There are 350 students graduating on Sunday. 84% of the students are graduating with Bachelor’s degree in Business. How many students are getting their Bachelor's degree in Business?

Step-by-step explanation:

i think this is the answer if it's wrong I'm sorry

Answer:

ture

Step-by-step explanation:

Let

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots[/tex]

Differentiating twice gives

[tex]\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots[/tex]

[tex]\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n[/tex]

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0[/tex]

Then the coefficients in the power series solution are governed by the recurrence relation,

[tex]\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}[/tex]

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

[tex]k=0 \implies n=0 \implies a_0 = a_0[/tex]

[tex]k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}[/tex]

[tex]k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}[/tex]

[tex]k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}[/tex]

It should be easy enough to see that

[tex]a_{n=2k} = \dfrac{a_0}{(2k)!}[/tex]

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

[tex]k = 0 \implies n=1 \implies a_1 = a_1[/tex]

[tex]k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}[/tex]

[tex]k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}[/tex]

[tex]k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}[/tex]

so that

[tex]a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}[/tex]

So, the overall series solution is

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)[/tex]

[tex]\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}[/tex]

Answer:

8000

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The given line has a rise of 1 for each run of 1, so a slope of 1. If you draw a line with a slope of 1 through the given point, you can see that it intersects the  y-axis at y = -1. Then the slope-intercept equation is ...

  y = x -1 . . . . . equation of parallel line

__

The perpendicular line will have a slope that is the opposite reciprocal of the slope of the given line: m = -1/1 = -1

A point that is 1 unit right and 1 unit down from the given point is -3 on the y-axis. This is the y-intercept of the perpendicular line. The equation is ...

  y = -x -3 . . . . . equation of perpendicular line

9514 1404 393

Answer:

parallel: y = x -1

perpendicular: y = -x -3

Step-by-step explanation:

The given line has a rise of 1 for each run of 1, so a slope of 1. If you draw a line with a slope of 1 through the given point, you can see that it intersects the y-axis at y = -1. Then the slope-intercept equation is ...

 y = x -1 . . . . . equation of parallel line

__

The perpendicular line will have a slope that is the opposite reciprocal of the slope of the given line: m = -1/1 = -1

A point that is 1 unit right and 1 unit down from the given point is -3 on the y-axis. This is the y-intercept of the perpendicular line. The equation is ...

 y = -x -3 . . . . . equation of perpendicular line

Answer:

I dont know sry

Answer:

A p (x) = x3_ 7x2 _ 2x_ 40

B p (x) = x3 + 7x2 _ 2x_ 40

C p (x) =x3 _ 7x2 + 2x + 40

D p(x) = x3 +7x2 _ 2x + 40

Outliers are data elements that are far from the other elements of a dataset, and they have little or no effect on the median and the mode

Outliers are usually large or very low values, and they always affect the mean of the dataset.

Also, they affect the range of the dataset.

The standard deviation is dependent on the mean of the dataset.

This means that, outliers would also have effects on the standard deviation.

However, outliers are most likely not to have a considerable effect on the median and the mode of the dataset.

Hence, the true options are mode and median

Read more about outliers at:

https://brainly.com/question/23461655

1. [tex] \frac{5}{12} = \frac{35}{n} \\ 5n = 35 \times 12 \\ 5n = 420 \\ n = \frac{420}{5} \\ n = 84[/tex]

2. [tex] \frac{n}{52} = \frac{180}{120} \\ 120n = 180 \times 52 \\ 120n = 9360 \\ n = \frac{9360}{120} \\ n = 78[/tex]

Answer:

(saving my answer for the question)

what is the problem?

Step-by-step explanation:

Answer:

New price = $48

Step-by-step explanation:

New price = Original price - (original price × 20%)

New price = $60 - ($60 × .20)

New price = $60 - $12

New price = $48

Or If the jacket is 20%, you will pay 80% of the cost.

So Original price × the percentage that you paid = New price

                     $60 × 80% = New price

                      $60 × .80 =  $48

Answer:

c that is the answer yes .

Answer:

Step-by-step explanation:

c       i took the k121 online quiz in progress learning

A) Andrea will need to borrow $34,000 to buy the Camaro

B) Andrea will need to type =(34000x1.03 ^ 5) / 60 in Excel to figure her monthly payment, which will be $656,92.

C) The total of all of Andrea’s payments be over the lifetime of the car loan will be $39.415,31

D) Andrea will pay $5415.31 in interest over the lifetime of the car loan

Since Andrea's car has broken down for the third time this month, and she has decided to buy a different car, and her dream car, a 2016 Chevrolet Camaro, costs $ 38,000, and she has a $ 4,000 down payment saved, and the bank is offering 3.00% APR on 60 month loans for new cars, to determine A) how much will Andrea need to borrow to buy the Camaro; B) what would Andrea need to type in Excel to figure her monthly payment from her, and what will her her monthly payment be from her; C) what will the total of all of Andrea’s payments be over the lifetime of the car loan; and D) how much will Andrea pay in interest over the lifetime of the car loan, the following calculations must be performed:

Learn more in https://brainly.com/question/14295570

Answer:

u gotta answer

Step-by-step explanation:

choose a random question and answer it :)

Answer:

it is D

Step-by-step explanation:

I have to show you, but if I do it don't on the paper

Answer:

5.25m

Step-by-step explanation:

32 papers will make in 1 minute

(168 copies/32copies)×1min = 5.25m

Answer:

2/5m - 1/5

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Quadrants are 1 to 4 going counter clockwise, when you plot those points they are in the lower left which is quadrant 3.

Step-by-step explanation:

Given that :

Total length of the track = 630 m

Distance covered by Sweeti by walking = 2/7 of the running track

2/7 of 630 m

⇛ (2/7)×630

⇛ (2×630)/7

⇛ 1260/7

⇛ 180 m

Distance covered by walking = 180 m

Remaining distance =

Total distance - Distance covered by walking

⇛630 m - 180 m

⇛ 450 m

The total distance covered by running by Sweeti is 450 m.

Read more:

Similar Question

You can burn about 450 calories if you run 5 miles. How many miles will you need to run to burn 630 calories? Justify your reasoning.....

https://brainly.com/question/20123561?referrer

Answer:

The answer is -1008, it's in the comments

Answer:

for me the picture is blurry sorry

Step-by-step explanation:

Answer:

-23

Step-by-step explanation:

Answer:

3/151

Step-by-step explanation:

That's the answer

a = amount invested at 7%

b = amount invested at 8%

we know that total that he invested was 10000, therefore a + b = 10000.

hmmm how muich is 7% of "a"? well (7/100) * a => 0.07a.

how much is 8% of "b"? well (8/100) * b => 0.08b.

After a year he received in interest $730, so we know that at simple interest rate, 0.07a + 0.08b = 730.

[tex]\begin{cases} a+b=10000\\ 0.07a+0.08b=730\\[-0.5em] \hrulefill\\ b = 10000 - a \end{cases}\qquad \stackrel{\textit{substituting on the 2nd equation}}{0.07a+0.08(10000-a) = 730} \\\\\\ 0.07a+800-0.08a=730\implies 0.07a-0.08a=-70\implies -0.01a=-70 \\\\\\ a=\cfrac{-70}{-0.01}\implies \boxed{a = 7000} ~\hfill \stackrel{\textit{we know that}}{b = 10000 -a}\implies \boxed{b = 3000}[/tex]

m-18

If z = (6x + 2y)⁹, then the partial derivatives of z are

• with respect to x :

∂z/∂x = 9 (6x + 2y)⁹⁻¹ • ∂(6x + 2y)/∂x

∂z/∂x = 9 (6x + 2y)⁸ • 6

∂z/∂x = 54 (6x + 2y)⁸

• with respect to y :

∂z/∂y = 9 (6x + 2y)⁹⁻¹ • ∂(6x + 2y)/∂y

∂z/∂y = 9 (6x + 2y)⁸ • 2

∂z/∂y = 18 (6x + 2y)⁸

Answer:

Collect terms in x on the left side  

subtract  

b

x

from both sides

a

x

−

b

x

=

−

c

take out a  

common factor  

x

x

(

a

−

b

)

=

−

c

divide both sides by  

a

−

b

x

=

−

c

a

−

b

Step-by-step explanation:

im sorry if its not cleear to explain

Answer:

= [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Result in decimals: 0.66666666666667

x = mutiply

[tex]=\frac{1}{3} x\frac{2}{1}[/tex]

[tex]\frac{1 x 2}{3 x 1 }[/tex]

= [tex]\frac{2}{3}[/tex]

(Hope this helps can I pls have brainlist (crown)☺️)

Answer:

This is 0.8 to the nearest tenth.

Step-by-step explanation:

FYI, to round to the nearest tenth, look at the second number after the decimal point. If it is 5 or more then round the first number after the point up one e.g.. If the answer was 0.850375,you round up which is 0.9 to the nearest 10th.

If the second number after the decimal point is less than 5 (in this case) you round down to 0.8.        (BRAINLIETS PRETTY PLEASEEEE OvO)

Answer:

33.20% probability that the sample mean would differ from the population mean by greater than 1 gallon

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.