The following cards are dealt to three people at random, so that everyone gets the same number of cards. What is the probability that everyone gets a red card?

[There are three red cards and three blue cards]

The given triangle is Equilateral triangle.

Triangle is a two dimensional shape having three side and sum of all angles is equals to 360 degree .

A right angled triangle is a triangle having one of its angle with measure of 90° The slant side of that triangle is called Hypotenuse and it is the longest side in that triangle.

We have, triangle with an angle equal to each other and three equal sides.

So, We know that,

When a triangle have angle equals to each other then it is  Equilateral triangle.

Now, When a triangle have equal sides then it is Equilateral triangle.

So,

From the above mentioned statements we can say that triangle is Equilateral triangle.

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Answer:

(3, 4 )

Step-by-step explanation:

under a reflection in the y-axis

a point (x, y ) → (- x, y ) , then

R (- 3, 4 ) → R' (3, 4 )

Using the Final Exam Grade formula above, I want a 90 in the class and I currently have an 85 . The final is worth [tex]$40 \%$[/tex] of the term grade.

First, convert the weight of the final exam from percent to decimal: [tex]$40 \div 100=0.40$[/tex]

[tex]$$\begin{gathered}F=\frac{90-((1-0.4) \times 85)}{0.4} \\F=\frac{90-((0.6) \times 85)}{0.4} \\F=\frac{90-51}{0.4} \\F=\frac{39}{0.4} \\F=97.5\end{gathered}$$[/tex]

So if I have an 85 in the class, I want a 90, and the final exam is worth 40%, I need a 97.5 to get a 90 in the class.

Using the Final Class Grade formula above, [tex]$F=88.6, w=15$, and $C=91$.[/tex]

First, convert the weight of the final exam from percent to decimal: 15 div 100=0.15

So I went into the final with a class grade of 91 . I got 88.6 on the final which was worth $15 \%$ of the course grade. My final grade in the class was 90.64.

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The price should be higher than the AVC and ATC in order to make a profit in the short term. Therefore, in order to achieve the requisite profit, the MR curve must rise above cost = 7.

When businesses in a cutthroat sector start making money, it opens the door for more businesses to enter the market, which leads to a shift to the right in the supply curve, a drop in price, and the return of all businesses to a state of no economic profit.

If the market price is lower than the average total cost, a company will experience positive economic profit in the short term.

In the short run, a monopolistically competitive firm optimises profits or avoids losses by producing the amount where marginal revenue equals marginal cost. If the average total cost is less than the market price, the company will make a profit.

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f(m) = 3 * 1.09 * m = 3.27 * m

A:

solve f(m) = 5.98 to find how long it takes for fish to reach that length

5.98 = 3.27 * m

m = 5.98/3.27 = 1.83 months

A reasonable domain would technically depend on other factors like standard deviation, however, a domain of [0,3] could be reasonable without further information.

B:

The y intercept (0 because f(0)=0 ) represents the length of fish at the beginning of the marine biologists study, or when the number of months is zero

C:

Rate of change equals the change in y over the change in x.

[tex]\frac{f(8)-f(2)}{8-2}=\frac{26.16-6.54}{6}=\frac{19.62}{6}=3.27\frac{cm}{month}\\[/tex]

This represents the average number of cm the length of the fish change per month in the interval [2, 8]

Answer:

  61 months, about 5.07 years

Step-by-step explanation:

You want the time it takes to pay off a loan of $11,000 at 4% compounded monthly when the payment is $200 per month.

The number of payments required can be found by solving the amortization formula, or using any spreadsheet, financial calculator, or suitable app.

The attachment shows the number of months required is about 60.9.

It will take 61 months, or about 5.07 years to pay off the loan.

__

Additional comment

The formula for the number of monthly payments on a loan amount of P at interest rate r with monthly payments of A is ...

  [tex]N = -\dfrac{\log{\left(1-\dfrac{Pr}{12A}\right)}}{\log{\left(1+\dfrac{\vphantom{R}r}{12}\right)}}[/tex]

Answer:

X= 6+y/7

Step-by-step explanation:

The equation which is equivalent to 60% of 25 is x = 0.6 * 25

What is a linear equation with an example?

Ax+By=C represents a two-variable linear equation in its standard form.

A standard form linear equation is, for instance, 2x+3y=5. Finding both intercepts of an equation in this format is rather simple (x and y).

A linear equation with one variable has the conventional form Ax + B = 0. x is a variable, A is a coefficient, and B is constant in this situation.

An equation is used to show the relationship between variables, and numbers.

Let x represent the value of 60% of 25. Hence:

x = 60% of 25

x = 0.6 * 25

Hence, the equation which is equivalent to 60% of 25 is x = 0.6 * 25

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Answer:  $16,800

Step-by-step explanation:

Answer: 20.98

Step-by-step explanation: Pythagorean theorem to find a is the square root of c^2 - b^2 C is 27 and b is 17 so square root of 27^2 17^2 is 20.98

Hence, the diagonals of parallelogram is not perpendicular to each other. They are equal in length and they bisect each other but diagonals are not perpendicular so it would be rectangle.

What is the parallelogram?

A parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.

The congruence of opposite sides and opposite angles is a direct consequence of the Euclidean parallel postulate and neither condition can be proven without appealing to the Euclidean parallel postulate or one of its equivalent formulations.

Here given that,

[tex]DE=3y+7 \\DB=10y-6[/tex]

As we know the slope of a line is

[tex]y=mx+c[/tex]

where [tex]m[/tex] is the slope.

So,

[tex]DE=3y+7\\\\m_1=3\\\\\\DB=10y-6\\\\m_2=10[/tex]

Then,

[tex](m_1)(m_2)=(3)(10)\\\\(m_1)(m_2)\neq 30[/tex]

Draw the graph of given equations

Hence, the diagonals of parallelogram is not perpendicular to each other. They are equal in length and they bisect each other but diagonals are not perpendicular so it would be rectangle.

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Answer:

B

Step-by-step explanation:

Answer: y= 0.64x

Step-by-step explanation:

Take 3.52 divided by 5.5 = $0.64 per pound of potato

y is the total cost, x is the number of pound

y= 0.64x

The linear systems has the ordered pair (1, 1)as a solution will be x + y = 2 and x - y = 0. Then the correct option is A.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

Let's check all the options, then we have

A)  x + y = 2 and x - y = 0

Add both equations, then we have

x + y + x - y = 2 + 0

2x = 2

x = 2 / 2

x = 1

Then the value of the variable 'y' is calculated as,

1 - y = 0

y = 1

Then the solution of the equations is (1, 1).

The linear systems has the ordered pair (1, 1)as a solution will be x + y = 2 and x - y = 0. Then the correct option is A.

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The missing option is given below.

A) x + y = 2 and x - y = 0

B) x + y = 2 and x + 2y = 0

C) x + y = 0 and x - y = 2

D) None of the above

Answer: Yes.

Step-by-step explanation:  3/8 and 1 1/2 of a fourth are equivalent amounts. To see why, you can use a common denominator to compare the two fractions. If we convert both fractions to eighths, then 3/8 becomes 3/8 and 1 1/2 of a fourth becomes 6/8. Since 3/8 and 6/8 are both equal to 3/4, it follows that 3/8 and 1 1/2 of a fourth are also equal.

The value of the equation A = 1/10 is 10 %

So , the 20 overseas investors owns 10 % of the business

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the percentage of business owned by the overseas investors be = A

Now , the equation will be

The number of overseas investors = 20

The fraction of business the overseas investors own = 1/10

Now , the percentage is always expressed in terms of 100

So ,

The percentage of business owned by the overseas investors = fraction of business the overseas investors own x 100

Substituting the values in the equation , we get

Percentage of business owned by the overseas investors = ( 1/10 ) x 100

Percentage of business owned by the overseas investors = 10 %

Therefore , the value of A is 10 %

Hence , the 20 overseas investors owns 10 % of the business

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Answer:

The answers are A B and C

they could be whole numbers

Step-by-step explanation:

need brainliest

Like has 47 red balls in the beginning.

A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

The likelihood of choosing a blue and then a red ball at random when two balls are pulled is 5/18.

since, he loses everyday 3 red balls; after 1 day (y-3) red balls

Case1:

x + 10 = y -15

x - y = -25    equation 1

Case2:

(x + 18) = 2(y - 27)

x + 18 = 2y - 54

x - 2y = -54 - 18

x - 2y = -72      equation 2  

Now subtract both eq1 and eq2

x - y = -25

x - 2y = -72

y = 47

Like has 47 red balls in the beginning.

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By using the concept of growth and depreciation, it can be calculated that

1a) Amount of sample left after 15 years = 123.76 g

b) Time taken by the substance to reduce to half is 21.66 years

2) Amount is $1560.97

3) It took 11.94 years for $900 to get doubled

What is growth and depreciation?

Growth is the increase in the value of an asset or cost or population at a certain rate over a certain period of time

Depreciation is the decrease in the value of an asset or cost or population at a certain rate over a certain period of time

1) Original weight of the isotope = 200g

Function = [tex]200e^{-0.032t}[/tex]

a) Time  = 15 years

Amount of sample left after 15 years = [tex]200e^{-0.032 \times 15}[/tex] = 123.76 g

b) Amount left = 100g

100 = [tex]200e^{-0.032t}[/tex]

[tex]e^{-0.032t} = \frac{100}{200}[/tex]

[tex]e^{-0.032t} = \frac{1}{2}[/tex]

[tex]-0.032t = ln(\frac{1}{2})\\-0.032t = -0.693\\t = \frac{0.693}{0.032}\\[/tex]

t = 21.66 years

2) Principal = $1100

   Rate = 5%

    Time = 7 years

  Amount =  [tex]1100e^{\frac{5}{100} \times 7}\\[/tex]

                  = [tex]1100e^{0.35}[/tex]

                  = $1560.97

3) Principal = $900

   Amount = $900 [tex]\times[/tex] 2 = $1800

   1800 = [tex]900(1 + \frac{6}{1200})^{12n}[/tex]

    [tex]\frac{1800}{900} = (\frac{201}{200})^{12n}[/tex]

     [tex](\frac{201}{200})^{12n} = 2[/tex]

     [tex]12n \times log(1.005) = log 2\\12n \times 0.0021 = 0.3010\\n = \frac{0.3010}{12 \times 0.0021}\\[/tex]

     n = 11.94 years

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The taylor series as per the power series operation is sin(x) = 0 + 1x + 0x + −1/3!+3 + 0x

given,

f(x) = sinx

c = 3pi/4

the required series will be .

f(x) = f(c) + f' (c)( x-c ) + f''(c)/2! + .... f x n(c)/n! (x-c)^n

f(c) = sin(c)

     = sin(3pi/4)

      = 1/2

on solving the equation becomes,

sin(x) = 0 + 1x + 0x + −1/3!+3 + 0x

Assume that f(x) is a real or composite function and that it is a differentiable function of a real or composite neighbourhood number. The following power series is then described by the Taylor series.

The Taylor series can be expressed using sigma notation, where f(n)(a) = nth derivative of f n! = factorial of n.

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We have a two-tailed test, as we are testing if the mean is different of a value.

The t-distribution is used, as we have the standard deviation for the sample, and the parameters are given as follows:

Using a t-distribution calculator, the critical value is of:

t = ± 1.7109.

The equation for the test statistic is defined as follows:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

In the context of this problem, the values of these parameters are of:

[tex]\overline{x} = -34.3, \mu = 0, s = 42.9, n = 25[/tex]

Hence the value of the test statistic is of:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{-34.3 - 0}{\frac{42.9}{\sqrt{25}}}[/tex]

t = -4.

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Answer:

[tex] \dfrac{2}{x} - 9[/tex]

Step-by-step explanation:

the quotient of 2 and x:

[tex] \dfrac{2}{x} [/tex]

9 less than the quotient of 2 and x:

[tex] \dfrac{2}{x} - 9[/tex]

Explanation

Solve for x:

[tex]-5\text{x}+5 \ge 7\\\\-5\text{x} \ge 7-5\\\\-5\text{x} \ge 2\\\\\text{x} \le 2/(-5)\\\\\text{x} \le -0.4\\\\[/tex]

Note the inequality sign flips when we divide both sides by a negative number.

If x is an integer, then the largest x can be is x = -1, which means x can be any of these values:  {..., -4, -3, -2, -1} where the three dots means the pattern continues on to the left forever. If it might help, then you can think of it like this: {-1, -2, -3, -4, ...} but it's of course not the standard way to sort negative numbers.

Now we're told that  -2 ≤ x ≤ 4 which when combined with the set above, gets us the answer {-2, -1}

If we replaced x with -2, then,

-5x+5 ≥7

-5(-2)+5 ≥7

10+5 ≥7

15 ≥7

which is true and confirms x = -2 works. I'll let you try out x = -1.

The pressure of 28 inches of mercury occurs about 50 miles far the eye.  

The measurement of air pressure in a certain location is called barometric pressure, which is the force of air pressing down on the surface of the globe, the oceans, and the land. .

p(x) =0.48ln (x + 1) + 27

Lets take P(50)

P(50)= barometric pressure at 50 miles from the eye of the hurricane P(50) as x

P(50) = 0.48 ln (50 + 1) + 27

P(50) = 0.48 ln (51) + 27

P(50) = 0.48 x 3.9318 + 27

where,

ln(51) = 3.9318

P(50) = 28.89

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The correct option for the equation is C.

What is equation?

An equation could be a formula that expresses the equality of 2 expressions, by connecting them with the sign =.

Main Body:

Using distance=rate multiplied by time as the  formula,  

mountaineer climbed 1,000 feet at a rate of x feet per hour  

1000 = xt₁           <--eq.1  

"He climbed an additional 5,000 feet at a different rate."  

5000 = x't₂         <--eq.2  

"This rate was 10 feet per hour less than twice the first rate."  

x' = 2x - 10 <--eq.3  

We now have 3 equations/expressions to solve for the number of hours:  

From eq. 1 and 2:  

Total time = t₁ +t₂ = t

t = 1000/x + 5000/x'  

but x' = 2x - 10  

t = 1000/x + 5000/(2x-10)  

t = 1000/x + 5000/[2(x-5)]  

t = 1000/x + 2500/(x-5)

Hence correct option is C.

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The point on the perpendicular bisector of the segment MN, M(7, 5), N(-1, 5), is (3, 9)

The perpendicular bisector of a segment, divides the segment into two segments that have the same length, and which forms an angle of 90° with the line.

The specified endpoints on the segment MN = M(7, 5), and N(-1, 5)

The y-coordinates of the points M and N are the same, therefore, the segment is an horizontal segment.

The midpoint of the line is therefore;

(7 + (-1 - 7)/2, 5 + (5 - 5)/2) = (3, 5)

The slope of the segment, MN, m = (5 - 5)/(-1 - 7) = 0

The slope of the perpendicular line is therefore;

-1/0 = ∞

The segment MN is parallel to the x-axis, therefore, the perpendicular bisector is parallel to the y-axis, and the x-values of points on the perpendicular bisector have the save value s the x-value of the midpoint of the segment MN, (3, 5), which is x = 3

The point that lies on the perpendicular bisector of the segment MN from the options is therefore; (3, 9)

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The constant of proportionality is 5.

What is the constant of proportionality?

When two variables move in the same direction, this is known as direct variation. The other variable also rises when one rises. The points rise along with the number of goblins defeated. This is an exact alteration.

The equation used to represent direct variation is: y = kx

Where k is the constant of proportionality

5 = k

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Arrays can be passed as parameters to a function by value, but it is faster to pass them by reference. The given statement is False.

An array is a collection of items of same data type stored at contiguous memory locations. This makes it easier to calculate the position of each element by simply adding an offset to a base value, i.e., the memory location of the first element of the array.

In Pass by value, function is called by directly passing the value of the variable as an argument. So any changes made inside the function does not affect the original value.

In Pass by Reference, Function is called by directly passing the reference/address of the variable as an argument. So changing the value inside the function also change the original value. In JavaScript array and Object follows pass by reference property. Parameters passed as an arguments does not create its own copy, it refers to the original value so changes made inside function affect the original value.

Thus, the statement that Arrays can be passed as parameters to a function by value, but it is faster to pass them by reference is False.

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[tex]\fbox{x=$\dfrac{-7}{6}$ }[/tex]

Flip the equation:

[tex]-6x-5=2[/tex]

Add 5 to both sides:

[tex]-6x-5+5=2+5[/tex]

[tex]-6x=7[/tex]

Divide both sides by -6:

[tex]\dfrac{-6x}{-6} =\dfrac{7}{-6}[/tex]

[tex]x=\dfrac{7}{-6}[/tex]