The manufacturer of an energy drink spends $1.20 to make each drink and sells them for $2. The manufacturer also has fixed costs each month of $8000

To combine like terms, you have to add the same variables and all

First You have to find if the Numbers are positive or Negative

2s is positive

4w is Negative because i has Minus sigh before it

5 is Positive because it has added sigh

6s s Positive because it has added sign

Second you have to find the Like terms

2s+6s=8s

so, the new equation is

8s-4w+5.

That is the simplest

If you have questions just ask me I went through it pretty fast

Answer:

1 is acute

2 is a right triangle

3 is obtuse

Step-by-step explanation:

A 90 degree angle will be written as a box in the corner. Any angle less than 90 is acute, and any angle more than 90 is obtuse.

My answer needs to be 32-25=7

Answer:

[tex]y=-1[/tex]

Step-by-step explanation:

[tex]y-14=6(x-2.5)[/tex]

[tex]y-14=6(0-2.5)[/tex]

[tex]y-14=6(-2.5)[/tex]

[tex]y-14=-15[/tex]

[tex]y=-1[/tex]

Answer:

-2F=7x

Step-by-step explanation:

F*-2= -2F       3x*3x=9x

-2F=9x-2x

-2F=7x

Answer:

m=1352

Step-by-step explanation:

(118.64-24)/0.07=m

Answer:

50(64+36) this would be your answer

50 x (64+36)

Step-by-step explanation:

According to PEMDAS, you will have to solve 64 + 36 first, so you need to put them in the parenthesis. Next, simply multiply by 50.

Answer:

d-7 divided by 2 or over 2

Using the t-distribution, it is found that since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.

At the null hypothesis, it is tested if the average box of cereal does not contain more than 368 grams, that is:

[tex]H_0: \mu \leq 368[/tex]

At the alternative hypothesis, it is tested if it contains, that is:

[tex]H_1: \mu > 368[/tex]

We have the standard deviation for the sample, hence, the t-distribution is used to solve this question.

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

In this problem, the values of the parameters are: [tex]\overline{x} = 372.5, \mu = 368, s = 15, n = 25[/tex].

Hence, the value of the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{372.5 - 368}{\frac{15}{\sqrt{25}}}[/tex]

[tex]t = 1.5[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, with 25 -1 = 24 df, is of [tex]t^{\ast} = 1.71[/tex].

Since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.

You can learn more about the use of the t-distribution to test an hypothesis at https://brainly.com/question/13873630

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    y-(x-4)=0  

STEP

1

:

Equation of a Straight Line

1.1     Solve   y-x+4  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line  y-x+4  = 0 and calculate its properties

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

The triangles are the same, except one is dilated.

So the hypotenuse of one is 5, and the other is 10. The triangle is dilated to double the other's size. so 4*2 = 8

I have no idea what i just wrote, but the answer is correct.

Answer:

11, 12, 13

Step-by-step explanation:

let's put the first number of the three as a:

a; a+1; a+2

The sum of the first and the twice second is 35 means:

a + 2(a+1) = 35

a + 2a + 2 = 35

3a = 33

a=11

now that we know a, we just need to add 1 and 2 as they are consecutive:

11, 12, 13

Answer:

-12.5

Step-by-step explanation:

-7x+8+11x=-42

-7x+11x=-42-8

4x=-50

x=-12.5

Hope this helped! :)

Hey There!

Question:-

[tex] \sf \: - 7x+8+11x= - 42[/tex]

We need to find the value of x.

Solution:-

[tex]\sf \longmapsto - 7x + 8 + 11x = - 42[/tex]

Combine Like terms:-

[tex]\sf \longmapsto \: ( - 7x+11x)+(8)= - 42[/tex]

On Simplification :-

[tex]\sf \longmapsto \: 4x +8 = - 42[/tex]

Subtract 8 from both sides:-

[tex]\sf \longmapsto \: 4x+8 - 8= - 42 - 8[/tex]

On Simplification:-

[tex]\sf \longmapsto \: 4x + 0 = - 42 - 8[/tex]

Note that (-) and (-) equals to (+).

[tex]\sf \longmapsto \: 4x = - 50[/tex]

Divide both sides by 4:-

[tex]\sf \longmapsto \: \dfrac{4x}{4} = \dfrac{ - 50}{4} [/tex]

On Simplification:-

[tex]\sf \longmapsto \: \dfrac{ \cancel2x}{ \cancel2} = \dfrac{ \cancel{- 50}}{ \cancel4} [/tex]

[tex]\sf \longmapsto \: x = \dfrac{ - 25}{2} [/tex]

Or in Decimal :-

[tex]\sf \longmapsto \: x = -12.5[/tex]

______________________________________

Henceforth, the value of x is :-

[tex]\boxed{\huge \red{x = - \dfrac{25}{2}}} [/tex]

In Decimal:-

[tex] \boxed{\huge\red{ x = -12.5}}[/tex]

________________________________

Please let me know if you have any questions.

~MisterBrian

Answer:

6 (20 + c) > 16

Step-by-step explanation:

the sum of the number and 20 is 20 + c. so you multiply that equation by 6 giving you 6 (20 + c)

Answer:

  g(x) = 4x² -x +64

Step-by-step explanation:

The integral of f(x) will be continuous. This means the value must be the same for x = 4- as for x = 4+.

For some constant c1, the integral in the region x ≤ 4 is ...

  ∫f(x)dx = (4x² -x +c1) +C = g(x) +C

The integral in the region x ≥ 4 is given as ...

  ∫f(x)dx = 31x +C

Evaluated at x=4, we must get the same value from either expression:

  4(4²) -4 +c1 +C = 31(4) +C

  60 +c1 = 124

  c1 = 64

__

In order to make the integral continuous at x=4, we must have ...

  g(x) = 4x² -x +64

Answer:

y=-3/2 x + 6Step-by-step explanation:

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

[tex]\%Percentage = \frac{450}{500}[/tex]

Divide 450 by 500

[tex]\%Percentage = 0.9[/tex]

Express as percentage

[tex]\%Percentage = 90\%[/tex]

Hence, the percentage of commuters that travel more than 45 minutes is 90%

Read more about histograms at:

https://brainly.com/question/2776232

Answer:

Ez 1+1=3 Duh

Step-by-step explanation:

Answer:

2,3,4,5,6 is the domain

4,6,8,10,12 is the range

Step-by-step explanation:

Answer:

The domain is {2,3,4,5,6} and the range is {4,6,8,10,12}.

Step-by-step explanation:

Answer:

A = (0,1)

B = (1,-1)

C = (-1,-1)

Step-by-step explanation:

If this helped leave a brainliest

Step-by-step explanation:

solution

here,

1 dollar = rs 72.45

or, 1/72.45 dollars= rs 1

or, rs 1 = 1/72.45 dollars

now,

rs 1449= 1449/72.45 dollars

or,rs1449= 20 dollars

therefore, 20 dollars can be exchanged for rs 1449

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]

on this one, we proceed the same as the other, we start off by graphing them, Check the picture below.  Now, we have a solid horizontal line at y = 7, that'd be our boundary, and a parabola that has a vertex at the origin, that's our other boundary, from 0 to 7.

In this case, is a solid area from the curve to the axis of rotation, so we can simply use the "disk" method to get the volume, lemme do it in the same way as "area under the curve", assuming h(y) = 0 for the axis of rotation

[tex]\textit{area under the curve}\\ \stackrel{f(y)}{2\sqrt{3y}}~~ - ~~\stackrel{h(y)}{0}\qquad \implies 2\sqrt{3y} \\\\\\ \displaystyle\int_{0}^7\pi \left( 2\sqrt{3y} \right)^2 dy\implies \int_{0}^7\pi(12y)dy\implies 12\pi \int_{0}^7 y\cdot dy \\\\\\ 12\pi \cdot \left. \cfrac{y^2}{2} \right]_{0}^7\implies12\pi \cdot \cfrac{49}{2}\implies 294\pi[/tex]

Answer:

A

Step-by-step explanation:

:)

hope it helps

Answer:

22.53-9.99=12.54

12.54 divided by 6 = 2.09

Each pencil costs $2.09

Step-by-step explanation: