This question involves the concepts of orbital velocity and orbital radius.
The orbital velocity of ISS must be "7660.25 m/s".
The orbital velocity of the ISS can be given by the following formula:
[tex]v=\sqrt{\frac{GM}{R}}[/tex]
where,
v = orbital velocity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m
R = 67.86 x 10⁵ m
Therefore,
[tex]v=\sqrt{\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{67.86\ x\ 10^5\ m}}[/tex]
v = 7660.25 m/s
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HELP!!!
Which of the following statements is true about magnets?
A. The molecules of the atom are unaligned
B. The orientation of atoms does not affect a magnet
C. The north pole is stronger than the south pole
D. The molecules of the atom are all aligned
Giving brainliest to the correct answer! (If both are correct I'll give whoever answered correctly 1st brainliest!)
Answer:
Explanation:
A is not correct. That means that D is since they offer exactly the opposite meanings.
C is rubbish. One pole could not be stronger than the other. Heaven help us if touched the stronger pole.
B the very point of a magnet is that it does matter how the atoms are orientated.
A 40 N block is resting on a rough inclined plane. The static friction between the block and the plane is ____ N.
The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
The given parameters:
Weight of the block, W = 40 NThe normal reaction on the rough surface due to weight of the block is calculated as follows;
[tex]F_n = 40 \ N[/tex]
The static friction between the block and the plane is calculated as follows;
[tex]F_s = \mu_s F_n[/tex]
where;
[tex]\mu_s[/tex] is coefficient of static frictionThus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
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A plane flies from New York to LA at a constant speed of 800 km an hour how long will it take the plane to fly to 4,200 kilometers
Answer:
3.5 hours
Explanation:
If the force to stretch a spring is given as k = (100N/m), then what is the potential energy of the spring if it is stretched 1 meters from rest?
Answer:
50 Joules
Explanation:
In an action-reaction pair
a. action force is exerted first
b. action force and the reaction force are equal in magnitude and act in the same direction.
c. action force and the reaction force are contact forces only.
d. action force and the reaction force act on two different objects.
Answer:
d. action force and the reaction force act on two different objects.
Hope you could understand.
If you have any query, feel free to ask.
In an action-reaction pair, action force and the reaction force act on two different objects.
What is Newton's Third Law of Motion?Newton's Third Law of Motion states that "For every action, there is an equal and opposite reaction, action and reaction act on two different bodies."
It means that equal force are act on reaction force that is it is also known as reciprocal law of motion.
When considering the options,
The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.So, In an action-reaction pair, action force and the reaction force act on two different objects. Thus, Option B is the correct answer.
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A rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foA rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foot longer. What is the length of the room
The length of the room is 96 ft.
Let L be the length of the room and W be the width of the room.
Since the length is twice its width, L = 2W.
Its area A = LW
= 2W × W
= 2W²
If each side were increased by 1 foot, then its new area is A' = (L + 1)(W + 1)
= (2W + 1)(W + 1)
= 2W² + 3W + 1
Since the room would contain 145 ft more if each side were increased by 1 foot, then its new area is A' = A + 145 = 2W² + 3W + 1
2W² + 145 = 2W² + 3W + 1
145 = 3W + 1
3W = 145 - 1
3W = 144
W = 144/3
W = 48 ft.
Since its length L = 2W, substituting W = 48 into the equation, we have
L = 2(48)
L = 96 ft
So, the length of the room is 96 ft.
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pls answer this question is due today
=============================================
Explanation:
To compute the speed, we divide the distance traveled over the time duration.
For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.
-----------------
For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)
speed = distance/time = (30 km)/(2 hrs) = 15 km/hr
-----------------
We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.
You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.
-----------------
For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)
So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr
The steeper slope of section C, compared to section A, means the car is going faster.
-----------------
Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km
(60 km)/(1.5 hrs) = 40 km/hr
The speed of the car during section D is 40 km per hour.
Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.
A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/a to the left (-x direction).what is the magnitude of the racquetball's change in momentum?
The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.
Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).
mass m = 42g = 42/1000 = 0.042kg
initial velocity before collision u = 7 m/s
It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,
velocity after collision v = 7 m/s
To calculate the magnitude of the racquetball's change in momentum, we will use the formula below
Change in momentum = Mv - Mu
Since momentum is a vector quantity, we will consider the direction.
Change in momentum = 0.042 x 7 - ( 0.042 x - 7)
Change in momentum = 0.294 + 0.294
Change in momentum = 0.588 kgm/s
Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.
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Ali kicks a soccer ball upward at 45° angle
with an initial speed of 32 m/s. What
expression should Ahmed use to calculate
the magnitude of the ball's initial velocity
the horizontal direction?
Select one:
a. 32 sin(45°) m/s
b. 32 cos(45°) m/s
c. 32 tan(45°) m/s
d. 45 m/s
Answer:
the answer is 32sin(45°)m/s
What size resistor would produce a 3 amp current flow with a 12 volt battery?
Resistance = volts / amps
Resistance = 12 volts / 3 amps
Resistance = 4 Ohms
Answer: 4 Ohms
How long will it take a projectile to hit the ground if it is launched at 4.2 m/s off a 12.6 m high platform?
Answer: 3
Explanation:
I think you are supposed to divided in those problems? I'm not sure but if you aren't then please let me know. The equation I did was:
12.6 / 4.2 = 3
Hope this helps!! :)
A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of mc001-1. Jpg 6. 67 inches 10. 47 inches 20. 94 inches 62. 8 inches.
The approximate length of the arc intersected by the central angle is 20.94 inches.
The given parameters:
Radius of the circle, r = 10 inchesCentral angle, [tex]\theta = \frac{2\pi }{3} \ rad[/tex]The approximate length of the arc intersected by the central angle is calculated as follows;
S = rθ
where;
S is the length of the arcSubstitute the given parameters and solve for the length of the arc
[tex]S = 10 \ in \times \frac{2\pi }{3} \\\\S = 20.94 \ inches[/tex]
Thus, the approximate length of the arc intersected by the central angle is 20.94 inches.
Your question is not complete, find the complete question below:
A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of [tex]\frac{2\pi}{3}[/tex].
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yvonne van gennip of the netherlands ice skated 10.0 km with an average speed of 10.8 m/s. suppose vang ennip crosses the finish line at her average speed and takes a huge boquet of flowers handed to her by a fan. as a result her speed drops t o10.01 m/s. if van gennip’s mass is 63.0 kg what is the mass of the boquet?
By conservation of momentum, we will find that the mass is 4.97 kg.
So in the original system, we have two objects, the bouquet of flowers of mass M that is not moving and Yvonne, which has a mass of 63 kg and a speed of 10.8 m/s.
Then the total momentum of this system is:
P = (63kg)*(10.8m/s) + M*(0 m/s) = 680.4 kg*m/s.
Remember the conservation of momentum, thus, the final momentum must be equal to the above one.
In the final situation, Yvonne and the bouquet move together with a speed of 10.01 m/s,
Then the final momentum is:
P' = (63kg + M)*(10.01 m/s)
And that must be equal to the initial momentum, then we have the equation:
(63kg + M)*(10.01 m/s) = 680.4 kg*m/s.
630.63kg*m/s + M*10.01 m/s = 680.4 kg*m/s.
M*10.01 m/s = 680.4 kg*m/s - 630.63kg*m/s = 49.77 kg*m/s
M = (49.77 kg*m/s)/(10.01 m/s) = 4.97 kg
So the mass of the bouquet is 4.97 kg
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If a 35 kg box collides with a stationary 120 kg box with a force of 90 N, what must
be true of the magnitude of the reaction force?
Answer:
yes , true the magnitude of the reaction force.
A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration
The acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
We know that acceleration is the change in velocity divided by the change in time. In this case, the bicycle is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.
We can use the following equation to find the acceleration:
a = (v2 - v1) / t
where:
a is the acceleration
v2 is the final velocity (6 m/s)
v1 is the initial velocity (0 m/s)
t is the time
Plugging in the values from the problem, we get:
a = (6 m/s - 0 m/s) / 50 s
= 0.12 m/[tex]s^{2}[/tex].
Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
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Alistar places a 6.4 kg block on an incline plane that is 23 degrees above the horizontal. The block starts from rest, and in 2.2 seconds, travels 1.4 meters. What is the force of friction on the block?
fh= 6.4×23
fh=147.2
fv=2.2×1.4
fv=3.08
f=147.2+3.08
f=150.28
The force of friction on the block is 20.798 N.
What is acceleration?Acceleration is the rate at which speed and direction of velocity vary over time. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the block: m = 6.4 kg.
Angle of inclination = 23°
Hence, Magnitude force acting along the motion = mg sin23°
= 6.4 × 9.8 × sin23° N
= 24.51 N.
The block travels 1.4 meters in 2.2 seconds. Acceleration = (2×1.4)/2.2² m/s²
= 0.58 m/s²
Hence, the force of friction on the block is = F - ma
= 24.51 N - 6.4×0.58 N
= 20.798 N
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1. Apply a constant force of 50 N directed to the right of the 50 kg Box. (2 pts)
Hypothesis:?
Conclusion: ?
As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.
Then friction force = 80 Newtons but in the opposite direction.
Friction force = Mu * Normal force exerted by ground = Mu * weight of box
So we find Mu.
Mu = coefficient of friction between box and horizontal surface
= Force of friction / weight = 80 / 50 * 9.81 = 0.163
When an identical box is placed on top, the force of friction is
= Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons
Twins Bo and Joe have a combined mass of 200 kg and are zooming along at 10 m/s in a 100 kg amusement park bumper car. They bump into Melinda’s car, which is sitting still. Melinda has a mass of 25 kg and is also in a 100 kg car. After the collision, the twins continue moving with a speed of 4.12 m/s.
a. What is the initial momentum of the system?
b. What must be the final momentum of the system?
c. How fast is Melinda’s car bumped across the floor?
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
Total mass of the twins and the car = 300 Kg
Initial velocity of the twins car = 10 m/s
Total mass of Melinda and her car = 125 Kg
Initial velocity of Melinda's car = 0 m/s (at rest)
Final velocity of the twins car = 4.12 m/s
Final velocity of Melinda's car = ?
Initial momentum of the system = (300 × 10) + (125 × 0) = 3000 Kgms-1
Final momentum of the system = (300 × 4.12) + (125 × x) = (1236 + 125x) Kgms-1
Using the principle of conservation of linear momentum;
Total momentum before collision = Total momentum after collision
m1u1 + m2u2 = m2v1 + m2v2
(300 × 10) + (125 × 0) = (300 × 4.12) + (125 × x)
3000 = 1236 + 125x
x = 3000 - 1236 /125
x = 14 ms-1
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
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What would be the impact on the environment if an artificial virus that attacked and destroyer chloroplast in plant cells was accidentally released by a research company?
Answer:Yes
Explanation:Because the virus is so dangerous
**BRAINLIEST** How does the Combining Vinegar and Baking Soda table represent the law of conservation of matter when baking soda and vinegar are combined?
Basically your liquid will go over the line because you are adding more mass. the balloon will inflate because of mass filling it. Part 1 I noticed that there was a change from the original line. part 2 Some mass is lost. The bubbles are the gas leaving. The balloon increases in size because of the mass. The cup got heavier when I added the vinegar.
Gas leaving caused the bubbles.
A 300 g ball swings in a vertical circle at the end of a 1.3-m-long string. When the ball is at the bottom of the circle, the tension in the string is 13 N.
What is the speed of the ball at that point?
Answer:
0.23N for the speed
at the bottom of the circle
explain maximum and minimum thermometer working(answer only for points will be reported)
Explanation:
Six’s Maximum and Minimum thermometer is a U shaped parallel tube made up of glass. One side registers the maximum temperature and the other side records the minimum temperature.The bend at the bottom of the thermometer contains mercury which moves up or down based on the expansion and contraction of alcohol.When the temperature rises, the alcohol expands and pushes the mercury up the maximum column. This also pushes the mercury down in the minimum column.Similarly, when the temperature falls, the alcohol contracts and pulls the mercury up in the minimum column resulting in a fall of mercury in the maximum column.The steel indexes are located on the surface of mercury. They move along with the flow of mercury up and down.When the temperature reaches its maximum and minimum limits, the metal indexes remain at that place. This helps in recording the maximum and minimum temperatures of the day.Jeremiah rides his bicycle 4 miles in 30 minutes. If he maintains this rate, how far will he ride in 3 hours?
Answer:
24 miles.
Explanation:
3 hours=180 minutes
180÷30=6
6x4=24
a car travels at a constant speed of 20m/s and yet it does not have a constant velocity. explain how this could be
Answer:
HOPE THIS HELPS!!
Explanation:
Velocity is speed as well as distance mentioned.
The car is traveling at a constant speed of 20m/s but it may not be traveling in any particular direction. It would be taking many turns (left and right) or it would be moving in a circular manner.
So,it is at constant speed but not constant velocity.
A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark. Assume each tick mark represents 1 cm. Calculate the total displacement if a toy car starts at 0, moves 5 cm to the left, then 8 cm to the right, and then 3 cm to the left. The car moves cm, so there is no displacement.
The total displacement of the toy car at the given positions is 0.
The given parameters;
First displacement of the car, = 5 cm leftSecond displacement of the car, = 8 cm rightThird displacement of the car, = 3 cm to the leftThe total displacement of the car is calculated as follows;
Let the left direction be "negative direction"Let the right direction be "positive direction"[tex]\Delta x = - \ 5\ cm \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0[/tex]
Thus, the total displacement of the toy car at the given positions is 0.
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Answer:0
Explanation:
A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)
The outer shell electrons move from the balloon to the sweater.
The fibers of the sweater lose electrons.
The balloon becomes positively charged.
The free electrons in the balloon decreases.
Answer:
The fibers of the sweater lose electrons.
If you walk at an average speed of 5 km/h for 30 minutes, how
far will you walk? (Write your answer with Sl unit.
the probe used in a medical ultrasound examination emits sound waves in air that have a wavelength of 0.12 mm.
Answer:
IF GOD IS TEIIING YOU SOMETHING JUST DO IT
Explanation:
The function of the liver in the metabolism of amino acids is to
Answer:
Produce energy, or make carbohydrates or fats.
Explanation:
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