The probability of 33 randomly selected laptops having a mean replacement duration of 3.5 years or fewer is roughly 0.0287, or 2.87%.
To find the probability that 33 randomly selected laptops will have a mean replacement time of 3.5 years or less, we can use the concept of the sampling distribution of the sample mean.
Given that the population means replacement time is 3.7 years and the standard deviation is 0.6 years, and assuming that the distribution is approximately normal, we can use the formula for the standard error of the mean:
Standard Error (SE) = σ / √n
where n is the sample size and σ is the population standard deviation.
In this case, σ = 0.6 years and n = 33. Plugging these values into the formula, we get:
SE = 0.6 / √33 ≈ 0.1045
Next, we need to calculate the z-score for the sample mean of 3.5 years. The z-score formula is:
z = (x - μ) / SE
where x represents the sample mean, μ represents the population mean, and SE represents the standard error.
Plugging in the values, we have:
z = (3.5 - 3.7) / 0.1045 ≈ -1.91
Now, we can use a standard normal distribution table to find the probability associated with this z-score. The probability represents the area under the curve to the left of the z-score.
Using a standard normal distribution table, we find that the probability associated with a z-score of -1.91 is approximately 0.0287.
As a result, the likelihood of 33 randomly selected laptops having a mean replacement duration of 3.5 years or fewer is roughly 0.0287, or 2.87%.
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hi so... im horrible at math and can't figure this out so can someone pls answer this? and in the most simplified way possible because my tiny brain can't handle too many steps aha. WILL GIVE BRAINLIEST... just so u guys know l mao
Analyze and sketch a graph of the function. Find any intercepts, relative extrema, points of inflection, and asymptotes. (If an answer does not exist, enter DNE.)
x/ x^2 +25 intercept (x, y) =
relative minimum (x, y) =
relative maximum (x, y) =
points of inflection (x, y) = (smallest x-value)
(x, y) =
(x, y) = (largest x-value)
Find the equation of the asymptote.
Use a graphing utility to verify your results.
The given function is f(x) = x/(x^2 + 25).
Intercepts:
To find the intercepts, we set f(x) = 0 and solve for x. However, in this case, the function does not have any x-intercepts because the numerator x cannot be zero.
The y-intercept occurs when x = 0. Substituting x = 0 into the function, we have f(0) = 0/(0^2 + 25) = 0.
Relative Extrema:
To find the relative extrema, we take the derivative of the function and find the critical points where the derivative is zero or undefined. However, in this case, the function does not have any relative extrema because its derivative is always nonzero and defined for all x.
Points of Inflection:
To find the points of inflection, we need to analyze the second derivative of the function. However, in this case, the second derivative is always zero, indicating that there are no points of inflection.
Asymptotes:
The function has two asymptotes: a vertical asymptote and a horizontal asymptote.
The vertical asymptote occurs when the denominator of the function is equal to zero. Solving x^2 + 25 = 0, we find that there are no real solutions. Therefore, there is no vertical asymptote.
The horizontal asymptote can be found by examining the behavior of the function as x approaches positive or negative infinity. As x approaches positive or negative infinity, the function approaches zero. Hence, the horizontal asymptote is y = 0.
To verify these results, a graphing utility can be used to plot the function and visualize its behavior.
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bill is trying to plan a meal to meet specific nutritional goals. he wants to prepare a meal containing rice, tofu, and peanuts that will provide 312 grams of carbohydrates, 328 grams of fat, and 180 grams of protein. he knows that each cup of rice provides 46 grams of carbohydrates, 0 grams of fat, and 2 grams of protein. each cup of tofu provides 6 grams of carbohydrates, 12 grams of fat, and 15 grams of protein. finally, each cup of peanuts provides 26 grams of carbohydrates, 70 grams of fat, and 28 grams of protein. how many cups of rice, tofu, and peanuts should he eat?
Bill should eat 4 cups of rice, 4 cups of tofu, and 4 cups of peanuts to meet his specific nutritional goals.
To determine how many cups of rice, tofu, and peanuts Bill should eat, we need to set up a system of equations based on the given nutritional information. Let's denote the number of cups of rice, tofu, and peanuts as x, y, and z respectively.
Based on the given information, we can establish the following equations
Carbohydrate equation: 46x + 6y + 26z = 312
Fat equation: 0x + 12y + 70z = 328
Protein equation: 2x + 15y + 28z = 180
We now have a system of three equations that we can solve to find the values of x, y, and z.
Using any appropriate method to solve the system of equations, we find
12y + 70z = 328
y = 328 - 70z/12
y = 27.33 - 5.833z
putting the value of y in both equation
2x + 15(27.33 - 5.833z ) + 28z = 180
2x + 28z + 409.95 - 87.45z = 180
(2x - 59.45z = -391.95)23
46x - 1367.35z = - 9014.85
46x + 6(27.33 - 5.833z) + 26z = 312
46x + 163.98 - 34.998z + 26z = 312
46x - 8.998z = 148.02
equation both equation
- 8.998z + 1367.35z = 9014.85 + 148.02
z = 9162.87/1358.352
z ≈ 4
Solving equation we get
x = 4 cups of rice
y = 4 cups of tofu
z = 4 cups of peanuts
Therefore, Bill should eat 4 cups of rice, 4 cups of tofu, and 4 cups of peanuts to meet his nutritional goals.
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Given m
n, find the value of x and y.
(37-18)
(8x+12)
m
(2X+18)
n
Answer:
Step-by-step explanation:
The two inside angles will sum to 180°.
The top to angles are equal.
Think about this as what if both of the parallel lines were intersected by a perpendicuar line. Every angle would be a right triangle 90°. The inside angles will sum to 180° and the opposite angles are again equal.
(2x + 18) + (8x + 12) = 180
10x + 30 = 180
10x = 150
x = 15
-------------------------
(3y - 18) = (8x + 12) x = 15
(3y - 18) = (8(15) + 12)
(3y - 18) = (120 + 12)
(3y - 18) = 132
3y = 132 + 18
3y = 150
y = 50
What's the number between 1.35 and 1.351
Answer: + 1000
Step-by-step explanation:
PLEASE HELP ME ANSWER QUICK!! (Volume)
Answer:
V = 50 m³
Step-by-step explanation:
The formula for the volume of a pyramid of base area b and height h is V = (1/3)(b)(h).
Here the volume is V = (1/3)(5 m)²(6 m), or V = 50 m³
Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They are having trouble deciding who will do what task, so they came up with a method based on probability. Letitia grabs some spoons and puts the is a bag. Some have purple handles and others have green handles. Scott has to pick two of the spoons. If their handles are the same, Scott will wash. If they are different colors, he will dry. It turns out there are two purple spoons and three green ones. What is the probability of Scott washing the dishes?
Answer:
The probability that Scott will wash is 2.5
Step-by-step explanation:
Given
Let the events be: P = Purple and G = Green
[tex]P = 2[/tex]
[tex]G = 3[/tex]
Required
The probability of Scott washing the dishes
If Scott washes the dishes, then it means he picks two spoons of the same color handle.
So, we have to calculate the probability of picking the same handle. i.e.
[tex]P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)[/tex]
This gives:
[tex]P(G_1\ and\ G_2) = P(G_1) * P(G_2)[/tex]
[tex]P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}[/tex]
[tex]P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}[/tex]
[tex]P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}[/tex]
[tex]P(G_1\ and\ G_2) = \frac{3}{10}[/tex]
[tex]P(P_1\ and\ P_2) = P(P_1) * P(P_2)[/tex]
[tex]P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}[/tex]
[tex]P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}[/tex]
[tex]P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}[/tex]
[tex]P(P_1\ and\ P_2) = \frac{1}{10}[/tex]
Note that: 1 is subtracted because it is a probability without replacement
So, we have:
[tex]P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)[/tex]
[tex]P(Same) = \frac{3}{10} + \frac{1}{10}[/tex]
[tex]P(Same) = \frac{3+1}{10}[/tex]
[tex]P(Same) = \frac{4}{10}[/tex]
[tex]P(Same) = \frac{2}{5}[/tex]
graph the solution to the inequality on the number line. y<43.5
The solution to the inequality y < 43.5 can be graphed on a number line. The graph will show all the values of y that are less than 43.5.
To graph the solution to the inequality y < 43.5 on a number line, we start by marking the point 43.5 on the number line. Since the inequality is y < 43.5, we represent it with an open circle at 43.5 to indicate that 43.5 itself is not included in the solution.
Next, we shade the region to the left of the open circle. This shaded region represents all the values of y that are less than 43.5, including any negative values and values approaching negative infinity.
The resulting graph on the number line will show a shaded region to the left of the open circle at 43.5, indicating that all values of y in that region satisfy the inequality y < 43.5.
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B.
The number of flowers in Lito's garden is represented as follows.
Gumamela
Orchid
Answer:
5 :12 ; what is the ratio of the number of gumamela to the total number of flowers
5 : 7 ; what is the ratio of the number of gumamela to the number of orchids
7:5 ; what is the ratio of the number of orchids to the number of gumamela
12 : 5 ; what is the ratio of the total number of flowers to the number of gumamela
12 : 7 ; what is the ratio of the total number of flowers to the number of orchid
Step-by-step explanation:
Ratios of a to b ;is written as a : b
Ratio of b to a is written as b : a
The ratio of a to the sum of a and b equals ;
a : (a + b)
Number of orchids = 7
Number of gumamela = 5
Total number of flowers = 7 + 5 = 12
Ratio two quantities are compared. A number of times a number contains another. It makes value comparisons. When two components of the same unit are compared, it is possible to determine how much of one number is represented in the other. The quotient of two mathematical equations is shown.
5:12 And what's the proportion from gumamela the total flowers in the garden?7:12 And what's the proportion of orchids in the field to the total number of flowers?5:7 And what's the number of gumamela to orchids ratio?7:5 And what's the orchid-to-gumamela ratio?12:12 What is the proportion of gumamela or orchids in the field to the overall flowers?Learn more:
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A project has the following projected outcomes in dollars: $240, $310, and $560. The probabilities of their outcomes are 20%, 60%, and 20% respectively. What is the expected value of these outcomes?
If the probabilities of their outcomes are 20%, 60%, and 20% respectively, the expected value of these outcomes is $346.
To calculate the expected value of the outcomes, we multiply each outcome by its corresponding probability and then sum up the results.
In this case, the projected outcomes are $240, $310, and $560, with probabilities of 20%, 60%, and 20% respectively.
To calculate the expected value, we use the formula:
Expected value = (Outcome 1 * Probability 1) + (Outcome 2 * Probability 2) + (Outcome 3 * Probability 3) + ...
Expected value = ($240 * 0.20) + ($310 * 0.60) + ($560 * 0.20)
Expected value = $48 + $186 + $112
Expected value = $346
The expected value represents the average value or the long-term average outcome we can expect from the given probabilities and outcomes. It provides a summary measure that helps in understanding the central tendency of the distribution of outcomes.
In this case, the expected value indicates that, on average, we can expect the project's outcome to be around $346.
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3. Use telescoping or iteration to find a closed form for the recurrence relation c₂ = 2cn-1 - 1 with co = 2.
Using telescoping or iteration, the closed form for the recurrence relation c₂ = 2cn-1 - 1 with co = 2 is `cₙ = 2ⁿ+1 - 1` for `n ≥ 0`.
As the recurrence relation is `c₂ = 2cn-1 - 1` with `c₀ = 2`. In the closed form, first, we write out the first few terms of the sequence: `c₀ = 2, c₁ = 3, c₂ = 5, c₃ = 9, c₄ = 17, c₅ = 33, c₆ = 65, ...`
Let's try a pattern in the sequence. Observe that `c₁ = 2c₀ + 1 = 2(2) + 1 = 5`. Similarly, `c₂ = 2c₁ + 1 = 2(5) + 1 = 11`. Continuing this process, we can see that `cₙ = 2cₙ₋₁ + 1` for `n ≥ 1`.
Let's apply telescoping to this formula:```
c₁ = 2c₀ + 1c₂ = 2c₁ + 1= 2(2c₀ + 1) + 1
= 2²c₀ + 2 + 1c₃ = 2c₂ + 1
= 2(2²c₀ + 2 + 1) + 1
= 2³c₀ + 2² + 2 + 1c₄
= 2c₃ + 1= 2(2³c₀ + 2² + 2 + 1) + 1
= 2⁴c₀ + 2³ + 2² + 2 + 1
```Note that each term in this sum telescopes. In general, we can write `cₙ = 2ⁿc₀ + 2ⁿ-1 + ... + 2² + 2 + 1`. Simplifying this expression gives:```
cₙ = 2ⁿc₀ + (2ⁿ - 1)
= 2ⁿ(2) + (2ⁿ - 1)
= 2ⁿ+1 - 1 ```
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Help me please....... :(
Answer:
The Degree of the polynomial is 3
Juan earns a flat fee of $150 plus $20 for every hour he works decorating 5 points
a house. Which graph correctly displays Juan's earnings?
Answer: The 3rd one is the correct answer
Step-by-step explanation:
Which rule can be used to show that the two triangles above are similar?
SSS
SAS
ASA
Answer:
Step-by-step explanation: 675 ssa SAS 342w
A number of days, d, of sunshine is not 28.
Answer:
D<28
Step-by-step explanation:
The required inequality for the given situation can be, d > 28 or d < 28
What is an inequality?A relationship between two expressions or values that are not equal to each other is called inequality.
Given that, write an inequality for the situation.
Situation :-
A number of days, d, of sunshine is not 28.
Here, the number of days is said to be not equal to 28, we are not given if is less or more,
It can be less or more than 28 but not 28
So, here we get two situations,
Either, the number of days, d, of sunshine is less than 28, or the number of days, d, of sunshine is more than 28.
If we write these situations, mathematically, the inequalities we will have, are :-
1) The number of days, d, of sunshine is less than 28 :-
d < 28
2) The number of days, d, of sunshine is more than 28 :-
d > 28
Therefore, the two inequalities, are :- d < 28 or d > 28
Hence, the required inequality for the given situation can be, d > 28 or d < 28
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The complete question is :-
Write an inequality for the situation.
A number of days, d, of sunshine is not 28 .
The desired accumulated is $150,000 after 6 years invested in an
account with 2% interest compounded quarterly.
The amount to be invested now, or the present value needed, is
$__. Round to the nearest
The present value needed to accumulate $150,000 after 6 years with a 2% interest rate compounded quarterly is $131,488
To calculate the present value needed to accumulate $150,000 after 6 years with a 2% interest rate compounded quarterly, we can use the formula for compound interest:
Present Value = Future Value / (1 + r/n)^(n*t)
Where:
Future Value = $150,000
Interest Rate (r) = 2% = 0.02 (converted to decimal)
Number of Compounding Periods per Year (n) = 4 (quarterly compounding)
Number of Years (t) = 6
Substituting these values into the formula, we have:
Present Value = $150,000 / (1 + 0.02/4)^(4*6)
Calculating inside the parentheses first:
Present Value = $150,000 / (1 + 0.005)^(24)
Next, calculate the exponent:
Present Value = $150,000 / (1.005)^(24)
Using a calculator or spreadsheet, we can evaluate the expression inside the parentheses and then divide $150,000 by that result to find the present value. Rounding to the nearest dollar, the present value needed is $131,488.
Therefore, the amount to be invested now or the present value needed is $131,488.
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Write the equation of a line that passes through the points (-2,-9) and (2,-9).
Answer:
mhmm feels so good
Step-by-step explanation:
In OK, which arc is a major arc?
G
H
74
K
A GEI
C FJG
D IJF
B HIJ
Answer:
D
i thank
Step-by-step explanation:
Maurice ran out of gas. The gas tank in his car can hold 13.6 gallons of gas, but the gas cans only hold 3.4 gallons. How many gas cans would he need to fill his tank
Answer: 4
Step-by-step explanation: 13.6 divided by 3.4 = 136 then divide by 34 you get 34 from 3.4 but divide by 34. Once you divide 136 and 34 you get your answer 4.
3.
Mrs Rita buys 6 cartons of soya bean milk. Each carton contains 1.251
of soya bean milk. Does Mrs Rita have enough soya bean milk to fill up
20 mugs with a capacity of 320 ml each? Explain.
Yes, it is possible to fill all twenty mugs.
Please help. No files allowed or you will be reported
Can someone help me with this question please
Answer:
61
Step-by-step explanation:
all angles that are in a triangle add up to 180
x+80+39=180
x+119=180
x=61
Hope that helps :)
Paulie’s pizza is considering expanding into the pizza truck business. They calculate that the costs of a pizza truck will be $1,420 per month. If they sell pizzas for $12 each, how many will they have to sell in a month to make a profit of at least $3,400
Answer:
283 1/3 pizzas
Step-by-step explanation:
I did 3,400 div 12 = 1,420
Can someone please help
Answer:
First row of blanks: -3 -3
Second row of blanks: 2 2 3
Third row blank: 6
Step-by-step explanation:
x/2 + 3 = 6
The objective is to isolate the variable:
Subtract both sides by 3
x/2 = 3
Multiply both sides by 2
x = 6
A.
f(x) = -4|x + 2| + 3
B.
f(x) = 4|x + 2| + 3
C.
f(x) = -4|x − 2| − 3
D.
f(x) = 4|x + 2| − 3
Answer:
D
Step-by-step explanation:
The seesaw moves and the angle created by the left side of the seating board and the central support is now 80 degrees. Create and use a model, to find the distance from point Q to the ground when the angle created by the left side of the seating board and the central support is 80 degrees. Show your work or explain your answer. Round your final answer to the nearest tenth of a foot. Enter your model, your answer, and your work or explanations in the space provided.
Answer:5.7
Step-by-step explanation:
The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. The distance between the point Q and the ground is h-[L cos(80°)].
What is Tangent (Tanθ)?The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,
[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]
where,
θ is the angle,
Perpendicular is the side of the triangle opposite to the angle θ,
The Base is the adjacent smaller side of the angle θ.
Let the height of the support be h and the height between the point q and the ground is x. Also, the distance between point Q and the support of the seesaw is L.
Now if we look at the ΔQAR, the measure of the ∠QRA is 80°, therefore, the sine of ∠QRA can be written as,
[tex]\rm Cos(\theta)=\dfrac{Base}{Perpendicular}\\\\Cos(\angle QRA) = \dfrac{AR}{QR}\\\\Cos(\angle QRA) = \dfrac{h-x}{L}\\\\L \times Cos(80^o)=h-x\\\\x=h-[L\ Cos(80^o)][/tex]
Hence, the distance between the point Q and the ground is h-[L cos(80°)].
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Please help with these questions... I've been trying to figure them out for like twenty minutes and at this point I just don't have the energy anymore... I will pick brainliest! Always do...
Answer:
1. y=2x^2-8X-1
2. y=-6x^2+36x-63
3. y=-3x^2+18x-34
4. y=9x^2+54x+76
5. y=-x^2+8x-22
6. y=6x^2-48x+90
7. y=8x^2+16x+5
8. y=2x^2-8x+1
Have a great day :)
solve the following recurrence relations:
a) an=an-1+3(n-1), a0=1
b) an=an-1+n(n-1), a0=3
c) an=an-1+3n^2, a0=10
a) To solve the recurrence relation an = an-1 + 3(n-1), a0 = 1, we can expand the recurrence relation iteratively.
a1 = a0 + 3(1-1) = 1 + 0 = 1
a2 = a1 + 3(2-1) = 1 + 3 = 4
a3 = a2 + 3(3-1) = 4 + 6 = 10
a4 = a3 + 3(4-1) = 10 + 9 = 19
...
We can observe a pattern from the values:
a0 = 1
a1 = 1
a2 = 4
a3 = 10
a4 = 19
We can notice that an = [tex]n^2 + 1.[/tex] We can prove this by induction, but in this case, we can also recognize that the given recurrence relation generates the triangular numbers (1, 3, 6, 10, 15, ...), which are defined by the formula Tn = n(n+1)/2.
Thus, the solution to the recurrence relation is an = [tex]n^2 + 1.[/tex]
b) For the recurrence relation an = an-1 + n(n-1), a0 = 3, we can again expand it iteratively:
a1 = a0 + 1(1-1) = 3 + 0 = 3
a2 = a1 + 2(2-1) = 3 + 2 = 5
a3 = a2 + 3(3-1) = 5 + 6 = 11
a4 = a3 + 4(4-1) = 11 + 12 = 23
...
Observing the values, we can notice that an =[tex]n(n^2 + 1).[/tex]
Thus, the solution to the recurrence relation is an = [tex]n(n^2 + 1).[/tex]
c) For the recurrence relation an = an-1 +[tex]3n^2[/tex], a0 = 10, we expand it iteratively:
a1 = a0 + [tex]3(1^2)[/tex] = 10 + 3 = 13
a2 = a1 + [tex]3(2^2) =[/tex] 13 + 12 = 25
a3 = a2 + [tex]3(3^2)[/tex]= 25 + 27 = 52
a4 = a3 + [tex]3(4^2)[/tex]= 52 + 48 = 100
...
We can notice that an = [tex]n^3 + 10.[/tex]
Thus, the solution to the recurrence relation is an = [tex]n^3 + 10.[/tex]
These are the solutions to the given recurrence relations.
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Not yet anvered Which of the following What if analysis scenarios can be solved using a two way data and out of 20 ago Select one: O a. to determine how the monthly payments will depend on the amount borrowed O b. to display how the profit of a lemonade stand will change when the price per cup and the count per cup chama Pc None of the mentioned d. to display how the demand and the profit of a lemonade stand change when the price per cup changes tion 13 Not yet answered Marked out
The scenario that can be solved using a two-way data table out of the options provided is to display how the profit of a lemonade stand will change when the price per cup and the count per cup change.
A two-way data table is a useful tool for conducting sensitivity analysis and exploring how changing two input variables affects the output or result of a formula or calculation. In this case, the profit of a lemonade stand is the output variable, while the price per cup and the count per cup are the two input variables. By creating a two-way data table with different values for the price per cup and the count per cup, we can systematically analyze how these two factors impact the profit of the lemonade stand. Each combination of the price per cup and the count per cup will be evaluated, and the corresponding profit will be calculated. This analysis allows us to observe the relationship between the input variables (price per cup and count per cup) and the output variable (profit). We can identify the optimal price per cup and count per cup that maximize the profit or explore different scenarios to understand how changes in these variables affect the overall profitability of the lemonade stand. Therefore, the option "b. to display how the profit of a lemonade stand will change when the price per cup and the count per cup change" can be solved using a two-way data table.
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The table below shows the number of families living in the city of Sunnyvale from 1965 to 2000. Year (after 1900) Number of Families (thousand) 65 O 31.1 70 T 30.5 75 2 30.1 80 2 28.7 85 4 27.1 90 5 25.7 95 6 23.2 20.3 2000 100 7 2015+7 -22 According to the best-fit quadratic model, approximately how many families will live in Sunnyvale in 2015? A. 18,000 y=-0.19378x² -0.15x65x +31.0148 B. 16,000 C. 14,000 D. 10,000 TI-84 Plus CE NORMAL FLOAT AUTO REAL RADIAN MP L1 L2 L3 L5 L4 0 123H567 4 ‒‒‒‒‒‒ L1(1)=0 31.1 30.5 30.1 28.7 27.1 25.7 23.2 20.3 TI-84 Plus CE NORMAL FLOAT AUTO REAL RADIAN MP QuadReg y=ax2+bx+c a= -0.1937822868 b=-0.1526507689 c=31.01480998
The best-fit quadratic model is given by the equation y = -0.19378x² - 0.15265x + 31.0148, where x represents the year after 1900.
According to the best-fit quadratic model obtained from the data, approximately 14,000 families will live in Sunnyvale in 2015.
To estimate the number of families in 2015, we substitute x = 115 (2015 - 1900) into the quadratic model:
y = -0.19378(115)² - 0.15265(115) + 31.0148
≈ 14,000
Therefore, based on the best-fit quadratic model, it is estimated that approximately 14,000 families will live in Sunnyvale in 2015. The model is obtained by performing a quadratic regression using the given data points, and it provides a reasonable estimate for the number of families in 2015 based on the trend observed in the data.
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