The supply and demand curves for a market are graft below with price in dollars and quantity in thousands. Which of the following would result from an increase in the supply curve? a. a market equilibrium price greater than $30 b. A market equilibrium price less than $30 c. A market equilibrium quantity less than $30 d. A market equilibrium quantity greater than $30

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7 times the product of -6 and a number. Let the number be

a. Now, "the product of" means we multiply.

Multiply -6 times a: -6a

If you notice, we write the number before the variable.

Now, multiply 7 times -6a:

7(-6a)

Simplify:

-42a

I hope this helps!

Have a Great Day!

-Content Girl

[tex]\bf{Mysterious^a^n^d\:M^a^gi^ca^l[/tex]

Answer:

Todo terreno+ caballo+caminado=distancia ; (2/5)d+(1/3)d+80=d

Step-by-step explanation:

Let's proof

PQ is the perpendicular bisector Hence

Now apply Pythagorean theorem

[tex]\\ \tt\hookrightarrow PQ^2+QD^2=PD^2[/tex]--(1)

[tex]\\ \tt\hookrightarrow PQ^2+CQ^2=PC^2[/tex]

As QD=CD

[tex]\\ \tt\hookrightarrow PQ^2+QD^2=PC^2[/tex]--(2)

From (1) and (2)

[tex]\\ \tt\hookrightarrow PC^2=PD^2[/tex]

[tex]\\ \tt\hookrightarrow PC=PD[/tex]

Answer:

Given [tex]\overline{\rm PQ}[/tex] is the [tex]\perp[/tex] bisector of [tex]\overline{\rm CD}[/tex]

⇒  [tex]\overline{\rm CQ}=\overline{\rm CD}[/tex]

⇒ ΔPQD ≅ ΔPQC

⇒ CP = PD

Step-by-step explanation:

Given [tex]\overline{\rm PQ}[/tex] is the [tex]\perp[/tex] bisector of [tex]\overline{\rm CD}[/tex]

⇒  [tex]\overline{\rm CQ}=\overline{\rm CD}[/tex]

⇒ ΔPQD ≅ ΔPQC

⇒ CP = PD

Answer:

A:61°

B:72°

C:47°

Explanation:

I took the test and it was correct

According to the question ,

So as per the question if we assume that the babysitter looked after the child for x hours in a week then , the total charge will be ,

→ Charge = $3/hr * x hr= $3x

So the total cost for a week , will be ,

→ Total cost = Base price + Charge

→ Total cost = $25 + $3x

And in the question we are told to assume total cost to be $C . Therefore ,

→ $C = $ (25 +3x)

→ C = 25 + 3x

Hence the required equation is C = 25 + 3x.

I hope this helps.

Here BD is perpendicular bisector

So

[tex]\\ \tt\hookrightarrow UV=74+74=148[/tex]

Apply Pythagorean theorem

[tex]\\ \tt\hookrightarrow BD^2=UD^2-UB^2=UD^2-VD^2[/tex]

[tex]\\ \tt\hookrightarrow TC^2=TD^2-CD^2[/tex]

[tex]\\ \tt\hookrightarrow TC^2=78^2-30^2[/tex]

[tex]\\ \tt\hookrightarrow TC^2=6084-900=5184[/tex]

[tex]\\ \tt\hookrightarrow TC=72[/tex]

Answer:

UV = 148

VD = 78

TC = 72

Step-by-step explanation:

BD is the perpendicular bisector of side UV.

Therefore, ΔUDV is an isosceles triangle.

This implies that UD = VD and BV = UB so UV = 2 x BV

ΔUDC is a right triangle.

Given CD = 30 and UD = 78,

and using Pythagoras' Theorem, we can calculate UC:

UC = √(UD² - CD²)

⇒ UC = √(78² - 30²)

⇒ UC = 72

CD is the perpendicular bisector of side UT.

Therefore, ΔUDT is an isosceles triangle, so UC = TC

Since UC = 72, then TC = 72

Answer:

y = - 7/4 x + 1 1 / 4

Step-by-step explanation:

Answer:

63x + 18

Step-by-step explanation:

9 multiply 7x to give 63x

and 9 multiplies 2 to give 18

Answer:

Option C. 63x +18 is correct.

Step-by-step explanation:

7x ×9= 63x

2×9=18

=63x + 18

Hope it helps.......

The expression which has the greatest value is; Choice B: f(g(-2))

The value of g(f(-4)) when f(x)= 4x+5 and g(x) = 4x^2 -5x - 3 is; 586

Question 1;

From the information given;

Hence, from the options given; upon substitution, it follows that the expression with the greatest value is;

Question 2;

From the task content;

Hence, upon substitution of -4 into the function;

Read more on functions of functions;

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Answer:

It's A :)

Step-by-step explanation:

ur welcome

Answer:

i took the test⬇️

Answer:

a = 10; a = 2

Step-by-step explanation:

Step 1: Use the Pythagorean theorem to solve this equation

    1. Orignal eqaution: (a + 2)² + (a - 5)² = (a + 3)²

    2. Expand (a + 2)² + (a - 5)² which will give us 2a² - 6a + 29

    3. Expand (a + 3)² giving us a² + 6a + 9

    4. Simplified equation: 2a² - 6a + 29 = a² + 6a + 9

Step 2: Subtract 9 from both sides

    1. 2a² - 6a + 29 - 9 = a² + 6a + 9 - 9

    2. Simplify: 2a² - 6a + 20 = a² + 6a

Step 3: Subtract 6a from both sides

    1. 2a² - 6a + 20 - 6a = a² + 6a - 6a

    2. Simplify: 2a² -12a + 20 = a²

Step 4: Subtract a2 from both sides

    1. 2a² - 12a + 20 - a² = a² - a²

    2. Simplify: a² - 12a + 20 = 0

Step 5: Use the quadratic formula to solve for a

    1. Quadratic formula: a = -b += √b² - 4ac/2a

    2. Plug in the correct values: a = -(-12) += √(-12)² + 4(1)(20)/2(1)

    3. Simplify the numerator and denominator: 12 += 8/2

    4. Final equation: a = 12 - 8/2  or a = 12 + 8/2

    5. Hence, the answer is 10 or 2

Answer:

2.5

Step-by-step explanation:

y=ax+b

9= -2a+b <=> b= 9+2a

34=8a+b = 8a+9+2a = 10a + 9

a = (34-9)/10 = 2.5

Answer:

Step-by-step explanation:

Use the slope formula:

The given properties of one pair of parallel sides in the four sided

quadrilateral, indicates that the shape is a trapezium.

Response:

Given that the side with length 6 is parallel to the side with length 8, we

and that the figure is four sided, we have;

The given figure is a trapezium;

Where;

a and b = The lengths of the parallel sides

h = The height of the figure = 5

Which gives;

[tex]Area = \dfrac{6 + 8 }{2} \times 5 = \mathbf{35}[/tex]

Learn more about trapeziums here:

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Answer:35 sq units

Step-by-step explanation:

Answer:

y = 66

Step-by-step explanation:

y=3x+45

putting the value of x in equation which is 7 .

=> y = 3(7)+45

=> y = 21+45

=> y = 66

Answer:

Step-by-step explanation:

Taking the log of both sides, we get:

a log 2 = b log 3

                                                                     b log 3

Dividing both sides by log 2 yields  a = ------------------

                                                                       log 2

Finally, dividing both sides by b yields the desired ratio, a/b:

a         log 3

---- = --------------

b         log 2

Take 2 points

Slope:-

[tex]\\ \rm\hookrightarrow m=\dfrac{6-4}{2+7}[/tex]

[tex]\\ \rm\hookrightarrow m=\dfrac{2}{9}[/tex]

[tex]\\ \rm\hookrightarrow m=0.2[/tex]

Answer:

x=-55

Step-by-step explanation:

(2)(4)+(11)(3)+(13)(2)+2x−8=x+4

Simplify both sides of the equation.

8+33+26+2x+−8=x+4

Combine like terms

(2x)+(8+33+26+−8)=x+4

2x+59=x+4

2x+59=x+4

Subtract from both sides

2x+59−x=x+4−x

x+59=4

Subtract 59 from both sides

x+59−59=4−59

x=−55

The PDF for the wait time (denoted by the random variable X) is

[tex]f_X(x) = \begin{cases}\lambda e^{-\lambda x} & \text{if }x \ge 0 \\ 0 &\text{otherwise}\end{cases}[/tex]

where λ = 1/75. We want to find Pr[X > 70 | X ≥ 40]. Pierre has already been waiting for 40 min, so if he waits another 30 min he will have waited for a total of 70 min.

By definition of conditional probability,

Pr[X > 70 | X ≥ 40] = Pr[X > 70 and X ≥ 40] / Pr[X ≥ 40]

If X > 70, then automatically X ≥ 40 is satisified, so the right side reduces to

Pr[X > 70 | X ≥ 40] = Pr[X > 70] / Pr[X ≥ 40]

Use the PDF or CDF to find the remaining probabilities. For instance, using the PDF,

[tex]\mathrm{Pr}[X > 70] = \displaystyle \int_{-\infty}^{70} f_X(x) \, dx = \int_0^{70} f_X(x) \, dx \approx 0.3932[/tex]

Or, using the CDF,

[tex]F_X(x) = \displaystyle \int_{-\infty}^x f_X(t) \, dt = \begin{cases}0&\text{if }x<0 \\ 1-e^{-\lambda x} & \text{if }x \ge 0\end{cases}[/tex]

[tex]\implies \mathrm{Pr}[X > 70] = 1 - \mathrm{Pr}[X \le 70] = 1 - F_X(70) \approx 0.3932[/tex]

Similarly, you'll find that Pr[X ≥ 40] ≈ 0.5866.

It follows that

Pr[X > 70 | X ≥ 40] ≈ 0.3932 / 0.5866 ≈ 0.6703

Answer:

x = 145

Step-by-step explanation:

The sum of the angles of a quadrilateral is 360

35+x+35+x = 360

2x+70 = 360

Subtract 70 from each side

2x+70-70 = 360-70

2x = 290

Divide by 2

2x/2 =290/2

x = 145

Answer:

x=145

(145+145+35+35=360)

Step-by-step explanation:

This question is very simple to answer if you remember that all parallelograms have two pairs of equal and opposite angles, and that the four angles in any quadrilateral must add up to 360 degrees.

Answer:

8.5

Step-by-step explanation:

For inverse variation of (x, y), x*y = constant

so 4*17 = 8*y

y = 4*17/8 = 17/2 = 8.5

Answer:

551/1650

Step-by-step explanation:

(58/100)(57/99)=551/1650

Answer:

The area of the drawing is 12 Squares

Answer:

-1, 0, 1, 2, 3, 4, 5 are the values greater than -2

Step-by-step explanation:

Let's imagine a number line.

Numbers that are bigger are on the right side of the number line.

The numbers to the right of -2 are:

And so on...

Numbers that would be less than -2 will be on the left side

etc...

-Chetan K

Answer:

-1,0,1,2,3,4,5

ep-by-step explanation:

think of it on a number line

Answer:

  GPA ≈ 2.67

Step-by-step explanation:

Grade points are weighted by credit hours:

  GPA = ∑(grade points×credit hours) / ∑(credit hours)

  GPA = (3×2 +2×4 +4×3 +2×3)/(2 +4 +3 +3)

  = (6 +8 +12 +6)/12 = 32/12 = 2 2/3

  GPA ≈ 2.67

Answer:

I believe the answer is B.1

Answer:

6

Step-by-step explanation:

First divide 9 by 25 to get 0.36 and then divide 3 by 50 to get 0.36 . Finally divide the first result which os 0.36 by the second result which is 0.06 to get 6

Answer:

56

Step-by-step explanation:

8 x 8 = 64

4 x 4 = 16

16/2 = 8

64-8 =56

The average value of f(x) over [2, 6] is given by the definite integral,

[tex]\displaystyle f_{\rm ave[2,6]} = \frac1{6-2} \int_2^6 3\ln(2+x^3)\cos(x) \, dx[/tex]

and is approximately -1.67284.

The approximate average value of the function in the closed interval [2,6] is -1.628.

It is given that the f is the function given by:  [tex]\rm f(x) = 3ln(2+x^2)cosx[/tex]

It is required to find the average value of f in the closed interval [2,6]

It is defined as the mathematical approach to calculating the smaller parts or components.

We have function f:

[tex]\rm f(x) = 3ln(2+x^2)cosx[/tex]

For the average value in [2,6]

We integrate the function with lower limit 2 and higher limit 6.

[tex]\rm \int_{2}^{6}f(x) =\int_{2}^{6}( 3ln(2+x^2)cosx)\\[/tex]

The average value of the above function:

[tex]\rm =\frac{1}{6-2} \int_{2}^{6}( 3ln(2+x^2)cosx)\\[/tex]

Further solving:

[tex]\rm =\frac{3}{4} \int_{2}^{6}( ln(2+x^2)cosx)\\[/tex]

Further solving and applying limits we get:

[tex]=\frac{3}{4}\times-2.2304[/tex]

= -1.628

Thus, the approximate value of the function in the closed interval [2,6]

is -1.628.

Learn more about the integration here:

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