this circle has a diameter of 5 inches which of these measurements is closest to the circumference of the circle 15.7 7.85 31.4 19.625

Answer:

The desired data-set is: {12,12,12,12,12,12,12}

Step-by-step explanation:

n = 7

Data set of 7 elements.

x = 12

Mean of 12

S = 0

Standard deviation of 0.

Desired data-set:

Since the desired standard deviation is 0, all the elements in the data-set will be the same. Since the mean is 12, all elements is 12. 7 elements.

The desired data-set is: {12,12,12,12,12,12,12}

Answer:

Step-by-step explanation:

Hope this helps u!!

Answer:

18.28 m

Step-by-step explanation:

Given the flower garden in the question :

The shape is composite and can be divided into 2 semicirles and rectangle

The perimeter of a semicircle is the Circumference of the semicircle = πr

Hence, 2 semicirles = 2πr

Radius of semicircle = 2/2 = 1

Perimeter = 2 * 3.14 * 1² = 2 * 3.14 * 1 = 6.28 m

The perimeter of rectangle; length and width are 6m and 2 m respectively :

Perimeter of rectangle = 2(l + w) = 2(4+2) = 2(6) = 12m

Tve perimeter of garden = 6.28 + 12 = 18.28 m

Answer:

does not have a solution because √-0.75 ≠ R

Step-by-step explanation:

x^2 - 5x + (5/2)^2 = -7

x^2 - 5x + 6.25 = -7 + 6.25

(x - 2.5)^2 = -0.75

(x - 2.5) = √-0.75

does not have a solution because √-0.75 ≠ R

Answer:

x = (1/2)(5 ± i√3)

Step-by-step explanation:

x² - 5x + 7 = 0

subtract 7 from both sides

x² - 5x = -7

Use half the x coefficent, -5/2, as the complete the square term

(x - 5/2)² = -7 + (-5/2)²

(x - 5/2)² = -7 + 25/4

(x - 5/2)² = -3/4

Take the square root of both sides

x - 5/2 = ±(√-3) / 2

x - 5/2 = ±(i√3) / 2

Add 5/2 to both sides

x = 5/2 ± (i√3) / 2

factor out 1/2

x = (1/2)(5 ± i√3)

Answer:

Step-by-step explanation:

a= 2qr^3 quotent 6p^2

Answer:

Assuming normal distribution, the mean number of calls for a n-hour day is of [tex]m = n\mu[/tex], in which [tex]\mu[/tex] is the mean number of calls per hour, and the standard deviation is [tex]s = \sqrt{n}\sigma[/tex], in which [tex]\sigma[/tex] is the standard deviation of the number of calls per hour.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

N-instances of a normal variable:

For n-instances of normal variable, the mean of the distribution is: [tex]m = n\mu[/tex], and the standard deviation is [tex]s = \sqrt{n}\sigma[/tex]

What is the mean and standard deviation of the number of calls it receives for ​n-hour ​day?

Assuming normal distribution, the mean number of calls for a n-hour day is of [tex]m = n\mu[/tex], in which [tex]\mu[/tex] is the mean number of calls per hour, and the standard deviation is [tex]s = \sqrt{n}\sigma[/tex], in which [tex]\sigma[/tex] is the standard deviation of the number of calls per hour.

Answer:

0.75 points per minute

Step-by-step explanation:

9/12 is 0.75

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines :  y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) [tex]\int\limits^2_0 {ph} \, dy[/tex]

     = [tex]( 2\pi ) \int\limits^2_0 {y.y^2} \, dy[/tex]  

∴ Vol = 8π

b) The line y = 2  ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) [tex]\int\limits^2_0 {ph} \, dy[/tex]

     = [tex]( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy[/tex]

     = ( 2π ) * [ 2/3 * y^3  - y^4 / 4 ] ²₀

∴ Vol  = 8/3 π

c) The y-axis  ( using shell method )

h = 2-y  = h = 2 - √x

p = x

vol = [tex](2\pi ) \int\limits^4_0 {ph} \, dx[/tex]

     = [tex](2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx[/tex]

     = ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1    (using shell method )

p = 1 + x

h = 2√x

vol = [tex](2\pi ) \int\limits^4_0 {ph} \, dx[/tex]

Hence   vol = 176/15 π

attached below is the graphical representation of P and h

Answer:

[tex]116^o[/tex]

Step-by-step explanation:

All triangles equal [tex]180^o[/tex]. Therefore, in order to find the value of [tex]x^o[/tex], all you will have to do is subtract [tex]64^o[/tex] from [tex]180^o[/tex].

[tex]180^o-64^o=116^o[/tex]

[tex]x^o=116^o[/tex]

Answer:

40 m

Step-by-step explanation:

158 · 2.54 = 401.32

401.32/100 = 40.132

40.132 ≈ 40

Answer:

[tex](4x - 3)(5x - 8) = 20x^2 -47x + 24[/tex]

Step-by-step explanation:

Given

[tex](4x - 3)(5x - 8)[/tex]

Required

Identify and correct error

The error is when the inner and outer terms are multiplied. i.e.

[tex]4x * -8 = -32x[/tex] not 32x

[tex]-3 * 5x = -15x[/tex] not 15x

So, the expression is:

[tex](4x - 3)(5x - 8) = 20x^2 - 32x -15x + 24[/tex]

[tex](4x - 3)(5x - 8) = 20x^2 -47x + 24[/tex]

Answer:

x< 4/7

Step-by-step explanation:

See image below:)

Answer:

I'll setup the problem and you can compute the answer

Step-by-step explanation:

The formula for simple:

I = P*r*t

I = interest

P = loan amount

r = interest rate per period (period = days)

n = number of periods

P = 10,170

r = .0764/365

t = 272

Answer:

5 hour and 25 mins

Step-by-step explanation:

Answer:

d=23.43

Step-by-step explanation:

Given data

A(-6,8)

X1=-6

Y1=8

B(12, - 7)

X2=12

Y2=-7

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²

Substitute

d=√((12+6)²+(-7-8)²

d=√((18)²+(-15)²

d=√324+225

d=√549

d=23.43

I.)

1.) 7N = 50

2.) 35 - 16 = N

3.) 2P + 8 = 24

4.) R/5 = 9

5.) 30 - 10 = 20

II.)

1.) Twinity increased by eight times N

2.) D decreased by eleven

3.) The quotient of X and nine is K

4.) Five times X

5.) Three times a decreased by 5 is thirteen

6.) Nothing

7N = 50

35 - 16 = N

2P + 8 = 24

R/5 = 9

30 - 10 = 20

Twenty increased by eight times N

D decreased by eleven

The quotient of X and nine is K

Five times X

Three times a decreased by 5 is thirteen

Answer:

The answer is below

Step-by-step explanation:

Similar triangle are triangles with the same shape, equal pair of corresponding angles. Also they have the same ratio of the corresponding sides.

From the diagram attached, we can see that triangle ABC and triangle CEF are similar triangles. Hence:

AB/BC = CF/EF

Given that BC = 1 km = 1000 m, CF = 2 m - 1.5 m = 0.5 m, EF = 2.5 m.

Hence:

AB/1000 = 0.5/2.5

AB = (0.5/2.5) * 1000 = 200 m

The height of the building = AB + height of Steve = 200 m + 2 m

The height of the building = 202 m

Answer:

Terry has 1500 sweets.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the number of sweets Terry has.

y is the number of sweets Alex has.

If Terry gives 30% of his sweets to Alex,they will have the same number of sweets.

This means that:

[tex](1 - 0.3)x = y + 0.3x[/tex]

[tex]0.7x = y + 0.3x[/tex]

[tex]y = 0.4x[/tex]

If Terry gives 750 of his sweets to Alex,then Alex will have 80% more sweets than Terry.

This means that:

[tex]y + 750 = 1.8(x-750)[/tex]

We want to find x, and since [tex]y = 0.4x[/tex]

[tex]y + 750 = 1.8x - 1350[/tex]

[tex]0.4x + 750 = 1.8x - 1350[/tex]

[tex]1.4x = 2100[/tex]

[tex]x = \frac{2100}{1.4}[/tex]

[tex]x = 1500[/tex]

Terry has 1500 sweets.

It was some mistake in previous one so i edited this one.

Answer:

[tex]95 - \frac{3}{4} [/tex]

[tex] = \frac{95}{1} - \frac{3}{4} [/tex]

[tex] = \frac{380}{4} - \frac{3}{4} [/tex]

[tex] = \frac{380 - 3}{4} [/tex]

[tex] = \frac{377}{4} [/tex]

[tex] = 376\frac{1}{4} [/tex]

Answer:

Approximately 46.29 feet

Step-by-step explanation:

I assume you meant to say "a differentiable function f has the values ..." and not g.

Since f is differentiable, the mean value theorem holds, so you can approximate

f ' (2.5) ≈ (f (2.6) - f (2.4)) / (2.6 - 2.4) = (24 - 18) / (0.2) = 30

Answer:

2

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\frac{-2}{3}*\frac{3}{5}+\frac{5}{2}-\frac{3}{5}*\frac{1}{6}=\frac{-2}{5}+\frac{5}{2}-\frac{1}{5*2}\\\\= \frac{-2}{5}+\frac{5}{2}-\frac{1}{10}\\\\=\frac{-2*2}{5*2}+\frac{5*5}{2*5}-\frac{1}{10}\\\\=\frac{-4}{10}+\frac{25}{10}-\frac{1}{10}\\\\=\frac{-4+25-1}{10}\\\\=\frac{20}{10}\\\\= 2[/tex]

I assume that the equation you mean is below:

[tex] \large \boxed{w + \frac{ {w}^{2} }{3} = 0}[/tex]

To find roots for this equation, we have to get rid of the denominator. We can do by multiplying both sides by 3.

[tex] \large{w(3) + \frac{ {w}^{2} }{3} (3) = 0(3)} \\ \large{3w + {w}^{2} = 0}[/tex]

Factor w-term out (common factor)

[tex] \large{w(3 + w) = 0} \\ \large{w = 0 \: \: \: or \: \: \: 3 + w = 0} \\ \large{w = 0, - 3}[/tex]

Answer