The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map. (b) Calculate length of a road on the map which is 0.58 km. (c) Calculate, in km2, the ACTUAL area of a lake which is 12 cm2 on the map. (d) Calculate the area of a play field on the map which has has an actual area of 90 km2.

Answers

Answer 1

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So,  1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²


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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

A. Acute Triangle

Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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The expansion of the given logarithm [tex]\mathbf{Log_3 (4x^2)}[/tex] is [tex]\mathbf{= 2log_3(2)+2log_3(x)}[/tex]

What is the expansion of the logarithm?

A Logarithm is an exponent to which a base must be raised in order to result in a given number. The expansion of the logarithm takes a predictable approach and set guidelines.  

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By expansion;

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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down below is a cheatsheet.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

to find the answer you need to put this equation into a calculator

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer

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Answers

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Step-by-step explanation:

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Answers

Answer: 45°

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Answers

Answer:

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Answers

I believe it is B, k is always y, meaning -h would have to be x
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Answers

Answer:

B

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Answers

So we know that the bald eagle drinks 0.16 per day. (I am not sure liters, gallons, etc because it is not stated in the question.) Now, the question tells us that River Otters drink about 5 times MORE then the bald eagle. So first we need to multiply.  

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Now to find out how much a River Otter drinks in 3 days do:

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O.8 is how much they drink a day

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Answers

Answer:

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Answers

Answer:

X = 42x - 24

Showing the work :

6(7x−4)

=(6)(7x+−4)

=(6)(7x)+(6)(−4)

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_____________________

*rate this answer and say thanks please!

the answer is 42x - 24

Each team in the league can spend a maximum of $33 million per year on salaries. If the Whalers have 45 players and the average salary is $700,000, how much do they have left under the cap?

Answers

Answer:

1.5 million

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Answers

Answer:

x = 7/3 or 2.33

Step-by-step explanation:

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x3 = 8 - 1

x3 = 7

x = 7/3 or 2.33

HOPE THIS HELPS YOU!! :)

Answer: x = 2

Step 1.

In order to solve this non-linear equation, we need to move all the terms to the left side.

In x³ + 1 = 9...

- term 1, will be moved to the right side.

Notice that a term changes sign when it 'moves' from one side of the equation to the other.

Rewrite the equation like this:  (x³ + 1) + (-1) = 9 + (-1)

Step 2.

Add x³ + 1 + (-1)

x³ + 1 + (-1) = 8

Now, x = 8.

Step 3.

In this non-linear equation, the variable needs to be isolated.

This is accomplished when both sides are exponentiated by the reciprocal of the variable's exponent, which in our example, 1/3 is equal to

Notice that since we exponentiated a simplified fraction with an odd denominator, only one solution has been created.

Rewrite the equation: [tex](x^3)^\frac{1}{3} =8^\frac{1}{3}[/tex]

Step 4.

We need to exponentiate the power.

The following rule is applied: [tex](A^B)^C=A^B^C[/tex]

According to the formula,

A = X

B = 3

C = 1/3

Rewrite the equation: [tex]x^3^\times^\frac{1}{3} =(2^3)^\frac{1}{3}[/tex]

Step 5.

We need to reduce this fraction, the 3 in x to the lowest terms.

This can be done by dividing out those factors that appear both in the numerator and in the denominator.

In our example, 3 is the common factor.

Rewrite the equation: [tex]x=2^\frac{3}{3}[/tex]

Step 6.

Lastly, we'll need to do the same thing as we did in step 5. Reduce the fraction in [tex]x=2\frac{3}{3}[/tex]. This can be done by dividing out those factors that appear both in the numerator and in the denominator.

Hence, the common factor is 3 since it occurs both in the numerator and the denominator.

Hence, x = 2.

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