The Taylor polynomial P, = (-10 * 9 about x = 0 is used to approximate the value of the function f at x=1 Find the value that verifies 5p (1)-(1)-500 n=1 n! Pa 1 384 1 384 0 ਤਕ OP PA 1 6144 PA 6144

Answers

Answer 1

The value that verifies 5p (1)-(1)-500 is -124.04

To approximate the value of the function f at x = 1 using the Taylor polynomial Pₙ = (-10)^n/ n! about x = 0, we need to find the value of P₅(1).

First, let's compute the derivatives of f(x) = e^x up to the fifth derivative:

f'(x) = e^x

f''(x) = e^x

f'''(x) = e^x

f''''(x) = e^x

f⁽⁵⁾(x) = e^x

Now, let's evaluate these derivatives at x = 0:

f(0) = e^0 = 1

f'(0) = e^0 = 1

f''(0) = e^0 = 1

f'''(0) = e^0 = 1

f''''(0) = e^0 = 1

f⁽⁵⁾(0) = e^0 = 1

Using these values, we can compute the Taylor polynomial P₅(x):

P₅(x) = f(0) + f'(0)(x - 0) + f''(0)(x - 0)²/2! + f'''(0)(x - 0)³/3! + f''''(0)(x - 0)⁴/4! + f⁽⁵⁾(0)(x - 0)⁵/5!

P₅(x) = 1 + 1x + 1x²/2! + 1x³/3! + 1x⁴/4! + 1x⁵/5!

Now, let's evaluate P₅(1):

P₅(1) = 1 + 1(1) + 1(1)²/2! + 1(1)³/3! + 1(1)⁴/4! + 1(1)⁵/5!

P₅(1) = 1 + 1 + 1/2 + 1/6 + 1/24 + 1/120

P₅(1) = 227/120

Therefore, the value that verifies 5P₅(1) - (1) - 500 is:

5P₅(1) - (1) - 500 = 5 * (227/120) - 1 - 500

= 1135/120 - 1 - 500

= 1135/120 - 120/120 - 60000/120

= (1135 - 120 - 60000)/120

= -59485/120

= -124.04

So, the value that verifies 5P₅(1) - (1) - 500 is approximately -124.04.

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Related Questions

A test for divisibility by 11 is to see if the digits taken in order and alternately added and subtracted produce a number which is divisible by 11. Consider 5-digit numbers of the form "abcde'. Show that "abcde' will be divisible by 11 if and only if a - b+c-d+e is divisible by 11.

Answers

An test for divisibility that a 5-digit number "abcde" will be divisible by 11 if and only if "a - b + c - d + e" is divisible by 11.

To show that a 5-digit number "abcde" is divisible by 11 if and only if "a - b + c - d + e" is divisible by 11, the concept of modular arithmetic.

The 5-digit number "abcde" as a sum of its digits multiplied by their respective place values:

"abcde" = a × 10000 + b × 1000 + c × 100 + d × 10 + e

Then express "a - b + c - d + e" in terms of the digits:

a - b + c - d + e = a × (10,000 mod 11) - b × (1,000 mod 11) + c × (100 mod 11) - d × (10 mod 11) + e

examine the patterns of the modulos:

10,000 mod 11 = 1

1,000 mod 11 = 10

100 mod 11 = 1

10 mod 11 = 10

Substituting these values back into the expression,

a - b + c - d + e = a × 1 - b ×10 + c × 1 - d × 10 + e

Simplifying further:

a - b + c - d + e = a - b + c - d + e

observe that the expression "a - b + c - d + e" is equivalent to the original 5-digit number "abcde." This means that if "abcde" is divisible by 11, then "a - b + c - d + e" will also be divisible by 11.

Conversely, if "a - b + c - d + e" is divisible by 11, it implies that the expression and the 5-digit number "abcde" have the same remainder when divided by 11. Since they are equivalent, "abcde" must also be divisible by 11.

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It takes me into 30 minutes to walk from home to school when walking at 5 km per hour What is her average cycling speed If it takes her 15 minutes by bike to travel the same distance​

Answers

Answer:

10 km/h

Step-by-step explanation:

I'm not really sure about this but no ones answering your question and I wanna help.

So basically to calculate the average speed you need to divide the distance travelled by time taken

But you do not have the distance traveled. But it is mentioned that it takes u 30 minutes to walk from home to school when walking at 5 km/h so to find the distance all you have to do is... 30 x 5 = 150 km

Now that we have the time and distance all we have to do is find the average speed.

Average Speed = distance ÷ time

So 150 ÷ 15 = 10 km/h

The table below gives a record of variations of the values of y with the values of x. Draw a scatter plot for the data.
x
0.4
1.2
2.0
3.1
4.5
5.7
7.1
8.4
9.3
9.8
y
7.8
7.1
6.8
6.0
5.2
4.3
3.4
2.3
1.1
0.5

a.
On a graph, points are at (2, 6.9), (9.3, 1.2), (9.8, 0).
c.
On a graph, points are at (0.4, 7.8), (3.1, 6.0), and (9.8, 0.5).
b.
On a graph, points are at (2, 7), (9.3, 1.2), (9.8, 1.5).
d.
On a graph, points are at (1.2, 7.2), (9.3, 1.2), (9.8, 0.2).



Please select the best answer from the choices provided


A
B
C
D

Answers

Answer: taake this link,  it has all the answers

Step-by-step explanation:                 https://quizlet.com/183183758/statistical-studies-scatterplots-practiceamdm-flash-cards/

The best option for the points on the graph is points are at (0.4, 7.8), (3.1, 6.0), and (9.8, 0.5).

What are co ordinate axis?

In two-dimensional Cartesian geometry, two intersecting straight lines are used as reference lines. In three-dimensional Cartesian geometry, three straight lines with a common point are the intersections of the three coordinate reference planes.

Estimation of the coordinates from the graph:

From the attached file of scatter plot for the data, it is clear that the for every value of x there is a suitable value of y which was given in the question.

Considering x values and plot the y vale on the graph.

For x = 0.4; y = 7.8

For x = 3.1; y = 6.0

and for x = 9.8; y = 0.5

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The moment generating function for the standard normal distribution is given by My(t)=et. Use this MGF (and its derivatives) to show that the mean and variance of the standard normal distribution is 0

Answers

Using the MGF and its derivatives, we have shown that the mean and variance of the standard normal distribution are both 0.

The MGF for the standard normal distribution is given as:

M(t) = e^(t²/2)

To find the mean of the standard normal distribution, we take the first derivative of the MGF with respect to t and evaluate it at t = 0:

M'(t) = (1/2)e^(t²/2) × 2t

Evaluating at t = 0:

M'(0) = (1/2)e⁰ × 2(0) = 0

Since the first derivative of the MGF evaluated at t = 0 is 0, this implies that the mean of the standard normal distribution is 0.

To find the variance of the standard normal distribution, we take the second derivative of the MGF with respect to t and evaluate it at t = 0:

M''(t) = (1/2)e^(t²/2) × 2t² + (1/2)e^(t²/2)×2

Evaluating at t = 0:

M''(0) = (1/2)e⁰ × 2(0)² + (1/2)e⁰ × 2

= 0 + 1

= 1

Since the second derivative of the MGF evaluated at t = 0 is 1, this implies that the variance of the standard normal distribution is 1.

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Marlene went shopping and bought a bunch of candy for her swim team. She bought packs of Skittles for $1.50 each and packs of M&Ms for $2 each. She spent a total of $39 and bought 24 items. How many of each item did she buy?

Answers

Answer:

18 Skittles

6 M&Ms

Step-by-step explanation:

Set up an equation:

Variable x = number of skittles

Variable y = number of M&Ms

1.50x + 2y = 39

x + y = 24

In the second equation, isolate a variable:

x = 24 - y

Substitute the value of x for 24 - y in the first equation:

1.50(24 - y) + 2y = 39

Use distributive property

36 - 1.5y + 2y = 39

Combine like terms

36 + 0.5y = 39

Isolate variable y:

0.5y = 3

y = 6

Substitute the value of y for 6 in the second equation:

x + 6 = 24

Isolate variable x:

x = 18

Plug these values into any equation of your choice to see if these values are correct (I'll do both equations just to prove it):

1.50(18) + 2(6) = 39

27 + 12 = 39

39 = 39

Correct

x + y = 24

18 + 6 = 24

24 = 24

Correct

Lindsay and Lorraine are trying to match the jump rope world record. Together, they need to jump 48 times in a row. Lindsay has gotten 14 jumps in a row, and Lorraine has gotten 13. Write an equation using (j) as the variable and show your work to determine how many more jumps they need to complete.



( if u steal my points ill steal yours)

(no links or ill report)

Answers

Answer: They need to complete 21 more jumps all together .

Step-by-step explanation: So 14+13=J

14+13=27

27=j

World record: 48; 48-27=21

They will have to jump 21 more times in a row .

sum of -10°C,24°C,-12°C,8°C,-1°C​

Answers

Answer:

9°C

Step-by-step explanation:

Group the terms and get [tex]24+8-1-10-12[/tex]

Then simplify to get [tex]32-23[/tex]

Subtract and you get 9

So the answer is 9°C.

Hope this helps!

pls help i'll give u a brainlyy

Answers

Answer: -633

Explanation:

formula is a0= a1 + (n-1)d

a0 is what ur tryig to find

a1 = -14

n= 60

d = -11

Answer:

-674

Step-by-step explanation:

As,

There is always a gap of -11 in all the proceedings

Hence,

- 14 -11 = -25

-14 -(11 ×2) = -36

So,

60th term

-14 -(11 × 60) = -674 (Ans)

Please help.
Indices and Standard Form question

Answers

Answer:

A= 4.5×10^11

B= 3.5×10^3

Step-by-step explanation:

A

(5×10^3)= 5000

(9×10^7)=90000000

multiply both of them

=450000000000 or 4.5×10^11

B

(7×10^5)=700000

(2×10^2)=200

700000÷200

3500 or 3.5×10^3

Find the general solution of the given differential equation. 7 dy dx + 56y = 8
y(x) =
Give the largest interval I over which the general solution is defined. (Think about the implications of any singular points. Enter your answer using interval notation.)
Determine whether there are any transient terms in the general solution.

Answers

The general solution of the given differential equation 7dy/dx + 56y = 8 is y(x) = -x/8 + C e^(-8x/7), where C is a constant.

To solve the differential equation, we first rearrange it to isolate dy/dx: dy/dx = (8 - 56y)/7. This is a first-order linear differential equation. The integrating factor is e^(∫(-56/7)dx) = e^(-8x/7). Multiplying both sides of the equation by this integrating factor, we obtain e^(-8x/7) dy/dx + 8e^(-8x/7)y = 8e^(-8x/7). The left-hand side can be written as the derivative of y multiplied by e^(-8x/7). Integrating both sides gives ∫d(y e^(-8x/7)) = ∫8e^(-8x/7) dx. Solving these integrals and rearranging, we find the general solution y(x) = -x/8 + C e^(-8x/7), where C is the constant of integration.

The largest interval I over which the general solution is defined is (-∞, ∞) since there are no singular points or restrictions mentioned in the differential equation. This means that the solution is valid for all real values of x.

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kelly deposits $3,000 at a rate of 5.2ompounded quarterly. with no additional deposits or withdrawals, what is the account balance after 10 years?

Answers

The account balance after 10 years will be approximately $5,259.99.

The balance in Kelly's account after 10 years can be determined using the formula for compound interest which is given as:

A = [tex]P(1 + r/n)^{nt}[/tex]

Where, A is the balance after time t, P is the principal amount (initial deposit), r is the annual interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time in years.

Using this formula and substituting the given values, we get:

A = [tex]3000(1 + 0.052/4)^{4 \times 10}[/tex]

= [tex]3000(1.0125)^{40}[/tex] ≈ $5,259.99

Therefore, the account balance after 10 years will be approximately $5,259.99.

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A sample of two items is selected without replacement from a batch. Describe the ordered sample space for the following batch:
(a)The batch contains 3 defective items and 10 good times.Hint: suppose we denote defective item by ‘d’ and good item as ‘g’, so one possible outcome could be "dg".
(b)The batch contains the items {a, b, c, d}.

Answers

For both scenarios, a sample is selected without replacement from a batch of items. In the first scenario, the batch contains 3 defective items ('d') and 10 good items ('g'). The ordered sample space consists of all possible ordered pairs of items: {dd, dg, gd, gg}. In the second scenario, the batch contains the items {a, b, c, d}. The ordered sample space also consists of all possible ordered pairs of items: {aa, ab, ac, ad, ba, bb, bc, bd, ca, cb, cc, cd, da, db, dc, dd}.

In the first scenario, the ordered sample space is derived by considering all possible combinations of the two items selected from the batch. Since the selection is done without replacement, the first item can be either defective ('d') or good ('g'). For each case, the second item can also be defective or good, depending on what was chosen as the first item. Therefore, the ordered sample space consists of four possibilities: dd, dg, gd, and gg.

In the second scenario, the batch consists of four distinct items: a, b, c, and d. Again, the ordered sample space is obtained by considering all possible combinations of the two items selected without replacement. Since there are four items, there are 16 possible combinations. Each combination is represented by an ordered pair of the selected items, such as aa, ab, ac, and so on.

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The question is in the photo above plz answer

Answers

Answer:

surface area of cuboid=2(lb+bh+hl)

surface area of cuboid=2(12×5+5×2+2×12 )

surface area of cuboid=188in²

Is (2,0) a solution for the equation -3+9y=-6

Answers

Answer:

[tex]y=-\frac{1}{3}[/tex]

Step-by-step explanation:

- 3 + 9y = - 6

- 3 + 3 + 9y = - 6 + 3

9y = - 3

9y ÷ 9 = - 3 ÷ 9

[tex]y=- \frac{1}{3}[/tex]

Determine the area of a circle whose radius is 15 feet. Use pie=3.14​

Answers

Answer:

Down below

Step-by-step explanation:

[tex]A=\pi r^2\\A=3.14*(15)^2\\A=3.14*225\\A=706.5[/tex]

Hey I'm Chloe Can you Help Me, I will give Brainlest, Thank you :)
During a professional baseball game, every spectator placed his or her ticket stub into one of several containers. After the game, the coach chose twenty people to march in the victory parade. What is the sample in this situation?

Answers

Answer:

The sample is the amount of people because not everyone is getting chosen

Step-by-step explanation:

I also agree, the coach choose certain people to march cuz not everyone is gonna be able to get used.

is 12, -15, -18, -21 arithmetic

Answers

The first person might be right

use the inner product u, v = 2u1v1 u2v2 in r2 and the gram-schmidt orthonormalization process to transform {(2, 1), (−2, −5)} into an orthonormal basis.

Answers

The orthonormal basis for (2, 1), (2, 5) is therefore u1, u2 = (2/5, 1/5), (2/5, -1/5) because u2 = v2_orth/||v2_orth|| = (2/5, -1/5).

In R2, the internal result of the two vectors u and v is as follows: The Gram-Schmidt procedure can be used to request the transformation of (2, 1), (2, 5) into an orthonormal premise. u, v = 2u1v1 + u2v2. An orthonormal premise is made by changing over a bunch of directly free vectors utilizing the Gram-Schmidt process. Our set's principal vector, v1 = (2, 1), should serve as our starting point.

We standardize v1 to obtain our first orthonormal premise vector: We must locate the second vector in our set, v2 = (-2, -5), and we can orthogonalize v2 by deducting its projection from u1: u1 = v1/||v1|| = (2/5, 1/5) proj_u1(v2) = (v2 u1)u1 = (- 8/5, - 4/5)v2_orth = v2 - proj_u1(v2) = (6, - 21/5)Our second orthonormal premise vector is acquired by normalizing v2_orth: The orthonormal reason for (2, 1), (2, 5) is subsequently u1, u2 = (2/5, 1/5), (2/5, - 1/5) in light of the fact that u2 = v2_orth/||v2_orth|| = (2/5, - 1/5).

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The number of calories of a food item varies directly with the size of the portion. If a 2-inch slice of a certain delicacy contains 170 calories, how many calories are in a 3-inch slice?​

Answers

Answer:

A 3-inch slice of the food item contains 255 calories.

Step-by-step explanation:

Set calories per inch slice as variable x.

2x = 170

x = 85 cal

Since each inch slice of the food item contains 85 calories, a 3-inch slice would contain:

3x = 3(85) = 255 cal

Tue diameter of a bike is 27 inches if the wheel makes 15 complete rotations how far does the bike travel?

Answers

Answer:

1271.7 inches

Step-by-step explanation:

Given

[tex]d = 27in[/tex]

[tex]Rotations = 15[/tex]

Required

The total distance moved

First, we calculate the circumference of the wheel

[tex]c = \pi *d[/tex]

[tex]c = 3.14 * 27[/tex]

[tex]c = 84.78[/tex]

This represents the distance traveled in one complete rotation.

So, in 15 rotations.

[tex]Total = 15 * 84.78[/tex]

[tex]Total = 1271.7[/tex]

whats 38 divided by 70

Answers

Answer:

.5428571 repeating

or 19/35

Assume that a sample is used to estimate a population proportion μ. Find the margin of error M.E. that corresponds to a sample of size 10 with a mean of 33.7 and a standard deviation of 13.3 at a confidence level of 95%. Report ME accurate to one decimal place because the sample statistics are presented with this accuracy. M.E. = _________ Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Answers

The margin of error for a 95% confidence level is 8.2.

How to find the margin of error?

The margin of error (ME) is determined using the formula:

ME= z ∗ σ/√n

where:

z is the z-score for the desired confidence level

σ is the population standard deviation

n is the sample size

For a 95% confidence level, the z-score is 1.96. Thus, we have:

z = 1.96

σ  = 13.3

n = 10

Substituting these values into the formula, we have:

ME =  1.96 ∗ 13.3/√10

ME = 8.2

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use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.)

Answers

The inverse Laplace transform of X(s) = [tex]1/s^7[/tex] is f(t) =[tex]t^6.[/tex]

To locate the inverse Laplace rework of X(s) =[tex]1/(s^7[/tex]), we are able to use algebraic manipulation and the inverse Laplace transform assets said in Theorem 7.2.1, which permits us to discover the original characteristic while given its Laplace rework.

Using the assets of the Laplace transform, we will rewrite the given expression as:

X(s) = [tex]x^-1(1/s^7) = (1/s^7)[/tex]

We need to locate the feature f(t) such that its Laplace transform is X(s) = [tex]1/s^7[/tex]. By making use of Theorem 7.2.1, we understand that the inverse Laplace remodels of X(s) will give us f(t).

Now, we need to find a characteristic f(t) that has a Laplace transform [tex]1/s^7[/tex]. By examining the Laplace transform a desk or the usage of regarded formulas, we will decide that the Laplace remodel of [tex]t^n[/tex](wherein n is a high-quality integer) is given by means of[tex]n!/s^(n+1).[/tex]

In our case, we're looking for a function whose Laplace remodel is[tex]1/s^7.[/tex]Comparing this with the Laplace transform formulation cited earlier, we see that the exponent within the denominator of sought to be [tex]8 ^(7+1).[/tex]

Hence, f(t) must be t^6 (given that 6+1 = 7), and its Laplace remodel maybe [tex]6!/s^7 = 720/s^7.[/tex]

Therefore, the inverse Laplace transform of X(s) = [tex]1/s^7 is f(t) = t^6.[/tex]

In precis, by applying algebraic manipulation and making use of the inverse Laplace rework assets, we determined that the inverse Laplace transform of [tex]1/s^7 is f(t) = t^6[/tex]. This approach that a unique feature corresponding to the given Laplace rework is [tex]t^6.[/tex].

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What is the area of this polygon?

Answers

The middle is a square with side length of 12cm

Area of the square = 12 x 12 = 144 cm^2

There are 4 triangles with base of 13cm and height of 8 cm

Area of triangle = 1/2 x base x height

Area = 1/2 x 12 x 8 = 48cm^2 each

48 x 4 = 192 cm^2

Total area = 144 + 192 = 336 cm^2

HELPPPP PLZ BEST ANSWER GET BRAINLIEST

Answers

The answer is A hope that helps

***I WILL GIVE BRAINIEST TO THE CORRECT ANSWER**
Translate the description as an algebraic expression:
double the product of 15 and k

Answers

Answer:

2•15k

Step-by-step explanation:

Answer:

2(15k)

Step-by-step explanation:

PLZZ GIVE BRAINLIEST

iGive a combinatorial proof of 1, 2+ 2.3+3.4++ (x - 1)^n = 2 =>("") Hint: Classify sets of three numbers from the integer interval [0...n] by their maximum element.

Answers

By classifying sets of three numbers from the interval [0...n] by their maximum element, we have provided a combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1).

The combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1) revolves around classifying sets of three numbers from the integer interval [0...n] by their maximum element.

Let's consider the right-hand side of the equation, which is 2^(n+1). This represents the number of subsets of an n-element set. We can think of each element in the set as having two choices: either it is included in a subset or not. Therefore, there are 2 choices for each element, resulting in a total of 2^(n+1) subsets.

Now, let's look at the left-hand side of the equation, which is the sum 1 + 2 + 2.3 + 3.4 + ... + (x - 1)^n. We can interpret each term as follows:

1: Represents the number of subsets with a maximum element of 0, which is only the empty set.

2: Represents the number of subsets with a maximum element of 1, which includes the subsets {0} and {1}.

2.3: Represents the number of subsets with a maximum element of 2, which includes the subsets {0, 1}, {0, 2}, and {1, 2}.

Similarly, for each subsequent term (x - 1)^n, it represents the number of subsets with a maximum element of x-1.

Now, if we add up all these terms, we are essentially counting the total number of subsets from the original set. This matches the right-hand side of the equation, which is 2^(n+1).

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Q1) Eruptions of the Old Faithful geyser in Yellowstone National Park typically last from 1.5 to 5 minutes. Between eruptions are dormant periods, which typically last from 50 to 100 minutes. A dormant period can also be thought of as the waiting time between eruptions. The duration in minutes for 40 consecutive dormant periods are given in the following table. 91 82 84 85 80 73 72 84 86 76 51 70 71 83 79 79 67 76 60 81 55 53 51 53 45 49 67 76 86 88 82 68 82 51 51 75 86 沙575 66 Assuming that the waiting time follows an Exponential distribution with mean parameter A, develop a uniformly most powerful test of size a = 0.01 for Hoλ2 80 vs H₁ A<80. Based on this test, draw a conclusion.

Answers

The duration in minutes for 40 consecutive dormant periods are given in the following table:91 82 84 85 80 73 72 84 86 76 51 70 71 83 79 79 67 76 60 81 55 53 51 53 45 49 67 76 86 88 82 68 82 51 51 75 86 575 66.

Assuming that the waiting time follows an exponential distribution with mean parameter A, a uniformly most powerful test of size α = 0.01 for H o λ^2=80 vs H1 A<80 can be developed as follows: The null and alternative hypotheses are as follows:H0:λ^2=80, that is, the mean of the exponential distribution is 80 squared.H1:A<80, which implies that the mean waiting time between eruptions is less than 80 squared.α=0.01 is the level of significance.

The following test statistic T is used: T = [n(λ^2-80)] / 80^2where n is the sample size, and the critical region is the left-tail rejection area. The probability of observing the values in the given sample or a more extreme set of values is calculated as follows: Since we are performing a one-tailed test, we divide α by 2.α/2 = 0.005

The area in the left tail is 0.005, and the corresponding z-score is -2.33.The null hypothesis is rejected if the computed value of the test statistic falls in the critical region, which is in the left-tail rejection region. T < -2.33

Since the test statistic T = -1.91 falls in the non-critical region, we fail to reject the null hypothesis at the α=0.01 level of significance. Therefore, based on this test, we can conclude that there is insufficient evidence to suggest that the mean waiting time between eruptions is less than 80 squared.

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What is the value of g^-1(7)? PLEASE HELP!!! I’ll give brainliest!!

Answers

Answer: g-7

Step-by-step explanation:

Answer:

Step-by-step explanation:

5 is the correct answer

Does any one know the answer to this thank you

Answers

Answer:

The First choice

Step-by-step explanation:

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asap thansksContrast ethnocentric, polycentric, and geocentric managers, and give a behavioral example of each. Edit Format Table 12pt Paragraph BIUA 2 T : Duval Company issues four-year bonds with a $111,000 par valueon January 1, 2020, at a price of $106,880. The annual contractrate is 8%, and interest is paid semiannually on June 30 andDecember 31. Use the following information to answer #10 and #11 Custard's Bakery produces a pie that requires 2.6 pounds of fruit per pie. The allowance for waste and spoilage per pie is.2 pounds and .1 pounds, respectively. The purchase price of fruit is $2 per pound, but a 4% discount is usually taken. Freight costs are $.10 per pound, and receiving and handling costs are $.07 per pound. The hourly wage rate is $12.00 per hour, but a raise which will average $.30 will go into effect soon. Payroll taxes are $1.20 per hour, and fringe benefits average $2.40 per hour. Standard production time is 1 hour per pie, and the allowance for rest periods and setup is.2 hours and .1 hours, respectively. The standard direct materials price per pound is: $2.17 $2.09 $2.00 $2.13 What are the general legal requirements in organizing acharitable foundation in the Philippines? movetar inc., of phoenix need a new long distance moving van that cost $53,000 with an estimated lifespan of six years and salvage value of $11,000. movetar can secure a $53,000 loan from a local bank repayable in six equal payments at a 10 percent interest rate. Alternatively, movetar can lease the van for $15,000 annually. if purchased, movetar will incur an annual maintenace cost of $2,000. Assume a straight line depreciation, a tax rate of 40% and a cost of capital (WACC) of 16%Given the above information, should movetar, inc. purchase or lease the van. why? provide quatitative support for your recommendation. (60 POINTS) Go back and read the goals for this lesson on page 1. Form a summary statement for each goal, showing you understand and have met the goals of this lab. Be sure to explain all major concepts and relationships presented in this lab. (3-5 sentences)1: Compare the masses, radii, and densities of terrestrial planets and gas giants.2: Describe the shape of planetary orbits.3: Discover Keplers laws:4: Planets revolve around the Sun in elliptical orbits.5: Planets speed up as they move closer to the Sun and slow down as they move farther away from the Sun.6: The cube of a planets orbital radius is proportional to the square of its period.7: Use Keplers third law to predict a bodys period given its orbital radius. _____is defined as the ratio of the compressor (or pump) work input to the turbine work output. Multiple Choice a.Compression ratio b.Pressure ratio c.Cutoff ratio d.Back work ratio True or False? Our town is growing with a doubling time of 40 years so its population will triple in 120 vears. True False The following inventory transactions took place for Oriole Ltd. for the year ended December 31, 2020:Date Event Quantity Cost/Selling PriceJan 1 opening inventory 25,000 $50.00 Jan 5 sale 6,500 71.00 Feb 15 purchase 32,500 41.25 Mar 10 purchase 9,500 48.00 May 20 sale 41,500 71.00 Aug 22 purchase 14,500 48.50 Sep 12 sale 20,500 71.00 Nov 24 purchase 9,500 58.50 Dec 5 sale 16,700 71.00 Calculate the ending inventory balance for Oriole Ltd., assuming the company uses a perpetual inventory system and the first-in, first-out cost formula. Also calculate the per-unit cost of the last item sold. (Round unit costs to 2 decimal places, e.g. 52.75 and ending inventory to 0 decimal places, e.g. 5,276.)Ending inventory $Unit cost of the last item sold $ Why does the author use a question-and-answer format to develop the main points of the passage?A. to better show how different types of clocks compare and contrastB. to guide readers' understanding of a complex topicC. to more easily reveal the timeline of eventsD. to present a sequential order of events in an understandable way 60 papers cost $27. Find the cost of 16 papers. $0.72 The answer is not among the choices provided. $7.00 $7.25 O $72.00 $7.02 Estrogen levels rise during the follicular phase of the ovarian cycle, and estrogen assists with the development of the dominant follicle.a. trueb. false Which type(s) of solute dissolve readily in water?A. polarB. ionicC. nonpolarD. colloidal Which of the following statements is incorrect? O a. Entrepreneurship requires a balance between risk propensity and financial motivation O b. None O c. True entrepreneurship is limited to developed nations that can exploit resources efficiently. O d. Entrepreneurial thinking is not as important as entrepreneurial action. Oe. Entrepreneurship is a method that requires practice. According to the accountability principle, the file clerk supervisor shall oversee the information governance program.a. trueb. false Explain how the proper implementation of internal controls undera framework such as the COSO framework can reduce the incidence offraud in public companies. A monopolist faces a demand curve given by P = 210-5Q where P is the price of the good and Q is the quantity demanded. The marginal cost of production is constant and is equal to $60. There are no fixed costs of production. How much output should the monopolist produce in order to maximize profit? 30 units 21 units 42 units 27 units None of these A monopolist faces a demand curve given by P = 210-5Q where P is the price of the good and Q is the quantity demanded. The marginal cost of production is constant and is equal to $60. There are no fixed costs of production. What price should the monopolist charge in order to maximize profit? $60 $30 There are four basic stages of the health information management cycle. These include coding and revenue cycle, informatics, data analysis, and risk management. Identify potential compliance requirements of each stage and provide a potential solution to the compliance issue. For example, a documentation error can cause problems with billing. A solution may be to educate the staff on proper documentation. Your response should be approximately 100 words for each stage. In the P.O.W.E.R. process, both evaluating and rethinking involve assessing the outcome of your effort. Rethinking is different from evaluating, however, in that rethinking involves:____________ Selecting the best development strategy is an important decision that requires companies to consider multiple factors. The systems analyst has an important role to play in this decision-making process. In particular, analyzing the costs and benefits of each development alternative is a key to providing objective data to management. A cost-benefit checklist can help guide this analysis.The evaluation and selection of alternatives is not a simple process. The objective is to obtain the product with the lowest TCO, but actual cost and performance can be difficult to forecast. When selecting hardware and software, systems analysts often work as an evaluation and selection team. A group of people involved in selecting hardware and software. The group includes systems analysts and users. A team approach ensures that critical factors are not overlooked and that a sound choice is made. A team approach ensures that critical factors are not overlooked and that a sound choice is made. The evaluation and selection team also must include users, who will participate in the selection process and feel a sense of ownership in the new system.Evaluate and select who would be on the team to eliminate system alternatives that will not meet requirements, rank the alternatives that are feasible, and present the viable alternatives to management for a final decision. The process begins with a careful study of the costs and benefits of each alternative, as explained in the following section.