The speed v of a car after a time (t) is given by
V= u+at
Where u is the initial speed and a is the acceleration
a. Re-arrange this equation to make u the subject of the formula

We have that the magnitude of the gravitational force  is mathematically given as

f=6.377N

Question Parameters:

Earth exerts a 100 N gravitational force on a metal box.

(Mass of the earth is 6e24 kg and radius of the earth is 6.4e6m.)

Generally the equation for the Gravitational mForce  is mathematically given as

[tex]F=\frac{GMm}{r^2}\\\\Therefore\\\\F=\frac{100/9.8* 6e116e24}{6.4e6^2}[/tex]

f=6.377N

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Answer:

velocity arrow

Explanation:

When velocity decreases, acceleration and velocity are in opposite directions, so the acceleration arrow and velocity arrow point in the opposite directions.

Answer:

W = 10000J

Explanation:

W = F • s

W = Work in J

F = Force in N

s = displacement in m

W = 5000N • 2m

W = 10000J

You need the distance travelled and how long it took so the time. You can use this in the formula Speed = distance / time to calculate the speed or velocity.

Answer:I dont know

Explanation:

Because I dont  know

Answer: 63.753 mph

Explanation:

[tex]28.5 \frac{m}{s} * \frac{1 mile}{1609.34 m} * \frac{3600s}{1 hour} = 63.753 \frac{miles}{hour}[/tex]

Answer:

i think the answer is (a) since c is not responsible for the electricity

Answer: Try and subtract

Explanation:

Answer:

I AM COOL DUDE HOW R U?

Explanation:

Answer:

False

Explanation:

Unless it encounters external factors, the ship will continue to move at a fixed pace even if the engine is turned off.

Answer:

I actually don't know bc I only need point s so yeah

Explanation:

the explanaition is nothing bc I have nothing

C) end Q attracts both X and Y

Reason: The metal bar PQ is magnetized and has magnetic properties in it, that's I why the point Q is pointing towards the north. The XY bar doesnt point towards any specific direction because it isn't magnetized and doesn't have magnetic properties in it, and that's why it gets attracted by Q and it's both ends.

The focal length of the lens is 2m and the position of the image is 6 m.

The size of the image formed depends on the position of the object from the lens.

[tex]M = \frac{v}{u}[/tex]

where;

The image distance is calculated as follows;

[tex]2 = \frac{v}{3} \\\\v = 2(3) \\\\v = 6 \ m[/tex]

The focal length of the lens is calculated as follows;

[tex]\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\\\\\frac{1}{f} = \frac{1}{6} + \frac{1}{3} \\\\\frac{1}{f} = \frac{3}{6} \\\\f = 2m[/tex]

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The second wire is stretched by 15.4 cm long provided the two-wire are made of the same materials and equal forces.

Young's Modulus of Elasticity explains the elastic characteristics of a solid experiencing tension or compression in a unilateral direction

Here,  the material used is a wire which returns to its length after being stretched or compressed.

From the parameters given:

If the second wire is as twice as first, then:

where;

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A truck weighing 5 x 10³ kg force.

A cart weighing 500 kg force.

Moving with the same speed complete their

kinetic energies.

As we know that,

Formula of:

→ Kinetic energy = 1/2 x m x v².

Using this formula in the equation, we get.

(1).

→ For truck = 1/2 x 5 x 10³ x v².-----

→ For cart = 1/2 x 500 x v². -----(2).

Divide equation (1) and (2), we get.

⇒ KE₁/KE₂ = 5 x 10³/5 x 10².

➡ KE₁/KE₂ = 10/1.

⇒ KE₁/KE₂ = 10:1.

Answer:

1. C semi truck

2. C acceleration

Explanation:

The work is simply W = V Q where V is the voltage of the battery and Q the charge on the electron

W = V joules/coulomb * E coulombs = joules

Answer:

The skier is in a conservative system, as the only force acting upon him is gravity. Instead of calculating the work done over the curved hills, we can construct an alternate path, because of the principle of path independence:

Explanation:

The power of the fan is 70 Watt.

Power can be defined as the rate at which energy is used. The S.I unit of power is Watt (W)

The power of the fan can be calculated using the formula below.

From the question,

Substitute these values into equation 1

Hence, The power of the fan is 70 Watt.

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Answer:

1/4

Explanation:

Total radiation energy depends on temperature, so [tex]E_A=E_B[/tex]

Radius [tex]R_A=2R_B[/tex]

so the surface area [tex]S_A=4 S_B[/tex]

energy per unit area

[tex]\frac{E_A}{S_A}=\frac{1}{4}\frac{E_B}{S_B}[/tex]

Apply ohms law

[tex]\\ \tt\hookrightarrow \dfrac{V}{I}=R[/tex]

[tex]\\ \tt\hookrightarrow R=\dfrac{125.6}{7.9}[/tex]

[tex]\\ \tt\hookrightarrow R=15.8\Omega[/tex]

While cooking dinner, Dinah's oven uses a 125.6 V line and draws 7.9 A of current when heated to its maximum temperature. What is the resistance of the oven when it's fully heated?

[tex] \frac{v}{i} = r[/tex]

[tex]r = \frac{125.6}{7.9} [/tex]

[tex]r = 15.8[/tex]

The tension in the coupling between the second and third cars is 269,730 N.

Since the weight of each car is the same, the applied force on each will be the same and the tension on the coupling between the cars will be the same.

T = F = ma

T = 9(37,000 x 0.81)

T = 269,730 N

Thus, the tension in the coupling between the second and third cars is 269,730 N.

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Answer:

The strategy we would like you to learn has five major steps: Focus the Problem, Physics Description, Plan a Solution, Execute the Plan, and Evaluate the Solution. Let's take a detailed look at each of these steps and then do an sample problem following the strategy.

Answer:

10 minutes

Explanation:

Given:

Given:Speed of bus excluding stoppages =54 km/h

Speed of bus including stoppages = 45 km/h

To calculate: Minutes/per hour the bus stopped = ?

Distance covered by bus without stopping =54 km/h

Distance covered by bus with stopping =45 km/h

Due to stoppages it could

9km (54-45km) less

Time taken to cover 9 km=?

time \: taken \: = \frac{distane}{speed }timetaken=

speed

distane

Distance=9km

Speed = 54km/h.

Substituting given values on the above formula we get,

time \: taken \: = \frac{9}{54} hour = \frac{1}{6} hour \:timetaken=

54

9

hour=

6

1

hour

=10 minutes

Hence,the correct answer is 10 minutes.

When the resistance is doubled, the current reduces by half.

Ohms law states that the voltage applied to a circuit is directly proportional to the current flowing in the circuit.

V = IR

V/R = I

where;

From the equation above, when the resistance is doubled, the current reduces by half.

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Answer

Sun and Moon's gravity

We will increase the amplitude of the wave by a factor of 4 If we want to double this rate

Transverse wave, travels in a way in which points on a wave oscillate along paths at right angles of 90 degrees to the direction of the wave.

We see that energy transported along a wave path is directly proportional to the square of the amplitude.

E =kA^2

Therefore, we will increase the amplitude of the wave by a factor of 4 If we want to double this rate.

Option B

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The number of valance electrons in the given Bohr Diagram is 7 electrons each.

Bohr diagrams depict electrons orbiting the nucleus of an atom in the same way that planets orbit the sun.

Electrons in the Bohr model are depicted as traveling in circles at different shells depending on the element.

We now know that the Bohr Model has some flaws, but it is still widely used because of its straightforward approach to atomic theory.

The Bohr model was also the first to incorporate quantum theory into an atomic model, making it the forerunner of today's more accurate quantum-mechanical models.

Each valance electron in the given Bohr Diagram has 7 electrons.

Thus, the valance electrons in each of the given diagram is 7 electrons as they have these electrons in their outermost shell.

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A car starts from rest and accelerates at 9 m/s². After 240 m. the final speed is 66 m/s.

Uniformly Accelerated Motion is the motion of an object where the acceleration is constant.

A car starts from rest, that is, its initial speed is 0 m/s. It accelerates at 9 m/s². We can find the final speed after 240 m using the following kinematic equation.

v² = u² + 2 × a × s

v² = (0 m/s)² + 2 × (9 m/s²) × 240 m

v = 66 m/s

where,

A car starts from rest and accelerates at 9 m/s². After 240 m. the final speed is 66 m/s.

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