The height reached by a model rocket can be calculated using the equation h= -16t2 + vt +
where t is the time the rocket is in flight, vis the rocket's velocity, and n is the rocket's beginning
height.
Calculate the height, h at 3 seconds given that the rocket travels 85 feet per second and starts on a
launch pad 15 feet off the ground.
Knowns:
t = 3 seconds
v = 85 feet per second
n = 15 feet
If we plug all those values in, our Formula becomes h= (–16.32) + (85.3) + (15).
Solve for h

Answers

Answer 1

Answer:

Step-by-step explanation:

9.0

Answer 2

The height (h) reached by model rocket will be equal to 126 ft.

It is given that the height reached by a model rocket can be calculated using the equation h = - 16 [tex]t^{2}[/tex] + ( v × t ) + n

We have to calculate the height (h) at 3 seconds.

What is algebra ?

Algebra is the branch of mathematics that deals with various symbols and the arithmetic operations such as multiplication , division , etc.

As per the question ;

h = - 16 [tex]t^{2}[/tex] + ( v × t ) + n   ---------- Equation 1

t = time rocket is in flight = 3 seconds

  v = velocity at which rocket travels = 85 ft. per second

  n = height of rocket at beginning = 15 ft

Putting these values in equation 1 , we get.

h = - 16 × ( 3² ) + (85) × (3) + 15

h = - 16 × 9 + 255 + 15

h = -144 + 270

h = 126 ft.

Thus , the height (h) reached by model rocket will be equal to 126 ft.

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Hope this helped!

Answer:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

REF: 060309a

ANS:

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Answers

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The second one I believe so because I just finished learning this last year
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