Answer:
Arsenic (As)
Explanation:
Arsenic is the only answer choice that has five valence electrons like the electron dot structure shows.
Answer:
Arsenic (As)
Explanation:
1) 1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the centripetal force acting on the car? *
1 point
1 N
100 N
1000 N
10000 N
2) 1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the acceleration of the car? *
1 point
0.1 m/s^2
1 m/s^2
10 m/s^2
100 m/s^2
Answer:
(1) 1000 N (2) 1 m/s²
Explanation:
(1) Given that,
The mass of a car, m = 1000 kg
Radius of a circular track, r = 100 m
Speed of the car, v = 10 m/s
We need to find the magnitude of the centripetal force acting on the car. The magnitude of the centripetal force is given by :
[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{1000\times (10)^2}{100}\\\\F=1000\ N[/tex]
So, the correct option is (c) i.e. 1000 N
(2).The mass of a car, m = 1000 kg
Radius of a circular track, r = 100 m
Speed of the car, v = 10 m/s
We need to find the magnitude of the centripetal acceleration of the car. The magnitude of the centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(10)^2}{100}\\\\a=1\ m/s^2[/tex]
So, the correct option is (b) i.e. [tex]1\ m/s^2[/tex]
Is Natural Gas nonrenewable or renewable? Why? Use in your own words.
Answer:
Natural gas is non renewable energy.
Explanation:
Because they were formed from the buried reamains of plants and animals that live a million years ago. It is formed from fossil fuels.
Which describes the genetic disorder that causes neurons in the brain to break down? scribes the genetic disorder that causes neurons in the brain to break down need help will mark brainliest
Genetic disorders and Parkinson's disease.
An oscilloscope is set on a TIME/DIV setting of 50 ms. There are 10 divisions on the time scale. A sinewave on the oscilloscope display has exactly three full cycles of the sine wave that fit on the 10 divisions. What is the frequency of the wave?
Answer:
f= 6 Hz
Explanation:
Since the TIME/DIV setting is set to 50 ms, and there 10 divisions on the time scale, that means that full scale display is 500 msec.If a sinewave has exactly three full cycles of the sine wave that fit on the 10 div, this means that one cycle is just one-third of the 10 div value, as follows:[tex]T = \frac{500 msec}{3} = 166.7 msec (1)[/tex]
Since the frequency of a wave is just the number of cycles per unit time, can be written as follows:F = 1/T = 1/(166.7 msec) = 6 HzA ball is launched from a 300m cliff and lands 380m away from the cliff in 9 seconds. Calculate the initual speed and the angle of the ball when it was launched.
Answer:
Explanation:
Given
Maximum height H = 300m
Range (horizontal distance) = 380m
Required
Initial speed U and the angle of the ball when it was launched.
Range = U√2H/g
380 = U√2(300)/9.8
380 = U√600/9.8
380 = 7.8246U
U = 380/7.8246
U = 48.57m/s
The initial speed is 48.57m/s
b) Using the formula for calculating time of flight;
T = 2Usin theta/g
9 = 2(48.57)sin theta/9.8
9*9.8 = 97.14sin theta
88.2 = 97.14sin theta
88.2/97.14 = sin theta
sin theta = 0.9079
theta = sin^-1(0.9079)
theta = 65.23°
hence the angle when the ball was launched is 65.23°
A wave has a period 2.00 s, an amplitude 20.0 cm, and a wavelength 3.00 m. What is the speed of the wave?
a. 10.0 cm/s
b. 0.100 cm/s
c. 340 m/s
d. 0.667 m/s
e. 1.50 m/s
Answer:
a)
Explanation:
because if in 2 seconds have 20.0 cm/2s cm in 1 second have 10.0 cm/s
Light from two lasers is incident on an opaque barrier with a single slit of width 4.0 x 10-5 m. One laser emits light of wavelength 4.0 x 10-7 m and the other is 6.0 x 10-7 m. A screen to view the light intensity pattern is 2.0 m behind the barrier. What is the distance from the center of the pattern to the nearest completely dark spot (dark for both colors)?
Answer:
y = 6 10⁻² m
Explanation:
This is a diffraction exercise which is described by the expression
a sin θ = m λ
we can use trigonometry to find the distance from the inside of the screen to the dark point (y)
tan θ = y / L
angles are very small in diffraction experiments, so we can approximate
tan θ = sin θ /cos θ = sin θ
sin θ = y / L
substituting
a (y / L) = m λ
Let's find the points where the intensity becomes zero
y = m L λ / a
λ₁ = 4.0 10⁻⁷ m
m = 1
y = 1 2.0 4.0 10⁻⁷/ 4.0 10⁻⁵
y = 2 10⁻² m
m = 2
y = 4 10⁻² m
λ₂ = 6.0 10⁻⁷ m
m = 1
y = 1 2.0 6.0 10⁻⁷ / 4.0 10⁻⁵
y = 3 10⁻² m
m = 2
y = 6 10⁻² m
if we want a point where the two colors are dark, we set the two expressions equal
y₁ = y₂
m₁ L λ₁ / a = m₂ L λ₂ / a
m₁/m₂ = λ₂/λ₁
m₁ / m₂ = 6 10⁻⁷ / 4 10⁻⁷
m₁ / m₂ = 1.5
since the quantities m must be integers, the smallest relation that the relation fulfills is
m₁ = 3
m₂ = 2
the distance for this destructive interference is
y = 3 2 4.0 10⁻⁷ / 4.0 10⁻⁵
y = 6 10⁻² m
this is the first point where the minimum of the two wavelengths coincide
10- The coefficient of volumetric expansion for gold is 4.20 x 10°/C°. The density of gold is
19 300 kg/m at 0.0 °C. What is the density of gold at 1050 °C?
(a) 20 200 kg/m
(b) 19 000 kg/m
(c) 18 500 kg/m
(d) 19 300 kg/m
(e) 18 800 kg/m
Answer:
ρ = 19215 kg / m³ , the answer the correct is D
Explanation:
All materials are sold when heated, in first approximation
ΔV = β V₀ (T -T₀)
for this case
ΔV = 4.20 10⁻⁶ Vo (1050 - 0)
ΔV = 4.41 10⁻³ Vo m³
V-Vo = 4.41 10⁻³ Vo
V = 1.00441 Vo
density is defined by
ρ = m / V
a T = 0ºc
ρ₀ = m / Vo
aT= 1050ºC
ρ = m / V
ρ = m / (1,00441 Vo)
ρ = 1 / 1.00441 m/Vo
ρ = 0.9956 ρ₀
ρ = 0.9956 19300
ρ = 19215 kg / m³
when checking the answers the correct one is D
Why is the metric system used globally, but we use the US customary units?
Answer:
The biggest reasons the U.S. hasn't adopted the metric system are simply time and money. When the Industrial Revolution began in the country, expensive manufacturing plants became a main source of American jobs and consumer products.
Explanation:
HELP THIS IS DUE IN 5 MINUTES!!!!!!!!!!!! WILL GIVE BRAINLIEST
what is the definition of total velocity?
Answer:
Image result for total velocity definition
The average speed of an object is defined as the distance traveled divided by the time elapsed.
Explanation:
A rollercoaster moves from the bottom of a hill and approaches the top of the hill. If friction between the wheels and the track is ignored, which statement describes the components of the total energy?
*answer choices pic attached*
{If anyone has the answers to the Energy Flows Quick Check or others please let me know}.
Answer:
The kinetic energy remains same and gravitational potential energy increases.
Explanation:
KINETIC ENERGY:
As, we know that the kinetic energy depends upon the speed of the object. Hence, the kinetic energy is given as:
K.E = (1/2)mv²
where,
m = mass
v = speed
K.E = Kinetic Energy
Since, the friction is ignored, therefore the speed of roller coaster will remain same.
Therefore, its Kinetic Energy will also remain same.
POTENTIAL ENERGY:
The potetial energy od a body depends upon its height, as follows:
P.E = mgh
where,
P.E = potential Energy
m = mass
g = acceleration due to gravity
h = height
As, the roller coaster moves up hill its height increases.
Therefore, its potential energy will also increase.
hence, the correct option is:
The kinetic energy remains same and gravitational potential energy increases.
You are explaining to friends why astronauts feel weightless orbiting in the space shuttle, and they respond that they thought gravity was just a lot weaker up there. Convince them and yourself that it isn't so by calculating how much weaker gravity is 200 above the Earth's surface.
Delta G/G = ? %
Answer:
The gravity is 87.4% as strong as at the Earth’s surface.
Explanation:
Hope this helped!
If the total mechanical energy of the block spring system is 512 J, what is the amplitude for this oscillation?
Answer:
A = 2.26 m
Explanation:
Given that,
The total mechanical energy of the block spring system is 512 J
Let the spring constant, k = 200 N/m
We need to find the amplitude for this oscillation. The mechanical energy of the spring mass system is given by :
[tex]E=\dfrac{1}{2}kA^2[/tex]
k is spring constant
[tex]A=\sqrt{\dfrac{2E}{k}} \\\\A=\sqrt{\dfrac{2\times 512}{200}} \\A=2.26\ m[/tex]
So, the amplitude of the oscillation is 2.26 m
Erma built the simple motor shown below with a battery, a permanent magnet, a copper coil of wire, and an iron bar. When the motor is turned on, the iron bar and coil spin in a circle The motor transforms _______ energy into _______ energy. Question 27 options: mechanical; chemical electrical; mechanical mechanical; electrical thermal; electrical
Answer:
electrical to mechanical
Explanation:
Suppose you put an ice cube into a cup of hot tea. In what direction does energy in the form of heat flow? What happens to the ice cube as this flow of energy occurs?
Answer:
The energy flows between the ice and the tea equally. The table below shows the temperatures of several different objects made of the same material.
A step-down transformer converts 120 V to 5 V in a phone charger. If the primary coil has 600 turns, how many turns are in the secondary coil? Show all work with correct answer and unit as well.
Answer:
25 turns
Explanation:
Given the following data;
Input voltage = 120V
Output voltage = 5V
Number of turns in primary coil = 600 turns
[tex] \frac {Ns}{Np} = \frac {Vs}{Vp} [/tex]
Where;
Ns is the number of turns on the secondary coil. Np is the number of turns on the primary coil. Vs is the voltage across the secondary coil (output voltage). Vp is the voltage across the primary coil (input voltage).Substituting into the equation, we have;
[tex] \frac {Ns}{600} = \frac {5}{120} [/tex]
Cross-multiplying, we have;
[tex] 120*Ns = 600*5[/tex]
[tex] 120Ns = 3000[/tex]
[tex] Ns = \frac {3000}{120}[/tex]
Ns = 25 turns
Therefore, the number of turns in the secondary coil is 25 turns.
Hence, it is a step-down transformer because the number of turns on the primary coil is greater than the number of turns on the secondary coil. Consequently, the output voltage (5V) will be lesser than the input voltage (120V).
A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, what is its velocity as it leaves his hand?
Answer:
25.82 m/s
Explanation:
We are given;
Force exerted by baseball player; F = 100 N
Distance covered by ball; d = 0.5 m
Mass of ball; m = 0.15 kg
Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.
We should note that work done is a measure of the energy exerted by the baseball player.
Thus;
F × d = ½mv²
100 × 0.5 = ½ × 0.15 × v²
v² = (2 × 100 × 0.5)/0.15
v² = 666.67
v = √666.67
v = 25.82 m/s
This question involves the concepts of the law of conservation of energy and kinetic energy.
The baseball leaves the hand with a velocity of "25.82 m/s".
From the law of conservation of energy the work done on the ball must be equal to the kinetic energy of the ball:
[tex]W=K.E\\\\Fd=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{2Fd}{m}}\\\\v=\sqrt{\frac{2(100\ N)(0.5\ m)}{0.15\ kg}}[/tex]
where,
F = force applied = 100 N
d = displacement of ball = 0.5 m
m = mass of ball = 0.15 kg
v = 25.82 m/s
Learn more about the law of conservation of energy here:
brainly.com/question/20971995?referrer=searchResults
The attached picture explains the law of conservation of energy.
What would happen if there is more male hyenas than female hyenas in a population?
Choices:
Male hyenas will compete to mate with the females.
Some male hyenas will die.
Male hyenas for wait for more females to join the population.
Answer:
Option 1
Explanation:
I always see animals do that
A current-carrying wire passes through a region of space that has a uniform magnetic field of 0.96 T. If the wire has a length of 2.7 m and a mass of 0.79 kg, determine the minimum current needed to levitate the wire.
Answer:
I = 2.99 A
Explanation:
magnetic field, B = 0.96 T, length of wire, l = 2.7 m, mass of wire, m = 0.79 kg.
Since it is expected that the wire would vibrate or move in the magnetic field, from Newton's second law of motion;
F = mg
where F is the force on the wire, m is the mass of the wire and g is the acceleration due to gravity.
But,
F = BIL
⇒ BIL = mg
0.96 x I x 2.7 = 0.79 x 9.8
2.592I = 7.742
I = [tex]\frac{7.742}{2.592}[/tex]
= 2.9869
I = 2.99 A
The required minimum current is 2.99 A.
A sample of gas, initially with a volume of 1.0 L, undergoes a thermodynamic cycle. Find the work done by the gas on its environment during each stage of the cycle described below. (Enter your answers in J.)
Answer:
(a) W₁ = 3293.06 J = 3.293 KJ
(b) W₂ = 0 J
(c) W₃ = - 506.625 J = - 0.506 KJ
(d) W₄ = 0 J
(e) W = 2786.435 J = 2.786 KJ
Explanation:
The complete question has following parts:
(a) First gas expands from a volume of 1 L to 6 L at a constant pressure of 6.5 atm
(b) Second, the gas is cooled at constant volume until the pressure falls to 1 atm
(c) Third, the gas is compressed at a constant pressure of 1 atm from a volume of 6 L to 1 L.
(d) Finally the gas is heated until its pressure from 1 atm to 6.5 atm at constant volume
(e) what is the net work?
ANSWERS:
(a)
The work done by a gas at constant pressure is given as follows:
W = PΔV
where,
W = Work done by the gas
P = Constant Pressure of the Gas
ΔV = Change in Volume of The gas
Therefore, for the first step:
P = P₁ = (6.5 atm)(1.01325 x 10⁵ Pa/1 atm) = 6.58613 x 10⁵ Pa
ΔV = ΔV₁ = 6 L - 1 L = (5 L)(0.001 m³/1 L) = 5 x 10⁻³ m³
W = W₁
Therefore,
W₁ = (6.58613 x 10⁵ Pa)(5 x 10⁻³ m³)
W₁ = 3293.06 J = 3.293 KJ
(b)
The work done at a constant volume by a gas is always zero due to no change in volume:
W₂ = P₂ΔV₂
W₂ = P₂(0)
W₂ = 0 J
(c)
For the third step:
P = P₃ = (1 atm) = 1.01325 x 10⁵ Pa
ΔV = ΔV₃ = 1 L - 6 L = (- 5 L)(0.001 m³/1 L) = - 5 x 10⁻³ m³
W = W₃
Therefore,
W₃ = (1.01325 x 10⁵ Pa)(-5 x 10⁻³ m³)
W₃ = - 506.625 J = - 0.506 KJ
(d)
The work done at a constant volume by a gas is always zero due to no change in volume:
W₄ = P₄ΔV₄
W₄ = P₄(0)
W₄ = 0 J
(e)
Hence, the net work is given as follows:
W = W₁ + W₂ + W₃ + W₄
W = 3293.06 J + 0 J + (- 506.625 J) + 0 J
W = 2786.435 J = 2.786 KJ
If Earth’s Moon were replaced with a typical neutron star, what would the angular diameter of the neutron star be as seen from Earth?
Answer:
[tex]0.00005202\ \text{rad}=0.003^{\circ}[/tex]
Explanation:
d = Diameter of typical neutron star = 20 km = 20000 m
D = Distance between Earth and Moon = [tex]384.4\times 10^6\ \text{m}[/tex]
Here, [tex]D>>d[/tex] so we use small angle approximation
[tex]\delta=\dfrac{d}{D}\\\Rightarrow \delta=\dfrac{20000}{384.4\times 10^6}\\\Rightarrow \delta=0.00005202\ \text{rad}=\dfrac{0.00005202\times 180}{\pi}=0.003^{\circ}[/tex]
The angular diameter of the neutron star would be [tex]0.00005202\ \text{rad}=0.003^{\circ}[/tex] from Earth.
7. It is the art of drawing solid objects on two-dimensional surfaces.
Explanation:
Perspective- the art of drawing solid objects on a two-dimensional surface so as to give the right impression of their height, width, depth, and position in relation to each other when viewed from a particular point.
Three moles of a monatomic ideal gas are heated at a constant volume of 1.20 m3. The amount of heat added is 5.22x10^3 J.(a) What is the change in the temperature of the gas?________ ? K(b) Find the change in its internal energy.________ ? J(c) Determine the change in pressure.________ ? Pa
Answer:
A) 140 k
b ) 5.22 *10^3 J
c) 2910 Pa
Explanation:
Volume of Monatomic ideal gas = 1.20 m^3
heat added ( Q ) = 5.22*10^3 J
number of moles (n) = 3
A ) calculate the change in temp of the gas
since the volume of gas is constant no work is said to be done
heat capacity of an Ideal monoatomic gas ( Q ) = n.(3/2).RΔT
make ΔT subject of the equation
ΔT = Q / n.(3/2).R
= (5.22*10^3 ) / 3( 3/2 ) * (8.3144 J/mol.k )
= 140 K
B) Calculate the change in its internal energy
ΔU = Q this is because no work is done
therefore the change in internal energy = 5.22 * 10^3 J
C ) calculate the change in pressure
applying ideal gas equation
P = nRT/V
therefore ; Δ P = ( n*R*ΔT/V )
= ( 3 * 8.3144 * 140 ) / 1.20
= 2910 Pa
A) The change in the temperature of the gas is; ΔT = 139.5 K
B) The change in internal energy of the gas is; ΔU = 5.22 × 10³ J
C) The change in pressure of the gas is; ΔP = 2899.5 Pa
We are given;
Volume of Monatomic ideal gas; V = 1.2 m³
Amount of heat added; Q = 5.22 × 10³ J
number of moles; n = 3
A) To calculate the change in temperature of the monatomic idea gas, we will use formula;
Q = ³/₂nRΔT
Where R is a constant = 8.314 J/mol.K
ΔT is the change in temperature
Making ΔT the subject of the formula;
ΔT = ²/₃(Q/(nR))
ΔT = ²/₃(5.22 × 10³)/(3 × 8.314)
ΔT = 139.5 K
B) Due to the fact that no work was done, then from first law of thermodynamics, we can say that;
ΔU = Q
Thus;
change in internal energy; ΔU = 5.22 × 10³ J
C) The change in pressure will be calculated from the formula;
ΔP = (n*R*ΔT)/V
ΔP = (3 * 8.314 * 139.5)/1.2
ΔP = 2899.5 Pa
Read more at; https://brainly.com/question/14122248
what happens to the strength of an electromagnet when the voltage in the coils of the solenoid is decreased
Answer:
Make sure you look at the wording!
Explanation:
if the last word is increased, the answer is increased
if the last word is decreased, the answer is it decreases!
Assume a hockey player accelerates from 0 ft/s to 24 ft/s over a period of 2
seconds. What is his acceleration if his direction does not change? Explain in
words what this acceleration means.
Answer:
12ft/s or 4m/s
Explanation:
Temporary Wind Turbines-
Answer:
lol what
Explanation:
A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist’s acceleration?
Answer:
[tex]\boxed {\boxed {\sf a\approx -0.08 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The final velocity is 3 meters per second. The initial velocity is 8 meters per second.
We need to convert the time to seconds.
t= 1 minute 60 seconds = 1 minute t=60 secondsSo, we know that:
[tex]v_f=3 \ m/s \\v_i= 8 \ m/s\\t= 60 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{3 \ m/s - 8 \ m/s}{60 \ s}[/tex]
Solve the numerator.
3 m/s - 8 m/s = -5 m/s[tex]a=\frac{-5 \ m/s}{60 \ s}[/tex]
Divide.
[tex]a=-0.0833333333 \ m/s/s[/tex]
Let's round to the nearest hundredth.
The 3 in the thousandth place tells us to leave the 8 in the hundredth place.
[tex]a\approx -0.08 \ m/s^2[/tex]
The cyclist's acceleration is about [tex]\boxed {-0.08 m/s^2}[/tex]
Which temperature is warmer than the freezing point of water?
O A. OK
O B. 33K
O C. 1°C
O D.O°F
Answer:
C 1 degree
Explanation:
Please answer my question
Answer:
Answer is (b) Mercury, venus and Mars.
Explanation:
i think b is correct!!
;-) :-) :-) :-)
You are hanging on to the edge of a merry-go-round, and must exert a force of 100 N to hang on. If the speed of the merry-go-round doubles, how much force will you need to exert to hang on?
Answer:
If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.
Explanation:
Given;
initial force exerted to hang on, F₁ = 100 N
The force exerted on the merry-go-round in order to hang on must be an inward force known as centripetal force.
Centripetal force is given by;
[tex]F_c = \frac{mv^2}{r} \\\\keeping \ "m" \ and \ "r" \ constant, we \ will \ have \ the \ following \ equation;\\\\\frac{F_c_1}{v_1^2} = \frac{F_c_2}{v_2^2} \\\\F_c_2 = \frac{F_c_1*v_2^2}{v_1^2}\\\\when \ the \ speed\ doubles \ i.e, v_2 = 2v_1\\\\ F_c_2 = \frac{F_c_1*(2v_1)^2}{v_1^2}\\\\ F_c_2 = \frac{F_c_1*4v_1^2}{v_1^2}\\\\F_c_2 = F_c_1 *4\\\\F_c_2 = 4(F_c_1)\\\\F_c_2 = 4 (100 \ N)\\\\F_c_2 = 400 \ N[/tex]
Therefore, If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.