The length of side AC in AABC is 5 units.
5
ty
4
3
2.
1
A
B
0
0
Х
5
1
2.
3
4
What is the perimeter of AABC?
A 12 units
B. 13 units
C 15 units
D. 16 units
Answers
The solution is, 12units is the perimeter of AABC.
Here, we have,
Perimeter of ∆ABC = AB + BC + AC
Formula: distance= √(x_2-x_1)²+(y_2-y_1)²
Distance between A(1, 1) and B(4,1):
Where,
AB = √(4-1)^2 + ( 1-1)^2
AB = 3 units
Distance between B(4,1) and C(4,5)
Where,
BC = √(4-4)^2 + (5-1)^2
BC = 4 units
and, we have,
AC = 5 units
so, we get,
Perimeter of ∆ABC = 3+4+5
= 12 units
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