the
The shape of a garden is rectangular in the middle and semi circular
at the ends as shown in the diagram. Find the area and the perimeter
Т.
of this garden [Length of rectangle is
7m 20-(3.5 +3.59 metres).
1
DI
20 m​

Answer:

[tex]Area = 129.5m^2[/tex]

[tex]Perimeter = 48m[/tex]

Step-by-step explanation:

Given

See attachment

Required

Determine the area and the perimeter of the garden

Calculating Area

First, we calculate the [tex]area\ of\ the\ rectangle[/tex]

[tex]A_1 = L * B[/tex]

Where:

[tex]L = 20-(3.5 +3.5)[/tex]

[tex]B = 7[/tex]

So:

[tex]A_1 = (20 - (3.5 + 3.5)) * 7[/tex]

[tex]A_1 = (20 - 7) * 7[/tex]

[tex]A_1 = 13 * 7[/tex]

[tex]A_1 = 91[/tex]

Next, we calculate the area of the two semi-circles.

Two semi-circles = One Circle

So:

[tex]A_2 = \pi r^2[/tex]

Where

[tex]r = \frac{7}{2}[/tex]

[tex]A_2 = \frac{22}{7} * (\frac{7}{2})^2[/tex]

[tex]A_2 = \frac{22}{7} * \frac{49}{4}[/tex]

[tex]A_2 = \frac{22}{1} * \frac{7}{4}[/tex]

[tex]A_2 = \frac{22*7}{4}[/tex]

[tex]A_2 = \frac{154}{4}[/tex]

[tex]A_2 = 38.5[/tex]

Area of the garden is

[tex]Area = A_1 + A_2[/tex]

[tex]Area = 91 + 38.5[/tex]

[tex]Area = 129.5m^2[/tex]

Calculating Perimeter

First, we calculate the perimeter of the rectangle

But in this case, we only consider the length because the widths have been covered by the semicircles

[tex]P_1 = 2 * L[/tex]

Where:

[tex]L = 20-(3.5 +3.5)[/tex]

So:

[tex]P_1 =2 * (20-(3.5 +3.5))[/tex]

[tex]P_1 =2 * (20-7)[/tex]

[tex]P_1 =2 * 13[/tex]

[tex]P_1 =26[/tex]

Next, we calculate the perimeter of the two semi-circles.

Two semi-circles = One Circle

So:

[tex]P_2 = 2\pi r[/tex]

Where

[tex]r = \frac{7}{2}[/tex]

[tex]P_2 = 2 * \frac{22}{7} * \frac{7}{2}[/tex]

[tex]P_2 = \frac{2 * 22 * 7}{7 * 2}[/tex]

[tex]P_2 = \frac{308}{14}[/tex]

[tex]P_2 = 22[/tex]

Perimeter of the garden is

[tex]Perimeter = P_1 + P_2[/tex]

[tex]Perimeter = 26 + 22[/tex]

[tex]Perimeter = 48m[/tex]

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