The diagram shows the curve y = √8x + 1 and the tangent at the point P(3, 5) on the curve. The tangent meets the y-axis at A. Find:
(i) The equation of the tangent at P.
(ii) The coordinates of A.
(iii) The equation of the normal at P.
Answers
The tangent and normal lines of the curve:
Case (i): y = (4 / 5) · x + 13 / 5
Case (ii): (x, y) = (0, 13 / 5)
Case (iii): y = - (5 / 4) · x + 35 / 4
How to determine the equations of the tangent and normal lines
In this problem we have the representation of a curve whose equations for tangent and normal lines must be found. Lines are expressions of the form:
y = m · x + b
Where:
m - Slopeb - Interceptx - Independent variable.y - Dependent variable.Both tangent and normal lines are perpendicular, the relationship between the slopes of the two perpendicular lines is:
m · m' = - 1
Where:
m - Slope of the tangent line.m' - Slope of the normal line.The slope of the tangent line is found by evaluating the first derivative of the curve at intersection point.
Case (i) - First, determine the slope of the tangent line:
y = √(8 · x + 1)
y' = 4 / √(8 · x + 1)
y' = 4 / √25
y' = 4 / 5
Second, determine the intercept of the tangent line:
b = y - m · x
b = 5 - (4 / 5) · 3
b = 5 - 12 / 5
b = 13 / 5
Third, write the equation of the tangent line:
y = (4 / 5) · x + 13 / 5
Case (ii) - Find the coordinates of the intercept of the tangent line:
(x, y) = (0, 13 / 5)
Case (iii) - First, find the slope of the normal line:
m' = - 1 / (4 / 5)
m' = - 5 / 4
Second, determine the intercept of the normal line:
b = y - m' · x
b = 5 - (- 5 / 4) · 3
b = 5 + 15 / 4
b = 35 / 4
Third, write the equation of the normal line:
y = - (5 / 4) · x + 35 / 4
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Related Questions
Pls help I beg thank you
Answers
Answer:
8cm
Step-by-step explanation:
perimiter A = 11+11+4+4=30
perimiter B = 4+4+8+8=24
24+30=54
perimeter c =4+8+8+4+11+7+4=46
so perimiter of c is 8cm shorter than A and B total
hope this helps
measure abc bac=40degree abc=20degree ab=7cm
Answers
The length of side BC is approximately 3.725 cm.
In triangle ABC, we are given that angle BAC is 40 degrees, angle ABC is 20 degrees, and side AB measures 7 cm. We need to find the length of side BC.
To solve this problem, we can use the law of sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides.
Applying the law of sines, we have:
sin(ABC) / BC = sin(BAC) / AB
Since sin(ABC) = sin(20 degrees) and sin(BAC) = sin(40 degrees), we can substitute these values into the equation:
sin(20 degrees) / BC = sin(40 degrees) / 7 cm
Now, we can rearrange the equation to solve for BC:
BC = (7 cm * sin(20 degrees)) / sin(40 degrees)
Using a calculator to evaluate the trigonometric functions, we find that sin(20 degrees) ≈ 0.3420 and sin(40 degrees) ≈ 0.6428. Substituting these values into the equation:
BC ≈ (7 cm * 0.3420) / 0.6428
BC ≈ 3.725 cm
Therefore, the length of side BC is approximately 3.725 cm.
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Evaluate. -15 +7-(-8)
The answer options are
16
0
-16
-3
Answers
Answer:
To evaluate -15 + 7 - (-8), we can simplify the expression by first removing the double negative.
-15 + 7 + 8 = 0
Therefore, the answer is 0.
Step-by-step explanation:
The answer is:
0Work/explanation:
Remember the integer rule,
[tex]\bullet\phantom{4444}\sf{a-(-b)=a+b}[/tex]
Similarly
[tex]\sf{-15+7-(-8)}[/tex]
[tex]\sf{-15+15}[/tex]
Simplify fully.
[tex]\sf{0}[/tex]
Therefore, the answer is 0.Find the local and absolute maximum and minimum points in (x, y) format for the
function f(x) = 3/5x^5 - 9x^3 + 2 on the closed interval [-4,5]. Answer the following
questions.
a) Find all critical numbers (x- coordinates only)
b) Find the intervals on which the graph is increasing Mark critical numbers
c) Find the intervals on which the graph is decreasing.
d) Find all local maximum points.
e) Find all local minimum points.
f) Find all absolute maximum points.
g) Find all absolute minimum points.
Answers
To find the local and absolute maximum and minimum points of the function f(x) = (3/5)x^5 - 9x^3 + 2 on the closed interval [-4,5], we need to follow these steps:
a) Find all critical numbers (x-coordinates only):
To find the critical numbers, we need to identify where the derivative of the function is zero or undefined. Let's find the derivative of f(x) first:
f'(x) = 3x^4 - 27x^2
Now, set the derivative equal to zero and solve for x:
3x^4 - 27x^2 = 0
Factoring out a common factor of 3x^2, we get:
3x^2(x^2 - 9) = 0
This equation is satisfied when either 3x^2 = 0 or x^2 - 9 = 0.
For 3x^2 = 0, we have x = 0.
For x^2 - 9 = 0, we have x = -3 and x = 3.
Therefore, the critical numbers (x-coordinates) are 0, -3, and 3.
b) Find the intervals on which the graph is increasing (mark critical numbers):
To determine the intervals of increasing, we need to analyze the sign of the derivative on each side of the critical numbers. We create a sign chart for f'(x):
Interval (-∞, -3): Choose a test point x < -3, e.g., x = -4
f'(-4) = 3(-4)^4 - 27(-4)^2 = 768 > 0
The derivative is positive, indicating the graph is increasing.
Interval (-3, 0): Choose a test point x between -3 and 0, e.g., x = -1
f'(-1) = 3(-1)^4 - 27(-1)^2 = -24 < 0
The derivative is negative, indicating the graph is decreasing.
Interval (0, 3): Choose a test point x between 0 and 3, e.g., x = 1
f'(1) = 3(1)^4 - 27(1)^2 = -24 < 0
The derivative is negative, indicating the graph is decreasing.
Interval (3, ∞): Choose a test point x > 3, e.g., x = 4
f'(4) = 3(4)^4 - 27(4)^2 = 768 > 0
The derivative is positive, indicating the graph is increasing.
Therefore, the graph is increasing on the intervals (-∞, -3) and (3, ∞).
c) Find the intervals on which the graph is decreasing (mark critical numbers):
From the analysis above, we can see that the graph is decreasing on the intervals (-3, 0) and (0, 3).
d) Find all local maximum points:
To find the local maximum points, we need to examine the points where the graph changes from increasing to decreasing. By observing the sign changes in the derivative, we can identify potential local maximum points.
From our analysis in part b, we can see that the graph changes from increasing to decreasing at x = -3 and x = 0. Therefore, these are the local maximum points.
e) Find all local minimum points:
To find the local minimum points, we need to examine the points where the graph changes from decreasing to increasing. By observing the sign changes in the derivative, we can identify potential local minimum points.
From our analysis in part c, we can see that the graph changes.
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On her breakfast tray, Aunt Lily had a little vase of flowers - a mixture of primroses and celandines. She counted up the petals and found there were 39. "Oh, how lovely!" she said, "exactly my age; and the total number of flowers is exactly your age, Rose!" How old is Rose?
(NB: Primroses have five petals on each flower and Celandines have eight petals on each flower). Please show working
Answers
Rose's age should be a whole number, we can round 7.8 to the nearest whole number, which is 8.
Let's assume the number of primroses in the vase is p, and the number of celandines is c.
Each primrose has 5 petals, so the total number of primrose petals is 5p.
Each celandine has 8 petals, so the total number of celandine petals is 8c.
According to the given information, the total number of petals is 39. Therefore, we can set up the equation:
5p + 8c = 39 (Equation 1)
Aunt Lily mentions that the total number of flowers is exactly Rose's age. Since Rose's age is not provided, we'll represent it with the variable r.
The total number of flowers is p + c, which is also equal to Rose's age (r). Therefore, we have another equation:
p + c = r (Equation 2)
We need to find the value of r (Rose's age). To do that, we'll solve the system of equations by eliminating one variable.
Multiplying Equation 2 by 5, we get:
5p + 5c = 5r (Equation 3)
Now we can subtract Equation 1 from Equation 3 to eliminate the p term:
(5p + 5c) - (5p + 8c) = 5r - 39
This simplifies to:
-3c = 5r - 39
Now, let's rearrange Equation 2 to solve for p:
p = r - c (Equation 4)
Substituting Equation 4 into the simplified form of Equation 3, we have:
-3c = 5r - 39
Substituting r - c for p, we get:
-3c = 5(r - c) - 39
Expanding, we have:
-3c = 5r - 5c - 39
Rearranging the terms, we get:
2c = 5r - 39
Now we have a system of two equations:
-3c = 5r - 39 (Equation 5)
2c = 5r - 39 (Equation 6)
To solve this system, we can eliminate one variable by multiplying Equation 5 by 2 and Equation 6 by 3:
-6c = 10r - 78 (Equation 7)
6c = 15r - 117 (Equation 8)
Now, let's add Equation 7 and Equation 8 to eliminate c:
-6c + 6c = 10r + 15r - 78 - 117
This simplifies to:
25r = 195
Dividing both sides by 25, we get:
r = 7.8
Since Rose's age should be a whole number, we can round 7.8 to the nearest whole number, which is 8.
Therefore, Rose is 8 years old.
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21. Determine whether CD || AB. Explain your reasoning.
Answers
Reason:
If CD was parallel to AB, then triangles CDE and ABE would be similar. In turn it would mean that EA/EC = EB/ED is a true proportion.
Let's calculate each side separately.
EA/EC = 28/(28+20) = 0.5833EB/ED = 16/(16+10) = 0.6154Both decimal values are approximate.
The two values don't match up which makes EA/EC = EB/ED to be false.
Since EA/EC = EB/ED is false, we know that triangles CDE and ABE are not similar. Therefore, CD is not parallel to AB.
Answer:
CD is not parallel to AB
Step-by-step explanation:
According to the Side Splitter Theorem, if a line parallel to one side of a triangle intersects the other two sides, then this line divides those two sides proportionally.
Therefore, if CD is parallel to AB, then EA : AC = EB : BD.
Substitute the values of the line segments into the equation:
[tex]\begin{aligned}EA : AC &= EB : BD\\\\28:20&=16:10\\\\\dfrac{28}{20}&=\dfrac{16}{10}\\\\1.4 &\neq 1.6\end{aligned}[/tex]
As 1.4 does not equal 1.6, then CD is not parallel to AB.
A 52-card deck contains 13 cards from each of the four suits: clubs ♣, diamonds ♦, hearts ♥, and spades ♠. You deal four cards without replacement from a well-shuffled deck so that you are equally likely to deal any four cards.
What is the probability that all four cards are clubs?
13/52 ⋅ 12/51 ⋅ 11/50 ⋅ 10/49 ≈0.0026
13/52 ⋅ 12/52 ⋅ 11/52 ⋅ 10/52 ≈0.0023
1/4 because 1/4 of the cards are clubs
Answers
The probability that all four cards are clubs is approximately 0.0026. Option A.
To understand why, let's break down the calculation. In a well-shuffled deck, there are 13 clubs out of 52 cards.
When dealing the first card, there are 13 clubs out of the total 52 cards, so the probability of getting a club on the first draw is 13/52.
For the second card, after the first club has been removed from the deck, there are now 12 clubs left out of the remaining 51 cards. Therefore, the probability of getting a club on the second draw is 12/51.
Similarly, for the third card, after two clubs have been removed, there are 11 clubs left out of the remaining 50 cards. The probability of drawing a club on the third draw is 11/50.
Finally, for the fourth card, after three clubs have been removed, there are 10 clubs left out of the remaining 49 cards. The probability of drawing a club on the fourth draw is 10/49.
To find the probability of all four cards being clubs, we multiply the probabilities of each individual draw:
(13/52) * (12/51) * (11/50) * (10/49) ≈ 0.0026.
This calculation takes into account the fact that the deck is being dealt without replacement, meaning that the number of available clubs decreases with each draw.
The third option, 1/4, is incorrect because it assumes that each card dealt is independent and has an equal probability of being a club. However, as cards are drawn without replacement, the probability changes with each draw. So Option A is correct.
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Note the complete question is
A 52-card deck contains 13 cards from each of the four suits: clubs ♣, diamonds ♦, hearts ♥, and spades ♠. You deal four cards without replacement from a well-shuffled deck so that you are equally likely to deal any four cards.
What is the probability that all four cards are clubs?
A.) 13/52 ⋅ 12/51 ⋅ 11/50 ⋅ 10/49 ≈0.0026
B.) 13/52 ⋅ 12/52 ⋅ 11/52 ⋅ 10/52 ≈0.0023
C.) 1/4 because 1/4 of the cards are clubs
Which of the following is equal to the fraction below? (7/4)11
Answers
Answer:
It's A
Step-by-step explanation:
Use the following models to show the equivalence of the fractions 35 and 610 a) Set model
Use the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set model
Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 95 degrees and the low temperature of 75 degrees occurs at 6 AM. Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.
Answers
Answer:
Yes, a sinusoidal function is a great way to model temperatures over a 24-hour period because the pattern of temperature changes tends to be cyclic.
A sinusoidal function can be written in the general form:
D(t) = A sin(B(t - C)) + D
where:
- A is the amplitude (half the range of the temperature changes)
- B is the frequency of the cycle (which would be `2π/24` in this case because the temperature completes a full cycle every 24 hours)
- C is the horizontal shift (which is determined by the fact that the minimum temperature occurs at 6 AM)
- D is the vertical shift (which is the average of the maximum and minimum temperature)
Given the information you've provided, let's fill in the specifics:
- The high temperature for the day is 95 degrees.
- The low temperature is 75 degrees at 6 AM.
The amplitude, A, is half the range of temperature changes. It's the difference between the high and the low temperature divided by 2:
A = (95 - 75) / 2 = 10
The frequency, B, is `2π/24` because the temperature completes a full cycle every 24 hours.
The horizontal shift, C, is determined by the fact that the minimum temperature occurs at 6 AM. The sine function hits its minimum halfway through its period, so we want to shift the function to the right by 6 hours to make this happen. In our case, this means C = 6.
The vertical shift, D, is the average of the maximum and minimum temperature:
D = (95 + 75) / 2 = 85
So the equation for the temperature, D, in terms of t (the number of hours since midnight) is:
D(t) = 10 sin((2π/24) * (t - 6)) + 85
This equation represents a sinusoidal function that models the temperature over a day given the information provided.
joan’s finishing time for the bolder boulder 10k race was 1.81 standard deviations faster than the women’s average for her age group. there were 410 women who ran in her age group. assuming a normal distribution, how many women ran faster than joan? (round down your answer to the nearest whole number.)
Answers
Given that Joan's finishing time was 1.81 standard deviations faster than the women's average for her age group, we can use the properties of a normal distribution to find the corresponding percentage.
Since Joan is faster than the average, her finishing time would fall in the top portion of the distribution. Using a standard normal distribution table or a calculator, we can find the percentage of data below her finishing time. The Z-score associated with 1.81 standard deviations is approximately 0.9641, which corresponds to a percentage of 96.41%.
This means that approximately 96.41% of the women in her age group ran slower than Joan. To find the number of women who ran faster, we subtract this percentage from 100%: 100% - 96.41% = 3.59%.
To determine the number of women, we multiply the percentage by the total number of women in her age group: 3.59% * 410 = 14.709.
Rounding down to the nearest whole number, we can conclude that approximately 14 women ran faster than Joan.
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Please help with 35
Answers
Answer:
x = 4
Step-by-step explanation:
By property, if two tangents are drawn from an external point , then they are equal
⇒ 2x + 3 = 11
⇒ 2x = 11 - 3
⇒ 2x = 8
⇒ x = 8/2
⇒ x = 4
Answer:
x = 4
Step-by-step explanation:
To find the value of x, we can use the Two-Tangent Theorem.
The Two-Tangent Theorem states that if two tangent segments are drawn to a circle from the same external point, the lengths of the two tangent segments are equal.
Therefore:
[tex]\begin{aligned}AD &= AB\\\\2x+3&=11\\\\2x+3-3&=11-3\\\\2x&=8\\\\\dfrac{2x}{2}&=\dfrac{8}{2}\\\\x&=4\end{aligned}[/tex]
Therefore, the value of x is 4.
Use the formulas to answer this question.
One leg of a right triangle has length 11 and all sides are whole numbers. Find the lengths of the other two sides.
The other leg = and the hypotenuse =
Answers
The lengths of the other two sides of the right triangle are 36 and 85, respectively.
To find the lengths of the other two sides of a right triangle when one leg has a length of 11, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
Let's denote the lengths of the other leg and the hypotenuse as x and y, respectively.
According to the Pythagorean theorem, we have:
x² + 11² = y²
To find the values of x and y, we need to find a pair of whole numbers that satisfy this equation.
We can start by checking for perfect squares that differ by 121 (11^2). One such pair is 36 and 85.
If we substitute x = 36 and y = 85 into the equation, we have:
36² + 11² = 85²
1296 + 121 = 7225
This equation is true, so the lengths of the other two sides are:
The other leg = 36
The hypotenuse = 85
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[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Answers
Answer:
[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Step-by-step explanation:
[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Answer:
[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Step-by-step explanation:
what this is?
Which property is illustrated by the following statement? If A ABC = A DEF,
and ADEF=AXYZ, then AABC=AXYZ.
B.
A
с
E
D
O A. Reflexive
O B. Symmetric
O C. Transitive
O D. Commutative
F
Z
Answers
The property that is illustrated by the statements is Transitive. Option C
How to determine the propertyUsing the principle of transitivity, if two objects are equal to a third, they are also equal to one another.
From the information given, we have that;
< ABC = <DEF
< DEF = < XYZ
This simply proves that < ABC and < XYZ are both equivalent to < DEF in this situation.
By using the transitive property, we can determine that A ABC and A XYZ are also equal. This attribute enables us to construct relationships between many elements based on their equality to a shared third element and to connect logically equalities.
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Question 5(Multiple Choice Worth 1 points)
(01.07 MC)
Lines BC and ED are parallel. They are intersected by transversal AE, in which point B lies between points and E. They are also intersected by transversal EC. Angle ABC measures 70 degrees. Angle CED measures 30 degrees.
Given: line BC is parallel to line ED
m∠ABC = 70°
m∠CED = 30°
Prove:m∠BEC = 40°
Statement Justification
line BC is parallel to line ED Given
m∠ABC = 70° Given
m∠CED = 30° Given
m∠ABC = m∠BED Corresponding Angles Theorem
m∠BEC + 30° = 70° Substitution Property of Equality
m∠BEC = 40° Subtraction Property of Equality
Which of the following accurately completes the missing statement and justification of the two-column proof?
m∠BEC + m∠CED = m∠BED; Definition of a Linear Pair
m∠ABC + m∠BEC = m∠BED; Angle Addition Postulate
m∠ABC + m∠BEC = m∠BED; Definition of a Linear Pair
m∠BEC + m∠CED = m∠BED; Angle Addition Postulate
Answers
Answer:
m∠BEC + m∠CED = m∠BED; Angle Addition Postulate
Step-by-step explanation:
You need to show that <BED is made up of angles BEC and CED by the Angle Addition Postulate.
m∠BEC + m∠CED = m∠BED; Angle Addition Postulate
Determine the surface area and volume
Answers
The surface area of the cone is: 213.66 cm²
The volume of a cone is: 7.33 cm³
How to find the surface area and volume?The formula for the surface area of a cone is:
T.S.A = πrl + πr²
where:
r is radius
l is slant length
From the diagram and using Pythagoras theorem,we have:
l = √(7² + 5²)
l = √74
Thus:
TSA = (π * 5 * √74) + (π * 5²)
TSA = 213.66 cm²
Formula for the volume of a cone is:
V = ¹/₃πr²
V = ¹/₃π * 7
V = 7.33 cm³
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Please answer ASAP I will brainlist
Answers
Answer:
(a) The graph is entirely above the x-axis and rises from left to right, more steeply than the graph of y = 5^x.
(b) The second coordinate of the point with first coordinate 0 is 2.
The second coordinate of the point with first coordinate 1 is 10.
I'm unable to solve question 1 and 3 could anyone help me?
Answers
Answer:
Step-by-step explanation:
pic is not clear
Five angels of a hexagon are 123,124,118,130’110. Calculate the six angle
Answers
Answer:
The sixth angle is 115°.
Step-by-step explanation:
Number of sides in a hexagon = n =6
Sum of interior angles = (n−2)180°
= (6−2)180 ∘
= 720
∴ Let the six angle of hexagon be x.
⇒ x + 123 + 124 + 118 + 130 + 110 = 720°
⇒ x + 605 = 720°
⇒ x = 720 - 605
⇒ x = 115
F(x)=square root of 9-kx^2/k show your work
Answers
Sure! Here’s the solution:
F(x)=k9−kx2
First, let’s square both sides to get rid of the square root:
F(x)2=k9−kx2
Now, let’s multiply both sides by k to isolate the term with x^2:
kF(x)2=9−kx2
Next, let’s move all terms to one side of the equation:
kF(x)2+kx2=9
Finally, let’s factor out x^2:
x2(k+kF(x)2)=9
And solve for x^2:
x2=k+kF(x)29
Answer:
√((9 - kx^2) / k)Step-by-step explanation:
To show the work for evaluating the function f(x) = √(9 - kx^2) / k, we can follow these steps:
Step 1: Simplify the expression under the square root:9 - kx^2
Step 2: Divide the expression by k:(9 - kx^2) / k
Step 3: Take the square root of the expression:√((9 - kx^2) / k)
Note: It is important to consider any domain restrictions or assumptions about the values of k and x that would make the expression valid. For example, if k is negative, the expression would have an imaginary result.Seventy-Two Inc., a developer of radiology equipment, has stock outstanding as follows: 80,000 shares of cumulative preferred 3% stock, $20 par and 410,000 shares of $25 par common. During its first four years of operations, the following amounts were distributed as dividends: first year, $31,000; second year, $73,000; third year, $80,000; fourth year, $120,000. Determine the dividends per share on each class of stock for each of the four years. Round all answers to two decimal places. If no dividends are paid in a given year, enter "0.00". 1st Year 2nd Year 3rd Year 4th Year Preferred stock (dividends per share) $fill in the blank 1 $fill in the blank 2 $fill in the blank 3 $fill in the blank 4 Common stock (dividends per share)
Answers
Preferred stock (dividends per share) = $0.38
Common stock (dividends per share) = $0.00
Second Year:
Preferred stock (dividends per share) = $0.93
Common stock (dividends per share) = $0.00
Third Year:
Preferred stock (dividends per share) = $1.00
Common stock (dividends per share) = $0.00
Fourth Year:
Preferred stock (dividends per share) = $1.50
Common stock (dividends per share) = $0.00
In December 2016 the average price of unleaded
Answers
Please answer ASAP I will brainlist
Answers
(a) The average cost in 2011 is $2247.64.
(b) A graph of the function g for the period 2006 to 2015 is: C. graph C.
(c) Assuming that the graph remains accurate, its shape suggest that: A. the average cost increases at a slower rate as time goes on.
How to estimate the average cost in 2011?Based on the information provided, we can logically deduce that the average annual cost (in dollars) for health insurance in this country can be approximately represented by the following function:
g(x) = -1736.7 + 1661.6Inx
where:
x = 6 corresponds to the year 2006.
For the year 2011, the average cost (in dollars) is given by;
x = (2011 - 2006) + 6
x = 5 + 6
x = 11 years.
Next, we would substitute 11 for x in the function:
g(11) = -1736.7 + 1661.6In(11)
g(11) = $2247.64
Part b.
In order to plot the graph of this function, we would make use of an online graphing tool. Additionally, the years would be plotted on the x-axis while the average annual cost would be plotted on the x-axis of the cartesian coordinate as shown below.
Part c.
Assuming the graph remains accurate, the shape of the graph suggest that the average cost of health insurance increases at a slower rate as time goes on.
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The statement of cash flows for Baldwin shows what happens in the cash account during the year. It can be seen as a summary of the sources and uses of cash. Pleas answer which of the following is true if Baldwin issues bonds
Answers
The statement of cash flows would show an increase in the cash account due to the inflow of cash from the issuance of bonds.
When a company issues bonds, it typically receives cash from the bondholders as a form of borrowing. This inflow of cash would be categorized as a financing activity on the statement of cash flows. The specific section of the statement of cash flows that would capture this inflow would be the "Cash Flows from Financing Activities" section.
Therefore, if Baldwin issues bonds, the statement of cash flows would reflect an increase in the cash account due to the inflow of cash from the bond issuance.
The expression
28 (78-14)9-13(78-49)9
can be
rewritten as
(X-y)" (262 + y? + gxy). Whatis the value of p?
Answers
Answer:
p =1 0
Step-by-step explanation:
x³(x - y)⁹ - y³(x - y)⁹ = (x - y)⁹[x³ - y³]
= (x - y)⁹(x - y)(x² + y² + xy)
= (x - y)¹⁰(x² + y² + xy)
where p = 10 and q = 1
Answer:
p = 10
Step-by-step explanation:
Given expression:
[tex]x^3(x-y)^9 - y^3(x-y)^9[/tex]
Factor out the common term (x - y)⁹:
[tex](x-y)^9(x^3- y^3)[/tex]
[tex]\boxed{\begin{minipage}{5cm}\underline{Difference of two cubes}\\\\$x^3-y^3=(x-y)(x^2+y^2+xy)$\\\end{minipage}}[/tex]
Rewrite the second parentheses as the difference of two cubes.
[tex](x-y)^9(x-y)(x^2+y^2+xy)[/tex]
[tex]\textsf{Apply\:the\:exponent\:rule:} \quad a^b\cdot \:a^c=a^{b+c}[/tex]
[tex](x-y)^{9+1}(x^2+y^2+xy)[/tex]
[tex](x-y)^{10}(x^2+y^2+xy)[/tex]
Comparing the rewritten original expression with the given expression:
[tex](x-y)^{10}(x^2+y^2+xy)=(x-y)^p(x^2+y^2+qxy)[/tex]
We can see that [tex](x-y)^p[/tex] corresponds to [tex](x-y)^{10}[/tex] in the given expression.
Therefore, we can conclude that p = 10.
Please answer ASAP I will brainlist
Answers
Answer:
There is one solution. The solution is 2, 18, 19.
Step-by-step explanation:
If you want me to show working tell me in the comments and I'll edit the answer
Answer:
A. (2, 18, -19)
Step-by-step explanation:
To solve:
Z is the most suitable variable to remove first
Add the first equation to the second equation: (this conveniently removes both y and z)
(x+y-z) + (4x-y+z) = 1+9
Simplify
5x = 10
Solve
x = 2
Multiply the second equation by 2 and minus it to the third equation: (Solve for y)
2(4x-y+z) - (x-3y+2z) = 2(9) - (-14)
Simplify
8x-2y+2z-x+3y-2z=18+14
7x+y=32
Substitute using x=2
7(2) + y = 32
y = 32 - 14
y = 18
Now substitute x and y for their respective values into Equation 1
2 + (-18) - z = 1
Simplify
-z = 19
z = -19
So :
x = 2, y = 18 , z = -19
If the left-hand limit of is equal to the right-hand limit of as x approaches 10, the limit of as x approaches 10 is and the value of k is .
Answers
The limit of f(x) as x approaches 10 is 315 and The value of k is 250.
The function f(x) is a piecewise function, so we need to evaluate it separately for x < 10 and x >= 10.
[tex]f(x)= { \frac{(0.1x(2)+20x+15,x < 10)}{(0.25x(3)+k,x > 10)}[/tex]
For x < 10, the function is equal to 0.1x^2 + 20x + 15. So the left-hand limit of f(x) as x approaches 10 is equal to 0.1(10)^2 + 20(10) + 15 = 315.
For x >= 10, the function is equal to 0.25x^3 + k. So the right-hand limit of f(x) as x approaches 10 is equal to 0.25(10)^3 + k = 250 + k.
Since the left-hand limit and the right-hand limit are equal, the limit of f(x) as x approaches 10 is also equal to 315, and the value of k is equal to 250.
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NO LINKS!! URGENT HELP PLEASE!!
The perimeter of a shape is 15 cm and the area is 25 cm^2
Find the area of the larger shape if it is being enlarged by a scale factor of 6
Answers
Answer:
900 cm²--------------------------
Area is the product of two dimensions hence the ratio of areas of similar figures is the square of the scale factor.
Let the area of the enlarged shape be A, and the scale factor be k = 6.
Then we have the area of the larger shape:
A = 25*k²A = 25*6²A = 900 cm²what is the period of y=cos x?
Answers
The cosine function repeats its pattern every 2π radians (or 360 degrees), we can say that the period of y = cos(x) is 2π.
The period of the function y = cos(x) is 2π.
To understand the period of the cosine function, we need to examine its graph. The cosine function is a periodic function that oscillates between -1 and 1 as x varies. It repeats its pattern over regular intervals.
The cosine function completes one full cycle from 0 to 2π radians (or 0 to 360 degrees). This means that within this interval, the cosine function goes through one complete oscillation, starting from its maximum value of 1, then going through its minimum value of -1, and returning back to 1.
Since the cosine function repeats its pattern every 2π radians (or 360 degrees), we can say that the period of y = cos(x) is 2π.
This means that for any value of x, the value of cos(x) will repeat after an interval of 2π.
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(Comparing Data LC)
The histograms display the frequency of temperatures in two different locations in a 30-day period.
When comparing the data, which measure of variability should be used for both sets of data to determine the location with the most consistent temperature?
A IQR, because Sunny Town is symmetric
B IQR, because Beach Town is skewed
C Range, because Sunny Town is skewed
D Range, because Beach Town is symmetric
Answers
IQR, because Sunny Town is symmetric should be used for both sets of data to determine the location with the most consistent temperature?(option a).
1. The question asks for the measure of variability that should be used to determine the location with the most consistent temperature when comparing the data from two different locations.
2. The first option, A, suggests using the Interquartile Range (IQR) because Sunny Town is symmetric. This means that the data in Sunny Town is evenly distributed around the median, indicating consistency in temperatures.
3. The second option, B, proposes using the IQR because Beach Town is skewed. Skewness implies an asymmetrical distribution, which may indicate less consistency in temperatures.
4. The third option, C, suggests using the Range because Sunny Town is skewed. Skewed data in Sunny Town might imply a larger spread and less consistency in temperatures.
5. The fourth option, D, recommends using the Range because Beach Town is symmetric. However, symmetric data indicates consistency, making the Range less suitable as a measure of variability.
6. Considering the explanations for each option, the best choice is A, IQR, because Sunny Town is symmetric. The symmetric distribution suggests that the temperatures in Sunny Town are consistent and evenly distributed around the median.
7. Therefore, the measure of variability that should be used for both sets of data to determine the location with the most consistent temperature is the IQR, as indicated by option A.
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