The function f(x) = –3x2 + 36x – 119 written in vertex form is f(x) = –3(x – 6)2 – 11. Which statements are true about the graph of f(x)? Select three options.

The axis of symmetry is the line x = 6.
The vertex of the graph is at (–6, –11).
The parabola has a minimum.
The parabola opens down.
The value of h, when the equation is written in vertex form, is positive.

Answer:

A D and E

Step-by-step explanation:

The statements true about the graph of the function are

a) The axis of symmetry is the line x = 6

b) The parabola opens down

c) The vertex of the graph is at (-6, -11)

Graphs behave differently at various x-intercepts. Sometimes the graph will cross over the x-axis at an intercept. Other times the graph will touch the x-axis and bounce off.

Identify the even and odd multiplicities of the polynomial functions' zeros.

Using end behavior, turning points, intercepts, and the Intermediate Value Theorem, plot the graph of a polynomial function.

The graphs cross or are tangent to the x-axis at these x-values for zeros with even multiplicities. The graphs cross or intersect the x-axis at these x-values for zeros with odd multiplicities

Given data ,

Let the function be represented as f ( x )

Now , the value of f ( x ) = -3x² + 36x - 119

And , the vertex form of the function is

f ( x ) = -3 ( x - 6 )² - 11

Now , The axis of symmetry is the line x = 6. This is true because in vertex form, the equation of the axis of symmetry is given by x = h, where (h, k) is the vertex of the parabola. In this case, the vertex is (6, -11), so the axis of symmetry is x = 6.

The parabola has a minimum. This is also true because the coefficient of the x² term in the given equation is negative (-3), which means the parabola opens downward and has a minimum at the vertex.

Hence , the graph of the polynomial is solved

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