The wave height is equal to twice the amplitude of the wave.
The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.
The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.
Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.
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how much force is required to accelerate a 12 kg mass at 5 m/s 2
Answer:
60 N
Explanation:
This is just Newton's Second Law
F = m*a
F = ?
m = 12 kg
a = 5 m/^2
F = 5*12 = 60 Newtons
Historia de baloncesto internacional resumen
Answer:
?
Explanation:
Name two processes that release nuclear energy?
Answer: Nuclear energy is released from an atom through one of two processes: nuclear fusion or nuclear fission. In nuclear fusion, energy is released when the nuclei of atoms are combined or fused together. This is how the sun produces energy. In nuclear fission, energy is released when the nuclei of atoms are split apart.
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Surface ocean currents are generated MOSTLY by A) wind. B) tides. C) water density. D) the Coriolis effect.
Answer:
I think it's D) the Coriolis Effect
Explanation:
Answer: THE ANSWER IS D) the Coriolis effect.
Explanation: I GOT A 100 ON THE TEST
I will give a 5-star answer and Brainlest
Direct contact is necessary for which type of energy transfer?
A. Conduction
B. Sound Waves
C. Convection
D. Radiation
Answer:
D
Explanation:
What is the weight of a 68-kg astronaut in outer space traveling with constant velocity?.
The weight of an astronaut in outer space and traveling with constant velocity is equal to 0 Newton.
Given the following data:
Mass of astronaut = 68 kgTo determine the weight of an astronaut in outer space and traveling with constant velocity:
Mathematically, the weight of an object is calculated by using the following formula;
[tex]Weight = mg[/tex]
Where:
m is the mass of an object.g is the acceleration due to gravity.At a constant velocity, the value of the astronaut's acceleration is equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).
Substituting the given parameters into the formula, we have;
[tex]Weight = 68 \times 0[/tex]
Weight = 0 Newton
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CAN YALL GO FOLLOW MY INS PLSS yeabdagod
Answer:
just followed :)
Explanation:
please answer right please
Answer:
i think its A
Explanation:
I hope this helps :)
if you dropped a ball and you dropped a hammer will the two objects fall at the same speed or will they fall at a different speed
Answer:
they would fall at different speeds
Explanation:
The speed at which each falls is dependent on air resistance
Prove that the two equations shown below are equivalent.
F = ma and F = p/t
Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]
F = ma is the formula of Newton’s Second Law of Motion.
To prove Newton's second law of motion,
Given Force F = Δp/Δt
What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.Proof for F=ma
Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,
For initial velocity u, p1 = m × u
The final velocity v, p2 = m × v
The change in momentum can be expressed as
p2 – p1 = (m × v) – (m × u)
p2 – p1 = m (v – u)
Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.
The applied force F,
F ∝ [m (v – u)]/t
F ∝ m × a
As acceleration (a) is the rate of change of velocity with respect to time.
F = k × m × a
F = ma
where k can be the constant.
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What is a milliliter.
A milliliter, abbreviated as ml or mL, is a unit of volume in the metric system. One milliliter is equal to one thousandth of a liter, or 1 cubic centimeter. In the imperial system, that's a small amount: . 004 of a cup
calculate the density, in g/l, of sf6 gas at 27°c and 0.500 atm pressure.
The density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
The given parameters:
temperature of the SF₆ gas, T = 27 ⁰C = 273 + 27 = 300 Kpressure of the SF₆ gas, P = 0.5 atmThe molecular mass of the SF₆ gas is calculated as follows;
M of SF₆ = 32 + (6 x 19) = 146 g/mol
The density of the SF₆ gas is calculated by applying ideal gas law as follows;
[tex]PV = nRT\\\\PV = \frac{m}{M} RT\\\\PM = \frac{m}{V} RT\\\\PM = \rho RT\\\\\rho = \frac{PM}{RT}[/tex]
where;
[tex]\rho[/tex] is the density of the gasR is the ideal gas constant = 0.0821 L.atm/mol.K[tex]\rho = \frac{0.5 \times 146}{0.0821 \times 300} \\\\\rho = 2.96 \ g/l[/tex]
Thus, the density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
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7. A bus covers a certain distance in 60 minutes if it runs at a speed of 60 km/hr.
What must be the speed of the bus in order to reduce the time of journey by 40
minutes?
Answer:
90 Km/h
Explanation:
60 mins is 1 hr
so in an hour bus covers 60 Km
so new speed:
d/t
(60km/40mins)*60mins/h
90Km/h
definiciones de estrés
Answer:
dame la marca más inteligente, por favor
Explanation:
En el campo de la medicina, es la respuesta del cuerpo a una presión física, mental o emocional. El estrés produce cambios químicos que elevan la presión arterial, la frecuencia cardíaca y las concentraciones de azúcar en la sangre. También suele producir sentimientos de frustración, ansiedad, enojo o depresión.
Answer:
El estrés es la reacción del cuerpo al sentirse amenazado o bajo presión.
Explanation:
Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________
Answer:
100 m/s
Explanation:
Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.
Determine the elastic energy U stored in
the compressed spring.
Answer:
Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.
Explanation:
4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?
Answer:
A.)a=44.57m/s
B.)f=38,909.61
C.)f=666.4
Explanation:
A.) A=v/t 26.3/0.590=44.57
B.) 873kg x 44.57= 38,909.61
C.) 68kg x 9.8=666.4
It takes 4 seconds for a car to completely stop at a red light from a speed of 24 m/s
The car's acceleration is ____ m/s2. Use No decimal and no unit!
Answer:
6m/s^2
Explanation:
Acceleration is the change in speed/Velocity per unit time. That means the speed divided by the time. 24m/s divided by 4s=6m/s^2
ECONOMIC Q‼️
Which of these is a common concern of an economist ?
A-The distributions of populations and earths resources
B-How people have organized the rules and laws of their societies
C-The cultural habits and social customs of societies
D-How well resources are used by a society
Answer:
D-How well resources are used by a society
Explanation:
Most economists are concerned with practical applications of economic policy in a particular area, such as finance, labor, agriculture, transportation...
Hope this helps luvv :)
True or False: Objects fall at a constant speed.
Answer:
Explanation:
true
What is the number of the of significant figures in 2.50400-.pliz, help me l will mark you the brainest.(⊙_◎)
Answer:
Number of Significant Figures: 6
The Significant Figures are 2 5 0 4 0 0
Explanation:
Non-zero digits are always significant which are in this case 2,5,4, and Any zeros between two significant digits are significant and final zero or trailing zeros are significant therefore making the entire digit significant.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The number of significant figures in 2.50400 is ~
[tex] \boxed{6}[/tex]if a car travels around a circular track with a radius of 100 m once every 10s what will its average angular velocity around the track be?
Answer:
0.628 radians per second
Explanation:
Angular velocity
= 2pi/T
= 2(3.14159)/10
= 0.628 radians per second
The average angular velocity around the track is 62.8 m/s, using the circumference of the track as the total distance.
Average angular velocity:What information do we have?
Radius of track = 100 m
Time taken = 10s
Circumference of track = 2πr
Circumference of track = 2(3.14)(100)
Circumference of track = (2)(314)
Circumference of track = 628 m
Average angular velocity around the track = Circumference of track / Time taken
Average angular velocity around the track = 628 / 10
Average angular velocity around the track = 62.8 m/s
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A community plans to build a facility to convert solar radiation to electrical power. The community requires 1.00 MW of power, and the system to be installed has an efficiency of 30.0% (that is, 30.0% of the solar energy incident on the surface is converted to useful energy that can power the community). Assuming sunlight has a constant intensity of 1 000 W/m2, what must be the effective area of a perfectly absorbing surface used in such an installation?
We will find that the effective area that must be used to get the desired power is 3,333.33 m^2
The information we have is:
power needed = 1.00 MW = 1,000,000 watts
Energy of the Sun = 1,000 W/m^2
We know that the system has an efficiency of 30%, then per meter square, the energy converted is:
E = 0.3*1,000 W/m^2 = 300 W/m^2
Now we need to find the area (in meters squared) such that:
A*E = 1,000,000 watts
A*(300 W/m^2) = 1,000,000 watts
A = (1,000,000 watts)/(300 W/m^2) = 3,333.33 m^2
So the effective area that must be used is A = 3,333.33 m^2
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The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated to have originally contained 80 g of carbon-14?
The age of the bone is 45840 years.
We'll begin by calculating the number of half-lives that has elapsed.
Amount remaining (N) = 0.3125 g
Initial amount (N₀) = 80 g
Number of half-lives (n) =?N × 2ⁿ = N₀
0.3125 × 2ⁿ = 80
Divide both side by 0.3125
2ⁿ = 80 / 0.3125
2ⁿ = 256
2ⁿ = 2⁸
n = 8Thus, 8 half-lives has elapsed
Finally, we shall determine the age of the bone.
Half-life (t½) = 5730 years
Number of half-lives (n) = 8
Time (t) =?t = n × t½
t = 8 × 5730
t = 45840 yearsTherefore, the age of the bone is 45840 years.
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Saturn’s moon titan has a mass of 1.35 × 10^23 kg. if titan is 1.19 × 10^6 km from saturn, and saturn’s mass is 5.86 × 1026 kg, what is the gravitational force between saturn and its moon?
Answer:The gravitational force equation is Fg=(G*M*m)/r² where, G is the gravitational constant, G=6.67*10^-11 m³/kg*s², M is the mass of Saturn, M=5.86*10^26, m is the mass of Titan, m=1.35*10^23 and r is the distance, r=1.19*10^6 km=1.19*10^9 m. Now we simply input the numbers into the equation:
Fg=(6.67*10^-11)*(5.86*10^26)*(1.35*10^23)/(1.19*10^6)²
Fg=(5.277*10^39)/(1.41*10^18)=3.743*10^21 N
The correct answer is the third one.
Explanation:
When the atmosphere is absolutely unstable, the environmental lapse rate is ________ the dry adiabatic lapse rate.
Answer: greater than
Explanation:
Tommy does 45 Joules of work to push the pencil over 3 meter. How much force did he use?
Answer:
Work = Force × Distance
Therefore Force = Work/Distance
= 45 joules/3 metres
= 15 newton
Explanation:
Answer:
15
Explanation:
15
Which molecule is a high-energy output of the light reactions?.
Answer:
Gallium Arsenine
Explanation:
A cyclist is coasting at 12 m/s when she comes to a muddy stretch with an effective coefficient of friction of 0.60. Will the cyclist be able to get out of the muddy stretch without having to pedal if it lasts 10 meters
The cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
The given parameters;
speed of the cyclist, u = 12 m/scoefficient of friction, μ = 0.6length of the muddy stretch, L = 10 mThe effective acceleration of the cyclist at the given coefficient of friction is calculated as follows;
[tex]a = \ \mu g\\\\a = 0.6 \times 9.8\\\\a = 5.88 \ m/s^2[/tex]
The distance traveled by the cyclist at the give speed and acceleration is calculated as;
[tex]v^2 = u^2 + 2as\\\\12^2 = 0 + 2(5.88)s \\\\ 11.76 s = 144\\\\ s = \frac{144}{11.76} \\\\a = 12.24 \ m[/tex]
Thus, we can conclude that the cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
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I rode my bicycle to grandmother's house at 6 km/h in a flat road for 5 min before reach a hill. I went at 2 km/h up the hill for 3minutes. I met a friend and stopped to talk for 5 minutes. I went on at 2 km/h to my grandmother's house. Draw (plot) the v against t graph for this motion.
The graph can be plotted based on the given information which are given
in pairs (velocity and time), and which the coordinate pairs are formed.
Please find attached the required v against t graph created with MS ExcelReasons:
The given data are presented in a tabular form as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 - 5 &6 \\5 - 8&2\\8 -13&0&\\13- &2&\end{array}[/tex]
The velocity time graph can be plotted using the above table values on
MS Excel using the above table elaborated as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 &6 \\5&6\\5 &2\\8&2\\8&0\\13&0&\\13 &2&\end{array}[/tex]
The attached graph can then be created using the Insert → Chart menu
after selecting the data above inputted in the spreadsheet button on MS
Excel.
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