The population P (in thousands) of Austin, Texas, during a recent decade can be approximated by

y=494.29(1.03)t,
y=494.29(1.03)t,

where t is the number of years since the beginning of the decade. a. Tell whether the model represents exponential growth or exponential decay. Identify the annual percent increase or decrease in population. c. Estimate when the population was about 590,000.

Answers

Answer 1

The given model represents exponential growth as the base is greater than 1. Hence, the population will increase every year.

When a quantity grows or increases at a constant rate per unit of time, it is called exponential growth.Exponential decay: When a quantity decreases at a constant rate per unit of time, it is called exponential decay.The given model for population growth isy = 494.29(1.03)t, where t is the number of years since the beginning of the decade. Here, the base of the exponential is 1.03, which is greater than 1. So, the given model represents exponential growth.The annual percent increase in population is 3% (as 1.03 is a 3% increase in each year).c. We need to estimate when the population was about 590,000. To do this, we need to substitute y = 590 in the given equation and solve for t.494.29(1.03)t = 5904.31t = log(590/494.29) / log(1.03) = 12.91 years approximatelyTherefore, the population was about 590,000 in the 13th year, i.e., after 12 years (as it is given that t is the number of years since the beginning of the decade).

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Answers

Answer:

Step-by-step explanation:

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After considering all the given data we conclude that approximate percentage of area under the curve is 10.6%, which is approximately 0.106 as a decimal or 53/500 as a fraction

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Answer: This is what I have tried --

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Answer:

∠ W = 51°

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Answers

The trigonometric form of the complex number z = -1 - i is z = √2cis(3π/4) and the roots of √z are √2/2cis(3π/8) and √2/2cis(11π/8).

a) Trigonometric form of the complex number z = -1 - i is given by:

r = |z| = √(1²+1²) = √2θ = arctan(-1/-1) + π = 3π/4

Therefore, z = √2cis(3π/4)b)

Since, √z = (√2cis(3π/4))/2

= (√2/2)(cis(3π/4)/2), the roots of √z are given by:

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 In summary, the trigonometric form of the complex number z = -1 - i is z = √2cis(3π/4) and the roots of √z are √2/2cis(3π/8) and √2/2cis(11π/8).

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