The populations of 2 cities grow according to the exponential functions. Pi(t) = 120 e 0.011 t P2(t)= 125 e 0.007 t Where, P₁ and P2 are the populations (in thousands) of cities A and B respectively. t is the time in years such that t is positive and t = 0 corresponds to the year 2004. When were the populations of the two cities equal and what were their populations? ​

Answers

Answer 1

Hello,

I hope you and your family are doing well!

To find when the populations of the two cities are equal, we can set P1(t) = P2(t) and solve for t:

120 e 0.011 t = 125 e 0.007 t

Dividing both sides by e 0.007 t:

120 = 125 * (e 0.011 t / e 0.007 t)

Using the property that e^(a+b) = e^a * e^b, we have:

120 = 125 * e^(0.011 t - 0.007 t)

120 = 125 * e^(0.004 t)

Dividing both sides by 125:

1.2 = e^(0.004 t)

Taking the natural logarithm of both sides:

ln 1.2 = ln e^(0.004 t)

ln 1.2 = 0.004 t

t = ln 1.2 / 0.004

t = approximately 8.44 years

Therefore, the populations of the two cities were equal approximately 8.44 years after 2004, or in the year 2012. To find the population of the two cities at this point in time, we can substitute t = 8.44 into either of the exponential functions:

P1(8.44) = 120 e 0.011 * 8.44 = approximately 123.88 thousand

P2(8.44) = 125 e 0.007 * 8.44 = approximately 123.88 thousand

Therefore, the populations of the two cities were equal to approximately 123.88 thousand when they were equal.

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Related Questions

a) Work out the minimum number of dogs that could have a mass of more than 24kg}
b) Work out the maximum number of dogs that could have a mass of more than 24kg

Answers

The minimum number of dogs 24kg is 6 and the maximum number of dogs is 18    

Maximum and Minimum:

The highest amount or value or number that may be obtained or reached or can be counted is the Maximum value                              

The least amount or value or number that may be admitted or reached or can be counted is the Minimum value            

Here we have a table  

Which represents the masses of various dogs

Mass (x) kg          frequency  

0 ≤ x < 10                    2

10 ≤ x < 20                  7

20 ≤ x < 30                12

30 ≤ x < 40                 6      

Here the mass of dogs is represented in class intervals

a) The minimum number of dogs with a mass of more than 24kg.

From the given table,

24 kg will lie in class intervals 20 ≤ x < 30, and 30 ≤ x < 40                      

In class interval 20 ≤ x < 30, there is a possibility that the mass of dag will be less than 24 kg since it started from 20 kg and is up to 30 kg  

In class interval 30 ≤ x < 40, there is no possibility that the mass will be less than 24 kg since it started from 30 kg and is up to 40 kg

So The minimum number of dogs that have a mass of more than 24kg the frequency of class interval 30 ≤ x < 40

Therefore,

The minimum number of dogs with a mass of more than 24kg is 6

b) The maximum number of dogs that have a mass of more than 24kg.

To get the maximum number of dogs we need to take the class interval of 20 ≤ x < 30 as in this the mass could be more than 24 kg.

And in class 30 ≤ x < 40 the mass will be more than 24 kg.

Thus, the Maximum number of dogs with more than 24 kg = 12 + 6 = 18

Therefore,

The maximum number of dogs with a mass of than 24kg is 18    

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please help in this grade 7 percentage question im desperate

Answers

Answer:

See below

Step-by-step explanation:

320 x .1 = 32

320 + 32 = 352

352 x .5 = 176

352 + 176 = 528

320 x .65 = 208

320 + 208 = 528

6x + 3y = 3 3x - y = 4

Answers

Answer:

x = 1

y = -1

Step-by-step explanation:

Given equations:

6x + 3y = 3 -------------(1)

3x - y = 4 ----------------(2)

Multiply Eq. (2) by 2

2(3x - y) = 4 × 2

6x - 2y = 8 -------------(3)

Subtract Eq. (3) from Eq. (1)

6x + 3y - (6x - 2y) = 3 - 8

6x + 3y - 6x + 2y = -5

3y + 2y = -5

5y = -5

Divide 5 to both sides

y = -5/5

y = -1

Put y = -1 in Eq. (1)

6x + 3(-1) = 3

6x - 3 = 3

Add 3 to both sides

6x = 3 + 3

6x = 6

Divide 6 to both sides

x = 1

[tex]\rule[225]{225}{2}[/tex]

A dice game involves rolling 2 dice. If you roll a 2, 3, 4, 10, 11, or a 12 you win $5. If you roll a 5, 6, 7, 8, or 9 you lose $5. Find the expected value you win (or lose) per game.

Answers

The correct answer is option B which is  -1.67 is the expected value.

What is Probability?

It is a branch of mathematics that deals with the occurrence of a random event.

You have a higher probability of losing money than gaining it due to the distribution of probability.  

There are more chances to lose than win.

As a result, you are expected to lose money.

Only -1.67 is the only negative option, which means that we don't even need to do real math since there's already only one choice.

Hence, the correct answer is option B which is  -1.67 is the answer.

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Answer:

You will Gain 5 points.

Step-by-step explanation:

Got it right on the test!

The following are rules for repeating patterns. For which rule will the 12th shape be a circle?

A.
triangle, circle, square

B.
circle, square

C.
rectangle, circle

D.
circle, circle, triangle

Answers

Answer:

A Square

B Square

C Circle

D Triangle

Writing Equations of lines

Write the equation of each line with the given information

through: (-3, 4) and (-5, -1)

Answers

Answer:

y = 5/2x + 11.5

Step-by-step explanation:

(-3, 4) (-5, -1)

m = -1-4/ -5+3

m = -5 / -2

m = 5/2

y = 5/2x + b

-1 = 5/2(-5) + b

-1 = -12.5 + b

b = 11.5

y = 5/2x + 11.5

Answer:

y-y1=y2-y1/x2-x1(x-x1)

y-4= (-1-4/-5+3) (x+3)

y-4= -5/-2(x+3)

y=5/2x+15/2+4

y=5/2x+15+8/2

y=5/2x+23/2

A certain skincare company's profit in millions of dollars, P(t), can be modeled by the polynomial function P(t) = –2t3 + 8t2 + 2t, where t represents the number of skincare items produced, in thousands. Today, the company produces 1 thousand products for a profit of $8 million. According to the graph of the function, what other quantity of product would result in the same profit?

Answers

The required value of the production at which the company attained the same profit is 4 thousand skin care items.

Given that,

A certain skincare company's profit in millions of dollars, P(t), can be modeled by the polynomial function P(t) = –2t³ + 8t² + 2t, where t represents the number of skincare items produced, in thousands. Today, the company produces 1 thousand products for a profit of $8 million.

Here,
Plotting the graph of the polynomial equation,

P(t) = –2t³ + 8t² + 2t,
From the graph at x = 4,
The polynomial gives the same value as it gave at x = 1,

Thus, the required value of the production at which the company attained the same profit is 4 thousand skin care items.

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is a parallel to b? Explain using angels and measurements. Angel measrment should be part of your explanation.​

Answers

Answer:

Not parallel.

Step-by-step explanation:

Given:

m∠9 = 110°m∠8 = 70°

Linear Pair

Two adjacent angles that sum to 180° (two angles which when combined together form a straight line).

Angles 9 and 10 form a linear pair:

⇒  m∠9 + m∠10 = 180°

⇒  110° + m∠10 = 180°

⇒  m∠10 = 70°

Angles 7 and 8 form a linear pair:

⇒  m∠7 + m∠8 = 180°

⇒  m∠7 + 70° = 180°

⇒  m∠7 = 110°

Vertical Angles Theorem

When two straight lines intersect, the opposite vertical angles are congruent.

Corresponding Angles Postulate

When a straight line intersects two parallel straight lines, the resulting corresponding angles are congruent.

As line p is parallel to line q, and according to the vertical angles theorem and the corresponding angles postulate:

m∠1 = m∠6 = m∠9 = m∠14 = 110°m∠2 = m∠5 = m∠10 = m∠13 = 70°m∠3 = m∠8 = m∠11 = m∠16 = 70°m∠4 = m∠7 = m∠12 = m∠15 = 110°

If line a was parallel to line b, then according to the corresponding angles postulate:

m∠1 = m∠3 = m∠6 = m∠8m∠2 = m∠4 = m∠5 = m∠7

As m∠1 ≠ m∠8 and m∠2 ≠ m∠7 then lines a and b are not parallel.

A cable running from the top of a telephone pole creates a horizontal pull of 889 Newtons (N). A support cable running to the ground is inclined 71° from the horizontal.

Find the tension in the support cable. Give answer to the nearest whole number.

Answers

The tension in the support cable is 2731 N

How to find the tension in the support cable?

Given that:

A cable running from the top of a telephone pole creates a horizontal pull of 889 Newtons (N) and a support cable running to the ground is inclined 71° from the horizontal.

This can sketch as shown in the attached image. Considering the image:

T is the  tension in the support cable

Using trigonometric ratio:

cos 71° = 889/T    (adjacent/hypotenuse)

T = 889/cos 71°

T = 2731 N

Therefore, the tension in the support cable is 2731 N

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Cameron is deciding between two landscaping companies for his place of business.
Company A charges $25 per hour and a $300 equipment fee. Company B charges $55
per hour and a $150 equipment fee. Let A represent the amount Company A would
charge for t hours of landscaping, and let B represent the amount Company B would
charge for t hours of landscaping. Write an equation for each situation, in terms of t,
and determine the interval of hours, t, for which Company A is cheaper than
Company B.

Answers

Answer:

A = 25t + 300

B = 55t + 150

Less than 5 hours, company B would be cheaper.  At 5 hours the cost is equal.  After 5 hours, company A would be cheaper.

Step-by-step explanation:

Company B would be cheaper for lower hours.

The the two equation equal to each other and solve for to find out when the costs will be equal.

25t + 300 = 55t + 150  Subtract 25t from both sides

300 = 30t + 150  Subtract 150 from both sides

150 = 30t  Divide both sides by 30

5 = t

At 5 hours the cost are the same, after 5 hours company A would be cheaper.

Angle ABC is taken by a dilation with centerpoint, P and scale factor of four to angle A’B’C’ the measure of angle, BCA is 75° what is the measure of angle B’C’A’

Answers

Answer:

  75°

Step-by-step explanation:

You want to know the measure of the image angle B'C'A' after angle A'B'C' is dilated by a factor of 4 about point P. Angle BCA is 75°.

Dilation

Dilation does not affect angle measures, so angle B'C'A' has the same measure as angle BCA, 75°.

  m∠B'C'A' = 75°

write an expression that is equivalent to 2/3 (4x + 9)​

Answers

Hello,

I hope you and your family are doing well!

To write an expression that is equivalent to 2/3 (4x + 9), you can simply distribute the 2/3 over the parentheses:

2/3 (4x + 9) = (2/3 * 4x) + (2/3 * 9)

This simplifies to:

2/3 (4x + 9) = (8/3)x + (18/3)

Therefore, an expression that is equivalent to 2/3 (4x + 9) is (8/3)x + (18/3).

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Happy Holidays & New Year!

Answer: 2 2/3x + 6

Step-by-step explanation: 1 of 3 ways to find how to make the equivalent is to use the distributive property. So, that means we need to multiply or distribute 2/3 to both 4x and 9. So, 2/3 x 4 is roughly 2 2/3. Also, 2/3 x 9 = 6. So, I combined the like terms to get 2 2/3x + 6 as my equivalent expression. I hope this helps.

Use the Special Integration Formulas (Theorem 8.2) to find the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) squareroot of (9 + 49^x2) dx

Answers

The indefinite integral of given integral ∫√(9+49x^2)dx is ∫√(9+49x^2)dx = [tex]\int\sqrt{(9+49x^2)}dx = 1/98[98x\sqrt{9+49x^2}+9In|7x+\sqrt{9+49x^2}}|]+C[/tex].

In the given question we have to find the indefinite integral.

The given integral is

∫√(9+49x^2)dx

Now finding the indefinite integral using the C for the constant of integration.

An integral is regarded to be indefinite if it has no lower or upper bounds. In mathematics, the most generic antiderivative of f(x) is known as an indefinite integral and expressed by the expression f(x) dx = F(x) + C.

We can write it as:

[tex]\int\sqrt{(9+49x^2)}dx = \int\sqrt{[(3)^2+(7x)^2]}dx[/tex]

Taking common 7^2

[tex]\int\sqrt{(9+49x^2)}dx = 7\int\sqrt{[(3/7)^2+(x)^2]}dx[/tex]

Using the formula

[tex]\int\sqrt{(a^2+x^2)}dx = \frac{1}{2}\times\sqrt{a^2+x^2} + \frac{1}{2}\cdot a^2In|x+\sqrt{a^2+x^2}|+C[/tex]

[tex]\int\sqrt{(9+49x^2)}dx = 7[x\sqrt{(3/7)^2+x^2}+\frac{1}{2}\cdot(\frac{3}{7})^2In|x+\sqrt{(3/7)^2+x^2}|]+C[/tex]

[tex]\int\sqrt{(9+49x^2)}dx = 7[x\sqrt{9/49+x^2}+1/2\cdot(9/49)In|x+\sqrt{(9/49)+x^2}|]+C[/tex]

[tex]\int\sqrt{(9+49x^2)}dx = 7[x\cdot\frac{\sqrt{9+49x^2}}{7}+1/2\cdot(9/49)In|x+\frac{\sqrt{9+49x^2}}{7}|]+C[/tex]

[tex]\int\sqrt{(9+49x^2)}dx = 7[x\cdot\frac{\sqrt{9+49x^2}}{7}+(9/98)In|\frac{7x+\sqrt{9+49x^2}}{7}|]+C[/tex]

[tex]\int\sqrt{(9+49x^2)}dx = 1/98[98x\sqrt{9+49x^2}+9In|7x+\sqrt{9+49x^2}}|]+C[/tex]

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PS bisects ∠QPR . Complete the proof that ∠PSR ≅ ∠PSQ .

Answers

The proof is shown in the image.

Reasons for statement

Any line that bisects an angle divides the angle into two equal parts The two lines are congruent by cpct as the triangles are congruent The angle subtended the bisector line divides equally into two angles. Also, the triangles are congruent so angle QPS = angle RPS by cpct The common line between congruent triangles is the same Triangles are congruent by side angle side rule Angles are equal by corresponding parts of the congruent triangle rule.

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Prove that the roots of the equation mx² + (m − 2)x − (m + 1) = 0 are real for all values of m

Answers

Answer:

Below

Step-by-step explanation:

For REAL numbers, the discriminant of the Quadratic Formula has to be a positive value (or zero)

b^2 - 4ac   >= 0         where   a = m       b = m-2        c = -m-1  

(m-2)^2 - 4(m)(-m-1) >=0  

5m^2 +4   >= 0      

       5 m^2 +4     <===== will always be >= 0   for any value of 'm'

                                     so all roots will be real

1.6y+y-4/15y+1 1/6y=2 1/3 pls help

Answers

The simplification of the given equation is -630y² + 81y + (+2.6y) * 90y² = 0.

What is the domain of the function?

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

We have,

1.6y+y-4/15y+7/6y=21/3

Move all terms to the left:

1.6y+y-4/15y+7/6y-(21/3)=0

Domain of the equation: 15y!=0

y!=0/15

y!=0

y∈R

Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R

Add all the numbers together, and all the variables

1.6y+y-4/15y+7/6y-7=0

Add all the numbers together, and all the variables

2.6y-4/15y+7/6y-7=0

calculate fractions

2.6y+(-24y)/90y²+105y/90y²-7=0

multiply all the terms by the denominator

(2.6y) * 90y² + (-24y) + 105y - 7 * 90y² = 0

Add all the numbers together, and all the variables

(2.6y) * 90y² + (-24y) + 105y - 7 * 90y² = 0

Add all the numbers together, and all the variables

105y+(+2.6y)*90y² + (-24y) - 7*90y² = 0

multiply elements

-630y+105y+(+2.6y)*90y² + (-24y) = 0

get rid of parentheses

-630y² + 105y + (+2.6y)*90y² - 24y = 0

Add all the numbers together, and all the variables

-630y² + 81y + (+2.6y) * 90y² = 0

Hence, the simplification of the given equation is -630y² + 81y + (+2.6y) * 90y² = 0.

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High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capability Challenge Exam. Students who score in the top 18 percent are recognized publicly for their achievement by the Department of the Treasury. Assuming a normal distribution, how many standard deviations above the mean does a student have to score to be publicly recognized?

Answers

Using the normal distribution, it is found that a student has to score 0.675 standard deviations above the mean to be publicly recognized.

In a normal distribution with mean  and standard deviation , the z-score of a measure X is given by:

z=x-nuo/sigmaIt measures how many standard deviations the measure is from the mean.  After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.The top 25% is at least the 100 - 25 = 75th percentile, which is X when z has a p-value of 0.75.Looking at the z-table, z = 0.675 has a p-value of 0.75.Hence, a student has to score 0.675 standard deviations above the mean to be publicly recognized.

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50 minus 2.5 x greater-than-or-equal-to 20. Negative 2.5 x greater-than-or-equal-to negative 30. x greater-than-or-equal-to 12.

Answers

Negative 2.5 x greater-than-or-equal-to negative 30 is the equivalent expression of 50 minus 2.5 x greater than or equal to 20

How to find an equivalent expression?

Equivalent expressions can be defined as expressions that are the same, even though they may look a little different. If you plug in the same variable value into equivalent expressions, they will give you the same value when you simplify

Given: 50 minus 2.5 x greater than or equal to 20

50 - 2.5x ≥ 20

Subtract 50 from both sides:

-2.5x ≥ 20-50

-2.5x ≥  -30

Therefore, the equivalent expression is "negative 2.5 x greater-than-or-equal-to negative 30"

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Complete the ratio 4:16 = 1:?

Answers

Answer:

1:4

Step-by-step explanation:

4:16 = 1:?

4/4 = 1

16/4 = 4

= 1:4

What is the inverse of f(x)=2x+9?

Answers

Answer:Find the Inverse f (x)=-2x+9Find the Inverse f (x)=-2x+9 f (x) = −2x + 9 f (x) = - 2 x + 9 Write f (x) = −2x+ 9 f (x) = - 2 x + 9 as an equation. y = −2x+9 y = - 2 x + 9 f (x) = −2x + 9 f (x) = - 2 x + 9 Write f (x) = −2x+ 9 f (x) = - 2 x + 9 as an equation. y = −2x+9 y = - 2 x + 9

Step-by-step explanation:

The equation of the graph
is y = pq* where p and q are
positive constants.
Find the values of p and q.

Answers

The graph is y = 3 * 2^x where * means multiplication
It might be easier to read as y = 3(2^x)

Not sure what pq* meant in your question but p is probably 3 and q is 2

Write the following as an inequality.
−8 is less than or equal to w, and 3 is greater than or equal to w
Use w only once in your inequality.

Answers

Answer:

Step-by-step explanation:

If -8 is less than or equal to w, and 3 is greater than or equal to w, then we can combine these two inequalities into a single inequality by combining the left and right sides:

-8 ≤ w ≤ 3

This inequality can be read as "w is greater than or equal to -8 and less than or equal to 3." It represents all values of w that are greater than or equal to -8 and less than or equal to 3, including -8 and 3.

I hope this helps! Let me know if you have any questions.

-8w hope this answer helps u a lot!

Solve the equation for v.

0.5v + 0.03 > 2.83

v > 1.3
v < 1.3
v > 5.6
v < 5.6

Answers

Answer:

[tex] \huge{ \boxed{v > 5.6}}[/tex]

Step-by-step explanation:

[tex]0.5v + 0.03 >2.8[/tex]

In order to solve this inequality, first subtract 0.03 from both sides of the inequality to isolate 0.5v

[tex]0.5v + 0.03 - 0.03 > 2.83 - 0.03 \\ 0.5v > 2.8[/tex]

Next divide both sides by 0.5

[tex] \frac{0.5v}{0.5} > \frac{2.8}{0.5} \\ v > 5.6[/tex]

We have the final answer as

[tex] \bold{v > 5.6}[/tex]

help please very easy proportional relationship due hurry please than u!

Answers

1) h=1/5 k

(10/2 = 1/5, 20/4 = 1/5... etc)

2) k=5/4 h

(5/4 = 5/4, 10/8=5/4... etc)

3) h=5/1 k

(25/5 = 5/1, 30/6 = 5/1 ... etc)

Hope this helps!

:]


Which ordered pair satisfies the inequality? 6x + 5y < -15

Answers

The ordered pair of the inequality 6x + 5y < -15 are (2, 0) and (3, 2).

What is inequality?

When two expressions are connected by a sign like "not equal to," "greater than," or "less than," it is said to be inequitable. The inequality shows the greater than and less than relationship between variables and the numbers.

Considering the provided inequality and the provided ordered pairs, we will check it by replacing one by one in the inequality; if the inequality is fulfilled, they are the solution; otherwise, they are not, so we obtain:

(2, 0):

6x + 5y > 2

6(2)+5(0)>2

12+0>2

12>0

Since the inequality holds, then the ordered pair is a solution.

(7, -8):

6x + 5y > 2

6(7)+5(-8) > 2

42-40>2

2>2

Since the inequality is not satisfied, then the ordered pair is not a solution.

(3, 2):

6x + 5y > 2

6(3)+5(2) >2

18+10>2

28>2

Since the inequality holds, then the ordered pair is a solution.

(-8, 6):

6x + 5y > 2

6(-8)+5(6) >2

-48 + 30 > 2

-18 > 2

Since the inequality is not satisfied, then the ordered pair is not a solution.

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Find the Area of the figure below, composed of a rectangle and two semicircles. Round to the nearest tenths place.

Answers

The area of the given figure composed of a rectangle and two semicircles is 68.56 unit².

What is Area :

The space around a shape's perimeter or boundary is known as its area. To determine the areas of various forms, many mathematical formulae are available.

Area of circle = πr², where r is the radius of the circle. Area of rectangle = lb, where l = length and b = breadth.  

Here we have

composed of a rectangle and two semicircles.

Dimensions of the rectangle are,

Length = 14 and breadth = 4  

=>Area of the rectangle = 14 × 4 = 56 units²

If we join the two semicircles,

we will have one circle with a diameter of 4 units

=> As we know Radius of the circle = Diameter/2

=> Radius of circle = 4/2 = 2 units

=> Area of the circle = 2πr

= [tex]2 \times\frac{22}{7} \times 2[/tex] = 12.56 unit²  

Area of the figure = Area of rectangle + Area of the circle

= 56 units² + 12.56 unit²  

= 68.56 unit²

Therefore,

The area of the given figure composed of a rectangle and two semicircles is 68.56 unit².

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A side of the triangle below has been extended to form an exterior angle of 156°. Find the value of x.

Answers

The value of x inside the triangle is 24°

How to calculate the value of x(angle)?

A straight line's total number of angles adds up to 180°. Supplementary angles are two angles whose sums equal 180 degrees. Angles are referred to as neighbouring if they have a similar vertex and side.A straight angle in mathematics is one with a degree value of 180. Because it resembles a straight line, it is called straight.Angles in a straight line are the total of all the angles that can be arranged in a straight line. Straight line angles add up to 180°.

The angle of the straight line = 180°

156° + x = 180°

x = 180° - 156°

x = 24°

Hence, the value of x inside the triangle is 24°.

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Each morning Tess chooses either red ribbon or blue ribbon at random to wear in her hair what is the probability that Tess will choose a red ribbon on both Monday and Tuesday

Answers

The probability of choosing red ribbon on both Monday and Tuesday is 1/4.

What is the probability?

The Probability in mathematics is possibility of an event in time. In simple words how many times that incident is happening in any given time interval.

Given that each morning Tess chooses either red ribbon or blue ribbon at random to wear in her hair.

That means probability of choosing between blue or red is 1/2 in one morning.

Now the probability of choosing red ribbon on both Monday and Tuesday,

1/2 × 1/2

= 1/4

Therefore, the probability of choosing red ribbon on both Monday and Tuesday is 1/4.

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A certain vending machine offers 20-ounce bottles of soda for $1.50. The number of bottles X bought from the machine on any day is a random variable with mean 50 and standard deviation 15. Let the random variable Y equal the total revenue from this machine on a given day. Assume that the machine works properly and that no sodas are stolen from the machine. What are the mean and standard deviation of Y?

Answers

The mean and standard deviation of a random variable can be used to describe the distribution of its possible values. In this case, the mean of the random variable X represents the average number of bottles of soda that are bought from the vending machine on a given day, and the standard deviation represents the amount of variation in the number of bottles bought from one day to the next.

To find the mean and standard deviation of the random variable Y, which represents the total revenue from the vending machine on a given day, you will need to use the mean and standard deviation of X and the price per bottle of soda.

The mean of Y can be calculated using the formula:

mean of Y = mean of X * price per bottle

Plugging in the given values, we get:

mean of Y = 50 * $1.50 = $75

So the mean of the random variable Y, which represents the total revenue from the vending machine on a given day, is $75.

The standard deviation of Y can be calculated using the formula:

standard deviation of Y = standard deviation of X * price per bottle

Plugging in the given values, we get:

standard deviation of Y = 15 * $1.50 = $22.50

So the standard deviation of the random variable Y, which represents the total revenue from the vending machine on a given day, is $22.50.

Therefore, the mean and standard deviation of Y, the total revenue from the vending machine on a given day, are $75 and $22.50, respectively.

Chandrani had a Rs 100 note she bought a geometry box for ₹ 37 . 75. Find the amount left with her ​

Answers

Answer:

The amount left with her si 62.25

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