The length of a rectangular deck i 4 time it width, and it perimeter i 20ft , what the deck area?

Answers

Answer 1

The area of rectangular deck with length 8 feet and width 2 feet is 16 ft².

What is area of rectangle ?

Area can be defined as the amount of space covered by a plane of a particular shape. It is measured in "number" of square units (cm², inch², ft² etc.). In other words, the space occupied around this shape is called the area of the rectangle.

Rectangle perimeter = 2(length + width)Rectangle area = length x width

We have, a rectangular deck with

length is 4 times its width and perimeter is 20ft.

Let us assume that "l" and "w" be length and width of a rectangular deck.

so, l = 4 w --(1)

Now, perimeter of rectangular deck = 2 ( l+w)

=> 2(l+w) = 20 --(2)

we have to calculate the area of rectangular deck and for this we have to calculate measure of length and width.

plug the value of "l" in equation (2) from (1)

2(l+w) = 20

=> 2(4w + w) = 20

=> 2× 5w = 20

=> w = 20/10 = 2 feet

from equation (1) , l = 4 × 2 = 8 feet

Area of rectangular deck, A = l× w

=> A = 8× 2 = 16 square feet

So, the required area is 16 square feet.

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The Length Of A Rectangular Deck I 4 Time It Width, And It Perimeter I 20ft , What The Deck Area?

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