the expression negative one eighth j plus two thirds minus the expression five thirds j plus nine twelfths


negative 37 over 24 times j minus 17 over 12

negative 37 over 24 times j plus 17 over 12

43 over 24 times j plus 1 over 12

negative 43 over 24 times j plus negative 1 over 12

Simplify the expression.

the expression negative one eighth j plus two thirds minus the expression five thirds j plus nine twelfths

negative 37 over 24 times j minus 17 over 12
negative 37 over 24 times j plus 17 over 12
43 over 24 times j plus 1 over 12
negative 43 over 24 times j plus negative 1 over 12


Which expression is equivalent to 3(−4.5b − 2.1) − (6b + 0.6)?

19.5b + 1.5
−19.5b − 1.5
−19.5b − 6.9
19.5b − 6.9

Answers

Answer 1

A) Simplification of the given Algebraic Expression is; [-⁴³/₂₄j + (-1)]/12

B) The equivalent expression to 3(−4.5b − 2.1) − (6b + 0.6) is - 19.5b - 6.9

How to simplify Algebraic Expressions?

A) We want to simplify negative one eighth j plus two thirds minus the expression five thirds j plus nine twelfths. This would be expressed as;

-1/8j + 2/3 - (5/3j + 9/12)

= -1/8j + 2/3 - 5/3j - 9/12

= -1/8j - 5/3j + (2/3 - 9/12)

= (-3j-40j / 24 + (8-9) / 12

= [-⁴³/₂₄j + (-1)]/12

B) The expression equivalent to 3(−4.5b − 2.1) − (6b + 0.6)

Expand the brackets to get;

-13.5b - 6.3 - 6b - 0.6

= -13.5b - 6b - 6.3 - 0.6

= - 19.5b - 6.9

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Related Questions

Jerry, Jack and Sophie are all hoping to save money! Jerry thinks saving money in a shoe box in his closet every month is a good idea. He decides to start with $125, and then save $50 each month. Jack was given $3520 from his Grandma, and decides to put the money into an account that has a 6.5% interest rate that is compounded annually. Sophie has earned $3500 working at the movie theater decides to put her money in the bank in an account that has a 7.05% interest rate that is compounded continuously Part 3: Describe the type of equation that models Sophie’s situation. Create that equation of Sophie’s situation. Using the equation you created, how much money will be in Sophie’s account after 3 years? 10 years?

Answers

Sophie

- The formula for continuously compounded interest is given by:

[tex]A=Pe^{rt}[/tex]

Where:

A is the amount after t years.

P is the principal.

r is the annual interest rate.

Therefore the equation is:

P = $3500

r = 7.05% = 0.0705

[tex]A=3500e^{0.0705t}[/tex]

- Money in​ Sophie’s account after 3​ years:

t = 3

[tex]A=3500e^{0.0705(3)}=3500e^{0.2115}=4324.35[/tex]

This is $4324.35

- Money in​ Sophie’s account after 10 years:

t = 10

[tex]A=3500e^{0.0705(10)}=3500e^{0.705}=7083.46[/tex]

This is $7083.46

Answer

Describe the type of equation that models​ Sophie’s situation: exponential growth model.

Create that equation of​ Sophie’s situation:

[tex]A=3500e^{0.0705t}[/tex]

Money will be in​ Sophie’s account after 3​ years: $4324.35

Money will be in Sophie´s account after 10 years: $7083.46

Expressing the relationship between two quantities with a linear equation. A stationary store sells large and small packages of greeting cards. Each large package contains h greeting cards. Each small package contains k greeting cards., which is 4 less than the larger package. Express h in terms of k

Answers

large = h greeting cards

small = k greeting cards this is four less

h = k + 4 This is the answer

Need ASAP please and thank you! :)

Answers

Answer:

B. [tex]\dfrac{x^2+3}{\left(x-1\right)\left(x-3\right)}[/tex]

Step-by-step explanation:

Will provide explanation later since you are in a hurry

1. Find the LCM of the two denominators: x-1 and x -3

This is (x-1)(x-3)

2. Multiply each numerator by the same amount needed to multiply its​corresponding denominator to turn it into the LCM (x−1)(x−3)

[tex]\mathrm{For}\:\dfrac{x-3}{x-1}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:x-3[/tex]

[tex]\dfrac{x-3}{x-1} = \dfrac{\left(x-3\right)\left(x-3\right)}{\left(x-1\right)\left(x-3\right)} = \dfrac{\left(x-3\right)^2}{\left(x-1\right)\left(x-3\right)}[/tex]

[tex]\mathrm{For}\:\dfrac{6}{x-3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:x-1[/tex]
[tex]\dfrac{6}{x-3} = \dfrac{6\left(x-1\right)}{\left(x-3\right)\left(x-1\right)} = \dfrac{6\left(x-1\right)}{\left(x-1\right)\left(x-3\right)}[/tex]

[tex]2. \mathrm{Simplify\:}\left(x-3\right)^2+6\left(x-1\right)[/tex]
[tex]\left(x-3\right)^2 = x^2 - 6x + 9\\\\\\3. \; \text{Expand }6\left(x-1\right)\;6\left(x-1\right) = 6x-6\\\\[/tex]

4. Since the denominators are the same in both terms, we can add the numerators and use the common denominator as the denominator for the result

Adding numerators derived from steps 2 and 3 above we get
[tex]x^2-6x+9+6x-6 = x^2+3[/tex]Dividing by the common denominator (x-1)(x-3) gives the result as
[tex]\dfrac{x^2+3}{\left(x-1\right)\left(x-3\right)}[/tex]

Answer:

While adding two Fractions first we find the LCM of Denominators,

The LCM of x-1 and x-3 is (x-1)(x-3)

now, we perform the calculation as ,

[tex]{\frac{x-3}{x-1}} + {\frac{6}{x-3}}[/tex]

[tex]{\frac{(x-3)²+6(x-1)}{(x-1)(x-3)}}[/tex]

[tex]{\frac{x²+9-6x +6x-6}{(x-1)(x-3)}}[/tex]

[tex]{\frac{x²+3}{(x-1)(x-3)}}[/tex]

Hence option B is the answer

Name three points in the diagram that are not collinear.

Select all that apply.

A. F, N, R
B. F, N, C
C. F, R, V
D. F, C, V
E. F, N, V
F. C, F, R

Answers

Answer: B, D, and F

Step-by-step explanation:

        When points are collinear, it means they are all on a single line.

        View the attachments for all my work. I can only add up to five, but answer option E is similar to A and C.

Estimate by using the table of percent-fraction equivalents: 34% of 18 = _____table PercentFraction25% 1/433-1/3%1/350% 1/266-2/3%2/375% 3/4

Answers

34 % of 18

Using the table

the 33% of any value is 1/3 of the value, as follows

[tex]18*\frac{1}{3}=6[/tex]

then 33% of 18 is 6

then

34% of 18 is equivalent to 6

estimate the difference of 1 1/5 - 9/10

Answers

estimate the difference of 1 1/5 - 9/10​

we have

1 1/5=1+1/5=6/5

6/5=12/10

so

12/10-9/10=3/10=0.3

answer is 0.3

estimete

1 1/5 is about 1

9/10=0.9

so

1-0.9=0.10

the estimate is 0.10

steps

Rounded 1 1/5------> 1

we know that

9/10=0.9

so

substitute

1-0.9=0.10

chords AB and CD intersect as shown nelow find the length of CD

Answers

We are asked to determine the length of CD, to do that we will use the following relationship:

[tex]\begin{gathered} CD=21+x+1 \\ CD=22+x \end{gathered}[/tex]

Therefore, we need to determine the value of "x". To do that we will use the intersecting chords theorem, that is:

[tex](21)(x+1)=(9)(3x-9)[/tex]

Now we solve for "x" first by applying the distributive law:

[tex]21x+21=27x-81[/tex]

Now we will subtract 21 to both sides:

[tex]\begin{gathered} 21x=27x-81-21 \\ 21x=27x-102 \end{gathered}[/tex]

Now we will subtract 27x to both sides:

[tex]\begin{gathered} 21x-27x=-102 \\ -6x=-102 \end{gathered}[/tex]

Dividing both sides by -6:

[tex]x=-\frac{102}{-6}=17[/tex]

Now we replace the value of "x" in the expression for segment CD:

[tex]\begin{gathered} CD=22+17 \\ CD=39 \end{gathered}[/tex]

Therefore, the length of CD is 39.

the equation of line m is y =9/5x +9. line n is parallel to line m. what is the slope of line n?

Answers

the slope for the line n is 9/5

Help me please in need of it

Answers

Answer:

-2

Step-by-step explanation:

Substituting the points (0,2) and (1,0) into the slope formula, [tex]m=\frac{2-0}{0-1}=-2[/tex].

Jackson is donating some of his old games to the community center. He uses a frequency chart to record the number of pieces in each game.


If 1/8 of the chess pieces are knights, how many knights are there?

Answers

Answer:

4 knights

Step-by-step explanation:

32÷8=4

32 chess pieces divided by 8 is. 4 will represent 1/8 of the total of the amount of chess pieces. So, there are 4 chess pieces.

Solve the inequality and draw the solution |r|-3>2

Answers

We want to solve the following inequality

[tex]|r|\text{ -3 >2}[/tex]

To solve this inequality, we first add 3 on both sides, so we get

[tex]|r|>2+3=5[/tex]

So we have the inequality

[tex]|r|>5[/tex]

Recall that the absolute value represents the distance from a number to 0. So this means that the number r is greater than 5 or it is less than -5. So we have the following two inequalities

[tex]r>5[/tex][tex]r<\text{ -5}[/tex]

This could be drawn on the number line as follows. Greater than (>) means that the number 5 is on the left, and the less than (<) means that the number -5 is on the right side. So we get the following

Which rectangles have an area of 36 square feet? Choose all that are correct. 10 ft 8 ft 9 ft 4 ft 6 ft 6 ft 11 ft 7 ft 12 ft 3 ft

Answers

The area of a rectangle is given by the formula below.

[tex]A=bh[/tex]

Then, from top to bottom, the areas of the rectangles are

[tex]\begin{gathered} A_1=10\cdot8=80 \\ A_2=9\cdot4=36 \\ A_3=6\cdot6=36 \\ A_4=7\cdot11=77 \\ A_5=3\cdot12=36_{} \end{gathered}[/tex]

Therefore, the answers are (top to bottom) the second, third, and fifth rectangle.

How many pairs of parallel edges are there in a rectangular prism

Answers

Answer:

A rectangular prism has 3 pairs of congruent parallel faces.

Which set of ordered pairs (x,y) could represent a linear function?A. {(-7,3), (-2,1), (3,-1), (8,-3)}B. {(-2,8), (-1,4), (1,0), (3,-4)}C. {(-3,-6), (0,-5), (3,-3) (6,-2)}D. {(0,-8), (3,-5), (5,-2), (8,1)}

Answers

Answer:

A. {(-7,3), (-2,1), (3,-1), (8,-3)}

Explanation:

A linear function has a constant slope.

To determine the set of ordered pairs (x,y) that could represent a linear function, we find the slope for two pairs of points.

[tex]\text{Slope}=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}[/tex]

Option A

Using points (-7,3) and (-2,1).

[tex]\text{Slope}=\frac{3-1}{-7-(-2)}=\frac{2}{-7+2}=-\frac{2}{5}[/tex]

Using points (-7,3) and (3,-1).

[tex]\text{Slope}=\frac{3-(-1)}{-7-3}=\frac{4}{-10}=-\frac{2}{5}[/tex]

We see that the slopes are the same.

Therefore, the set of ordered pairs in Option A represent a linear function.

hat is the value of ?The solution is

Answers

l5l - l-5l - (-5)

the absolute value of l5l and l-5l is 5

5 - 5 - (-5)

Subtracting a negative number is the same as adding that number

5 - 5 + 5

5

Answer = 5

4. During a long weekend, Devon paid a total of x dollars for a rental car so he could visit his family. He rented the care for 4 days at a rate of $36 per day. There was an additional charge of $0.20 per mile after the first 200 miles.

a. Write an expression to represent the amount Devon paid for additional mileage.

b. Write an expression to represent the number of miles over 200 miles that Devon drove.

c. How many miles overall did Devon drive overall if he paid $174 for the car rental? Show work.​

Answers

Answer:

A)

c = 0.20m + 144

Where c is total cost and m is miles driven.

B)

c = (200 + 0.20m) + 144

C)

174 = 0.20m + 36x4

174 = 0.20m + 144

30 = 0.20m

30/0.20 = m

m = 150+200

m = 350miles

Hope that helps

a model of a skyscraper is made so that 1 inch represents 75 feet what is the height of the actual building if the height of the model is 20 1/4 inches

Answers

Given the proportional relationship:

1 in = 75 feet

To get feet, of 20 1/4th inches, we have to multiply the inches by 75:

[tex]\begin{gathered} 20\frac{1}{4}\times75 \\ =\frac{81}{4}\times75 \\ =\frac{6075}{4} \\ =1518\frac{3}{4}\text{ fe}et \end{gathered}[/tex]

Note: we converted 20 1/4th to improper fraction, then did the mulitplication.

The answer is:

[tex]1518\frac{3}{4}\text{ feet}[/tex]

Robert has two more than three times the number of cards that Amanda has which expression represents the number of cards that Robert has

Answers

To state the equation that represents the given situation, we take x as the number of cards Amanda has. Three times the number of cards is 3x, two more is +2. It means that the expression that represents this situation is:

[tex]3x+2[/tex]

Evaluate x^3 - 6y + 2 for x = 4 and y= 6.

Answers

The given expression is x^3 - 6y + 2

We are gven x = 4 and y = 6

Substituting the given values into the expression, it becomes

4^3 - 6*6 + 2

= 12 - 36 + 2

= - 22

Write the equation of the circle given the following information

Answers

Given;

There are given that points are:

[tex](1,13)\text{ and \lparen-3,-9\rparen}[/tex]

Explanation:

From the standard form of the circle:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

Where

a and b represent the center.

Now,

To establish the equation, we require to know it is center and radius.

Since we are given the endpoints of the diameter

Then,

The center will be at the midpoint and the radius will be the distance from the center to either of the two given points.

Then,

From the formula of midpoint to calculate the midpoint:

[tex](x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

Then,

From the given two points:

[tex]\begin{gathered} (x,y)=(\frac{1-3}{2},\frac{13-9}{2}) \\ (x,y)=(-\frac{2}{2},\frac{4}{2}) \\ (x,y)=(-1,2) \end{gathered}[/tex]

The midpoint is ( -1, 2).

Now,

We need to find the value of the radius.

So,

To calculate the radius, we need to use the distance formula:

Then,

From the formula of distance, here we will use the points: (-1, 2) and (1, 13)

[tex]\begin{gathered} r=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ r=\sqrt{\left(1+1\right)^2+\left(13-2\right)^2} \\ r=\sqrt{4+121} \\ r=\sqrt{125} \end{gathered}[/tex]

Now,

We have the value of radius and the point of center.

Then,

Put the value of radius and point of the center into the standard form of the circle:

So,

From the standard form of the circle:

[tex]\begin{gathered} (x-a)^{2}+(y-b)^{2}=r^{2} \\ (x-\left(-1\right))^2+(y-2)^2=\lparen\sqrt{125}^)^2 \\ (x+1)^2+(y-2)^2=125 \end{gathered}[/tex]

Final answer:

Hence, the equation of the circle is shown below;

[tex](x+1)^{2}+(y-2)^{2}=125[/tex]

which system of linear equations has the ordered pair (-4,-12)as it's solution?

Answers

In order to find which system has the ordered pair (-4, -12) as a solution, let's check this pair in each system.

We can see that the first two options have the function x = (1/3)y and the last two have the function y = (1/3)x.

Looking at the ordered pair, we have that x is 3 times smaller than y, therefore the correct equation is x = (1/3)y.

Then, the second equation has a constant value for the sum "x + y".

Calculating x + y using the coordinates of the ordered pair, we have a value of -16.

Therefore the correct equation is x + y = -16.

So the option that has the correct system is the second one.

What is the value of x?



4x=5x–12

Answers

Answer:

x=12

Step-by-step explanation:

I just know

Answer: 12

Step-by-step explanation: The value of x is 12
1. subtract 5 from both sides, 4x-5 and 5x-5
2. combine like terms
3. divided by -1
4. you get 12

I tried to do this on my own and I got nine and they said it was incorrect so please help

Answers

Answer:

9u

Explanation:

Given the expression:

[tex]3u(3)[/tex]

First, replace the parenthesis with a multiplication sign.

[tex]\begin{gathered} =3u\times3 \\ =3\times u\times3 \end{gathered}[/tex]

Next, reorder to bring the numbers together.

[tex]\begin{gathered} =3\times3\times u \\ =9u \end{gathered}[/tex]

The simplified form of the expression is 9u.

Identify the values of the variables that complete the table to show the equivalent fractions, decimals, and percents.

Answers

1.2 as a fraction is computed as follows:

[tex]1.2=1.2\cdot\frac{10}{10}=\frac{1.2\cdot10}{10}=\frac{12}{10}=\frac{6}{5}=a[/tex]

Computing 1 divided by 9, we get:

[tex]\frac{1}{9}=0.11111\ldots=b[/tex]

To convert 5/3 to percent, we have to multiply it by 100, as follows:

[tex]\frac{5}{3}\cdot100=\frac{500}{3}=166\frac{2}{3}\text{ \% = c}[/tex]

Refer to the photo that I have posted to much to type

Answers

The total cost of the chocolate cookies is $300

The markup cost on cookies is $135

The total selling price of cookies is $435

The percentage of defective cookies is 15%.

The number of sellable cookies after removing the defective cookie is 170

The price of each cookie is $2.56

What is the total cost?

The total cost of the chocolate cookies is the product of the cost per cookie and the number of cookies produced.

Total cost = cost per cookie x total cookies produced

$1.50 x 200 = $300

The markup cost on cookies can be determined by multiplying the percentage markup by the total cost of cookies

Markup = percentage markup x total cost of cookies

45% x $300

0.45 x $300 = $135

The total selling price of cookies is the sum of the markup on cost and the total cost of producing the cookies

Total selling price = $135 + $300 = $435

Number of sellable cookies after removing the defective cookies = (1 - percentage of defective cookies) x number of cookies produced

200 x (1 - 0.15)

200 x 0.85 = 170

Price of each cookie = total cost after markup / total number of sellable cookies

435 / 170 = $2.56

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all you need is in the photo please answer all the 3 questions

Answers

a) y =2^x

b) Exponential

c)

a) According to that graph, we have point (1,2) and (2,4) since that exponential function is

[tex]\begin{gathered} y=a(b)^x \\ 1=a(b)^0\rightarrow a\text{ =1} \\ 4=ab^2\text{ }\rightarrow4\text{ =}b^2\rightarrow\text{ }b=2 \\ y=2^x \end{gathered}[/tex]

Since the function is increasing, due to its direction, we can write y =2^x

b)The type of function is exponential, since x= 0, y = 1, and due to its shape.

3) As we can see the shape of the graph is curve,

Which of the following symbol will make a true sentence when inserted in the blank?
5/7___0.6

a. <
b. >
C. =

Answers

Answer:

b: >

Step-by-step explanation:

We know that 4/6 = 2/3 = 0.6667

This is bigger than 0.6.

Since 5/7 > 4/6, we directly see that 5/7 > 0.6

In fact, 5/7 is approximately 0.714 which tells us that we have found the correct answer

Added: A better method might be: 5/7 = 10*5 / (7 * 10) = 50/70,

where 0.6 = 6/10 = 6*7/(10*7) = 42 / 70.

Since 50/70 > 42/70, it follows that 5/7 > 0.6 so B is the right answer

option b. > is correct

triangle p undergoes a sequence of tranformations resultig in triangle Q which sequence of transformations could be used to show that triangle Q is similar but not congruent to triangle p

Answers

The most appropriate choice for Similar and congruent triangles will be given by

Third Option dilation is correct.

What are Similar and congruent triangles?

Two triangles are similar if their angles are equal but their sides are proportional

The different axioms of similarity are SAS, SSS, AA

Two triangles are congruent if their sides and angles are both equal

The different axioms of congruency are ASA, SAS, AAS, RHS, SSS

Here, A stands for angle, S stands for side R stands for right angle, H stands for hypotenuse.

Here,

Two Similar triangle means corrosponding sides are proportional and two congruent triangle means corrosponding sides and angles and angles are same

The triangle after rotation and reflection do not change any length of side or angle. So the triangles will be same after reflection or rotation. So congruency will not be disturbed here.

Now, in case of dilation, length of each side will change but in same proportion.

So dilation can make two similar triangles but not congruent triangles

So third option is correct.

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Complete Question

Triangle P undergoes a sequence of tranformations resultig in triangle Q which sequence of transformations could be used to show that triangle Q is similar but not congruent to triangle P

a) Rotation

b) Reflection

c) Dilation

d) Any of these could be the transformation

Put the following equation of a line into slope-intercept form, simplifying all
fractions.
2x - 3y = 18

Answers

Answer:

y = (2/3)x - 6

Step-by-step explanation:

Slope-intercept form is:

y = mx + b

Convert the given equation as following:

2x - 3y = 18                  Isolate the term with y3y = 2x - 18                  Divide all terms by 3y = (2/3)x - 6

Multiply. State any excluded values. Simplify your answer. Type your answer in factored form.

Answers

Multiplication:

[tex]\frac{f(x)}{g(x)}\cdot\frac{h(x)}{j(x)}=\frac{f(x)h(x)}{g(x)j(x)}[/tex]

For the given functions:

[tex]\begin{gathered} \frac{x}{x-7}\cdot\frac{x-2}{x-3}=\frac{x(x-2)}{(x-7)(x-3)} \\ \end{gathered}[/tex]

The expression cannot be simplified and is already written in factored form.

The exclude values are those that make the denominator be equal to zero: 7,3

[tex]\begin{gathered} (x-7)(x-3)=0 \\ \\ x-7=0 \\ z=7 \\ \\ x-3=0 \\ x=3 \end{gathered}[/tex]

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