False. The most energetic region of the electromagnetic spectrum is NOT the microwave region. It is the Gamma rays.
What are Gamma rays?
The electromagnetic radiation with the shortest wavelength and maximum energy is known as a gamma ray. The wavelengths of gamma radiation are often less than a few tenths of an angstrom (1010 meter), yet the energy of gamma photons exceed tens of thousands of electron volts.
Gamma rays are created when radioactive atomic nuclei break apart and when certain subatomic particles decay. Pair annihilation, in which two photons are formed along with the disappearance of an electron and its antiparticle, a positron, also results in the production of gamma rays. Additionally, they can be produced when some unstable subatomic particles, such the neutral pion, decay.
Therefore, The most energetic region of the electromagnetic spectrum are gamma rays.
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Downhill ski racing requires the racer to maintain the tuck position for over a minute while they are going extremely fast therefore the muscle fibers recruited must not fatigue easily or the scare could be severely injured which type of muscle fiber is predominantly recruited during downhill ski racing?
Answer:
slow twitch fibers
Explanation:
Slow twitch fibers can maintain a force for a longer period of time than fast twitch fibers
1. What is the speed of a rocket that travels 900 meters in 10.2 seconds?
Speed is a scalar quantity which only has magnitude but lack of direction. Speed is the distance that an object travels divided by the time it takes. Therefore we can mathematically express as:
[tex]\displaystyle v=\dfrac{s}{t}[/tex]
Where v is speed, s is distance and t is time. From the problem, we are given the distance equal 900 meters and time it takes is 10.2 seconds. Therefore substitute s = 900 meters and t = 10.2 seconds.
[tex]\displaystyle{v=\dfrac{900 \ \, \sf{meters}}{10.2 \ \, \sf{seconds}}}\\\\\displaystyle{v=88.24 \ \, \sf{m/s}}[/tex]
Therefore, the speed of rocket is 88.24 m/s or 90 m/s when rounding to one significant figure.
A ball was rolling with a velocity of 4 m/s across a 1.8 meter high table. How fast would the ball be moving when it hit the floor if it rolled off the table?
The final velocity of the ball moving initially with a velocity of 4 m/s across a 1.8 meter high table when it hits the floor is 5.94 m / s
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
In vertical motion,
u = 0
s = 1.8 m
a = 9.8 m / s²
v² = 0 + ( 2 * 9.8 * 1.8 )
v² = 35.28
v = 5.94 m / s
The equation used above is an equation of motion. There are 5 equations of motion.
v = u + ats = ut + 1 / 2 at²s = ( u + v ) t / 2 v² = u² + 2 a ss = vt - 1 / 2 at²Therefore, the final velocity of the ball is 5.94 m / s
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A 8.0-kg chunk of putty moving at 4m / s collides with and sticks to a 7.0-kg 1 bowling ball that is initially at rest. The bowling ball with its putty passenger will then be set in motion with a velocity of (round to the hundredths)
The velocity of the bowling ball with its putty passenger will be 2.28 m/s.
Velocity of the moving chunk = [tex]V_{c}[/tex] = 4 m/s
Mass of the chunk = [tex]M_{c}[/tex] = 8 kg
Mass of the bowling ball = [tex]M_{b}[/tex] = 7 kg
Velocity of the bowling ball = [tex]V_{b}[/tex] = 0
Since this is the perfect inelastic collision, so according to the law of conservation of momentum
Conservation of momentum is a fundamental law of physics that states that the total momentum of an isolated system is conserved in the absence of an external force.
Mathematically, it is p = m*v[tex]p_{initial} = p_{final}[/tex]
[tex]p_{initial}[/tex] = [tex]V_{c}[/tex] * [tex]M_{c}[/tex] + [tex]M_{b}[/tex] * [tex]V_{b}[/tex]
[tex]p_{initial}[/tex] = 8*4 + 7*0
[tex]p_{initial}[/tex] = 32 + 0
[tex]p_{initial}[/tex] = 32 kg.m/s
[tex]p_{final}[/tex] = ( [tex]M_{c}[/tex] + [tex]M_{b}[/tex] ) [tex]V_{final}[/tex]
[tex]p_{final}[/tex] = ( 8 + 7 ) [tex]V_{final}[/tex]
[tex]p_{final}[/tex] = 14 [tex]V_{final}[/tex] kg.m/s
[tex]p_{initial} = p_{final}[/tex]
32 = 14 [tex]V_{final}[/tex]
[tex]V_{final}[/tex] = [tex]\frac{32}{14}[/tex]
[tex]V_{final}[/tex] = 2.28 m/s
The bowling ball with its putty passenger will then be set in motion with a velocity of 2.28 m/s.
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A person with moment of inertia i is spinning at an angular velocity ω. At some point in time he moves his arm position such that his moment of inertia changes to 2i. What is the rotational kinetic energy k of the person after the change, in terms of his initial rotational kinetic energy ?.
A person with moment of inertia i is spinning at an angular velocity ω. At some point in time he moves his arm position such that his moment of inertia changes to 2i. the rotational kinetic energy k of the person after the change, in terms of his initial rotational kinetic energy is 1/4 .
The moment of inertia of a rigid body, also referred to as the mass moment of inertia, angular mass, second moment of mass, or more precisely, rotational inertia, is a property that establishes the torque required for the desired angular acceleration about a rotational axis, much like mass establishes the force required for the desired acceleration. The amount of torque required to modify the body's rate of rotation depends on the mass distribution of the body and the axis selected. For example, larger moments require more torque.
The moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. This is an extensive (additive) property.
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The left hand 'hill' is 15 m high. The right hand 'hill' is 26 m high. How fast must a 525kg cart have to go (at the top of the left hill) in order to get over the right hand hill?
Answer
A 51.7-kg hiker ascends a 43.2-meter high hill at a constant speed of 1.20 m/s. ... The initial kinetic energy can be found using the work-energy theorem.
Missing: 525kg | Must include: 525kg
A motor car having a mass of 2 tonnes is being accelerated up a gradient of 1 in 25. At an engine speed of 4 000 rimin the b. P. Is 57 kw the effective tyre radius is 330 mm, the rolling res?stance is 180 n/tonne, and the rear-axle ratio is 4. 4 to 1 assuming a transmission efficiency of 90 % and neglecting air res?stance, determine the value of the acceleration at the given speed 262 mls1.
The value of the acceleration at the given speed is 0.26333 m/s²
Acceleration is the price of the alternate speed of an object with admire to time. Accelerations are vector quantities. The orientation of an item's acceleration is given via the orientation of the net force appearing on that item.
Acceleration is the rate at which pace adjustments with time, in phrases of both velocity and path. A point or an item shifting in a direct line is extended if it accelerates or slows down. movement on a circle is extended despite the fact that the rate is constant because the route is usually changing.
Given,
mass of car = 2 tones
= 2000 kg
power transfer of wheel = efficiency × bp
P = 0.9 × 57000
P = 51300 W
Acceleration:-
Net force = mass × acceleration
2000 × a = F - ( Fr - Fg)
2000a = 1670.0418 - ( 360v+ 783.37)
Acceleration = 0.26333 m/s²
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2- An object travels for 5.0s at 15m/s and then changes speed and travels for
100m at 8.0m/s. What was his average velocity?
The average velocity is 10m/s.
How to slove the average velocity?
It travels for 5 sec at 15m/s
distance = speed x time
= 15 x 5
= 75 m
then, travels for 100 m at 8m/s
time = distance/time
= 100/8
= 12.5 sec
Average velocity= total distance travelled/ total time taken
= 100+75/5+12.5
= 175/17.5
= 10 m/s
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what is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding? (take the static coefficient of friction of rubber on concrete to be 1.0.)
The question is incomplete, however, 39.2 velocity is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding
Consider the net force acting horizontal component of friction [tex](\mu _sN \cos \theta)[/tex] and normal force Acting in horizontal component of friction [tex](N sin \theta)[/tex] , So the sum of force is
[tex]mv_max^2/r=N sin \theta+\mu _sN cos \theta[/tex]
Consider the net force acting vertical component of friction [tex](N cos \theta)[/tex] and normal force acting in Vertical component of friction [tex](\mu _sN sin \theta)[/tex] the wight of car is perpendicular to the force (-mg)
[tex]mg=N cos \theta-\mu _sN sin \theta[/tex]
[tex]v_max^2/rg=sin \theta+\mu _scos \theta/cos \theta-\mu _ssin \theta[/tex]
[tex]\nu_max=\sqrtrgsin \theta+\mu _scos \theta/cos \theta-\mu _ssin \theta[/tex]
[tex]" Substitute, "80" "m" for ' "r,,9.81" for ' "g" ', "18.0" for "\theta" and "1.0" for\mu_s[/tex]
after solving
[tex]v_max=39.2 m/s[/tex]
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Question 10
5 pts
Jet fighter planes have ejector seats for rapid escapes from
unresolvable mechanical failures during flight. The typical
mass of a jet fighter seat is 200lbs, while the typical mass
of a jet fighter pilot is 155lbs. For the pilot to safely escape
their crashing plane, they must get at least 100 feet away
from the plane within 2 seconds of ejecting. What force
must the ejector seat launch with to meet these
Requirements
Answer:
See below
Explanation:
d istance = 1/2 a t ^2
100 = 1/2 (a) 2^2 solves for a = 50 ft/s^2
F = ma
= (200+ 155) ( 50) = 17750 lb ft/ s^2 ( this is 2454 N )
The force must the ejector seat launch with to meet these requirements is 17750 lb ft/ s².
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Given that distance = 1/2 a t²
100 = 1/2 (a) 2² solves for a = 50 ft/s²
F = ma
F = (200+ 155) ( 50) = 17750 lb ft/ s² ( this is 2454 N )
The force must the ejector seat launch with to meet these requirements is 17750 lb ft/ s².
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What is the acceleration?
Answer:
3m/s²
Explanation:
From 60 to 70 s the velocity increases from 50 to 80 m/s
Acceleration is defined as a = Δv/Δt
where Δv = change in velocity
and Δt = change in time
Δv = 80 - 50 = 30 m/s
Δt = 70 - 60 = 10 s
Acceleration = 30/10 = 3m/s²
1. A skydiver jumps out of a plane and is in freefall. What is their acceleration?
If a skydiver jumps out of a plane and is in freefall, then his acceleration would be 9.8 meters / second².
What is gravity?It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.
As given in the problem statement if a skydiver jumps out of a plane and is in freefall, the acceleration due to gravity would be 9.8 meters / second².
Thus, if a skydiver jumps out of a plane and is in freefall, then its acceleration due to gravity would be 9.8 meters / second².
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some of the plans to restore the everglades will require millions of dollars and would negatively affect local farmers. what information would you consider in deciding what should be done?
The information which would be considered in deciding what should be done in restoring everglades is the cost, terrain and environmental effects.
What is Everglade?This is referred to a natural region of tropical wetlands which can be found in the southern region of the U.S. state of Florida. It is home to a lot of organisms ranging from plants to animals which ensures that they survive the various conditions due to the availability of nutrients etc.
The information which would be considered in deciding what should be done in restoring everglades is the cost as a cheap reliable method is preferable and also the effect on the environment as a whole.
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What is the mass of an object that has a weight of 69.3 N?
Answer:
7.06663336 kg
Explanation
to get the mass of an object divide the force of gravity(9.8) from the weight (in this case, 69.3 N) to get 7.06663336 kg. Or round it (if it's okay with your teacher) and get 7.07 or 7.1 kg
A train begins to slow down at a rate of -2.5 m/s2 and it takes 137 seconds to come to a complete stop. How fast was the train going when it started to slow down?
The train was moving with a velocity of 342.5 m/s when it started to slow down
How do I determine the initial velocity of the train?From the question given above, the following data were obtained:
Deceleration (a) = -2.5 m/s²Time (t) = 137 secondsFinal velocity (v) = 0 m/sInitial velocity (u) = ?Considering the above data, we can obtain the initial velocity of the train as follow:
v = u + at
0 = u + (-2.5 × 137)
0 = u - 342.5
Collect like terms
u = 0 + 342.5
u = 342.5 m/s
Thus, from the above calculation, we can say that the train was moving with a velocity of 342.5 m/s
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A person pushes a crate using 412 N. What is the mass of the crate if it accelerates at 1.1 m/s2?
Answer:
m=374.5kg
Explanation:
force=mass × acceleration
F=m × a
a=1.1m/s²
f=412N
412=m × 1.1
412=1.1m
m=412/1.1
m=374.5kg
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if the air inside the warehouse is at a warm while the outside air is a chilly and each friend is standing from the person in the doorway, what is the time difference between the arrival
The time difference between the arrival of the sound at the two friends is 27.4 milliseconds
In getting the difference between the arrival of the sound at the two friends, we first find the following:
Speed of sound at [tex]26.1^{o} C[/tex](v1):
[tex]v1=331*\sqrt{\frac{26.1+273K}{273K} }[/tex]
v1=346.5m/s
Speed of sound at [tex]-22.2^{o} C[/tex](v2):
[tex]v2=331*\sqrt{\frac{-22.2+273K}{273K} }[/tex]
v2=317.3m/s
The time difference:
Change in time, Δt=(d/v2)-(d/v1), where d=103m
Change in time=(103/317.3)-(103/346.5)
Δt=27.4ms
Change in time=27.4milliseconds
The question was incomplete, complete question is given below:
If the air inside the warehouse is at a warm 26.1*C while the outside air is a chilly -22.2*C, and each friend is standing 103 meters from the person in the doorway, then what is the time difference between the arrival of the sound at the two friends? Give your answer as a positive value in milliseconds
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what is the angular momentum of a 0.310 kg uniform ball revolving on the end of a thin string in a circle of radius 1.50 m at an angular speed of 12.5 rad/s? ignore the mass of the string.
The angular momentum of revolving ball is 8.72 kg.m²/s.
We need to know about the angular momentum to solve this problem. An angular momentum is a unit that measures the difficulty of stopping rotating objects. The angular momentum depends on the inertia and angular speed. It can be written as
L = I . ώ
where L is angular momentum, I is inertia and ώ is angular speed.
From the question above, the given parameters are
m = 0.31 kg
r = 1.5 m
ώ = 12.5 rad/s
Find the inertia of the revolving ball
I = m . r²
I = 0.31 . 1.5²
I = 0.6975 kgm
By substituting the given parameters, we can calculate the angular momentum
L = I . ώ
L = 0.6975 . 12.5
L = 8.72 kg.m²/s
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the difference between the amount of incoming radiation and the amount of outgoing radiation at a given location is known as .
Heat budget is the balance between incoming solar radiation and outgoing terrestrial radiation.
What is the heat budget?
A heat budget represents a perfect balance between incoming heat (insolation) absorbed by the earth and outgoing heat (terrestrial radiation) departing it as radiation. If incoming and leaving heat is not in equilibrium, the Earth will either become too warm or too cold.
The sun is the primary source of energy that sustains life on earth. At the surface of the earth, solar energy arrives in the form of short-wave solar radiation. Through the process of absorption, this energy is then transformed into heat. In the form of long-wave terrestrial radiation, the earth returns the same quantity of energy to space as it receives from space. The term "heat budget" refers to the equilibrium that must be maintained between the quantity of insolation the earth receives from the sun and the amount of radiation it emits into space.
Hence, on the basis of the physical principle of energy conservation, this radiation budget accounts for the balance between incoming and outgoing radiation.
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An iguana crawls from a position of 5.0m to a position of -18m. If it completes this in 9.0s, what was its average velocity?
The average velocity of Iguana is -2.55m/s when it crawls from 5m to -18m in 9 seconds.
Average velocity of a body is defined as the total displacement divided by the total time taken by the body.
Here, initial position of iguana is 5m and the final position of the iguana is -18m.
Total displacement D is,
D = final position - initial position.
D = -18-5
D = -23m
Total time taken by the iguana is 9.0 seconds.
Average velocity(V) = total displacement/total time taken.
Putting values,
V = -23/9
V = -2.55m/s.
So, the average velocity of the iguana is -2.55m/s.
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when a battery is connected to the plates of a 3.00-mf capacitor, it stores a charge of 27.0 mc. what is the voltage of the battery? (b) if the same capacitor is connected to another battery and 36.0 mc of charge is stored on the capacitor, what is the voltage of the battery
9V and 12V are the voltage of the battery respectively.
[tex]v_1=q/c=27 \mu c/3.00 \mu F=9v[/tex]
[tex]v_2=36.0 \mu c/3.00 \mu F=12V[/tex]
The electric potential difference per unit charge between two places in an electric field is referred to as voltage (also known as electric potential difference, electromotive force, electric pressure, or electric tension). The letters "V" or "E" are used to represent voltage in calculations and other mathematical contexts.
Voltage is the amount of effort needed to transport a unit of charge between two places in a static electric field. The voltage is the difference in potential energy between two places in a circuit, according to our definition. The potential of one point is higher than that of the other points. Voltage or potential difference refers to the difference in charge between higher and lower potentials.
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If A = i and B= i-j then angle btw them
The angle between them is 90°
A = √(1^2 + 1^2) = √2
B = √(1^2 + 1^2) = √2
The magnitude of both vectors is √2
Dot product
A.B = (i + j) . (i - j)
A.B = 1 - 1 = 0
The dot product of two vectors is equal to ABCosx
A.B = ABCosx
0 = √2 × √2 × Cosx
0 = Cosx
∴ x = 90°
The angle between them is 90°
An angle is a figure in Euclidean geometry created by two rays, called the sides of the angle, that share a common termination, called the vertex of the angle. Angles formed by two rays are located in the plane containing the rays. Angles are also generated when two planes intersect. These are known as dihedral angles. An angle defined by two intersecting curves is the angle of the rays lying tangent to the respective curves at their point of junction.
The angle can also refer to the measurement of an angle or of a rotation. This measurement is the length of a circular arc divided by its radius. In the case of a geometric angle, the arc is defined by the sides and is centered at the vertex.
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L Pretest: Unit 4Question 7 of 22What is the wavelength of an electromagnetic wave that has a frequency of1.82 x 10^18 Hz in a vacuum? (The speed of light in a vacuum is 3.00 x 10^8m/s.)A. 1.65 x 10-10 mB. 5.46 x 1026 mC. 6.07 x 109 m
A. 1.65 x 10^-10 m
Explanations:The relationship between the speed(v), frequency(f), and wavelength(λ) of an electromagnetic wave is given as:
v = λf
From the question:
[tex]\begin{gathered} v\text{ = 3}\times10^8m\text{ /s} \\ f\text{ = 1.82}\times10^{18}Hz \end{gathered}[/tex]Substituting the values of v and f into the equation v = λf
[tex]\begin{gathered} 3\times10^8=\lambda\times(1.82\times10^{18}) \\ \lambda\text{ = }\frac{3\times10^8}{1.82\times10^{18}} \\ \lambda\text{ = }1.65\text{ }\times10^{-10}m \end{gathered}[/tex]Therefore, the wavelength of the electromagnetic wave is 1.65 x 10^-10 m
how much time will it take a dog to run 15 meters if its running 5m/s
Uniform line movement
Data:
t = ?
d = 5 mt
V = 15 m/s
The rectilinear movement formula:
V = d/t
We clear for time t:
t = d/v
t = (15 m)/(5 m/s)
t = 3 s
Answer: The dog takes 3 seconds to travel 15 meters ✅.
The MRU is defined as the movement in which an object moves in a straight line, in a single direction, covering equal distances in the same time interval, maintaining a constant speed and no acceleration throughout its movement.
His formula for uniform rectilinear motion is as follows:
V = D/TWe first apply the data to the problem.
Data :T = ?D = 5 metersV = 15 m/sOnce having the data Now we will find the time.
T = D/VT = (15 meters)/(5 m/s)T = 3 secondsSo the result of the problem is 3 seconds.
Happy 2023.
A body is under the action of two forces 7n and 10n. find the resultant of the two forces if the two are inclined at an angle of 60degrees to each other
Mass x Acceleration equals force. Net force is equal to 7N plus 10N, or 17N, at a 60-degree angle with R equal to 12.2N.
How does physics define force?The definition of force in physics is: The push and pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
A force is an effect that tends to move a stationary object into motion, stop a moving object, alter the direction and speed of a moving object, or alter the size and shape of a body.
Which four sorts of forces are there?Any of the four fundamental forces in physics—gravitational, electromagnetism, strong, and weak—that control how objects and particles interact as well as how some particles decay—is referred to as a fundamental force or fundamental interaction.
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A car with a mass of 1500 kg travelling at 5m / s is accelerated for 10.0 s to a speed of 25m / s What force was required? The coefficient of rolling kinetic friction was 0.009.
Answer:
Force:
F = 3130 N
Explanation:
Given:
m = 1500 kg
V₀ = 5 m/s
V = 25 m/s
Δt = 10.0 s
μ = 0.009
g = 9.8 m/s²
___________
F - ?
1)
Car acceleration:
a = (V - V₀) / Δt = (25 - 5) / 10.0 = 2 m/s²
2)
Friction force:
F₁ = μ*m*g
3)
According to Newton's second law:
m*a = F - F₁
Force:
F = m*a + F₁
F = m*a + μ*m*g
F = m*( a + μ*g) = 1500*(2 + 0.009*9.8) ≈ 3130 N
What would your weight on the moon be if you weighed 120 pounds on Earth?
(50 POINTS !!)
Answer:
Explanation:
Given:
m = 120 pounds = 120·0,454 = 54.48 kg
g = 1.625 m/s² - Acceleration of free fall on the Moon
_______________________________
F - ?
F = m·g = 54.48·1.625 ≈ 88.5 N
Answer:
about 20 pounds
If you weigh 120 pounds on Earth, you will weigh about 20 pounds on the moon.
Explanation:
Dont ask for an explanation ok buddy?
What type of energy is the sum of kinetic and potential energy in an object that is used to do work?.
Mechanical energy can be described as a sum of kinetic and potential energy in an object that is used to do work
In the field of physics, we can describe mechanical energy that is either stored in an object at the time of rest or the energy of an object that is in a particular motion. As kinetic energy is the motion or movement energy and potential energy is the stored energy at rest, hence mechanical energy is the sum of both these energies.
In other words, we can also describe mechanical energy as an energy that is contained in a particular object that allows it to perform a specific work. It depends on the mechanical energy of an object to determine the amount of work it can do.
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Answer:
mechanical energy or A
Explanation:
Hope this helps
When do trilobites disappear from the rock sequence?
Answer:
252 million years ago
Explanation:
hope this helps :)
A student made the electromagnet shown and used it to pick up one sewing pin. Which change to the electromagnet would most likely allow it to pick up two sewing pins?A. Double the length of the wires that connect it to the battery.B. Replace the nail with a thick roll if paper.C. Double the number of coils of wires around the nail.D. Replace the nail with a large bolt.
ANSWER:
C. Double the number of coils of wires around the nail.
STEP-BY-STEP EXPLANATION:
In order to collect two sewing pins, the student must double the number of coils around the nail.
Answer: Double the number of coils of wires around the nail.
Explanation: Just did this on apex, mostly for their benefit.