the sum of two numbers is 10, and twice their diffrence is 4. find the two numbers by graphing
Answers
Answer:
One number is 6 and the other number is 4
Step-by-step explanation:
Helping in the name of Jesus.
Related Questions
inequality to show the lower and upper bounds of a number
Answers
You can use inequality signs to show lower and upper bounds of a number.
For example:
Lower bound:
x ≥ 5 (means x is greater than or equal to 5)
Upper bound:
x ≤ 10 (means x is less than or equal to 10)
Together they show a range:
5 ≤ x ≤ 10 (means x is between 5 and 10)
Some other examples:
0 < x < 100 (means x is between 0 and 100)
-10 ≤ y ≤ 50 (means y is between -10 and 50)
-5 < z < 12.5 (means z is between -5 and 12.5)
Does this help explain using inequalities to show boundaries or ranges of numbers? Let me know if you have any other questions!
For the lower bound, we can use the inequality:
LB ≤ x
where LB is the lower bound and x is the number we're interested in. This inequality tells us that x is greater than or equal to the lower bound.
For the upper bound, we can use the inequality:
x ≤ UB
where UB is the upper bound and x is the number we're interested in. This inequality tells us that x is less than or equal to the upper bound.
Putting these two inequalities together, we get:
LB ≤ x ≤ UB
This inequality tells us that x is between the lower and upper bounds, inclusive.
find the slope of the parametric curve x=-2t^3 7, y=3t^2, for , at the point corresponding to t
Answers
The slope of the parametric curve x=-[tex]2t^3[/tex]+7, y=3t² at the point corresponding to t is -1 divided by t.
How to find slope of the parametric curve?To find the slope of the parametric curve x=-[tex]2t^3[/tex]+7, y=3t², we need to take the derivative of y with respect to x.
To do this, we can use the chain rule:
(dy/dx) = (dy/dt) / (dx/dt)
where (dx/dt) is the derivative of x with respect to t, and (dy/dt) is the derivative of y with respect to t.
Taking the derivatives, we get:
dx/dt = -6t²
dy/dt = 6t
Substituting these values, we get:
(dy/dx) = (dy/dt) / (dx/dt) = (6t) / (-6t²) = -1/t
So, the slope of the curve at the point corresponding to t is -1/t.
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write a recursive formula sequence that represents the sequence defined by the following explicit formula a_n= -5(-2)^n+1
a1=
an= (recursive)
Answers
Answer:
[tex]\left \{ {{a_1=1} \atop {a_n=a_{n-1}-5}} \right.[/tex]
Step-by-step explanation:
The recursive formula of an arithmetic sequence is[tex]\left \{ {{a_1=x} \atop {a_n=a_{n-1}+d}} \right.[/tex]. Plugging in each value ([tex]a_1 = 1, d=-5[/tex]) gives us the recursive formula [tex]\left \{ {{a_1=1} \atop {a_n=a_{n-1}-5}} \right.[/tex].
Given the following set of functional dependencies F= { UVX->UW, UX->ZV, VU->Y, V->Y, W->VY, W->Y } Which ONE of the following is correct about what is required to form a minimal cover of F? Select one: a. It is necessary and sufficient to remove a dependency W->Y from F to form a minimal cover
Answers
The correct answer is: It is necessary to apply both the decomposition and the augmentation rules to F in order to form a minimal cover.
To form a minimal cover of a set of functional dependencies, we need to apply the decomposition rule, which involves breaking down each dependency in F into its simplest form, and the augmentation rule, which involves adding any missing attributes to the right-hand side of each dependency. In this case, we need to apply both rules to F to obtain a minimal cover.
For example, applying the decomposition rule to UVX->UW yields two dependencies: UV->UW and UX->UW. Applying the augmentation rule to UX->ZV yields UX->ZVY. Continuing in this way, we can obtain a minimal cover for F, which is:
UV->UW
UX->ZVY
VU->Y
V->Y
W->VY
a. It is necessary and sufficient to remove a dependency W->Y from F to form a minimal cover.
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Find the t values for each of the following cases
A) upper tail area of .025 with 12 degrees of freedom
B) Lower tail area of .05 with 50 degrees of freedom
C) Upper tail area of .01 with 30 degrees of freedom
D) where 90% of the area falls between these two t values with 25 degrees of freedom
E) Where 95% of the area falls bewteen there two t valies with 45 degrees of freedom
Answers
According to the information, we can find that the t-value for the lower endpoint is approximately -1.684, and the t-value for the upper endpoint is approximately 1.684.
How to find the t-values for each of the cases?To find the t-values for each of the given cases, we can use a t-distribution table or a calculator. Here are the answers for each case:
A) Upper tail area of .025 with 12 degrees of freedom:
The t-value for an upper tail area of .025 with 12 degrees of freedom is approximately 2.179.
B) Lower tail area of .05 with 50 degrees of freedom:
The t-value for a lower tail area of .05 with 50 degrees of freedom is approximately -1.677.
C) Upper tail area of .01 with 30 degrees of freedom:
The t-value for an upper tail area of .01 with 30 degrees of freedom is approximately 2.750.
D) Where 90% of the area falls between these two t values with 25 degrees of freedom:
We need to find the t-values that correspond to the middle 90% of the t-distribution with 25 degrees of freedom. This means that we want to find the t-values that divide the area under the curve into two equal parts, each with 45% of the area.
Using a t-distribution table or a calculator, we can find that the t-value for the lower endpoint is approximately -1.708, and the t-value for the upper endpoint is approximately 1.708.
E) Where 95% of the area falls between these two t values with 45 degrees of freedom:
We need to find the t-values that correspond to the middle 95% of the t-distribution with 45 degrees of freedom. This means that we want to find the t-values that divide the area under the curve into two equal parts, each with 2.5% of the area.
Using a t-distribution table or a calculator, we can find that the t-value for the lower endpoint is approximately -1.684, and the t-value for the upper endpoint is approximately 1.684.
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From a random sample of 43 business days, the mean closing price of a certain stock was $112.15. Assume the population standard deviation is $9.95. The 90% confidence interval is (Round to two decimal places as needed.) The 95% confidence interval is (Round to two decimal places as needed.) Which interval is wider?
A. You can be 90% confident that the population mean price of the stock is outside the bounds of the 90% confidence interval, and 95% confident for the 95% interval.
B. You can be certain that the population mean price of the stock is either between the lower bounds of the 90% and 95% confidence intervals or the upper bounds of the 90% and 95% confidence intervals.
C. You can be 90% confident that the population mean price of the stock is between the bounds of the 90% confidence interval, and 95% confident for the 95% interval.
D. You can be certain that the closing price of the stock was within the 90% confidence interval for approximately 39 of the 43 days, and was within the 95% confidence interval for approximately 41 of the 43 days
Answers
You can be 90% confident that the population mean price of the stock is between the bounds of the 90% confidence interval, and 95% confident for the 95% interval.
Given data ,
The problem states that a random sample of 43 business days was taken, and the mean closing price of the stock in that sample was $112.15. The population standard deviation is assumed to be $9.95. Based on this information, a confidence interval can be calculated for the population mean.
Now , A wider interval results from a greater confidence level since it calls for more assurance.
If you compare the offered alternatives, option C accurately indicates that you can have a 90% confidence interval for the population mean price of the stock being inside the boundaries, and a 95% confidence interval. Because a 90% confidence interval demands more assurance than a 95% confidence interval, it is smaller. As a result, the population mean is more likely to fall inside the 90% confidence interval's boundaries.
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Bookwork code: H16
The pressure that a box exerts on a shelf is 200 N/m
The force that the box exerts on the shelf is 140 N.
Work out the area of the base of the box.
If your answer is a decimal, give it to 1 d.p.
Answers
Answer:
The pressure exerted by the box on the shelf is given by the formula:
Pressure = Force / Area
where Pressure is measured in Newtons per square meter (N/m^2), Force is measured in Newtons (N), and Area is measured in square meters (m^2).
We are given that the pressure exerted by the box on the shelf is 200 N/m and the force that the box exerts on the shelf is 140 N. Using the formula above, we can solve for the area of the base of the box as follows:
200 N/m = 140 N / Area
Simplifying the equation above, we can multiply both sides by the Area to get:
Area * 200 N/m = 140 N
Dividing both sides by 200 N/m, we get:
Area = 140 N / 200 N/m
Simplifying the right-hand side, we get:
Area = 0.7 m^2
Therefore, the area of the base of the box is 0.7 square meters, or 0.7 m^2 to 1 decimal place.
Answer:
0.7 m²
Step-by-step explanation:
The pressure exerted by the box on the shelf is defined as the force per unit area, so we can use the formula:
[tex]\boxed{\sf Pressure = \dfrac{Force}{Area}}[/tex]
We need to determine the area of the base of the box, so we can rearrange the formula to solve for area:
[tex]\boxed{\sf Area= \dfrac{Force}{Pressure}}[/tex]
Given values:
Pressure = 200 N m⁻²Force = 140 NSubstitute the given values into the formula:
[tex]\implies \sf Area = \dfrac{140\;N}{200\;N\;m^{-2}}[/tex]
[tex]\implies \sf Area = \dfrac{140}{200}\;m^2[/tex]
[tex]\implies \sf Area = 0.7\;m^2[/tex]
Therefore, the area of the base of the box is 0.7 square meters.
approximate the value of the series to within an error of at most 10−3. ∑n=1[infinity](−1)n 1(n 2)(n 6)
According to Equation (2):
|SN−S|≤aN+1
what is the smallest value of N that approximates S to within an error of at most 10^(−5)?
N=
S≈
Answers
S ≈ -0.0010 (rounded to four decimal places).
To approximate the value of the series ∑n=1infinityn / (n^2)(n^6) within an error of at most 10^(-3), we can use the alternating series test and the remainder formula.
The series is alternating because the sign alternates between positive and negative. Moreover, the terms of the series are decreasing in absolute value because:
|(-1)^(n+1) / (n^2)(n^6)| < |(-1)^(n) / ((n+1)^2)((n+1)^6)| for all n
Therefore, we can apply the alternating series test and bound the error by the absolute value of the first neglected term:
|R_N| = |-1^(N+1) / (N+1)^2((N+1)^6)|
To find the smallest value of N that approximates S to within an error of at most 10^(-5), we need to solve the inequality:
|R_N| = |-1^(N+1) / (N+1)^2((N+1)^6)| ≤ 10^(-5)
Solving for N, we get:
N ≥ 14
Thus, the smallest value of N that approximates S to within an error of at most 10^(-5) is N=14.
To approximate S, we can sum the first 14 terms of the series:
S ≈ ∑n=114^n / (n^2)(n^6)
Using a calculator or a computer algebra system, we get:
S ≈ -0.00102583...
Therefore, S ≈ -0.0010 (rounded to four decimal places).
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what is quadratic equation
Answers
A quadratic equation is a polynomial equation of the second degree, meaning it contains at least one variable that is squared but no variables that are raised to a higher power. The general form of a quadratic equation in one variable (usually represented by x) is:
�
�
2
+
�
�
+
�
=
0
,
ax
2
+bx+c=0,
where a, b, and c are constants (numbers) and a is not equal to zero. The term ax^2 is called the quadratic term, bx is the linear term, and c is the constant term.
To solve a quadratic equation, we can use the quadratic formula:
�
=
−
�
±
�
2
−
4
�
�
2
�
.
x=
2a
−b±
b
2
−4ac
.
This formula gives us the solutions (values of x) for any quadratic equation in the standard form. The expression under the square root, b^2 - 4ac, is called the discriminant of the quadratic equation.
The discriminant can tell us a lot about the nature of the solutions of the quadratic equation. If the discriminant is positive, then the quadratic equation has two distinct real solutions. If the discriminant is zero, then the quadratic equation has one real solution, called a double root or a repeated root. If the discriminant is negative, then the quadratic equation has two complex (non-real) solutions, which are conjugates of each other.
homogeneous system of two linear differential equations with constant coefficients can be dx x(t) dt written as X=AX, where X = X = and A is 2x2 matrix_ y(t) dy dt Write down a fundamental system of differential equations with the created in Problem matrix A b) Rewrite the system of differential equations as one 2ud order linear differential equation using differentiation second time of the Ist equation of the system or by using the characteristic equation obtained in Problem 7_
Answers
(a) The fundamental system of differential equation is X(t) = c1 [tex]e^\((\lambda 1t)[/tex]v1 + c2 [tex]e^\((\lambda 1t)[/tex]v2
(b) The second-order linear differential equation with constant coefficients is d²x/dt² = (ad - bc)dx/dt + ([tex]a^2d + b^2c[/tex])x
How to find Homogeneous system of two linear differential equations with constant coefficients.?(a) The homogeneous system of two linear differential equations with constant coefficients can be written as:
dx/dt = ax + bydy/dt = cx + dywhere a, b, c, and d are constants.
We can write this system as X' = AX, where X =[tex][x, y]^T[/tex] and A is the 2x2 matrix:
A = [a b][c d]To find a fundamental system of differential equations, we need to find the eigenvalues and eigenvectors of A.
The characteristic equation of A is:
det(A - λI) = 0=> (a-λ)(d-λ) - bc = 0=> λ² - (a+d)λ + (ad-bc) = 0The eigenvalues of A are the roots of the characteristic equation:
λ1,2 = (a+d ± [tex]\sqrt^(a+d)^2[/tex] - 4(ad-bc))) / 2
The eigenvectors of A are the solutions to the equation (A - λI)v = 0, where v is a non-zero vector.
If λ1 and λ2 are distinct eigenvalues, then the eigenvectors corresponding to each eigenvalue form a fundamental system of differential equations. Specifically, if v1 and v2 are eigenvectors corresponding to λ1 and λ2, respectively, then the solutions to the differential equation X' = AX are given by:
X(t) = c1 [tex]e^\((\lambda 1t)[/tex] v1 + c2 [tex]e^\((\lambda 1t)[/tex] v2
where c1 and c2 are constants determined by the initial conditions.
If λ1 and λ2 are not distinct (i.e., they are repeated), then we need to find a set of linearly independent eigenvectors to form a fundamental system of differential equations. In this case, we use the method of generalized eigenvectors.
(b) To rewrite the system of differential equations as one 2nd order linear differential equation, we can differentiate the first equation with respect to t to obtain:
d²x/dt² = a(dx/dt) + b(dy/dt)=> d²x/dt² = a(ax + by) + b(cx + dy)=> d²x/dt² = (a² + bc)x + (ab + bd)ySubstituting the second equation into the last expression, we get:
d²x/dt² = (a² + bc)x + (ab + bd)(-cx + d(dx/dt))
Simplifying, we obtain:
d²x/dt² = (ad - bc)dx/dt + (a²d + b²c)x
This is a second-order linear differential equation with constant coefficients.
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write the equations in cylindrical coordinates. (a) 2x2 − 9x 2y2 z2 = 3 (b) z = 7x2 − 7y2
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The equation 2x^2 - 9x^2y^2z^2 = 3 in cylindrical coordinates is 2r^2 * cos^2(θ) - 9r^4 * cos^2(θ) * sin^2(θ) * z^2 = 3 and the equation z = 7x^2 - 7y^2 in cylindrical coordinates is z = 7r^2 * cos^2(θ) - 7r^2 * sin^2(θ).
The cylindrical coordinate system uses three parameters: radius (r), azimuthal angle (θ), and height (z). To convert from Cartesian coordinates (x, y, z) to cylindrical coordinates (r, θ, z), we use the following relations:
x = r * cos(θ)
y = r * sin(θ)
z = z
(a) 2x^2 - 9x^2y^2z^2 = 3
Replace x and y with their cylindrical counterparts:
2(r * cos(θ))^2 - 9(r * cos(θ))^2(r * sin(θ))^2z^2 = 3
Simplify the equation:
2r^2 * cos^2(θ) - 9r^4 * cos^2(θ) * sin^2(θ) * z^2 = 3
This is the equation 2x^2 - 9x^2y^2z^2 = 3 in cylindrical coordinates.
(b) z = 7x^2 - 7y^2
Replace x and y with their cylindrical counterparts:
z = 7(r * cos(θ))^2 - 7(r * sin(θ))^2
Simplify the equation:
z = 7r^2 * cos^2(θ) - 7r^2 * sin^2(θ)
This is the equation z = 7x^2 - 7y^2 in cylindrical coordinates.
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The growth model Eq. (5.18) was fitted to several U.S. economic time series and the following results were obtained: a. In each case find out the instantaneous rate of growth. b. What is the compound rate of growth in each case? c. For the S&P data, why is there a difference in the two slope coefficients? How would you reconcile the difference?
Answers
a. The instantaneous rate of growth can be found by taking the derivative of the growth model Eq. (5.18) with respect to time.
b. The compound rate of growth can be calculated by using the formula: [(1+instantaneous rate of growth)ⁿ]-1, where n is the number of periods.
c. The difference in the two slope coefficients for the S&P data may be due to changes in the underlying economic conditions or external factors affecting the market. To reconcile the difference, a more detailed analysis should be conducted to identify the specific factors contributing to the change in slope coefficients.
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Drag the tiles to the boxes to form correct pairs.
What are the unknown measurements of the triangle? Round your answers to the nearest hundredth as needed.
Answers
The values of the missing sides and angles using trigonometric ratios are:
b = 7.06
c = 3.76
C = 28°
How to use trigonometric ratios?The six trigonometric ratios are sine, cosine, tangent, cosecant, secant, and cotangent.
The symbols used for them are:
sine: sin
cosine: cos
tangent: tan
cosecant: csc
secant: sec
cotangent: cot
The trigonometric ratios are defined as the ratio of the sides in right triangles.
Using trigonometric ratios, we have:
b/8 = sin 62
b = 8 * sin 62
b = 7.06
Similarly:
c/8 = cos 62
c = 8 * cos 62
c = 3.76
Sum of angles in a triangle is 180 degrees. Thus:
C = 180 - (90 + 62)
C = 28°
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The graph shows the distance a horse ran in miles
per minute. A fox ran at a rate of .8 miles per
minute. Find the unit rate in miles per hour of the
horse using the graph. Then compare the horse with
the fox. Which statement about their speeds is true?
a. The horse traveled 8 miles per minute
b. The fox traveled 5 miles per minute
c. The fox was 0.3 miles/minute faster than the horse
d. The horse and the coyote traveled at the same rate
Answers
When the unit rate of the horse and the fox is compared, the statement that is true about them will be that The fox was 0.3 miles/minute faster than the horse. That is option C.
How to calculate the unit rate in miles per hour?From the graph,
30 miles distance covered by the horse = 60 mins
But 60 mins = 1 hours
Therefore, the rate of distance covered by the horse = 30 miles/hr.
But the rate of distance covered in miles/ min = 5/10 = 0.5 miles/min.
If the fox covers 0.8miles/min then the difference between it and the horse = 0.8-0.5 = 0.3miles/min.
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For the figure above, find the following: (PLEASE just type your numerical answer, do NOT include the units!)
Perimeter = m
Area = m²
Answers
Answer:
perimeter = 22
area = 26
5. invests $25,000 in a retirement fund that earns a 4.03% annual interest rate which is compounded continuously. The formula that shows the value in the account after tyears is A(t) = 250000.04036 A. (4 pts) What is the value of account after 10 years? (Round to 2 decimal places) Label with the correct units.
Answers
Since your retirement fund earns a 4.03% annual interest rate compounded continuously, we'll need to use the continuous compounding formula: A(t) = P * e^(rt)
where:
A(t) = value of the account after t years
P = principal amount (initial investment)
e = the base of the natural logarithm, approximately 2.718
r = interest rate (as a decimal)
t = number of years
Given that you've invested $25,000 (P) at a 4.03% interest rate (r = 0.0403), we'll find the value of the account after 10 years (t = 10).
A(10) = 25000 * e^(0.0403 * 10)
Now, calculate the value:
A(10) = 25000 * e^0.403
A(10) = 25000 * 1.4963 (rounded to 4 decimal places)
Finally, find the total value:
A(10) = 37357.50
After 10 years, the value of the account will be $37,357.50 (rounded to 2 decimal places).
Note that there is no indication of fraud in this scenario, and the interest rate used is 4.03%.
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Graph the following equation on the coordinate plane: y=2/3×+1
Answers
The correct graph of equation on the coordinate plane is shown in figure.
We know that;
The equation of line with slope m and y intercept at point b is given as;
y = mx + b
Here, The equation is,
y = 2/3x + 1
Hence, Slope of equation is, 2/3
And, Y - intercept of the equation is, 1
Thus, The correct graph of equation on the coordinate plane is shown in figure.
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2y = 3x - 16
y + 2x > -5
Answers
Answer:
Step-by-step explanation:
To solve this system of inequalities, we can first rearrange the first equation to solve for y:
2y = 3x - 16
y = (3/2)x - 8
Now we can substitute this expression for y into the second inequality:
y + 2x > -5
(3/2)x - 8 + 2x > -5
(7/2)x > 3
x > 6/7
So the solution to the system of inequalities is:
y > (-5 - 2x)
x > 6/7
Answer:
no solution
no absolute max or min
Step-by-step explanation:
For each geometric sequence given, write the next three terms a4, a5, and ag.
3, 6, 12,
a4 =____
a5= ____
a6= ____
Answers
The next three terms in the given geometric sequence are 24, 48, and 96
To find the next terms in the geometric sequence 3, 6, 12, we need to find the common ratio (r) first.
r = 6/3 = 2
Now we can use the formula for the nth term of a geometric sequence:
an = a1 * r^(n-1)
where n+1 is the nth term, a1 is the first term, r is the common ratio, and n is the term number.
Using this formula, we can find:
a4 = 24 (3 * 2^3)
a5 = 48 (3 * 2^4)
a6 = 96 (3 * 2^5)
Therefore, the next three terms in the sequence are 24, 48, and 96.
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Suppose a firm has a variable cost function VC = 20Q withavoidable fixed cost of $50,000. What is the firm's average costfunction?A. AC= 50,000 +20QB. AC = 50,000/Q +20C. AC = 50,000 + 40QD. AC = 20
Answers
Answer:
The formula for average cost (AC) is:
AC = (Total cost / Quantity)
To find the total cost, we need to add the variable cost (VC) and the avoidable fixed cost:
Total cost = VC + Fixed cost
Total cost = 20Q + 50,000
Now we can substitute this into the formula for average cost:
AC = (Total cost / Quantity)
AC = (20Q + 50,000) / Q
Simplifying this expression gives:
AC = 50,000/Q + 20
Therefore, the firm's average cost function is:
AC = 50,000/Q + 20
So, the correct answer is B.
17. A quadratic equation of the form 3x^2+bx+c=0 has roots of 6 plus or minus square root of 2. Determine the value of c.
Answers
The value of c in the quadratic equation given is 32.
Solving Quadratic EquationGiven a quadratic equation of the form 3x² + bx + c = 0 has roots of 6 plus or minus square root of 2, we know that the quadratic equation can be written as:
3(x - (6 + √2))(x - (6 - √2)) = 0
Expanding this product gives:
3[(x - 6 - √2)(x - 6 + √2)] = 0
Using the difference of squares, we can simplify this expression to:
3[(x - 6)² - (√2)²] = 0
3(x - 6)² - 6 = 0
Multiplying out the squared term, we get:
3x² - 36x + 102 - 6 = 0
Simplifying, we get:
3x² - 36x + 96 = 0
Dividing both sides by 3, we get:
x² - 12x + 32 = 0
Therefore, the value of c is 32.
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Nanette must pass through three doors as she walks from her company's foyer to her office. Each of these doors may be locked or unlocked. List the outcomes of the sample space. a. {L_L, LLU, LUL, LUU, ULL, ULU, UUL, UUU} b. {LLU, LUL, ULL, UUL, ULL, LUU} c. {LLL, UUU} d. None of these.
Answers
The correct answer is d. None of these.
What are the possible outcomes of Nanette passing through three doors?a. {L_L, LLU, LUL, LUU, ULL, ULU, UUL, UUU} represents the sample space of possible outcomes, where L represents a locked door and U represents an unlocked door. Each outcome represents a possible combination of locked and unlocked doors that Nanette may encounter.
b. {LLU, LUL, ULL, UUL, ULL, LUU} is not a complete sample space, as it is missing some possible outcomes. For example, the outcome where all doors are locked (LLL) is not included.
c. {LLL, UUU} is also not a complete sample space, as it only includes two possible outcomes. There are other possible combinations of locked and unlocked doors that are not represented.
Therefore, the correct answer is d. None of these. The complete sample space would include all possible combinations of locked and unlocked doors for the three doors that Nanette must pass through.
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Given RT = a + b log 2(N), calculate the decision complexity advantage for 10 decisions with two alternatives compared to one decision with 20 alternatives. Assume a = 1 s and b = 2 s/bit
Answers
The decision complexity advantage for 10 decisions with two alternatives compared to one decision with 20 alternatives is 3.31. This can be answered by the concept of Log.
To calculate the decision complexity advantage, we need to first plug in the given values for a and b into the formula RT = a + b log2(N), where N is the number of alternatives.
For 10 decisions with two alternatives each, N = 2¹⁰ = 1024. Thus, RT = 1 + 2 log2(1024) = 22 seconds.
For one decision with 20 alternatives, N = 20. Thus, RT = 1 + 2 log2(20) = 6.64 seconds.
The decision complexity advantage is calculated by taking the ratio of the RT values: 22/6.64 = 3.31. This means that making 10 decisions with two alternatives each is 3.31 times faster than making one decision with 20 alternatives.
Therefore, the decision complexity advantage for 10 decisions with two alternatives compared to one decision with 20 alternatives is 3.31.
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help asap, show work pls. find the vertices and name two points on the minor axis.
9x^2+y^2-18x-6y+9=0
Answers
Answer:
To find the vertices and name two points on the minor axis of the ellipse represented by the equation 9x^2+y^2-18x-6y+9=0, we need to first put it in standard form by completing the square for both x and y terms.
Starting with the x terms:
9x^2 - 18x = 0
9(x^2 - 2x) = 0
We need to add and subtract (2/2)^2 = 1 to complete the square inside the parentheses:
9(x^2 - 2x + 1 - 1) = 0
9((x-1)^2 - 1) = 0
9(x-1)^2 - 9 = 0
9(x-1)^2 = 9
(x-1)^2 = 1
x-1 = ±1
x = 2 or 0
Now we can do the same for the y terms:
y^2 - 6y = 0
y^2 - 6y + 9 - 9 = 0
(y-3)^2 - 9 = 0
(y-3)^2 = 9
y-3 = ±3
y = 6 or 0
So the center of the ellipse is (1, 3), the major axis is along the x-axis with a length of 2a = 2√(9/1) = 6, and the minor axis is along the y-axis with a length of 2b = 2√(1/9) = 2/3.
The vertices are the points on the major axis that are farthest from the center. Since the major axis is along the x-axis, the vertices will be (1±3, 3), or (4, 3) and (-2, 3).
To find two points on the minor axis, we can use the center and the length of the minor axis. Since the minor axis is along the y-axis, we can add or subtract the length of the minor axis from the y-coordinate of the center to find the two points. Therefore, the two points on the minor axis are (1, 3±1/3), or approximately (1, 10/3) and (1, 8/3).
Step-by-step explanation:
in this problem, p is in dollars and q is the number of units. find the elasticity of the demand function 2p 3q = 90 at the price p = 15
Answers
Your answer: The elasticity of the demand function 2p 3q = 90 at the price p = 15 is -0.5.
To find the elasticity of the demand function, we need to use the following formula:
Elasticity = (dq/dp) * (p/q)
where dq/dp is the derivative of q with respect to p, and (p/q) is the ratio of the two variables at a given point.
First, we need to solve the demand function for q in terms of p:
2p + 3q = 90
3q = 90 - 2p
q = (90 - 2p)/3
Next, we need to find the derivative of q with respect to p:
dq/dp = (-2/3)
Finally, we can plug in the values for p and q to find the elasticity at p = 15:
q = (90 - 2(15))/3 = 20
(p/q) = 15/20 = 0.75
Elasticity = (-2/3) * (15/20) = -0.5
Therefore, the elasticity of the demand function 2p + 3q = 90 at the price p = 15 is -0.5. This means that a 1% increase in price would lead to a 0.5% decrease in quantity demanded.
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A matrix A has the following LU factorization A = [1 0 1 -2 1 0 -1 2 1] [2 3 4 0 -4 3 0 0 -1], b = [4 17 43] To find the solution to Ax = b using the LU factorization, we would first solve the system LY= [] and then solve the system Ux= [] the second system yields the solution x = []
Answers
The solution to Ax=b using the LU factorization is: x = [27 -23/4 -30]
To find the solution to the system Ax=b using the LU factorization:
We need to first decompose the matrix A into its lower and upper triangular matrices L and U respectively, such that A = LU.
Using the given LU factorization of A, we can write:
L = [1 0 0] [1 0 0] [-1 3 1]
U = [2 3 4] [0 -4 3] [0 0 -1]
Next, we need to solve the system LY=b. We can substitute L and Y with their corresponding matrices and variables respectively:
[1 0 0] [1 0 0] [-1 3 1] [y1 y2 y3] = [4 17 43]
Simplifying this system, we get:
y1 = 4
y2 = 17
-y1 + 3y2 + y3 = 43
Solving for y3, we get:
y3 = 30
Now that we have the values for Y, we can solve the system Ux=Y to get the solution to Ax=b.
We can substitute U and X with their corresponding matrices and variables respectively:
[2 3 4] [0 -4 3] [0 0 -1] [x1 x2 x3] = [y1 y2 y3]
Simplifying this system, we get:
2x1 + 3x2 + 4x3 = 4
-4x2 + 3x3 = 17
-x3 = 30
Solving for x3, we get:
x3 = -30
Substituting x3 into the second equation, we get:
-4x2 + 3(-30) = 17
Solving for x2, we get:
x2 = -23/4
Substituting x2 and x3 into the first equation, we get:
2x1 + 3(-23/4) + 4(-30) = 4
Solving for x1, we get:
x1 = 27
Therefore, the solution to Ax=b using the LU factorization is:
x = [27 -23/4 -30]
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suppose x is a continuous variable with the following probability density: f(x)={c(10−x)2, if 0
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Given that x is a continuous variable with the probability density function f(x) = c(10-x)^2 for 0 < x < 10, we need to find the value of c.
Step 1: Understand that for a probability density function, the total area under the curve must equal 1. Mathematically, this is expressed as:
∫[f(x)] dx = 1, with integration limits from 0 to 10.
Step 2: Substitute f(x) with the given function and integrate:
∫[c(10-x)^2] dx from 0 to 10 = 1
Step 3: Perform the integration:
c ∫[(10-x)^2] dx from 0 to 10 = 1
Step 4: Apply the power rule for integration:
c[(10-x)^3 / -3] from 0 to 10 = 1
Step 5: Substitute the integration limits:
c[(-1000)/-3 - (0)/-3] = 1
Step 6: Solve for c:
(1000/3)c = 1
c = 3/1000
c = 0.003
So the probability density function f(x) = 0.003(10-x)^2 for 0 < x < 10.
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Solve the following quadratic equation, leaving your answer in exact form:
4e^2 - 15e = -4
e =
or e =
Answers
The solution of the quadratic equation 4e² - 15e = -4 in the exact form is e = (15 + √161)/8 or e = (15 - √161)/8
To solve the quadratic equation 4e² - 15e = -4, we can rearrange it into standard form as follows,
4e² - 15e + 4 = 0. We can then use the quadratic formula, which states that for an equation in the form ax² + bx + c = 0, the solutions are given by,
x = (-b ± √(b² - 4ac)) / 2a
Applying this formula to our equation, we have,
e = (-(-15) ± √((-15)² - 4(4)(4))) / 2(4)
Simplifying this expression, we get,
e = (15 ± √(225 - 64)) / 8
e = (15 ± √161) / 8
Therefore, the solutions to the equation 4e² - 15e = -4 are:
e = (15 + √161) / 8 or e = (15 - √161) / 8
These are exact solutions in radical form.
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2.a) Find the limit of
lim |x-1|÷x-1
x_1
Answers
Answer:
Lim
x - 1
Step-by-step explanation:
(x-1)
(|x-1|)
Pls help (part 1)
Find the volume!
Give step by step explanation!
Answers
The triangular prism has 3 cylindrical holes with a diameter of 4 cm. The volume of each hole is approximately 60π cubic centimeters, so the total volume of all three holes is about 180π cubic centimeters.
To find the volume of cylindrical holes in the triangular prism, we need to calculate the volume of one cylinder and then multiply it by three (since there are three cylindrical holes).
Volume of one cylinder = πr²h, where r is the radius of the cylinder and h is the height.
Given the diameter of the cylindrical hole is 4 cm, we can find the radius by dividing it by 2
radius (r) = 4 cm ÷ 2 = 2 cm
The height of the cylinder is the same as the length of the prism, which is 15 cm.
Volume of one cylinder = π(2 cm)² × 15 cm
= 60π cm³
Since there are three cylindrical holes, the total volume of the holes is
Total volume of cylindrical holes = 3 × 60π cm³
= 180π cm³
Therefore, the volume of the three cylindrical holes is 180π cubic centimeters.
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--The given question is incomplete, the complete question is given
" Pls help (part 1)
Find the volume of 3 cylindrical holes.
Give step by step explanation! "--