The activation energy for the thermal death of Bacillus subtilis is approximately 223,000 J/mol.
The activation energy for the thermal death of a strain of Bacillus subtilis can be determined using the Arrhenius equation. The equation is given by:
k = A * exp(-Ea / (R * T))
Where:
- k is the specific death constant,
- A is the pre-exponential factor,
- Ea is the activation energy,
- R is the gas constant (8.314 J/(mol*K)),
- T is the temperature in Kelvin.
To determine the activation energy, we need to use the given data for two different temperatures (85°C and 110°C) and their corresponding specific death constants (0.012 min^-1 and 1.60 min^-1).
Let's convert the temperatures from Celsius to Kelvin:
- 85°C + 273.15 = 358.15 K
- 110°C + 273.15 = 383.15 K
Now we can use the Arrhenius equation to set up two equations using the given data points:
For 85°C:
0.012 = A * exp(-Ea / (8.314 * 358.15))
For 110°C:
1.60 = A * exp(-Ea / (8.314 * 383.15))
By dividing the second equation by the first equation, we can eliminate the pre-exponential factor (A):
(1.60 / 0.012) = exp(-Ea / (8.314 * 383.15)) / exp(-Ea / (8.314 * 358.15))
133.33 = exp((8.314 * 358.15 - 8.314 * 383.15) / (8.314 * 358.15 * 383.15))
Taking the natural logarithm (ln) of both sides:
ln(133.33) = (8.314 * 358.15 - 8.314 * 383.15) / (8.314 * 358.15 * 383.15)
Simplifying the right side:
ln(133.33) = -Ea / (8.314 * 358.15 * 383.15)
Solving for Ea:
Ea = -ln(133.33) * (8.314 * 358.15 * 383.15)
Calculating Ea:
Ea ≈ 223,000 J/mol
Therefore, the activation energy for the thermal death of Bacillus subtilis is approximately 223,000 J/mol.
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Question 4: According to given water network system below; a) Design the main and primary pipes of the network by using dead point method. b) Find the elevation of the water tank. c) Find the dynamic pressures at points A, B, C, D, E. (maxqday = 300 1/day capita, William Hazen coefficient; C = 120, William Hazen formula; V = 0.85CR43 70.54, Minimum allowable pressure (Ply Janin, network=20 mwc) Use Standart Pipe Diameters as 80mm, 100mm, 125mm, 175mm, 200mm, 250mm, 300mm.... Q=41sec TANK B(35m) T(50m) L-100m L-600m 15 L-250m kw A(38m) C(30m) L-500m K1.5 L-400m k1 D(32m) L-700m k=15 E (26m)
Designing the water network system using the dead point method, determining the elevation of the water tank, and calculating the dynamic pressures at various points.
The main and primary pipes of the water network system can be designed using the dead point method, which involves considering the elevation of the water sources and the desired minimum allowable pressure at various points. By analyzing the given information and applying the William Hazen coefficient (C = 120) and formula (V = 0.85CR^0.43), the appropriate pipe diameters can be selected for the main and primary pipes.
Additionally, the elevation of the water tank can be determined by evaluating the given distances and elevations of the pipes. Finally, by considering the flow rates and pipe characteristics, the dynamic pressures at points A, B, C, D, and E can be calculated.
Step 2: In order to design the main and primary pipes of the water network system, we can utilize the dead point method. This method takes into account the elevation of the water sources and the desired minimum allowable pressure at various points.
By applying the given information and employing the William Hazen coefficient (C = 120) and formula (V = 0.85CR^0.43), we can select suitable pipe diameters for the main and primary pipes. The dead point method ensures that the water flow remains at a minimum acceptable pressure throughout the network.
To determine the elevation of the water tank, we need to consider the given distances and elevations of the pipes. By analyzing the information provided, we can calculate the elevation of the water tank by summing up the elevation changes along the pipe network. This will give us the necessary information to place the water tank at the appropriate height.
Additionally, we can calculate the dynamic pressures at points A, B, C, D, and E by taking into account the flow rates and pipe characteristics. The flow rate can be determined using the maximum daily water demand (maxqday = 300 1/day capita), and by applying the William Hazen formula (V = 0.85CR^0.43), we can calculate the velocity of the water in the pipes.
With the pipe diameters provided (80mm, 100mm, 125mm, 175mm, 200mm, 250mm, 300mm), we can calculate the dynamic pressures at each point using the Hazen-Williams equation.
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Help what's the answer
The linear equation represented by the table is:
y = -2.4*x + 18
How to find the equation of the line?A general linear equation can be written as follows:
y = ax + b
Where a is the slope and b is the y-intercept.
On the graph we can see that when x = 0, the value of y is 18, so that is the y-intercept, and thus, we can write the line as:
y = ax + 18
The next point is (2, 13.2)
Replacing that we can get:
13.2 = 2a + 18
13.2 - 18 = 2a
-4.8 = 2a
-4.8/2 = a
-2.4 = a
So the linear equation is:
y = -2.4*x + 18
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[50 pts] Two solid cylindrical rods AB and BC are welded together at B and loaded as shown. Knowing that P= 10 kips, find the average normal stress at the midsection of (a) rod AB, (b) rod BC. 30 in. -1.25 in. 12 kips 25 in. -0.75 in
The average normal stress at the midsection of rod AB is approximately 6.37 kips/in², and the average normal stress at the midsection of rod BC is approximately 22.43 kips/in².
To find the average normal stress at the midsection of rods AB and BC, we can use the formula for average normal stress:
Average normal stress = Force / Area
(a) Average normal stress at the midsection of rod AB:
Force P = 10 kips
Length of rod AB = 30 in.
Radius of rod AB = 1.25 in.
To calculate the average normal stress, we need to find the area of rod AB. The cross-sectional area of a cylindrical rod can be calculated using the formula:
Area = π * radius^2
Area of rod AB = π * (1.25 in)^2
Now, we can calculate the average normal stress:
Average normal stress at the midsection of rod AB = Force / Area
Average normal stress at the midsection of rod AB = 10 kips / (π * (1.25 in)^2)
(b) Average normal stress at the midsection of rod BC:
Force P = 12 kips
Length of rod BC = 25 in.
Radius of rod BC = 0.75 in.
Similar to rod AB, we need to find the area of rod BC:
Area of rod BC = π * (0.75 in)^2
Now, we can calculate the average normal stress:
Average normal stress at the midsection of rod BC = Force / Area
Average normal stress at the midsection of rod BC = 12 kips / (π * (0.75 in)^2)
Now, let's calculate the values:
(a) Average normal stress at the midsection of rod AB:
Average normal stress at the midsection of rod AB ≈ 10 kips / (3.14 * (1.25 in)^2) ≈ 6.37 kips/in²
(b) Average normal stress at the midsection of rod BC:
Average normal stress at the midsection of rod BC ≈ 12 kips / (3.14 * (0.75 in)^2) ≈ 22.43 kips/in²
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Most engaged couples expect or at least hope that they will have high levels of marital satisfaction. However, because 54% of first marriages end in divorce, social scientists have begun investigating influences on marital satisfaction. (Data Source: These data were obtained from the National Center for Health Statistics. ) Suppose a counseling psychologist sets out to look at the role of having children in relationship longevity. A sample of 78 couples with children score an average of 51. 1 with a sample standard deviation of 4. 7 on the Marital Satisfaction Inventory. A sample of 94 childless couples score an average of 45. 2 with a sample standard deviation of 12. 1. Higher scores on the Marital Satisfaction Inventory indicate greater satisfaction.
Suppose you intend to conduct a hypothesis test on the difference in population means. In preparation, you identify the sample of couples with children as sample 1 and the sample of childless couples as sample 2. Organize the provided data by completing the following table:
To organize the provided data, we can create a table comparing the samples of couples with children (sample 1) and childless couples (sample 2) as follows:
Sample Sample Size Sample Mean Sample Standard Deviation
1 78 51.1 4.7
2 94 45.2 12.1
In this table, we have listed the sample number (1 and 2), the sample size (number of couples in each group), the sample mean (average Marital Satisfaction Inventory score), and the sample standard deviation (measure of variability in the scores) for each group. This organization allows us to compare the data and proceed with hypothesis testing on the difference in population means between the two groups.
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A student dissolves 40.0mg of lithium phosphate in enough water to make 250.0 mL of solution. What is the concentration of phosphate ions in solution in mEq/L ?
The given concentration of the lithium phosphate solution is 40 mg in 250 mL.To find out the concentration of phosphate ions, the molarity of the solution should be determined.
The molar mass of lithium phosphate can be calculated by adding the molar masses of its components Therefore, the molar mass of lithium phosphate By multiplying the concentration of lithium phosphate by its molar mass and dividing it by the volume of the solution, we can get the concentration of phosphate ions in the solution in moles per liter.The molarity is given by the formula: Molarity (M) = moles of solute / Liters of solution.
Therefore, the molarity of lithium phosphate solution can be calculated as follows:mass of lithium phosphate = 40.0 mg = 0.0400 gmolar mass of lithium phosphate = 101.87 g/molno. of moles = (mass of solute) / (molar mass)no. of moles = 0.0400 / 101.87no. of moles = 0.000393 MTherefore, the concentration of phosphate ions is 0.000393 M.From the previous knowledge of molarity, one mole of any monovalent ion, such as phosphate, has one equivalent.
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A student dissolves 40.0mg of lithium phosphate in enough water to make 250.0 mL of solution. The concentration of phosphate ions is 0.000393 M.
The given concentration of the lithium phosphate solution is 40 mg in 250 mL.
To find out the concentration of phosphate ions, the molarity of the solution should be determined.
The molar mass of lithium phosphate can be calculated by adding the molar masses of its components Therefore, the molar mass of lithium phosphate
By multiplying the concentration of lithium phosphate by its molar mass and dividing it by the volume of the solution, we can get the concentration of phosphate ions in the solution in moles per liter.
The molarity is given by the formula: Molarity (M) = moles of solute / Liters of solution.
Therefore, the molarity of lithium phosphate solution can be calculated as follows:
mass of lithium phosphate = 40.0 mg
= 0.0400 g
molar mass of lithium phosphate = 101.87 g/mol
no. of moles = (mass of solute) / (molar mass)
no. of moles = 0.0400 / 101.87
no. of moles = 0.000393 M
Therefore, the concentration of phosphate ions is 0.000393 M.
From the previous knowledge of molarity, one mole of any monovalent ion, such as phosphate, has one equivalent.
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aracely and jonah went to breakfast and ordered chicken and waffles aracely ordered 1 waffle and 2 pieces of chicken and paid $8.50 joah order 2 waffles and 1 piece of chicken and paid $7.25 how much is each waffle and each piece of chicken
Answer: waffle = 2$ chicken = 3.25$
Step-by-step explanation: w=waffle c=chicken
W + 2C = 8.50
2w + c = 7.25
4w + 2c + 14.50 compared to w + 2c = 8.50
Each of last two orders have 2c so subtract chicken to leave waffles.
4w + 2c = 14.50
- w + 2c = 8.50
3w = 6.00 divide both sides of equal sign by 3 to find value of w
w = 2.00
If w=2$ and w+2c = 8.50,
then 2$ + 2c = 8.50
subtract 2$ from both sides of equal sign
2c = 6.50 divide both sides by 2 to find value of c
c = 3.25
What is the systematic name of ammonia?
A. Hydrogen Trinitrogen
B. Trihydrigen Nitride
C. Hydrogen Trinitride
D. Nitrogen Trihydride
The correct option of the given statement "What is the systematic name of ammonia?" is D. Nitrogen Trihydride.
Ammonia is a compound composed of one nitrogen atom and three hydrogen atoms. In the systematic naming of compounds, the first element is named according to its elemental name, which is nitrogen in this case. The second element, hydrogen, is named "hydride" to indicate that it is a compound containing hydrogen.
To form the systematic name, we combine the names of the elements, with the name of the second element ending in "-ide." In this case, the systematic name becomes "Nitrogen Trihydride."
Option A, "Hydrogen Trinitrogen," does not follow the correct naming convention. Option B, "Trihydrigen Nitride," is also incorrect as it does not indicate that nitrogen is the first element. Option C, "Hydrogen Trinitride," is incorrect because it does not follow the correct naming convention for compounds.
In summary, the correct systematic name for ammonia is "Nitrogen Trihydride."
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After the BOD test, you obtained the following DO data in the lab. The results of which sample volume(s) could be used for further analysis?
4. Use only those valid data sets you identified in Question 3, calculate BOD5 using the formula BOD5 (mg/L) = (D1 - D2) / P where P = decimal volumetric fraction of sample to total combined volume of 300 mL. Calculate the average and enter the value.
The main answer is that without specific data for D1 and D2, it is not possible to calculate the average BOD5.
To determine the sample volumes that could be used for further analysis, we need to refer to the valid data sets identified in Question 3. Once we have those valid data sets, we can calculate the BOD5 (Biochemical Oxygen Demand) using the formula BOD5 (mg/L) = (D1 - D2) / P, where P represents the decimal volumetric fraction of the sample to the total combined volume of 300 mL.
Let's assume we have identified three valid data sets from Question 3, with sample volumes of 50 mL, 100 mL, and 150 mL.
For the 50 mL sample volume:
BOD5 (mg/L) = (D1 - D2) / P = (D1 - D2) / (50 mL / 300 mL) = 6(D1 - D2)
For the 100 mL sample volume:
BOD5 (mg/L) = (D1 - D2) / P = (D1 - D2) / (100 mL / 300 mL) = 3(D1 - D2)
For the 150 mL sample volume:
BOD5 (mg/L) = (D1 - D2) / P = (D1 - D2) / (150 mL / 300 mL) = 2(D1 - D2)
To calculate the average BOD5, we can sum up the BOD5 values for each sample volume and divide by the number of valid data sets.
Average BOD5 = (6(D1 - D2) + 3(D1 - D2) + 2(D1 - D2)) / 3
Simplifying the equation, we get:
Average BOD5 = (11(D1 - D2)) / 3
The value obtained from this calculation will be the average BOD5 for the valid data sets.
Note: Without specific values for D1 and D2, it is not possible to provide an exact numerical answer in this case. However, the formula and calculation method outlined above can be used with the actual values of D1 and D2 to obtain the average BOD5.
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(c) What is the average rate of change of f(x)=x² - 6x + 8 from 5 to 9?
f(9) = 9^2 - 6(9) + 8 = 81 - 54 + 8 = 35
f(5) = 5^2 - 6(5) + 8 = 25 - 30 + 8 = 3
the average rate of change is simply the slope of the line between those two points: (9,35) and (5,3)
m = (35-3)/(9-5)
= 32/4
= 8
What mass of sodium chloride (NaCl) is contained in 30.0 mL of a 17.9% by mass solution of sodium chloride in water? The density of the solution is 0.833 g/mL. a) 6.45 g b) 201 g c) 4.47 g d) 140 g
4.47 mass of sodium chloride (NaCI) is contained in 30.0 mL of a 17.9% by mass solution of sodium chloride in water. c). 4.47. is the correct option.
Mass of the solution (m) = Volume of the solution (V) × Density of the solution (d)= 30.0 mL × 0.833 g/mL= 24.99 g
Now, let the mass of sodium chloride be x.
So, the percentage of sodium chloride in the solution is given by: (mass of NaCl / mass of solution) × 100%
Hence, we can write the given percentage as:(x/24.99)× 100= 17.9% ⇒x = (17.9/100) × 24.99= 4.47 g
Hence, the mass of sodium chloride (NaCl) is contained in 30.0 mL of a 17.9% by mass solution of sodium chloride in water is 4.47 g.
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A pump is being utilized to deliver a flow rate of 500 li/sec from a reservoir of surface elevation of 65 m to another reservoir of surface elevation 95 m.
The total length and diameter of the suction and discharge pipes are 500 mm, 1500 m and 30 mm, 1000 m respectively. Assume a head lose of 2 meters
per 100 m length of the suction pipe and 3 m per 100 m length of the discharge pipe. What is the required horsepower of the pump?
provide complete solution using bernoullis equation..provide illustration with labels like datum line and such.
The required horsepower of the pump is 3 hp. Hence, the answer is 3 hp.
The Bernoulli's equation can be defined as the equation that explains the principle of energy conservation. It states that the total mechanical energy of the fluid along a streamline is constant if no energy is added or lost in the fluid flow. The equation also states that the sum of the potential energy, kinetic energy, and internal energy is a constant value for incompressible fluid flow.
The Bernoulli's equation is applied to the hydraulic jump, the flow in the open channel, and the flow in the pipeline. Now, let's calculate the required horsepower of the pump below.
Given values are,Flow rate Q = 500 li/secReservoir surface elevation, z1 = 65 mReservoir surface elevation, z2 = 95 mDiameter of suction pipe, d1 = 500 mmLength of suction pipe, L1 = 1500 m,Diameter of discharge pipe, d2 = 30 mmLength of discharge pipe, L2 = 1000 mHead loss in suction pipe, hL1 = 2 m/100m,Head loss in discharge pipe, hL2 = 3 m/100mBernoulli's equation:
P1/ρg + v1²/2g + z1 + hL1 = P2/ρg + v2²/2g + z2 + hL2 … (i)
P1 = Pressure at the suction sideP2 = Pressure at the discharge sideρ = Density of waterg = Acceleration due to gravityv1 = Velocity of water at the suction sidev2 = Velocity of water at the discharge sideTaking the datum line at point 2, P2 = 0.
Therefore equation (i) can be simplified as:P1/ρg + v1²/2g + z1 + hL1 = v2²/2g + z2 + hL2 … (ii)The pump head (HP) is defined as,HP = ρQH / 75 kWWhere ρ = Density of the fluid (water),Q = Flow rateH = Total head75 kW = 100 hpRequired horsepower of the pump is given as,HP = (ρQH / 75) hp … (iii)
Now, let's solve the above equation step by step:Velocity at suction side,v1 = Q / A1Where,A1 = πd1² / 4d1 = Diameter of the suction pipe = 500 mm = 0.5 m,
A1 = π(0.5)² / 4,
A1 = 0.196 m²,
v1 = 500 / 0.196
v1 = 500 / 0.196
v1 = 2551.02 m/s.
From Bernoulli's equation (ii), (z1 + hL1) = (v2²/2g + z2 + hL2) - (P1/ρg)
(v2²/2g) - (v1²/2g) = z1 - z2 - hL1 - hL2 … (iv)Total length of the suction and discharge pipes,L = L1 + L2 = 1500 + 1000L = 2500 mHead loss in suction pipe,h
L1 = 2 m/100mh,
L1 = (2/100) * 15h,
L1 = 0.3 m,
Head loss in discharge pipe,hL2 = 3 m/100mhL2 = (3/100) * 10h,
L2 = 0.3 m.
Substituting the above values in equation (iv),
((v2² - v1²) / 2g) = 95 - 65 - 0.3 - 0.3
((v2² - v1²) / 2g) = 29.4g = 9.81 m/s².
Now,Velocity at discharge side,
v2 = √(2g(z1 - z2 - hL1 - hL2) + v1²),
v2 = √(2 * 9.81 * 29.4 + 2551.02²),
v2 = 2569.42 m/s.
Now, we need to calculate the Total Head (H),
H = (P2 - P1) / ρg + (v2² - v1²) / 2g + (z2 - z1) + hL1 + hL2.
Taking P1 as atmospheric pressure,
P1 = 1 atmH = (P2 - P1) / ρg + (v2² - v1²) / 2g + (z2 - z1) + hL1 + hL2H = (0 - 1) / (1000 * 9.81) + (2569.42² - 2551.02²) / (2 * 9.81) + (95 - 65) + 0.3 + 0.3H = 29.88 m.
Substituting the above values in equation (iii),HP = (1000 * 500 * 29.88) / (75 * 1000)HP = 199.2 / 75HP = 2.65 hp ≈ 3 hp.
Therefore, the required horsepower of the pump is 3 hp. Hence, the answer is 3 hp.
Total Head (H) = 29.88 mHorsepower (HP) = 3 hp.
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help me pls
Which point on the scatter plot is an outlier? (4 points)
A scatter plot is shown. Point D is located at 1 and 1, Point C is located at 2 and 3, Point B is located at 7 and 6, and Point A is located at 8 and 1. Additional points are located at 2 and 2, 4 and 3, 5 and 5, 6 and 4.
a
Point A
b
Point B
c
Point C
d
Point D
Point A is likely the outlier in this scatter plot. the outlier on the scatter plot is point A (8, 1). option A
To identify the outlier on the scatter plot, we need to analyze the data points and look for any point that deviates significantly from the overall pattern or cluster of points.
Based on the given information, the scatter plot includes four points: D (1, 1), C (2, 3), B (7, 6), and A (8, 1). Additionally, there are four additional points: (2, 2), (4, 3), (5, 5), and (6, 4).
To visually assess the outlier, we can plot the points on a graph. Here is a visualization of the scatter plot with the points labeled:
(6, 4) (5, 5)
| |
(4, 3) --+-- (2, 2) |
| |
C (2, 3) +-- (7, 6) |
| |
| |
D (1, 1) A (8, 1) B (7, 6)
By examining the scatter plot, we can see that point A (8, 1) deviates significantly from the overall pattern. It is located far away from the other points and does not seem to follow the general trend or relationship between the variables.
Therefore, point A is likely the outlier in this scatter plot.
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What is the value of x in the equation ?
Answer: 2
Step-by-step explanation:
An Ontario business man purchased a machine from Prince Edward Island that cost $9000, before 14% HST. How much would he pay including taxes for the machine? a. $10380 b. $10500 c. $10260 d. $10450
The businessman would pay $10260 including taxes for the machine. So, the correct answer is c. $10260.
The Ontario businessman purchased a machine from Prince Edward Island that cost $9000 before 14% HST. To calculate the total cost including taxes, we need to add the HST to the original price of the machine.
1: Calculate the HST amount
To find the HST amount, we multiply the original price by the HST rate (14% or 0.14).
HST amount = $9000 * 0.14 = $1260
2: Add the HST amount to the original price
To identify the total cost including taxes, we add the HST amount to the original price of the machine.
Total cost including taxes = $9000 + $1260 = $10260
Hence, c is the correct answer.
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3 pts Question 10 The continuous flow in a horizontal, frictionless rectangular open channel is subcritical. A smooth step-up bed is built downstream on the channel floor. As the height of the step-up bed is increased, choked condition is attained. With further increase in the height of the step-up bed, the water surface O flow will stop. over the step-up bed will decrease to the extent that it will be below the critical depth. O over the step-up bed will decrease to the extent that it will be above the critical depth. O upstream will increase to the extent that it will create supercritical flow over the step-up bed.
The continuous flow in a horizontal, frictionless rectangular open channel is subcritical. A smooth step-up bed is built downstream on the channel floor. With further increase in the height of the step-up bed, the water surface over the step-up bed will decrease to the extent that it will be below the critical depth.
A flow that is slower than critical velocity is known as subcritical flow. The Froude number in subcritical flow is less than one. Subcritical flow occurs when water is flowing slowly, and the water surface is higher than the critical depth of flow.
The critical depth of flow is the depth of flow at which the specific energy of flow is minimum. The flow is critical if the velocity of water is equal to the velocity of the wave. In open channels, the critical depth is determined by the specific energy equation.
When a flow is restricted, choked conditions occur. When a flow in a channel reaches the maximum possible velocity, the flow becomes choked. The flow will be choked, and the water surface will rise if the depth of the flow exceeds the critical depth in a horizontal, frictionless rectangular open channel with a smooth step-up bed built downstream. With further increase in the height of the step-up bed, the water surface over the step-up bed will decrease to the extent that it will be below the critical depth.
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All else being equal, a study with which of the following error ranges would be the most reliable? • A. +12 percentage points • B. +7 percentage points O c. +2 percentage points • D. #17 percentage points
Plusminus 2 percentage points, would be the most reliable as it reflects a higher level of precision and provides more confidence in the reported findings.The correct answer is option C.
When evaluating the reliability of a study, the error range is an important factor to consider. A smaller error range indicates a more reliable study because it reflects a higher level of precision in the data collected.
Among the given options, the study with an error range of plusminus 2 percentage points (option C) would be the most reliable. This narrower range means that the reported results are likely to be closer to the true value.
The smaller the error range, the more confidence we can have in the findings of the study.
In contrast, the studies with larger error ranges (options A, B, and D) would be less reliable. Option D, with an error range of plusminus 17 percentage points, indicates a wide range of potential error, making it difficult to draw meaningful conclusions from the study results.
Options A and B, with error ranges of plusminus 12 and plusminus 7 percentage points respectively, also have wider margins of error, indicating lower reliability.
In summary, a study with a smaller error range, such as plusminus 2 percentage points, would be the most reliable as it reflects a higher level of precision and provides more confidence in the reported findings.
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The probable question may be:
All else being equal, a study with which of the following error ranges would be the most reliable?
A. plusminus 12 percentage points
B. plusminus 7 percentage points
c. plusminus 2 percentage points
D. plusminus 17 percentage points
Find the eigenvalues λn and eigenfunctions yn(x) for the equation y′′+λy=0 in each of the following cases: (a) y(0)=0,y(π/2)=0; (b) y(0)=0,y(2π)=0; (c) y(0)=0,y(1)=0; (d) y(0)=0,y(L)=0 when L>0; (e) y(−L)=0,y(L)=0 when L>0; (f) y(a)=0,y(b)=0 when a
we have y[tex]n= n2π24L2n = 1,3,5,...[/tex]0.
his gives us the following solutions: λ[tex]n= n2π24L2n = 1,3,5,...[/tex]
yn([tex]x) = sin(nπxL), n = 1,3,5,...(f) y(a)=0,y(b)=0[/tex]
For the boundary conditions, we have y(0)=0 and y(π/2)=0. This gives us the following solutions:
λn= n2π2n = 1,2,3,... yn(x)
= sin(nπx2), n = 1,2,3,...(b)
y(0)=0,y(2π)=0
For the boundary conditions, we have y(0)=0 and y(2π)=0.
This gives us the following solutions:λn= n2π2n = 1,2,3,... y[tex]n(x) = sin(nπxπ), n = 1,2,3,...(c) y(0)=0,y(1)=0[/tex]
For the boundary conditions, we have y(0)=0 and y(1)=0.
This gives us the following solutions:λn= n2π2n = 1,2,3,...
yn(x) = sin(nπx), n = 1,3,5,... and
yn(x) = cos(nπx) − cos(nπ),
n = 2,4,6,...(d)
y(0)=0,y(L)=0 when L>0
For the boundary conditions, we have [tex]y(0)=0 and y(L)=0[/tex].
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find 95% reliability on 1.000.000 people when conducting a sample
or trend
assignment
Keep in mind that the estimated proportion, p, can affect the sample size significantly.
If you can provide an estimated proportion or an assumed value for p, I can calculate the sample size for you.
To determine the required sample size for a given population with a desired level of reliability, we need to consider the margin of error and confidence level.
The margin of error defines the maximum allowable difference between the sample estimate and the true population parameter, while the confidence level indicates the level of certainty we want to have in our results.
Since you mentioned a 95% reliability, we can assume a 95% confidence level, which is a common choice. The standard margin of error associated with a 95% confidence level is approximately ±1.96 (assuming a normal distribution).
However, it's important to note that the margin of error can be adjusted based on the specific characteristics of the population being studied.
To calculate the required sample size, we also need to know the estimated proportion of the population exhibiting the trend or characteristic of interest.
Without this information, we can't provide an exact sample size. However, I can show you a general formula for calculating the sample size based on an estimated proportion.
The formula to determine the sample size is:
n = (Z^2 * p * (1 - p)) / E^2
Where:
n = required sample size
Z = Z-score corresponding to the desired confidence level (95% is approximately 1.96)
p = estimated proportion of the population exhibiting the trend or characteristic
E = margin of error
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Implement the Boolean function AB+C with up to 4 NAND gates.
In this implementation, we used a total of 7 NAND gates (N1, N2, N3, N4, N5, N6, and N7).
To implement the Boolean function AB+C using up to 4 NAND gates, we can break it down into multiple steps. Each step involves using NAND gates to perform logical operations and combine the inputs in a specific way. Here's one possible implementation:
Step 1:
Create the NAND gates for the individual inputs and their negations:
- Create NAND gate N1 with inputs A and A (A NAND A).
- Create NAND gate N2 with inputs B and B (B NAND B).
- Create NAND gate N3 with inputs C and C (C NAND C).
Step 2:
Combine the inputs using NAND gates:
- Create NAND gate N4 with inputs A and B (A NAND B).
- Create NAND gate N5 with inputs N4 (output of N4) and N4 (output of N4 NAND N4). This is equivalent to inverting the output of N4.
- Create NAND gate N6 with inputs N5 (output of N5) and N5 (output of N5 NAND N5). This is equivalent to inverting the output of N5.
Step 3:
Combine the outputs of Step 2 with the C input:
- Create NAND gate N7 with inputs N6 (output of N6) and C.
- The output of N7 represents the desired function AB+C.
In this implementation, we used a total of 7 NAND gates (N1, N2, N3, N4, N5, N6, and N7).
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Water is flowing in a pipeline 600 cm above datum level has a velocity of 10 m/s and is at a gauge pressure of 30 KN/m2. If the mass density of water is 1000 kg/m3, what is the total energy per unit weight of the water at this point? Assume acceleration due to Gravity to be 9.81 m/s2.
The total energy per unit weight of the water at the specified point is determined by adding the kinetic energy per unit weight and the potential energy per unit weight of the fluid. According to the principle of conservation of energy, the total energy per unit weight of the fluid in a flow system is constant and is known as Bernoulli's equation.
The following formula can be used to determine the total energy per unit weight of the water at the specified point: T.E./w = P/w + V^2/2g + Z. Where, T.E./w = Total energy per unit weightP/w = Pressure energy per unit weightV = Velocity of the water, g = Acceleration due to gravity Z = Potential energy per unit weight of the water in the pipeline. Thus, putting all the given values into the equation, we get:T.E./w = 30 × 103/1000 + (10)2/(2 × 9.81) + 600/1000= 30 + 5.092 + 0.6= 35.692 m. Therefore, the total energy per unit weight of water at the given point is 35.692 m. Water flows through pipelines due to the pressure difference between two points, and the velocity of the fluid inside the pipeline is determined by the pressure and other factors, such as the diameter of the pipe, the roughness of the surface of the pipe, and the viscosity of the fluid. Bernoulli's equation is a fundamental principle of fluid mechanics that explains how the energy of a fluid changes as it flows along a pipeline or around a curve. It is the basic principle used to describe the behavior of fluids in motion. Bernoulli's equation can be used to calculate the total energy per unit weight of a fluid at a given point in the pipeline by adding the kinetic energy per unit weight and the potential energy per unit weight of the fluid. In this problem, water is flowing through a pipeline 600 cm above datum level, with a velocity of 10 m/s and a gauge pressure of 30 KN/m2, and the mass density of water is 1000 kg/m3. We have to calculate the total energy per unit weight of water at this point. Using Bernoulli's equation, we can obtain the following expression: T.E./w = P/w + V^2/2g + Z, Where, T.E./w = Total energy per unit weight P/w = Pressure energy per unit weight, V = Velocity of the water, g = Acceleration due to gravity, Z = Potential energy per unit weight of the water in the pipe line. Putting the given values into the equation, we get: T.E./w = 30 × 103/1000 + (10)2/(2 × 9.81) + 600/1000= 30 + 5.092 + 0.6= 35.692 m, Thus, the total energy per unit weight of water at the given point is 35.692 m.
In conclusion, the total energy per unit weight of water at a point 600 cm above datum level in a pipeline with a velocity of 10 m/s and a gauge pressure of 30 KN/m2, with a mass density of 1000 kg/m3, is 35.692 m.
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Gwendolyn shot a coin with a sling shot up into the air from the top of a building. The graph below represents the height of the coin after x seconds.
What does the y-intercept represent?
A.
the initial velocity of the coin when shot with the sling shot
B.
the rate at which the coin traveled through the air
C.
the number of seconds it took for the coin to reach the ground
D.
the initial height from which the coin was shot with the sling shot
Answer:
D
Step-by-step explanation:
Answer:
D) The initial height from which the coin was shot with the sling shot
Step-by-step explanation:
No time has passed before the slingshot has occured, so at t=0 seconds, the coin is at an initial height of y=15 feet, which is the y-intercept.
For each of the following, either show that G is a group with the given operation or list the properties of a group that it does not have: i. G = N; addition ii. G = Z; a.b=a+b-ab iii. G = {0,2,4,6}; addition in Zg iv. G = {4,8,12,16}; multiplication in Z_20
i. For G = N with addition, N represents the set of natural numbers. While addition is a valid operation on N, it does not form a group because it lacks the inverse property. In a group, for every element a, there must exist an inverse element -a such that a + (-a) = 0. However, in N, there is no negative counterpart for every natural number, so the inverse property is violated.
ii. For G = Z with the operation a.b = a + b - ab, Z represents the set of integers. To show that it is a group, we need to verify four properties: closure, associativity, existence of an identity element, and existence of inverses.
Closure: For any a, b ∈ Z, a.b = a + b - ab is also an integer, so closure is satisfied.
Associativity: The operation of addition in Z is associative, so a + (b + c) = (a + b) + c. Therefore, the operation a.b = a + b - ab is also associative.
Identity Element: In this case, the identity element is 0 since a + 0 - a*0 = a + 0 - 0 = a for any a ∈ Z.
Inverses: For every element a ∈ Z, we can find an inverse element -a such that a + (-a) - a*(-a) = 0. In Z, the additive inverse of a is -a.
Therefore, G = Z with the operation a.b = a + b - ab forms a group.
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In a buffer system, what will neutralize the addition of
a strong acid?
hydronium
water
conjugate acid
conjugate base
A buffer is a solution that is capable of resisting large changes in pH upon the addition of a small amount of acid or base. It is made up of a weak acid and its conjugate base or a weak base and its conjugate acid.
Buffer systems are important in many biological processes as they help to maintain the pH balance in living systems. If the pH of a system gets too acidic or too basic, In a buffer solution, the weak acid will donate a proton to neutralize the added base while the weak base will accept the proton to neutralize the added acid.
This is because the conjugate base of a weak acid is a weak base and can accept a proton while the conjugate acid of a weak base is a weak acid and can donate a proton. The addition of a strong acid to a buffer solution will result in the formation of the weak acid, while the addition of a strong base will result in the formation of the weak base.In a buffer system, a conjugate acid or conjugate base will neutralize the addition of a strong acid.
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In a buffer system, the conjugate base is the species that will neutralize the addition of a strong acid. The correct answer is Option D.
In a buffer system, the addition of a strong acid can be neutralized by the presence of a conjugate base. A buffer system consists of a weak acid and its conjugate base (or a weak base and its conjugate acid) in approximately equal concentrations. When a strong acid is added to the buffer, it will react with the conjugate base present in the buffer, forming the weak acid and reducing the concentration of the strong acid.
The conjugate base in the buffer acts as a base, accepting a proton from the strong acid and neutralizing it. This reaction helps maintain the pH of the solution relatively constant, as the weak acid in the buffer will resist changes in pH due to the presence of its conjugate base.
For example, in an acetic acid-sodium acetate buffer, acetic acid is the weak acid and sodium acetate is its conjugate base. When a strong acid is added, such as hydrochloric acid, the conjugate base (sodium acetate) will react with the hydronium ions from the strong acid, forming acetic acid and water. This reaction prevents the pH of the solution from drastically changing.
Therefore, in a buffer system, the conjugate base is the species that will neutralize the addition of a strong acid.
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Given: 1,2,x,5,y,8
Find the vaule of "X" and "y" if the resulting number is 5 and the mean is 4
This system of equations is inconsistent because there is no solution that satisfies both equations simultaneously. Therefore, there is no value of x and y that satisfies the given conditions.
To find the values of x and y in the sequence 1, 2, x, 5, y, 8, given that the resulting number is 5 and the mean is 4, we can use the concept of the mean.
The mean is calculated by summing all the numbers in a sequence and dividing by the total count. In this case, the mean is given as 4.
The sum of the numbers in the sequence is 1 + 2 + x + 5 + y + 8. We need to find the values of x and y such that the resulting number is 5 when added to the sequence.
Using the mean formula, we can set up the equation:
(1 + 2 + x + 5 + y + 8) / 6 = 4
Simplifying this equation, we have:
(16 + x + y) / 6 = 4
Multiplying both sides of the equation by 6, we get:
16 + x + y = 24
Rearranging the equation, we have:
x + y = 8
Since the resulting number is 5 when added to the sequence, we can write:
1 + 2 + x + 5 + y + 8 = 5
Simplifying this equation, we get:
x + y = -11
Now, we have a system of equations:
x + y = 8
x + y = -11
This system of equations is inconsistent because there is no solution that satisfies both equations simultaneously.
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Solve y′++36y=δ(t−3),y(0)=y′(0)=0 y(t)= for t<3 for t≥3
The solution to the differential equation is y(t) = 0, for t < 3
[tex]y(t) = (1/6) * (e^{-6(t-3)} - e^{6(t-3)})[/tex], for t ≥ 3
How to solve differential equationSolve the differential equation using Laplace transform.
Taking the Laplace transform of both sides of the equation
[tex]s^2 Y(s) + 36 Y(s) = e^{-3s}[/tex]
[tex]Y(s) = e^{-3s} / (s^2 + 36)[/tex]
Partial fraction decomposition of Y(s)
[tex]Y(s) = e^{-3s} / (s^2 + 36) = (1/6) * (1/(s+6)) - (1/6) * (1/(s-6)) * e^{-3s}[/tex]
Take the inverse Laplace transform
[tex]y(t) = (1/6) * (e^{-6(t-3)} - e^{6(t-3)}) * u(t-3)[/tex]
where u(t) is the unit step function.
For t < 3, the unit step function is 0
y(t) = 0.
For t ≥ 3, the unit step function is 1
[tex]y(t) = (1/6) * (e^{-6(t-3)} - e^{6(t-3)})[/tex]
Therefore, the solution to the differential equation is
y(t) = 0, for t < 3
[tex]y(t) = (1/6) * (e^{-6(t-3)} - e^{6(t-3)}),[/tex] for t ≥ 3
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Let A be a matrix 3x2 and ba vector 3x1, solve the system of linear equation by one of the 3 methods you have learned in class by checking first the rank of matrix A and the rank of [A b] 2x +3y = 1 eq (1) -x + 4y = 6 eq (2) eq (3) 5x - 6y = -3
the values of x and y that satisfy the system of equations are x = -14/11 and y = 13/11.
To solve the system of linear equations using one of the three methods (elimination, substitution, or matrix inversion), let's first check the rank of matrix A and [A b].
The matrix A is a 3x2 matrix:
A = [2 3]
[-1 4]
[5 -6]
To find the rank of A, we can perform row operations to reduce the matrix to row-echelon form. The rank of A is equal to the number of non-zero rows in its row-echelon form.
Performing row operations on A, we have:
Row 2 = Row 2 + 0.5 * Row 1
Row 3 = Row 3 - 2.5 * Row 1
The row-echelon form of A is:
A = [2 3]
[0 5]
[0 -21]
Since A has two non-zero rows, the rank of A is 2.
Next, we check the rank of [A b]. The vector b is a 3x1 vector:
b = [1]
[6]
[-3]
We can append vector b as an additional column to matrix A:
[A b] = [2 3 1]
[-1 4 6]
[5 -6 -3]
Performing row operations on [A b], we have:
Row 2 = Row 2 + Row 1
Row 3 = Row 3 - 2 * Row 1
The row-echelon form of [A b] is:
[A b] = [2 3 1]
[0 7 7]
[0 -12 -5]
Since [A b] has two non-zero rows, the rank of [A b] is also 2.
Since the rank of A and [A b] are both 2, we can proceed with solving the system of linear equations using any of the three methods.
Let's use the method of matrix inversion to solve the system.
The system of equations can be written as a matrix equation:
Ax = b
To find x, we can multiply both sides of the equation by the inverse of A:
[tex]A^(-1) * A * x = A^(-1) * b[/tex]
[tex]I * x = A^(-1) * b[/tex]
[tex]x = A^(-1) * b[/tex]
To find the inverse of A, we can use the formula:
[tex]A^(-1) = (1 / (ad - bc)) * [d -b][-c a][/tex]
Plugging in the values of matrix A, we have:
[tex]A^(-1) = (1 / (2 * 4 - 3 * -1)) * [4 -3][1 2][/tex]
Calculating the inverse of A, we have:
A^(-1) = (1 / 11) * [4 -3]
[1 2]
Multiplying A^(-1) by vector b, we have:
[tex]x = (1 / 11) * [4 -3] * [1][6][-3][/tex]
Calculating the product, we get:
x = (1 / 11) * [4 * 1 + -3 * 6]
[1 * 1 + 2 * 6]
Simplifying, we have:
x = (1 / 11) * [-14]
[13]
Therefore, the solution to the system of linear equations is:
x = -14/11
y = 13/11
Hence, the values of x and y that satisfy the system of equations are x = -14/11 and y = 13/11.
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Which reactor type best describes a car with a constant air ventilation rate ? a.Plug flow reactor b.Completely mixed flow.reactor c. Batch reactor d. none of the above
Among the given options, none of them describes the reactor type best for a car with a constant air ventilation rate
A reactor is a machine or vessel used for the manufacture of chemical reactions. The reactor can be cylindrical, spherical, conical, or some other geometric form. The reactor's size may range from a fraction of a cubic centimeter to several cubic meters.
The types of reactors are:
- Plug flow reactor: It is a type of chemical reactor where the fluid moves continuously through the reactor. In this type of reactor, the chemical reaction proceeds as the chemicals move along the reactor's length.
- Completely mixed flow reactor: In this type of reactor, chemicals are uniformly distributed throughout the reactor, and the reaction is done. It's also known as a continuous stirred tank reactor (CSTR).
- Batch reactor: A reactor is a machine or vessel used for the manufacture of chemical reactions. In a batch reactor, chemicals are combined in a single batch and then processed. In the reactor, there is no input or output of chemicals while the reaction is taking place.
So, none of the given options describes the reactor type best for a car with a constant air ventilation rate. As the ventilation rate is constant, there's no input or output of air, and there's no reaction occurring. Thus, none of the given options is applicable.
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A fully penetrating unconfined well of 12 in. diameter is pumped at a rate of 1 ft³/sec. The coefficient of permeability is 750 gal/day per square foot. The drawdown in an observation well located 200 ft away from the pumping well is 10 ft below its original depth of 150 ft. Find the water level in the well
Therefore, the water level in the well is 160 ft.
A fully penetrating unconfined well of 12 in. diameter is pumped at a rate of 1 ft³/sec.
The coefficient of permeability is 750 gal/day per square foot.
The drawdown in an observation well located 200 ft away from the pumping well is 10 ft below its original depth of 150 ft.
To find: The water level in the well.
Let the water level in the well be h ft.
The discharge of the well (Q) = 1 ft³/sec. = 7.48 gallons/sec.
The radius of the well (r) = 12/24 = 0.5 ft.
The distance between the well and observation well (r) = 200 ft.
The original water level in the observation well = 150 ft.
The drawdown (s) = 10 ft.
The coefficient of permeability (k) = 750 gal/day per square foot.
Q = 7.48 gallons/sec.
s = h - 150ft.
k = 750 gallons/day/ft².
Convert k into feet by the following conversion,1 day = 24 hours 1 hour = 60 min 1 min = 60 sec 1 day = 86400 sec
So, k = (750/86400) ft/sec =(0.00868055) ft/sec
Now, we can use Theis' formula to find the value of h.
The Theis' formula is given by,
s = (Q/4πT) W(u) ------(1)where, T is the transmissivity, W(u) is the well function, and u is the distance between the pumping well and observation well such that u = r²S/4Tt, where,
S is the storativity, and t is the time
.π = 3.14
Using the above values in equation (1), we get10 = [7.48/(4 x 3.14 x T)] W(u) -------(2)T = k x b
where, b is the thickness of the aquifer, and k is the coefficient of permeability.
T = 0.00868055 ft/sec x 150 ftT = 1.3021 ft²/sec
Substituting the value of T in equation (2),10 = [7.48/(4 x 3.14 x 1.3021)] W(u)
W(u) = 0.1416
For u > 1, W(u) can be approximated as, W(u) = ln(u) + 0.57721 + 0.0134u² + 0.76596u² + 0.25306u³ + ........(3)
Here, u = r²S/4Tt. We don't know the value of S yet, so we can use a trial and error method to find the value of S and u.
Using S = 0.0002 for trial, we get u = 2.76.
Using equation (3),W(u) = ln(2.76) + 0.57721 + 0.0134(2.76)² + 0.76596(2.76)³W(u) = 0.2419
Now, substituting the values of T and W(u) in equation (2), we get10 = [7.48/(4 x 3.14 x 1.3021)] x 0.2419T = 1.3021 ft²/sec
Hence, the water level in the well is given by,
h = s + 150h = 10 + 150 = 160 ft
Therefore, the water level in the well is 160 ft.
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Use the References to access important values if needed for this question. Queen Ort. The nuclide 48c decays by beta emission with a half-life of 43.7 hours. The mass of a 18sc atom is 47.952 u. Question (a) How many grams of sc are in a sample that has a decay rate from that nuclide of 401 17 Question 01.8 g Question 5 1.511.5 (b) After 147 hours, how many grams of 48sc remain? Question 1.15 g Sub 5 question attempts remaining
The initial mass of 48Sc in the sample is 1.5115 g, and its decay rate is 401.17 decays per hour. After 147 hours, the remaining mass of 48Sc is 1.15 g.
Explanation:
The decay rate of a radioactive nuclide is proportional to the number of radioactive atoms present in the sample. We can calculate the initial mass of 48Sc by using its atomic mass and the Avogadro constant. The decay rate is given as 401.17 decays per hour, indicating the number of decays occurring in one hour. By multiplying the decay rate by the half-life of 48Sc (43.7 hours), we can determine the number of decays that have occurred in 147 hours.
This can then be used to calculate the remaining mass of 48Sc using the initial mass and the decay constant.
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Acetic acid (100,0%) produced from the biomass pyrolysis is a promising feedstock for the production of clean-energy source of hydrogen. You are working for a company that produces hydrogen and your boss asks you to prepare a design project for a hydrogen synthesis plant which would be located close to your current plant site. Hydrogen synthesis plant is supposed to be only 500 m away from the storage tank area of the acetic acid and will have an attitude of 25 m with respect to this plant. The storage tank, which is the start point of the pipeline, is being operated at 25°C and 1 atm. Volumetric flow rate of the acetic acid is 6 x 10-3³ m³/s. The storage tank, which is the end point of the pipeline is opened to the atmosphere. All of the piping is 4 in schedule 40 pipe. At this stage, you are expected to i) Decide on the material of pipes (Hint:Check corrosivity from "Safety Data Sheet" for your chemical), ii) Decide on type and number of valves and fittings, $ iii) Calculate the total frictional loss, iv) Decide on pump efficiency, iv) Calculate the kW power needed for the pump. You must present a detailed sample-hand calculation in your report as well as an explicit diagram of your pipeline with all fittings and valves, etc. Your report should include: Cover page Statement of the problem Method of calculations Assumptions/decisions made Hand calculation results Discussion (Discussing the assumptions and decisions made)
(i) Material considered for Design - PP (Polypropylene)
(ii) Valve such as Gate & Globe can be used.
(iii) the total frictional loss - 57.255 m.
(iv) Total Power Consumption - 3370.02 W.
(i) Material of Pipe used - 304 & 316L Grade of STAINLESS STEEL, Haste alloy B & C & PP ( Polyproypene ) can be used for the piping material of acetic acid.
From cost point of view Haste alloy is quite expensive material, so we can go for SS 304 , SS 316 L or PP (Polypropylene)
But as the operating temperature and pressure is very less PP (Polypropylene) would be best material from design and from cost point of view,.
So Final Material considered for Design - PP (Polypropylene)
(ii) Type & Number of Valve & Fittings -
A pump with suitable head will be needed to pump the acetic acid to desired location.
Number of Bend - 2 nos of 90 Degree Bends (On Assumption )
Fittings - Flange fittings
Valves - 2 nos Butterfly valve ( One At Inlet & and other at Outlet of Pump)
1 nos NRV (Non-Return Valve) or Check Valve at discharge side to prevent backflow of acetic acid.
1 nos Butterfly valve for isolation purpose at the end discharge point
Other type of Valve such as Gate & Globe can also be used but I have considered Butterfly valve.
(iii) Friction Loss Calculation -
1) Volumetric Flowrate (Q) - 4 X 10⁻³ m3/sec
2) Size of Pipe - 2 in Secduled 40 -
ID - 2.067 inch (52.5018 mm)
OD - 2.375 inch (60.325 mm)
3) A (Area of Pipe) - pi/4 * ID² - 2.164 x 10⁻³ sqm
4) Velocity in Pipe - Q/A - 1.84 m/s
5) Reynolds Number -(D*V*Rho)/viscosity - 87032 (turbulent flow)
So now we will calculation friction factor for Turbulent flow with smooth
pipes
We will use Blasius equation
f - 0.316/Re
f - 0.01839 ............................ (1)
Now Let's calculate friction coefficient for minor losses
Friction loss due to 90 Degree bend - 0.45
Total Friction Losses - Major Loss + Minor Loss
- 4fLv² /2gD + hv²/2g
- 11.967 + 0.288
Total Friction Losses - 12.255 m .................. (1)
Static Head Required - 45 m ................ (2)
We are using Darcy Weisbach equation for calculation friction loss
where,
f - friction factor
v - velocity in pipe (m/s)
D - ID (Inside diameter of Pipe)
g - 9.81 m/s² acceleration due to gravity
h - Sum of Friction factor due to bends and other minor losses
From (1) & (2)
Total Head Required - Static Head + Dynamic Head
- 45 + 12.255
- 57.255 m
(iv) Total Power consumption by Pumps - Rho * g * Q * H / Efficiency
Efficiency not given ( So Assuming 70 % )
Rho (density of acetic Acid ) - 1050 kg /m³
Total Power Consumption - 3370.02 W or 3.370 kW
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