater than 0, indicating a positive x-coordinate, and the y-values are less than 0, indicating a negative y-coordinate. This is because in Quadrant IV, the x-axis is to the right of the y-axis, and the y-axis is below the x-axis.
Hence, the statement x > 0 and y < 0 must be true for any point (x, y) located in Quadrant IV.
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