The missing value in the table is 64 miles.The correct answer is option C.
To determine the missing value in the table, we can observe the pattern in the given data. Looking at the time values, we can see that they are increasing by a constant interval of 2 hours: 2, 4, 6, 8, 10. The corresponding distances traveled are 16, 32, 48, ?, 80.
By examining the distances, we can see that they are increasing by a constant interval of 16 miles. The first distance is 16 miles when the time is 2 hours, and it increases by 16 miles for every 2-hour increment.
To find the missing value, we need to determine the distance traveled at 8 hours. Since the interval is 16 miles for every 2 hours, the distance traveled at 8 hours can be calculated by multiplying the interval by the number of 2-hour increments from the first data point: 16 miles * (8 hours / 2 hours) = 16 miles * 4 = 64 miles.
Therefore, the missing value in the table is 64 miles, which corresponds to option C.
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The probable question may be:
The table shows how the distance traveled by a dogsled is changing over time.
Time (in hours) :- 2,4,6,8,10.
Distance Traveled (In miles) :- 16,32,48,?,80.
What value is missing from the table?
A. 50.
B. 68.
C. 64.
D. 60.
Michelle has $15 and wants to buy a combination of dog food to feed at least four dogs at the animal shelter. A serving of dry food costs $1, and a serving of wet food costs $5.
1, Write the system of inequalities that models this scenario
2, Describe the graph of the system of inequality’s including shading and the types of lines graphed. Provide a description of the solution set.
Answer:
Step-by-step explanation:
1. The system of inequalities that models this scenario can be represented as:
Let x be the number of servings of dry food.
Let y be the number of servings of wet food.
The cost constraint:
1x + 5y ≤ 15
The minimum number of dogs constraint:
x + y ≥ 4
2. The graph of the system of inequalities would be a shaded region in the coordinate plane.
To graph the inequality 1x + 5y ≤ 15, we can first graph the equation 1x + 5y = 15 (the corresponding boundary line) by finding two points on the line and connecting them. For example, when x = 0, y = 3, and when y = 0, x = 15. Plotting these points and drawing a line through them will represent the equation 1x + 5y = 15.
Next, we need to shade the region below the line because the inequality is less than or equal to (≤). This shaded region represents the solutions that satisfy the cost constraint.
To graph the inequality x + y ≥ 4, we can again find two points on the line x + y = 4 (the corresponding boundary line). For example, when x = 0, y = 4, and when y = 0, x = 4. Plotting these points and drawing a line through them will represent the equation x + y = 4.
Lastly, we shade the region above the line x + y = 4 because the inequality is greater than or equal to (≥). This shaded region represents the solutions that satisfy the minimum number of dogs constraint.
The solution set is the overlapping region where the shaded areas of both inequalities intersect. This region represents the combination of servings of dry food and wet food that Michelle can purchase within her budget ($15) to feed at least four dogs at the animal shelter.
The inequalities D + W > 4 and D + 5W ≤ 15 model the problem. The graph represents these inequalities, with the overlap of shaded regions showing possible food serving combinations.
Explanation:
Let's define D as the number of servings of dry food and W as the number of servings of wet food. The system of inequalities that models this scenario is:
D + W > 4: Michelle needs enough food for at least four dogs.D + 5W ≤ 15: Michelle cannot spend more than $15.The graph will show the solution sets to the inequalities. D and W must both be non-negative, hence the graphed area is in the first quadrant. The first inequality requires shading above a line that connects (0,4) and (4,0). This line is solid since numbers equal to 4 are included. The second inequality requires shading below a line that connects (0,3) and (15,0). This is also a solid line because Michelle can spend exactly $15. The overlapping region of the graph is the solution set, quantifying the combinations of dry and wet food servings that Michelle can buy.
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Predict the number of sales in month 5
The predicted sales in month 5 is -2778.
Obtaining the linear equation which models the data :
y = bx + cb = slope = (y2-y1)/(x2-x1)
b = (926-7408)/(4-1)
b = -2160.67
c = intercept ;
taking the points (x = 2 and y = 3704)
Inserting into the general equation:
3704 = -2160.67(2) + c
3704 = -4321.33 + c
c = 3704 + 4321.33
c = 8025.33
General equation becomes : y = -2160.67x + 8025.33
To obtain sales in month 5:
y = -2160.67(5) + 8025.33
y = -2778
Hence, the predicted sales in month 5 is -2778.
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A spinner is divided into five colored sections that are not of equal size: red, blue, green, yellow, and purple. The spinner is spun several times, and the results are recorded below. Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
The probability that the next spin will land on red is 7%
How to express the probability that the next spin will land on red?To express the probability that the next spin will land on red as a percent to the nearest whole number. We need to consider the number of red as proportion of the total.
From the table:
number of red = 4
total = 4 + 18 + 10 + 18 + 11 = 61
Probability that the next spin will land on red = 4/61
As percent to the nearest whole number:
Probability that the next spin will land on red = (4/61) * 100
Probability that the next spin will land on red = 7%
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Complete Question
Check attached image
complete the table of values for y=3/x
The table of values for the equation y = 3/x can be completed as follows:
x | y
1 | 3/1 = 3
2 | 3/2 = 1.5
3 | 3/3 = 1
4 | 3/4 = 0.75
5 | 3/5 = 0.6
To complete the table of values for the equation y = 3/x, we substitute different values of x into the equation and calculate the corresponding values of y.
When x = 1:
Substitute x = 1 into the equation: y = 3/1 = 3
So, when x = 1, y = 3.
When x = 2:
Substitute x = 2 into the equation: y = 3/2 = 1.5
So, when x = 2, y = 1.5.
When x = 3:
Substitute x = 3 into the equation: y = 3/3 = 1
So, when x = 3, y = 1.
When x = 4:
Substitute x = 4 into the equation: y = 3/4 = 0.75
So, when x = 4, y = 0.75.
When x = 5:
Substitute x = 5 into the equation: y = 3/5 = 0.6
So, when x = 5, y = 0.6.
By substituting different values of x into the equation y = 3/x, we can complete the table of values as shown above.
Hence, the completed table of values for y = 3/x is:
x | y
1 | 3
2 | 1.5
3 | 1
4 | 0.75
5 | 0.6
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Does the mapping diagram represent a function? Why or why not?
-5
8
9
y
-8
A. Yes; each input pairs with only one output.
B. No; the input value x = -5 pairs with two output values.
C. No; each input pairs with only one output.
D. No; each output value pairs with two input values.
The correct answer is: A. Yes; each input pairs with only one output.
To determine whether the given mapping diagram represents a function, we need to analyze the relationship between the input values (x) and the corresponding output values (y).
Looking at the mapping diagram, we can see that the input value -5 is paired with the output value 8. This implies that when x = -5, the corresponding y value is 8. Similarly, when x = 9, the corresponding y value is -8.
Since each input value has a unique and specific output value, we can conclude that the mapping diagram represents a function. In other words, for every input value, there is only one output value associated with it.
This is consistent with the definition of a function, where each input has a single and distinct output. Therefore, the mapping diagram satisfies the criteria for a function, and the correct answer is:
A. Yes; each input pairs with only one output.
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The mapping diagram does not represent a function that reflects this is: No; each output value pairs with two input values. D.
To determine whether the mapping diagram represents a function, we need to assess whether each input value pairs with only one output value.
Looking at the given mapping diagram:
-5 -> 8
9 -> y
-8 -> y
We can see that the input value -5 maps to the output value 8.
There are two different input values, 9 and -8, that map to the same output value, y.
In a function, each input should correspond to exactly one output, but in this case, the output value y is associated with two different input values.
In this case, y, the output value, pairs with both 9 and -8, indicating that the diagram does not meet the criteria for a function.
We must examine if each input value couples with only one output value in order to evaluate whether the mapping diagram reflects a function.
Observing the provided mapping diagram:
-5 -> 8 9 -> y -8 -> y
As can be seen, the input value of -5 corresponds to the output value of 8.
The identical output value, y, is mapped to two distinct input values, 9 and -8.
A function should have only one output for each input, however in this situation, the output value y is connected to two separate input values.
This figure does not fit the definition of a function because the output value, y, couples with both 9 and -8.
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Let A be the point (7,4) and D be (-5, -3). What is the length of the shortest path ABCD, where B is a point (x, 2) and C is a point (x,0)? This path consists of three connected segments, with the middle one vertical.
The length of the shortest path ABCD is 7 units.
To find the length of the shortest path ABCD, we need to determine the coordinates of points B and C and then calculate the distances between these points.
Given that B has a y-coordinate of 2, it lies on a horizontal line. Therefore, the y-coordinate of B is 2, and the x-coordinate is the same as the x-coordinate of point A, which is 7. So, B is the point (7, 2).
Similarly, C lies on a vertical line, and its x-coordinate is the same as the x-coordinate of point D, which is -5. So, C is the point (-5, 0).
Now, we can calculate the distances between the points. The distance between A and B can be found using the distance formula:
AB = √[tex]((x2 - x1)^2 + (y2 - y1)^2[/tex])
Substituting the coordinates of A and B, we have:
AB = √[tex]((7 - 7)^2 + (2 - 4)^2) = √(0^2 + (-2)^2[/tex]) = √4 = 2
The distance between B and C is simply the difference in their y-coordinates:
BC = |y2 - y1| = |2 - 0| = 2
Finally, the distance between C and D can be calculated using the distance formula:
CD = √[tex]((-5 - (-5))^2 + (0 - (-3))^2)[/tex] = √[tex](0^2 + 3^2)[/tex] = √9 = 3
Therefore, the length of the shortest path ABCD is the sum of the distances AB, BC, and CD:
Shortest path ABCD = AB + BC + CD = 2 + 2 + 3 = 7
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Jake drives a tractor from one town to another, a distance of 120 kilometers. He drives 6 kilometers per hour faster on the return trip, cutting 1 hour off the time. How fast does he drive each way?
The speed of Jake's initial trip is x = 24 kilometers per hour, and the speed of the return trip is x + 6 = 30 kilometers per hour.
Let's assume that Jake's speed during the initial trip is represented by "x" kilometers per hour.
On the return trip, he drives 6 kilometers per hour faster, so his speed can be represented as "x + 6" kilometers per hour.
To find the time taken for each trip, we can use the formula Time = Distance / Speed.
For the initial trip, the time taken is 120 kilometers divided by x kilometers per hour, which gives us 120/x hours.
On the return trip, the time taken is 120 kilometers divided by (x + 6) kilometers per hour, which gives us 120/(x + 6) hours.
According to the problem, the return trip takes 1 hour less than the initial trip. So we can set up the equation:
120/x - 1 = 120/(x + 6)
To solve this equation, we can multiply both sides by x(x + 6) to eliminate the denominators:
120(x + 6) - x(x + 6) = 120x
Simplifying this equation:
120x + 720 - x² - 6x = 120x
Combining like terms:
x² + 6x - 720 = 0
Now we can solve this quadratic equation by factoring or using the quadratic formula. By factoring, we find:
(x + 30)(x - 24) = 0
This gives us two potential solutions: x = -30 or x = 24.
Since speed cannot be negative, we discard the solution x = -30.
Therefore, the speed of Jake's initial trip is x = 24 kilometers per hour, and the speed of the return trip is x + 6 = 30 kilometers per hour.
So, Jake drives at a speed of 24 kilometers per hour on the initial trip and 30 kilometers per hour on the return trip.
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Suppose we have two equations and they are both equal to each other. Equation A is "y = x^2 - 9" and Equation B is "y = x + 3". If we had to solve this system of equations, what quadratic equation do we have to solve in order to get our x values?
a. x^2 - x - 12 = 0
b. x^2 + x + 3 = 0
c. x^2 - x - 6 = 0
Answer:
a) x² - x - 12 = 0
Step-by-step explanation:
We have equation A = equation B
⇒ x² - 9 = x + 3
⇒ x² - 9 - x - 3 = 0
⇒ x² - x - 12 = 0
Select the correct text.
Regina’s teacher recently gave her a homework assignment on solving equations. Since she has been thinking about saving for a new cell phone, she decided to use the assignment as an opportunity to model a savings plan.
She created this equation to model the situation. In it, y represents the total amount saved for the new cell phone, 74 is the amount of money she has now, 40 is the amount of money she saves each month for the phone, and x represents the number of months since she started saving a regular amount:
74 + 40x = y.
She then solved the equation to determine how many months she’d need to save to have enough to purchase the new cell phone. Review her work, and select the error.
Justification
1: given
2: subtraction property of equality
3: simplification
4: multiplication property of equality
5: simplification
6: substitution, y = 834
7: simplification
Step 1: 74 + 40x = y
Step 2: 74 + 40x − 74 = y − 74
Step 3: 40x = y − 74
Step 4:
=
Step 5: x =
Step 6: x =
Step 7: x = 19
Find the measure of the indicated angle.
- 20°
161"
61*
73"
H
73
195
E
The measure of the indicated angle formed by a secant and tangent line is 61 degrees.
What is the measure of the missing angle?The outside or external angles theorem states that "the measure of an angle formed by two secant lines, two tangent lines, or a secant line and a tangent line from a point outside the circle is half the difference of the measures of the intercepted arcs.
It is expressed as;
External angle = 1/2 × ( x - y )
From the diagram:
Intercepted arc GE = y = 73°
Intercepted arc HE = x = 195°
External angle GFE = ?
Plug the given values into the above formula and solve for the indicated angle:
External angle = 1/2 × ( x - y )
External angle GFE = 1/2 × ( 195 - 73 )
External angle GFE = 1/2 × 122
External angle GFE = 61°
Therefore, the outside angle is 61 degrees.
Option C) 61° is the correct answer.
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Please answer ASAP I will brainlist
The solution to the system is (a) a = 4/5, b = 5, c = -4 and d =-4
How to determine the solution to the systemFrom the question, we have the following parameters that can be used in our computation:
The augmented matrix
Where, we have
[tex]\left[\begin{array}{cccc|c}1&0&0&0&4/5\\0&1&0&0&5\\0&0&1&0&-4\\0&0&0&1&-4\end{array}\right][/tex]
From the above, we have the diagonals to be 1
And other elements to be 0
This means that the equation has been solved
So, we have
a = 4/5, b = 5, c = -4 and d =-4
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A rigidly tie bar in a heating chamber has a diameter of 10 mm and is tensioned
The initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex] and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.
To calculate the initial stress in the tie bar, we can use the formula:
Stress = Load/Area
The area of the tie bar can be calculated using the formula for the area of a circle:
Area = π * [tex](diameter/2)^2[/tex]
Plugging in the values, we get:
Area = π * [tex]10 mm^{2}[/tex] = π *[tex](5 mm)^2[/tex] = 78.54 [tex]mm^2[/tex]
Converting the area to square meters, we have:
Area = 78.54 [tex]mm^2[/tex]* (1 m^2 / 1,000,000 [tex]mm^2[/tex]) = 7.854 × 1[tex]0^-5 m^2[/tex]
Now we can calculate the initial stress:
Initial Stress = 100 kN / 7.854 ×[tex]10^-5 m^2[/tex] = 1.273 × [tex]10^9 N/m^2[/tex]To calculate the resultant stress when the temperature rises to 50°C, we need to consider the thermal expansion of the tie bar. The change in length can be calculated using the formula:
ΔL = α * L0 * ΔT
Where ΔL is the change in length, α is the coefficient of linear expansion, L0 is the initial length, and ΔT is the change in temperature.
The induced force in the bar can be calculated using the formula:
Induced Force = Initial Stress * Area + E * α * ΔT * Area
Plugging in the values, we get:
Induced Force = (1.273 × 10^9 N[tex]m^2[/tex] * 7.854 × [tex]10^-5 m^2[/tex]) + (200 × [tex]10^9[/tex] N/[tex]m^2[/tex] * 14 × [tex]10^-6[/tex] /K * (50 - 15) K * 7.854 × [tex]10^-5 m^2[/tex])
Simplifying the equation, we find:
Induced Force = 100.03 kN
Therefore, the initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.
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The probable question may be:
A rigidly held tie bar in a heating chamber has a diameter of 10 mm and is tensioned to a load of 100 kN at a temperature of 15°C. What is the initial stress, the resultant stress and what will be the induced force in the bar when the temperature in the chamber has risen to 50°C? E= 200 GN/ m2 and the coefficient of linear expansion of the material for tie bar = 14 × 10−6 /K.
please help quick
Which of the following are solutions to the quadratic equation? Check all that
apply.
The correct solutions to the quadratic equation are:
c. -8
e. 2
To determine the solutions to the quadratic equation 2x^2 + 6x - 10 = x^2 + 6, we need to solve for x.
First, let's simplify the equation by combining like terms:
2x^2 + 6x - 10 - x^2 - 6 = 0
x^2 + 6x - 16 = 0
Now, we can solve this quadratic equation by factoring or by using the quadratic formula.
By factoring:
(x + 8)(x - 2) = 0
Setting each factor equal to zero, we get:
x + 8 = 0 --> x = -8
x - 2 = 0 --> x = 2
So, the solutions to the quadratic equation are x = -8 and x = 2.
Now, let's check the given options:
a. -2: This value is not a solution to the equation.
b. 1/3: This value is not a solution to the equation.
c. -8: This value is a solution to the equation.
d. -1/2: This value is not a solution to the equation.
e. 2: This value is a solution to the equation.
f. 8: This value is not a solution to the equation.
The following are the proper answers to the quadratic equation: c. -8 e.2
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Roger can run one mile in 9 minutes. Jeff can run one mile in 6 minutes. If Jeff gives Roger a 1 minute head start, how
long will it take before Jeff catches up to Roger? How far will each have run?
They each will have run of a mile.
Both Roger and Jeff will have run a distance of 1/3 mile when Jeff catches up to Roger after 2 minutes.
To solve this problem, we can determine the relative speeds of Roger and Jeff.
Since Roger runs one mile in 9 minutes, his speed is 1/9 miles per minute.
Similarly, Jeff runs one mile in 6 minutes, so his speed is 1/6 miles per minutes.
Let's assume that Jeff catches up to Roger after t minutes.
In that time, Roger would have run (1/9) [tex]\times[/tex] t miles, and Jeff would have run (1/6) [tex]\times[/tex] t miles.
Since Jeff gives Roger a 1-minute head start, we can express their distances covered as:
Distance covered by Roger = (1/9) [tex]\times[/tex] (t+1) miles
Distance covered by Jeff = (1/6) [tex]\times[/tex] t miles
For Jeff to catch up to Roger, their distances covered must be equal. So we can set up the equation:
(1/9) [tex]\times[/tex] (t+1) = (1/6) [tex]\times[/tex] t
To solve for t, we can cross-multiply and simplify:
6(t+1) = 9t
6t + 6 = 9t
6 = 9t - 6t
6 = 3t
t = 2
Therefore, it will take 2 minutes for Jeff to catch up to Roger.
Substituting t = 2 back into the equations, we can find the distances covered by each:
Distance covered by Roger = (1/9) [tex]\times[/tex] (2+1) = 1/3 mile
Distance covered by Jeff = (1/6) [tex]\times[/tex] 2 = 1/3 mile
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Let V=W+W* be a vector space, being the direct product of the (finite dimensional) vector space W and its dual space W*. Now, let us define a bilinearform B: VxV -> R by
<(a,p), (b,q)> := q(a) + p(b).
Now let us suppose we have both e_1, …, e_n Basis of W and e*_1,….,e*_n Basis of W*.
What is the matrix of this bilinear form?
(I know how these matrices usually look like, but the inner product makes me very confused about the layout of this matrix).
If f(x) = 16x2, what is the value of f(2.5)?
Answer:
f(2.5) = 100
Step-by-step explanation:
to evaluate f(2.5) substitute x = 2.5 into f(x)
f(2.5) = 16(2.5)² = 16 × 6.25 = 100
X-2
5 = 8 using the change of base formula logby=
log y
log b
By using the change of base formula: The solution to the equation log(base y) (X-2) = 5 is [tex]X = y^5 + 2.[/tex]
To solve the equation log(base y) (X-2) = 5 using the change of base formula, we can rewrite the equation as log(base b) (X-2) / log(base b) y = 5.
Using the change of base formula, we can choose any base for b.
Let's choose base 10 for simplicity.
So the equation becomes log(base 10) (X-2) / log(base 10) y = 5.
We know that log(base 10) (X-2) represents the logarithm of (X-2) to the base 10, and log(base 10) y represents the logarithm of y to the base 10.
Now, to solve for X, we can isolate it by multiplying both sides of the equation by log(base 10) y:
log(base 10) (X-2) = 5 [tex]\times[/tex] log(base 10) y.
This simplifies to:
log(base 10) (X-2) [tex]= log(base 10) y^5.[/tex]
Since the logarithms on both sides have the same base, we can remove the logarithm and equate the arguments:
[tex]X - 2 = y^5.[/tex]
Now we can solve for X by adding 2 to both sides:
[tex]X = y^5 + 2.[/tex]
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(|7 − 3 x 5) | ÷ 4)³ + √64
Answer:
16
Step-by-step explanation:
(|7 − 3 x 5| ÷ 4)³ + √64
(|7 − 3 x 5| ÷ 4)³ + √64
(|7 − 15| ÷ 4)³ + √64
(|7 − 15| ÷ 4)³ + √64
(8 ÷ 4)³ + √64
(8 ÷ 4)³ + √64
2³ + √64
8 + 8
16
Answer:
16
Step-by-step explanation:
To solve, use PEMDAS as it applies to the expression.
First, you must carry out what is in the parenthesis.
Multiply (3*5 = 15), then subtract (7 - 15 = -8). The two little vertical lines surrounding (7 - 3 x 5) mean absolute value. This means that you will write -8 as +8.
Continuing on in the parenthesis, carry out (8 ÷ 4 = 2).
Next, we must do exponents.
We see that everything in the parenthesis is being raised to the power of three (cubed). Since we've solved what was in the parenthesis, we simply need to carry out ([tex]2^{3}[/tex] = 8).
Now, we need to quickly carry out [tex]\sqrt{64}[/tex]. Square roots are just whatever number can be multiplied by itself to get, in this case, 64.
[tex]\sqrt{64} = 8[/tex].
Finally, we must add what remains.
8 + 8 = 16.
So, (|7 - 3 x 5) | ÷ [tex]4)^{3}[/tex] + [tex]\sqrt{64}[/tex] = 16.
6. For each final matrix, state the solution.
Please answer this picture
The solutions associated with the final matrices representing a system of linear equations are listed below:
First case: x = 3, y = 1, z = 8
Second case: No solution
Third case: No solution
What are the solutions contained in each final matrix?
In this problem we find three of final matrices, each of them representing a system of linear equations. There are two rules to be considered:
A system has no solution if there is a row with only zeroes in the dependent coefficients matrix.A system has a solution if there is a singular matrix, there is, the dependent coefficients matrix has only ones in the main diagonal and the rest of elements are zeroes.Now we proceed to determine the solution associated with each matrix:
First matrix:
x = 3, y = 1, z = 8
Second matrix:
No solution
Third matrix:
No solution
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Step-by-step explanation:
For the left matrix, since the matrix is already in reduced row form,
The solutions to the matrix is (3,-1,8)
For the middle matrix, we need to convert the -6 to a zero,
notice how in the third row, every entry except the last one is 0, this implies that
0=-2, which is not the case thus the middle matrix has no solution.
For the last one, notice that we have 3 colums but only two non zero rows, this means that this matrix has infinite solutions.
This table shows the number of customers who have come in to Trent’s Hobby Shop each day since he opened the doors.
A 2-column table with 4 rows. Column 1 is labeled Number of Days Open with entries 1, 2, 3, 4. Column 2 is labeled Number of customers with entries 3, 11, 24, 30.
Is this function discrete or continuous?
Answer:
a
Step-by-step explanation:
A 18-foot ladder leaning against a building forms an 22angle with the side of the building How far is the base of the ladder from the base of the building?
Answer:
Using the sine function, we have:
sin(angle) = opposite / hypotenuse
sin(22 degrees) = opposite / 18 feet
We can rearrange this equation to solve for the opposite side (height of the building):
opposite = sin(22 degrees) * 18 feet
Calculating this:
opposite ≈ 6.24 feet
Therefore, the base of the ladder from the base of the building is approximately 6.24 feet.
A container holds 2 pounds of peanuts. How many ounces of peanuts are in the container? (1 pound = 16 ounces)
16 ounces
32 ounces
36 ounces
40 ounces '
PLEASEEE HELPPP
A company has recently been hiring new employees. Today the company has 32% more employees than it did a year ago. If there are currently 69,300 employees, how many employees did the company have a year ago?
Answer:
52500
Step-by-step explanation:
Let there be x employees in the previous year
Now, the company has 32% more employees whis is 69300
i.e.
[tex]x + \frac{32}{100} x = 69300\\\\ \implies\frac{132x}{100} = 69300 \\\\\implies 132x = 6930000\\\\\implies x = \frac{6930000}{132}\\[/tex]
⇒ x = 52500
There were 52500 employees in the previous year
25 ÷ 5+7-(4 x 3) Solve the problem is fast as possible
Answer:
Step-by-step explanation:
0
Answer:
0
Step-by-step explanation:
25 ÷ 5+7-(4 x 3)
25 ÷ 5+7-(4 x 3)
5+7-(4 x 3)
5+7-(4 x 3)
5+7-12
12-12
0
I wrote in bold the steps you need to follow using PEMDAS (Parentheses, Exponents, Multiplication and Divison left to right, and Addition and Subtraction left to right).
Please awnser asap I will brainlist
The row operation on the matrix [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex] is [tex]\left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]
How to perform the row operation on the matrixFrom the question, we have the following parameters that can be used in our computation:
[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]
The row operation is given as
1/2R₁
This means that we divide the entries on the first row by 2
Using the above as a guide, we have the following:
[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]
Hence, the row operation on the matrix is [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]
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A rotation of a figure can be considered
A rotation is a geometric transformation that preserves the shape and size of a figure while changing its orientation in space. It is a fundamental concept in geometry and is used in various fields, including art, design, and engineering.
A rotation of a figure can be considered as a transformation that rotates the figure around a fixed point, known as the center of rotation. During the rotation, each point of the figure moves along an arc around the center, maintaining the same distance from the center.
To perform a rotation, we specify the angle of rotation and the direction (clockwise or counterclockwise). The center of rotation remains fixed while the rest of the figure rotates around it. The resulting figure is congruent to the original figure, meaning they have the same shape and size but may be in different orientations.
Rotations are commonly described using positive angles for counterclockwise rotations and negative angles for clockwise rotations. The magnitude of the angle determines the amount of rotation. For example, a 90-degree rotation would result in the figure being turned a quarter turn counterclockwise.
In general, a rotation is a geometric transformation that keeps a figure's size and shape while reorienting it in space. It is a fundamental idea in geometry that is applied in a number of disciplines, including as engineering, design, and the arts.
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Roger can run one mile in 9 minutes. Jeff can run one mile in 6 minutes. If Jeff gives Roger a 1 minute head start, how
long will it take before Jeff catches up to Roger? How far will each have run?
They each will have run of a mile.
It will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.
Let's calculate the time it takes for Jeff to catch up to Roger and the distance each will have run.
First, we need to determine how much distance Roger covers during the 1-minute head start. Since Roger runs one mile in 9 minutes, in 1 minute, he would cover 1/9 of a mile.
Now, let's set up an equation to represent the time it takes for Jeff to catch up to Roger:
Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start
Let's denote the time it takes for Jeff to catch up as t minutes. During this time, Jeff runs a distance of 1 mile, while Roger runs a distance of 1/9 of a mile (from the head start).
Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start
1 mile = (1/9) mile + (6 minutes) × t × (1 mile/6 minutes)
Now, let's solve this equation to find the time it takes for Jeff to catch up:
1 = (1/9) + (1/6)t
Multiplying the equation by the least common multiple (LCM) of 9 and 6, which is 18, to clear the fractions:
18 = 2 + 3t
Subtracting 2 from both sides:
16 = 3t
Dividing by 3:
t = 16/3 = 5.33 minutes (rounded to two decimal places)
Therefore, it will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.
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a 4-foot length of ribbon costs $1.32. how much will it cost to buy 10 yards of ribbon?
Answer:
$3.3
Step-by-step explanation:
4x = 1.32
x = 0.33$ / ft
10x = 10 * 0.33 = 3.3$
A wooden board in the shape of a rectangle prism measures 0.3 m by 2.1 m by 0.1 m and has a mass of 0.17 kilogram. What is the density of the board?
Enter your answer as a decimal in the box. Round your answer to the nearest tenth.
Answer:
Step-by-step explanation:
To find the density of the wooden board, we need to divide the mass of the board by its volume. The volume of a rectangular prism is calculated by multiplying its length, width, and height.
Given:
Length (l) = 0.3 m
Width (w) = 2.1 m
Height (h) = 0.1 m
Mass (m) = 0.17 kg
Volume (V) = l × w × h
V = 0.3 m × 2.1 m × 0.1 m
V = 0.063 m³
Density (ρ) = mass / volume
ρ = 0.17 kg / 0.063 m³
ρ ≈ 2.7 kg/m³
The density of the wooden board is approximately 2.7 kg/m³.
I need help with this problem a s a p.
The calculated vertex of the function y = 2(x + 4)(x - 2) is (-1, -18)
Examining the function for the vertexFrom the question, we have the following parameters that can be used in our computation:
y = 2(x + 4)(x - 2)
Expand the equation
So, we have
y = 2x² + 4x - 16
Differentiate the function and set to 0
So, we have
4x + 4 = 0
So, we have
4x = -4
Evaluate
x = -1
Next, we have
y = 2(-1 + 4)(-1 - 2)
Evaluate
y = -18
This means that the vertex is (-1, -18)
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