The standard height from the floor to the bull's-eye at which a standard dartboard is hung is 5 feet 8 inches. A standard dartboard is
18 inches in diameter.
Suppose a standard dartboard is hung at standard height so that the bull's-eye is 11 feet from a wall to its left.
Samuel throws a dart at the dartboard that lands at a point 11.5 feet from the left wall and 5.5 feet above the floor.
Does Samuel's dart land on the dartboard?

Answer: 37.50-18.30+4.80h

Answer:

Yes to both

Step-by-step explanation:

Answer:

52

Step-by-step explanation:

156:    22       313

260:    22        513

GCF:    22         13

The Greatest Common Factor (GCF) is:   2 x 2 x 13 = 52

Answer:

grapgh?????

Step-by-step explanation:

Answer:

I think its 300

Step-by-step explanation

This is from my understanding, so I may be a bit wrong.

1. First observe the amount of triangles that form, you have two main triangles and one isosceles triangle that forms in the middle by how these are joined together.

2. Using this idea we will come up  with the equations of  each triangle that has been formed.

3. We can observe that almost all angles are named with a variable except the one in the middle, being an isosceles we will name the missing variable y.

4. Triangle 1(left side) or T1 equals 180 degrees but what angles form this triangle, these would be p+q+y = 180, T2(right side) = r+s+y = 180

5. After creating these two triangles we notice that we have not taken into account the triangle in the middle, we are given 1 angle of this isosceles. There is a mathematical property which I don't remember the name, but essentially the angle below is the same as the angle above, this being 120 degrees. This will result in T3 = 2y + 120 = 180

6. Solve for y, which gives us y=30, *simple triangle math you know*

7. Finally we fix our equations for p+q+r+s, essentially T1 and T2 will transform into p+q = 180-y and r+s = 180-y, we add them up forming p+q+r+s = 2(180-y)

8. Solve the equation p+q+r+s = 360 - 2y which when adding y becomes p+q+r+s = 360-60 = 300

Notes: when doing these exercises it is important to take into account every triangle, the isosceles triangle is very vital for solving it, as it gives us a way for making an equation that is single handedly dependent on y a constant we can find and use. A good approach for these issues would be writing every piece of information as separate sets and then trying to join them using algebra.

Answer: x=7

Step-by-step explanation:

Answer:

40,000

Step-by-step explanation:

You just add 60,000 and 30,000 which makes 90,000 and subtract it with the 50,000 then which equals to 40,000. you don't need to rate me.

Answer:

3x^2-x-2 or (x+1) (3x-2) (x-2)

Step-by-step explanation:

I'm assuming you have to divide:

(x-2)[tex]\sqrt{3x^3-5x^2-4x+4}[/tex]

Hope this helps.

Answer:

p(x)=(x+1)(3x-2)(x-2)

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

$140

Step-by-step explanation:

8x+6x

Answer:

about 1854.55 miles (rounded to the hundredth)

Step-by-step explanation:

1.

[tex] \frac{44}{100} = \frac{816}{x} [/tex]

The first fraction represent the percentage of the distance.

The second one represent the number of 816 miles out of x

2. 100 × 816 = 44 × x

3. You'll get 81,600 = 44x

4. and then you divided both side by 44 to solve for x

Answer:

the correct answer would be -2f+7

Answer:

$2.50

Step-by-step explanation:

to find the unit price you would divide it by 23

so 57.50/23=2.50

hope this helps

brainliest?

Answer:

Step-by-step explanation:

3 7/10 *7

37/10 *7

259/10

25.9 or 25 9/10

Answer:

Both castles will have the same height at 3.33 minutes

Step-by-step explanation:

This problem will be solved with linear modeling, that is, expressing both people's sand castle's height as a function of time.

Justin built a sandcastle 180 cm tall, and its height is losing at 8 cm/min by the effect of wind. Thus, the height of Justin's sandcastle is:

[tex]H_J=180-8t[/tex]

Where t is the time expressed in minutes.

Taylor's sandcastle is initially 160 cm tall. The wind blows away sand at 8 cm/min but she adds sand at 6 cm/min, thus the real loss of sand is 8 cm/min - 6 cm/min= 2 cm/min. Thus, the height of Taylor's sandcastle is:

[tex]H_T=160-2t[/tex]

To find when both castles have the same height, we set:

[tex]180-8t=160-2t[/tex]

Simplifying:

6t=20

Solving:

t=20/6=3.33\ minutes

Both castles will have the same height at 3.33 minutes

9514 1404 393

Answer:

  A(x) = -2/5x^2 +200x

Step-by-step explanation:

There are 5 lengths of fence that are y long, and 2 lengths of fence that are x long. So, the perimeter is ...

  5y +2x = 1000

Then the value of y is ...

  y = (1000 -2x)/5

The area is the product of x and y:

  A(x) = xy

  A(x) = x(1000 -2x)/5

  A(x) = (2/5)(x)(500-x) . . . a convenient form for finding the maximum area

In standard form, the equation is ...

  A(x) = -2/5x^2 +200x

[tex]b = - a + \frac{1}{3} d[/tex]

Answer:

its right

Step-by-step explanation:

you are insine or what ever you know what i mine alright im not smart or dum

Answer:

d=5

Step-by-step explanation:

0.4 times 3= 1.2

0.4 times -5= -2

4+5= 6

6/1.2=5

Answer:

6

Step-by-step explanation:

They are asking you to plug in 2 for the g(x) equation

5(2)-4=6

Given:

She is required to read a total = [tex]10\dfrac{5}{6}[/tex] hours a week.

Monday she read [tex]1\dfrac{1}{3}[/tex] hours.

Tuesday she read [tex]\dfrac{3}{4}[/tex] of an hour.

Thursday she read 3 hours.

To find:

The total hours does she still need to read in order to get full credit.

Solution:

Total time = [tex]10\dfrac{5}{6}[/tex] hours a week.

Total time she already read [tex]=1\dfrac{1}{3}+\dfrac{3}{4}+3[/tex] hours

                                              [tex]=\dfrac{1\times 3+1}{3}+\dfrac{3}{4}+3[/tex] hours

                                              [tex]=\dfrac{4}{3}+\dfrac{3}{4}+3[/tex] hours

                                              [tex]=\dfrac{16+9+36}{12}[/tex] hours

                                              [tex]=\dfrac{61}{12}[/tex] hours

Now,

Remaining time = Total time - Total time she already read

                         [tex]=10\dfrac{5}{6}-\dfrac{61}{12}[/tex]

                         [tex]=\dfrac{65}{6}-\dfrac{61}{12}[/tex]

                         [tex]=\dfrac{130-61}{12}[/tex]

                         [tex]=\dfrac{69}{12}[/tex]

                         [tex]=\dfrac{23}{4}[/tex]

                         [tex]=5\dfrac{3}{4}[/tex]

Therefore, the required time is  [tex]5\dfrac{3}{4}[/tex] hours.

Answer: 1595 jumbo size

Step-by-step explanation:

From the question, let regular size toys be represented by a.

We are informed that the company made 11 times as many regular size toys as jumbo size toys. This means that:

Jumbo side toys = 11 × a = 11a

To calculate the number of jumbo size dog toys they make goes thus:

11a + a = 1740

12a = 1740

a = 1740/12

a = 145

Jumbo size toys = 11a

= 11 × 145

= 1595

Answer:

the answer is b between 6 and 7

Step-by-step explanation:

i say this because the square root of 41 is 6.4031.

6.4031 is in between 6 and 7.

hope this helps :)

Answer:

The answer is B.200

Step-by-step explanation:

145.93×1.37=199.9

We need to multiply because the second team takes the times as longer than the first team. The answer is 200 because we need to roundup 199.9 into 200

Hope it helps :)

Answer:

The minimum horizontal force that must be applied to keep the bag moving  at constant velocity once it has started to move is 16 newtons.

Step-by-step explanation:

According to the First and Second Newton's Laws, an object has net force of zero when it is at rest or moves at constant velocity. Given that bag rests on a horizontal surface, the equation of equilibrium is:

[tex]\Sigma F = P - f = 0[/tex] (Eq. 1)

Where:

[tex]P[/tex] - Horizontal force exerted on the bag, measured in newtons.

[tex]f[/tex] - Kinetic friction force, mesured in newtons.

From (Eq. 1), we get that horizontal force is:

[tex]P = f[/tex]

On the case of a horizontal surface, normal force exerted from ground on the bag and kinetic friction force is:

[tex]f = \mu_{k}\cdot W[/tex] (Eq. 2)

Where:

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]W[/tex] - Weight of the bag, measured in newtons.

Then we eliminate kinetic friction force by equalizing (Eqs. 1, 2):

[tex]P = \mu_{k}\cdot W[/tex]

If we know that [tex]\mu_{k} = 0.2[/tex] and [tex]W = 80\,N[/tex], then the horizontal force that must be applied to is:

[tex]P =0.2\cdot (80\,N)[/tex]

[tex]P = 16\,N[/tex]

The minimum horizontal force that must be applied to keep the bag moving  at constant velocity once it has started to move is 16 newtons.

Answer:

27

Step-by-step explanation:

 To solve this problem, let us follow it step by step;

 Let Peter's number  = P;

     So;

    ⇒   P - 17

    ⇒  -2 (P - 17 )

    ⇒  -2 (P - 17 ) = -20

Solve the problem for P;

        -2 (P - 17 ) = -20

        -2P + 34  = -20

        -2P = -20 -34

          -2P  = -54

              P = 27

Answer:

Answer:

27

Step-by-step explanation:

To solve this problem, let us follow it step by step;

Let Peter's number  = P;

    So;

   ⇒   P - 17

   ⇒  -2 (P - 17 )

   ⇒  -2 (P - 17 ) = -20

Solve the problem for P;

       -2 (P - 17 ) = -20

       -2P + 34  = -20

       -2P = -20 -34

         -2P  = -54

             P = 27

Step-by-step explanation:

Answer:

See picture below.

Explanation

I took the test and got a 100% on it, so this should be right for any future students.